Your task is to complete a method that swaps the first and second half.docx

•Download as DOCX, PDF•

0 likes•3 views

This document provides code to swap the first and second halves of an integer array. It includes a method that takes an integer array as a parameter, calculates the midpoint and length of each half, and swaps the values in the first half with the values in the second half using a temporary variable. It also includes a check method that calls the swap method and returns the modified array to validate the solution works as intended.

Education

Your task is to complete a method that swaps the first and second half of an array of integers. For
example, if the array contains the values
then after calling the method, it should contain the values
If the array contains an odd number of elements, leave the middle element in place. For example,
becomes
Complete the following code:
Solution
public class Swapper { /** This method swaps the first and second half of the given array.
@param values an array */ public void swapFirstAndSecondHalf(int[] values) { final int len =
values.length / 2; final int offset = values.length - len; for (int i = 0; i < len; i++) { int temp =
values[i]; values[i] = values[offset + i]; values[offset + i] = temp; } // This method is used to
check your work public int[] check(int[] values) { swapFirstAndSecondHalf(values); return
values; } }

Similar to Your task is to complete a method that swaps the first and second half.docx

**********Evaluator.java**************** package evaluator; import java.util.*; import operand.Operand; import operator.Operator; public class Evaluator { private Stack<Operand> operandStack; private Stack<Operator> operatorStack; private StringTokenizer tokenizer; private static final String DELIMITERS = "+-*^/() "; public Evaluator() { operandStack = new Stack<Operand>(); operatorStack = new Stack<Operator>(); } public int eval(String expression) { int result = 0; String token; Operator hashOpr = Operator.operators.get("#"); oprStack.push(hashOpr); String delimiters = "+-*/#!"; // The 3rd argument is true to indicate that the delimiters should be used // as tokens, too. But, we'll need to remember to filter out spaces. this.tokenizer = new StringTokenizer(expression, DELIMITERS, true); while (this.tokenizer.hasMoreTokens()) { // filter out spaces if (!(token = this.tokenizer.nextToken()).equals(" ")) { // check if token is an operand if (Operand.check(token)) { operandStack.push(new Operand(token)); } else { if (!Operator.check(token)) { System.out.println("*****invalid token******"); System.exit(1); } // TODO Operator is abstract - this line will need to be fixed: // ( The Operator class should contain an instance of a HashMap, // and values will be instances of the Operators. See Operator class // skeleton for an example. ) Operator newOperator = null; // new Operator( token ); while (operatorStack.peek().priority() >= newOperator.priority()) { // note that when we eval the expression 1 - 2 we will // push the 1 then the 2 and then do the subtraction operation // This means that the first number to be popped is the // second operand, not the first operand - see the following code Operator oldOpr = operatorStack.pop(); Operand op2 = operandStack.pop(); Operand op1 = operandStack.pop(); operandStack.push(oldOpr.execute(op1, op2)); } operatorStack.push(newOperator); } } } // Control gets here when we've picked up all of the tokens; you must add // code to complete the evaluation - consider how the code given here // will evaluate the expression 1+2*3 // When we have no more tokens to scan, the operand stack will contain 1 2 // and the operator stack will have + * with 2 and * on the top; // In order to complete the evaluation we must empty the stacks (except // the init operator on the operator stack); that is, we should keep // evaluating the operator stack until empty // Suggestion: create a method that takes an operator as argument and // then executes the while loop; also, move the stacks out of the main // method return 0; } /** * Class to help test your Evaluator: * javac EvaluatorTester * java EvaluatorTester "1+2" "3*5" */ public static void main(String[] args) { Evaluator evaluator = new Evaluator(); for (String arg : args) { System.out.format("%s = %d\n", arg, evaluator.eval(arg)); } } } ************************************Operand.Java************************************************** package operand; public class Operand { public .

