A fire chief knows that the probabilities for zero, one, two, three, four, or five fires on any given day are as shown in the following table. How many fires can he expect per day? (It is assumed here that the probability of more than five fires is negligible) Solution no of fires expected = 1*.34+2*.25 + 3*.13 + 4*.05 + 5*.01 = 1.48.