For a soil specimen, the followings are given: Passing sieve No. 4 sieve =92% Passing sieve No. 40 sieve =78% Passing sieve No. 10 sieve =81% Passing sieve No. 200 sieve =65% LL =48 PI =32 Classify the soil using the Unified Classification System Solution Since more than 50% is passing through a No. 200 sieve, it is a fine-grained soil, i.e., it could be ML, CL, OL, MH, CFI, or OH. Now, if we plot LL = 48 and PI = 32 on the plasticity chart, it falls in the zone CL. So the soil is classified as CL..