----------Evaluator-java---------------- package evaluator- import j.docx

Adamq0DJonese

Python_Module_2.pdf

R.K.College of engg & Tech

Java Code: The traditional way to deal with these in Parsers is the Expression-Term-Factor pattern: Expression: TERM {+|- TERM} Term: FACTOR {*|/ FACTOR} Factor: number | ( EXPRESSION ) A couple of notation comments: | means "or" - either + or -, either * or / {} means an optional repeat. That's what allows this to parse 1+2+3+4 Think of these as functions. Every CAPTIALIZED word is a function call. Consider our meme expression above: 6/2*(1+2) We will start by looking at expression. Expression starts with a TERM. We can't do anything until we resolve TERM, so let's go there. A term starts with FACTOR. Again, we can't do anything until we deal with that. A factor is a number or a (EXPRESSION). Now we can look at our token (hint: MatchAndRemove). We see a number. OK - our factor is a number. We "return" that. Remember that we got to factor from term. Let's substitute our number in: TERM: FACTOR(6) {*|/ FACTOR} Now we deal with our optional pattern. Is the next character * or /? Yes! Now is the next thing a factor? It turns out that it is. Let's substitute that in: TERM: FACTOR(6) / FACTOR(2) But remember that our pattern is a REPEATING pattern (hint: loop): TERM: FACTOR(6) / FACTOR(2) {*|/ FACTOR} We see the * and call factor. But this time, the factor is not a number but a parenthetical expression. Factor: number | ( EXPRESSION ) Factor calls expression. Expression calls term, term calls factor, factor returns the number 1. Term doesn't see a * or / so it passes the 1 up. Expression sees the + and calls term. Term calls factor which returns the 2. Expression doesn't see a +|- value so ends the loop and returns 1+2. So, remember that we were here: TERM: FACTOR(6) / FACTOR(2) * FACTOR Our factor is (1+2). That can't be broken down. That math HAS to be done before can multiply or divide. That's what enforces order of operations. In code, this looks like something like this (pseudo-code): Node Factor() num = matchAndRemove(NUMBER) if (num.isPresent) return num if (matchAndRemove(LPAREN).isPresent) exp = Expression() if (exp == null) throw new Exception() if (matchAndRemove(RPAREN).isEmpty) throw new Exception() Node Term() left = Factor() do op = MatchAndRemove(TIMES) if (op.isEmpty) op=MatchAndRemove(DIVIDE) if (op.isEmpty) return left right = Factor() left = MathOpNode(left, op, right) while (true) Node Expression() left = Term() do op = MatchAndRemove(PLUS) if (op.isEmpty) op=MatchAndRemove(MINUS) if (op.isEmpty) return left right = Term() left = MathOpNode(left, op, right) while (true) What is this "MathOpNode"? It's "just" a new node type that holds two other nodes (left and right) and an operation type: *, /, +, -. Notice that the loops use the result of one operation as the left side of the next operation. This is called left associative - the left most part is done first. Right associativity is the opposite - the rightmost part is done first, then we work our way left. Generally, notice the pattern here - we call a function that is the lo.

Java Code The traditional way to deal with these in Parsers is the .pdf

stopgolook

Lecture 8

Mohammed Saleh

Linq and lambda

John Walsh

C programming assignment help

Hebrew Johnson

data structures using C 2 sem BCA univeristy of mysore

ambikavenkatesh2

Space Complexity in Data Structure.docx

Mani .S (Specialization in Semantic Web)

03 function overloading

Jasleen Kaur (Chandigarh University)

The concept of stack is extremely important in computer science and .pdf

arihantsherwani

Extractors & Implicit conversions

Knoldus Inc.

