The F.S. Supplies Company buys calculators from a Japanese supplier..pdf

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The F.S. Supplies Company buys calculators from a Japanese supplier, with a 20% probability of each calculator being defective. The document provides the solution to calculating the probability that 5 or more of 15 randomly selected calculators will be defective, which is 0.1638 or approximately 16%.

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The F.S. Supplies Company buys calculators from a Japanese supplier. The probability of a
defective calculator is 20%. If 15 calculators are selected at random, what is the probability that
5 or more of the calculators will be defective?
Solution
P(defective)=0.20=p q = 0.80 p(x>=5)=1-( p(0)+p(1)+p(2)+p(3)+p(4)) =1-( q^15
+15C1(p)(q)^14+15C2(p)^2(q)13+15C3(p)^3(q)^12+15C4(p)^4(q)11) =1-
(0.035184+15*0.04398*0.20+105*0.20*0.20*0.05498
+455*0.008*0.06872+1365*0.0016*0.086) =1-( 0.0352+0.132+0.231+0.250+0.188) =1-0.8362
=0.1638 (answer)

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