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Find the unit vectors u that are perpendicular to both i+2j+k and 3i-4j+2k.
Solution
a=i+2j+k
b=3i-4j+2k
now the cross product axb is perpendicular to both a and b
axb = i j k
1 2 1
3 -4 2
=8i+j-10k
axb=(8^2+1^2+(-10^2))^0.5=(64+1+100)^0.5=165^0.5=12.845
so a unit vector perpendicular to both a and b is a unit vector along axb
now unt vector along axb is
c = axb/(axb)=(8i+j-10k)/12.845=0.623 i +0.07785 j -0.7785 k ans

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Find the unit vectors u that are perpendicular to both i+2j+k and 3i.pdf

  • 1. Find the unit vectors u that are perpendicular to both i+2j+k and 3i-4j+2k. Solution a=i+2j+k b=3i-4j+2k now the cross product axb is perpendicular to both a and b axb = i j k 1 2 1 3 -4 2 =8i+j-10k axb=(8^2+1^2+(-10^2))^0.5=(64+1+100)^0.5=165^0.5=12.845 so a unit vector perpendicular to both a and b is a unit vector along axb now unt vector along axb is c = axb/(axb)=(8i+j-10k)/12.845=0.623 i +0.07785 j -0.7785 k ans