C++ - UNIT_-_IV.pptx which contains details about Pointers

ANUSUYA S

Functional object

ruchijindal87

C++ Course - Lesson 2

Mohamed Ahmed

Data structures arrays

maamir farooq

How do I fix it in LinkedList.java? this is what i did LabProgram.java LinkedList.java: /** * Defines a doubly-linked list class * @author * @author */ import java.util.NoSuchElementException; public class LinkedList { private class Node { private T data; private Node next; private Node prev; public Node(T data) { this.data = data; this.next = null; this.prev = null; } } private int length; private Node first; private Node last; private Node iterator; /**** CONSTRUCTORS ****/ /** * Instantiates a new LinkedList with default values * @postcondition */ public LinkedList() { first = null; last = null; iterator = null; length = 0; } /** * Converts the given array into a LinkedList * @param array the array of values to insert into this LinkedList * @postcondition */ public LinkedList(T[] array) { } /** * Instantiates a new LinkedList by copying another List * @param original the LinkedList to copy * @postcondition a new List object, which is an identical, * but separate, copy of the LinkedList original */ public LinkedList(LinkedList original) { } /**** ACCESSORS ****/ public T getFirst() throws NoSuchElementException { if (isEmpty()){ throw new NoSuchElementException("The list is empty"); } return first.data; } public T getLast() throws NoSuchElementException { if (isEmpty()){ throw new NoSuchElementException("The list is empty"); } return last.data; } /** * Returns the data stored in the iterator node * @precondition * @return the data stored in the iterator node * @throw NullPointerException */ public T getIterator() throws NullPointerException { if (iterator != null){ return iterator.data; }else{ throw new NullPointerException("Iterator is off the end opf the list."); } } /** * Returns the current length of the LinkedList * @return the length of the LinkedList from 0 to n */ public int getLength() { return length; } /** * Returns whether the LinkedList is currently empty * @return whether the LinkedList is empty */ public boolean isEmpty() { return length == 0; } /** * Returns whether the iterator is offEnd, i.e. null * @return whether the iterator is null */ public boolean offEnd() { return iterator == null; } /**** MUTATORS ****/ public void addFirst(T data) { Node newNode = new Node(data); if(isEmpty()){ first = newNode; last = newNode; } else{ newNode.next = first; first.prev = newNode; first = newNode; } length++; } public void addLast(T data) { Node newNode = new Node(data); if(isEmpty()){ first = newNode; last = newNode; } else{ last.next = newNode; newNode.prev = last; last = newNode; } length++; } /** * Inserts a new element after the iterator * @param data the data to insert * @precondition * @throws NullPointerException */ public void addIterator(T data) throws NullPointerException{ if(iterator != null){ Node newNode = new Node(data); newNode.next = iterator.next; iterator.next = newNode; if (iterator == first){ first = newNode; } }else{ throw new NullPointerException("Iterator is off the end opf the list."); } } / public void remov.

How do I fix it in LinkedList.javathis is what i didLabProgra.pdf

mail931892

golang_refcard.pdf

Spam92

Computer programming 2 Lesson 13

MLG College of Learning, Inc

Copy your completed LinkedList class from Lab 3 into the LinkedList.java file below. During this lab we will add more constructors, an equals method and more challenging methods as listed below. Also inspect the LabProgram.java file and notice that the main() method of the LabProgram copies and compares two linked lists. The main() method also calls the more challenging methods. Use Develop mode to test your LinkedList iterator code as you develop it. In Submit mode you will need to complete all lab steps to pass all automatic tests. Step 2: Implement clear() Method clear() re-sets the LinkedList to empty as if the default constructor had just been called. Constructor LinkedList(T[] array) converts the given array into a LinkedList. Constructor LinkedList(LinkedList original) instantiates a new LinkedList by copying another List. Method equals() determines whether the given Object is another LinkedList, containing the same data in the same order, returning whether there is equality. Method spinList(int numMoves) moves all nodes in the list towards the end of the list the number of times specified. Any node that falls off the end of the list as it moves forward will be placed at the front of the list. Method altLists() splices together two LinkedLists to create a third List which contains alternating values from the original list and the given parameter. *Below is my Lab3 LinkedList.class. import java.util.NoSuchElementException; public class LinkedList { private class Node { private T data; private Node next; private Node prev; public Node(T data) { this.data = data; this.next = null; this.prev = null; } } private int length; private Node first; private Node last; private Node iterator; /**** CONSTRUCTORS ****/ /** * Instantiates a new LinkedList with default values * @postcondition */ public LinkedList() { first = null; last = null; iterator = null; length = 0; } /** * Converts the given array into a LinkedList * @param array the array of values to insert into this LinkedList * @postcondition */ public LinkedList(T[] array) { } /** * Instantiates a new LinkedList by copying another List * @param original the LinkedList to copy * @postcondition a new List object, which is an identical, * but separate, copy of the LinkedList original */ public LinkedList(LinkedList original) { } public T getFirst() throws NoSuchElementException { if (first == null) throw new NoSuchElementException(); return first.data; } public T getLast() throws NoSuchElementException { if (last == null) throw new NoSuchElementException(); return last.data; } public T getIterator() throws NullPointerException { if (iterator == null) { throw new NullPointerException("Iterator is off end."); } return iterator.data; } public int getLength() { return length; } public boolean isEmpty() { return length == 0; } public boolean offEnd() { return iterator == null; } public void addFirst(T data) { Node newNode = new Node(data); if (length == 0) { first = newNode; last = newNode; } else .

