Construct the requested confidence interval. From a sample of 1201.pdf

A

Construct the probability distribution for the value of a 2-card hand dealt from a standard deck of 52 cards (all face cards have a value of 10 and ace has a value of 11). What is the probability of being dealt 21? Solution P(dealt 21)= C4,1*C12,1/C52,2=4*12/(51*51/2)=96/2652=.0362.

Último(20)

Material del tarjetero LEES Travesías.docx
Norberto Millán Muñoz57 visualizações
Class 10 English lesson plans
Tariq KHAN172 visualizações
BYSC infopack.pdf
Fundacja Rozwoju Społeczeństwa Przedsiębiorczego144 visualizações
Women from Hackney’s History: Stoke Newington by Sue Doe
History of Stoke Newington103 visualizações
Chemistry of sex hormones.pptx
RAJ K. MAURYA97 visualizações
STERILITY TEST.pptx
Anupkumar Sharma102 visualizações
Industry4wrd.pptx
BC Chew153 visualizações
UWP OA Week Presentation (1).pptx
Jisc51 visualizações
Scope of Biochemistry.pptx
shoba shoba110 visualizações
DU Oral Examination Toni Santamaria
MIPLM128 visualizações
Psychology KS5
WestHatch53 visualizações
2022 CAPE Merit List 2023
Caribbean Examinations Council3K visualizações
Sociology KS5
WestHatch50 visualizações
ANATOMY AND PHYSIOLOGY UNIT 1 { PART-1}
DR .PALLAVI PATHANIA156 visualizações
Ch. 7 Political Participation and Elections.pptx
Rommel Regala55 visualizações
SIMPLE PRESENT TENSE_new.pptx
Dance KS5 Breakdown
WestHatch52 visualizações
Plastic waste.pdf
alqaseedae81 visualizações
Narration ppt.pptx
Tariq KHAN62 visualizações

Construct the requested confidence interval. From a sample of 1201.pdf

• 1. Construct the requested confidence interval. From a sample of 1201 Americans, it was found that 1139 of them lived in neighborhoods with acceptable levels of carbon monoxide (from data obtained from the Environmental Protection Agency). Find a 99% confidence interval for the population proportion of Americans that live in neighborhoods with acceptable levels of carbon monoxide. Solution Given n=1201, p=1139/1201= 0.95 a=0.01, |Z(0.005)|=2.58 (check standard normal table) So 99% CI is p±Z*[p*(1-p)/n] --> 0.95 ± 2.58*sqrt(0.95*0.05/1201) --> ( 0.9337746, 0.9662254)
Idioma atualEnglish
Español
Portugues
Français
Deutsche