Copy your completed LinkedList class from Lab 3 into the LinkedList..pdf

facevenky

Below is the assignment description and the file I have written. I would love to test this file to make sure that everything is satisfied (vector with all modes in ascending order). I\'m having a really hard time constructing a main method to test it. Help!! ------------------------------------------------------- The mode is the value that appears most often in a set of data. Write a function named findMode that takes as parameters an array of int and the size of the array, and returns a vector containing the mode(s). If there is just a single most frequent value, the vector will only contain that one value, but if multiple values tie for maximum frequency, the vector will need to contain all such values. This includes the case where every number in the array appears only once. Each mode should appear only once in the vector. The values in the vector that is returned must be in ascending order. If you need to sort a vector, it\'s similar to sorting an array, but specifying the beginning and end of the vector look a little bit different. If your vector is named result, then it would look like this: \"std::sort(result.begin(), result.end());\". ------------------------------------------------------- #include // needed for the sort() function #include // needed to use the vector type #include // needed for the main function using std::vector; using std::sort; vector findMode(int array[], int size) { int maxFreq = 1; // initalizing the largest frequency to be 1 vector result; // results is an empty vector //Initializing the loop through the integer array for (int i = 0; i < size; i++) { int count = 1; //started the counter at 1 //started the the loop after the 1st entry, looking for matches with the value at index i. for (int j = i + 1; j < size; j++) { //if an entry matches another, then add one to the counter if (array[i] == array[j]) { count++; } } //when the counter is equal to the max frequency, the integer is added to the result vector. if (count == maxFreq) { result.push_back(array[i]); } //when the counter for i is greater than the max frequency, updates the maxFreq, clear the values stored in the result vector, and push the value to the empty vector. if (count > maxFreq) { maxFreq = count; result.clear(); result.push_back(array[i]); } } //sort the modes in ascending order sort(result.begin(), result.end()); return result; Below is the assignment description and the file I have written. I would love to test this file to make sure that everything is satisfied (vector with all modes in ascending order). I\'m having a really hard time constructing a main method to test it. Help!! ------------------------------------------------------- The mode is the value that appears most often in a set of data. Write a function named findMode that takes as parameters an array of int and the size of the array, and returns a vector containing the mode(s). If there is just a single most frequent value, the vector will only contain that one value, but if mult.

Below is the assignment description and the file I have written..pdf

info673628

Similar to Your task is to complete a method that swaps the first and second half.docx (20)

----------Evaluator-java---------------- package evaluator- import j.docx

Python_Module_2.pdf

Java Code The traditional way to deal with these in Parsers is the .pdf

Lecture 8

Linq and lambda

C programming assignment help

data structures using C 2 sem BCA univeristy of mysore

Space Complexity in Data Structure.docx

03 function overloading

The concept of stack is extremely important in computer science and .pdf

Extractors & Implicit conversions

C++ - UNIT_-_IV.pptx which contains details about Pointers

Functional object

C++ Course - Lesson 2

Data structures arrays

How do I fix it in LinkedList.javathis is what i didLabProgra.pdf

golang_refcard.pdf

Computer programming 2 Lesson 13

Copy your completed LinkedList class from Lab 3 into the LinkedList..pdf

Below is the assignment description and the file I have written..pdf

More from altonm

Nuclear disarmament should result in the retrieval of large amounts of plutonium from nuclear weapons that are being destroyed. Suggest one method for disposing of this plutonium and one method for repurposing this material. Some people have suggested that radioactive waste should be shot to the sun or outer space. List two reasons that this is not an attractive disposal method. Solution There are several methods to dispose of nuclear waste. However all methods have certain advantages and disadvantages. We cannot use storage containers to dispose plutonium because of its great half life of around 24000 years. We can bury it deep down but it has been proved dangerous . Plutonium can be used to power the reactors but it is a lot more expensive then we think. It is better to dispose off plutonium in water ponds and make use as needed. Why disposing nuclear waste in space is not a good option ????? It would be too costly, but there is a bigger reason not to launch nuclear waste into space: safety. The failure rate may be good enough when the only lives at stake are those who willingly went aboard, but when there is a chance that an explosion in the atmosphere will disperse nuclear waste over a wide area, the failure rate must be much, much lower. It would be a very, very, very bad idea to leave nuclear waste in LEO, so you would actually need to blast it off to deep space. This is exponentially more expensive. Further, if we balst it into space, the material may make an orbit around earth which will affect the incomping sunlight and may enter earth\'s atmosphere because of high half life .

Nuclear disarmament should result in the retrieval of large amounts of.docx

altonm

Nomenclature Practice Problems Ch 20 Part I For compounds represented by the following formulas, what is the systematic name for the compound? 1. Na[CoF] 2. [Al(H2O)2(en)2](NO3)3 3. Pd(NHs)2(CN)2 4. [Ru(en)]Brs 5. K?HgCl2BT2] Part II For compounds whose systematic name is provided below, what is the formula? 1. tris(ethylenediamine)manganese(II)sulfate 2. ammonium tetrahydroxochromate(III) 3. diaquatetraamminetin(IV) nitrate 4. potassium hexacyanomanganate(II) 5. sodium dioxalatocuprate(II) Solution part1 1. sodium tetrafluorocobaltate(III) 2. diaquadiethylenediaminealuminiium(III) nitrate 3.diaminedicyanopaladium(II) 4. tris(ethylenediamine)ruthenium(III) bromide 5. potassium dibromotrichloromercurate(II) Part II 1. [Mn(en) 3 ]SO 4 2. NH 4 [Cr(OH) 4 ] 3. [Sn(H 2 O) 2 (NH 3 ) 4 ](NO 3 ) 4 4. K 4 [Mn(CN) 6 ] 5. Na 2 [Cu(C 2 O 4 ) 2 ] .

Nomenclature Practice Problems Ch 20 Part I For compounds represented.docx

altonm

NO2 is a yellow gas responsible for the brownish haze that builds up periodically over large cities like Los Angeles. NO2 readily decomposes to NO + O in sunlight (a reaction called photodissociation ). NO2 + hv -> NO2* -> NO + O ground state excited state You can assume the relevant part of the molecular orbital diagram for NO2 (HOMO and LUMO) closely resembles the diagram for O3, shown above (although the number of valence electrons is not the same). b. Which electronic transition (movement of electron from one orbital to another) accounts for the yellow color? c. Explain why the excited state molecule is more likely to undergo photodissociation than the ground state. Solution Nitrogen dioxide has one unpaired electron which makes very reactive.nitrogen dioxide gas is also very toxic. When heated to higher temperatures its color becomes dark and eventually brown gas. When it is cooled down, the color becomes yellow then more paler and subsequently colorless. The color of nitrogen dioxide gas is consequence of absorption of light in 400- 500 nm region. The brown color is complimentary color of green - blue color which is absorbed at 400- 500nm. The transition is likely to be n??* . .

NO2 is a yellow gas responsible for the brownish haze that builds up p.docx

altonm

No need for any sort of explanation. Please only a straightforward answer with no additional explanation. As few steps as possible. Kindly type clear. Solution (a) Hume-Rothery rules named after William Hume Rothery are the set of rules which states the conditions in which an element can dissolve in a metal resulting in the formation of a solid solution. There are two set of rules: 1. Substitutional Solid Solutions 2. Interstitial Solid Solutions There are different rules for both types of solid solutions. (b) Frenkel defect is a defect which occurs in crystalline solids when an atom or ion(normally cation) leaves its own lattice site and occupy an interstitial site thus resulting in the vacant site. This defect occurs in lattice structures which are relatively open and possess low coordination number. (c) A Schottky defect is a vacancy defect in ionic solids. It occurs when an equal number of anions and cations are missing from the lattice. It occurs in ionic compounds of high coordination number in which anions and cations are of the same size. (d) Domain boundaries can carry information and act as memory devices. Domains are bulky objects in which large response to changing external fields is due to change in volume which results in the movement of domain boundaries. .

No need for any sort of explanation- Please only a straightforward ans.docx

altonm

No copy and paste from other website, must be in your own words. Thank You! 1. What is the smallest amount of an element that still has the properties of that element? 2. The nucleus of an atom is composed of what two subatomic particles? 3. The atomic number determines what kind of an element an atom is. What is the atomic number? 4. What are isotopes? 5. The quantum concept is based on what simple idea? Solution 1.) an atom is the smallest amount of an element that has properties of that element 2.) nucleus is composed of protons and neutrons with electrons revolving around nucleus. 3.) atomic number usually represents the number of protons in the element 4.) isotopes are two different states of an element having different values of atomic mass i.e they have same number of protons but different neutrons thus same atomic number but different atomic mass. 5.)The quantum concept is based on simple idea that the energy of universe is constant. .

No copy and paste from other website- must be in your own words- Thank.docx

altonm

nidly s wht is ment the er Solution The branch of science and technology concerned with the use of high temperatures to extract and purify metals .It consists of the thermal treatment of minerals and metallurgical ores and concentrations to bring about physical and chemical transformation in the materials to enable recovery of valuable metals Pyrometallurigical processes are generally grouped into one or more of the following categories : Calcination :calcination is the thermal decomposition of materials Smelting:smelting involves thermal reactions in which at least one product is a molten phase . Refining :refining is the removal of impurities from materials by a thermal process .This covers a wide range of processes ,involving different kinds of furnace at a plant Hydrometallurgy is a method for obtaining metals from their ores .It is a technique within the field of extractive metallurgy involving the use of aqueous chemistry for the recovery of metals from ores ,concentrates ,and recycled or residual materials . It is typically divided into three general areas 1.Leaching 2.solution concentration and purification . 3.metal or metal compound recovery .

nidly s wht is ment the er SolutionThe branch of science and technolog.docx

altonm

Newton Inc. uses a calendar year for financial reporting. The company is authorized to issue 9,013,000 shares of $12 par common stock. At no time has Newton issued any potentially dilutive securities. Listed below is a summary of Newton Solution Assumption 1. Accouting period includes from april 2013 to march 2014 2.Number of common shares issued and outstanding at December 31, 2012 is same as on 1st april 2013. .

Newton Inc- uses a calendar year for financial reporting- The company (1).docx

altonm

olecular Forces liquid and sold states, molecules are held together by attractions called intermolecular forces. There are several types of intermolecular forces London dispersion forces, found in all substances, resuit fom the motion of electrons. These work to atract both polar and nonpolar molecules to one another via instantaneous dipole moments Dipole-dipole forces arise from molecular dipole moments lon-dipole forces result from the interaction of an ion and a molecular dipole attraction of a hydrogen atom bonded to a small highly electronegative atom (N, O, and F) and the unshared electron pairs of another electronegative atom cal propertles such as beiling point, melting point, vapor pressure, viscosity, and surface tension are all affected by the strength of the intermolecular forces within a subatance Part A Mhat happens to these physical propetios as the shengh of intermnoleoula forces increases? Drag each item to the appropriate bin View Available Hint(s) Reset Help viscosity boing point vaper pressuretace tensionmelting point increase Decrease Submi Solution As strength of intermolecular forces increase we get Viscocity , boiling point , surface tension , melting point increases The only factor that decreases is Vapor pressure .

olecular Forces liquid and sold states- molecules are held together by.docx

altonm

Okay- so I understand questions 1- however I don-'t get how to find ou.docx

altonm

ofa fallowing sormally wuma vp faest wee heot in appliod A) water B) wood D) inn 16. Iee bas a lower dmsity than waler Hewass ice: wser motecuies B) moleacales are more compact in the solid sate C) sinks. D) is made of open-structured, hexagonal cryst 17. Consider a closed, sealel cans of air placed on a hot sove. The comained sir undergnes an increase in: A) volume C) density D) peessure and sempecracure Diffraction is a result ot A) refractics. B) refilection. C) dispersion. ID) interlierence. 18. 19. Colors seen when gasoline forms a thin film on wanes are a demonstration of A) interference B) refraction C) dispersion D) reflection. Eloctromagnetic waves can travel A) through a vacuum. 20. B) through a medium. C) through either a medium or a vacuum. D) thruugh a current. Solution 15. D. Iron 16. D. is made of open structured, hexagonal crystals. 17. D. Pressure and Temperature 18. D. Interference 19. A. Interference 20. C. through either a medium or a vacuum. .

ofa fallowing sormally wuma vp faest wee heot in appliod A) water B) w.docx

altonm

Often in science it is helpful to talk about a representative example of the objects or phenomena being studied. However, you must always keep in mind that the average case is not always representative. For example, our Sun is often described as an \"average\" star in the Milky Way. In what sense is this statement true? In what sense is this statement seriously misleading? Do you think it is useful to characterize the stars in the Milky Way by simply citing our \"average\" Sun? Solution Our galaxy is comprised of millions of stars spread over tens of thousands of light years and each of these has planets of their own. Stars are divided into classes and ours is a G class in the middle of its lifespan, there are tons of different types of stars from blue giants, red giants, hypergiants, neutron stars, white dwarfs, red dwarfs, brown dwarfs and a thousand others. However the Sun is a very average star indeed there is nothing special about it other than having a planet orbiting it with life on it. It was born out of the ashes of other stars before it and will die like its predecessors to become part of other star billions of years from now. The Sun is not anything special at all it is a main sequence star but if it makes you feel better the majority of the stars are dwarfs in our galaxy however in relative terms the Sun is still very average. I don\'t know what makes you think this is misleading because that idea that we are special or our sun is died out a long time ago with the rest of the religious bigots and narrow minded individuals of past centuries. .

Often in science it is helpful to talk about a representative example.docx

altonm

Obstacles in EHRs Implementation Discuss the major local, national, and international obstacles to implementing standardized terminologies within EHRs. Solution there are many obstacles in implementing the EHR in a real world. they are it is very costly process so many are not willing to change in their working environment technicakl skills are recquired softwares related to the EHR should be developed technical barriers organizational limitations and their attitude and behaviour of that people there is no sharing and accessing of data in state wide national wideor international wide to help the patients when necessary every people health data must be stored in the digital form so that it will be helpful for the doctors to know the report of the patient but maintaining every people record from the starting of their life is very difficult because the volume ofthe data is very huge and the velocity of the data is also becomes huge. so there are technical limitations and we have to over come the problems by using big data,map reduce,haoop programs. .

Obstacles in EHRs Implementation Discuss the major local- national- an.docx

altonm

o be (11) Explain why an object (like a pencil) that is partially submerged in water appears to be bent. Solution The reason behind this phenomena is refraction of light in two medium.. The light as we know needs a medium for its propagation. Every medium has its own refractive index which is usually taken with respect to air. For sake of simplicity the refractive index of air is taken as unity. When we see any object, the light from that object travels through medium of air and reaches to our retina. The light has its specific wavelength and speed during its propagation. When an object is placed such that it is in two medium, the light travels from both the media before reaching our eye. Here the two media are air and water. Water has higher refractive index than air which causes refraction. Due to the change in medium the speed of light decreases. The refraction causes difference in speed of light the pencil like object kept in water appears to be bent or broken. .

o be (11) Explain why an object (like a pencil) that is partially subm.docx

altonm

Numerical Analysis: (Matlab) Write a program that computes an integral numerically, using the composite trapezoidal, midpoint, and Simpson methods. Input for the program consists of the integrand, the ends of the integration interval and the number of (uniform) subintervals. Apply your program to the two following integrals: Solution function integral = trapezoidal(a,b,n,f) h = (b-a)/n; x = [a+h:h:b-h]; integral = h/2*(2*sum(feval(f,x))+feval(f,a)+feval(f,b)); trapezoidal(1,2,4,\'f\') end function y = f(t) y = t.*log(t); end function integral = simpsons(a,b,n,f) h = (b-a)/n; xi0 = feval(\'f\',a)+feval(\'f\',b); xi1 = 0; xi2 = 0; for i = 1:n-1 x = a+i*h; if mod(i,2) == 0 xi2 = xi2+feval(\'f\',x); else xi1 = xi1+feval(\'f\',x); end end xi = h*(xi0+2*xi2+4*xi1)/3; end function integral = midPoint(a,b,n,f) h = (b-a)/(n+2); x = [a+h:2*h:b-h]; integral = 2*h*sum(feval(f,x)); end --------------------------------------------------------------------------------------------- a) f1 = @(x)4/(1+x.^2); res1 = trapezoidal(1,1,4,f1) res2 = simpsons(1,1,1,1f1) res3 = midPoint(1,1,1,f1) b) f2 = @(x)sqrt(x); res1 = trapezoidal(1,1,4,f2) res2 = simpsons(1,1,1,1f2) res3 = midPoint(1,1,1,f2) .

Numerical Analysis- (Matlab) Write a program that computes an integral.docx

altonm

Yvon- an accountant- is charged with negligence by Zesty Sauce- Inc--.docx

altonm

Your host has automatically received an IPv6 address working in conjunction with its local router that is not configured for DHCP. What technology is at work here? A. ICMPv6 B. SLAAC C. Stateless DHCP D. Stateful DHCP Solution Stateless DHCP : Stateless DHCP refers to the DHCP server(s), which is not required to store any dynamic state information on the DHCP server(s) about any indivisual DHCP clients. The DHCP clients don\'t use the DHCP server(s) to obtain IP address(es) information, they use the DHCP server(s) to obtain the other useful configuration informaiton. Option C. Stateless DHCP is correct choice. .

Your host has automatically received an IPv6 address working in conjun.docx

altonm

Your community has decided to construct a hazardous waste facility for incinerating hazardous waste. What types of contracts would you use for securing solid waste services? What elements would you include in your request for proposal? Solution 1) public private contracting Solid waste contract between local government and private sectors are common 2) intergovernmental contract It involves more than one authority. Two main types of intergovernmental contract. Service contract and. Joint cooperative arrangements. Elements for request proposal 1) proposers statement Includes Fees, proposers packaging requirements , proposers qualifications, proposers facilities,, disposal option emphasis, others 2)price proposal and certification form .

Your community has decided to construct a hazardous waste facility for.docx

altonm

Young Corporation incurred research and development costs of $500-000.docx

altonm

You work for a small city IT department, and you are reviewing computer security procedures with a new technician. You are discussing the differences between BitLocker and NTFS Encrypted File System (EFS). Which of the following describes attributes of BitLocker? A. It stores encryption keys in user profiles. B. It can always be used when the system and boot volumes are combined. C. It protects system integrity during the boot process. D. It can only be enabled or disabled by administrators. Solution C. It protects system integrity during the boot process. D. It can only be enabled or disabled by administrators. BitLocker protects system integrity during the boot by scanning for unauthorized system changes. BitLocker can only be enabled or disabled by an administrator user. NTFS EFS canâ€™t protect system integrity, and all users can use NTFS EFS to encrypt files. .

You work for a small city IT department- and you are reviewing compute.docx

altonm

Your CEO is from the old school. What steps would you take to entice him toward an Executive Information (DSS) System? Explainâ€¦donâ€™t simply list. Solution An Executive Information System (EIS) is a tool that provides direct on-line access to relevant information in a useful and navigable format. Relevant information is timely, accurate, and actionable information about aspects of a business that are of particular interest to the senior manager. An EIS is easy to navigate so that managers can identify broad planned issues, and then travel around the information to find the root causes of those issues. Executive Information Systems differ from traditional information systems in the following ways: Decision Support Systems .

Your CEO is from the old school- What steps would you take to entice h.docx

altonm

More from altonm (20)