Construct the requested confidence interval. From a sample of 1201.pdf
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Construct the probability distribution for the value of a 2-card hand dealt from a standard deck of 52 cards (all face cards have a value of 10 and ace has a value of 11). What is the probability of being dealt 21? Solution P(dealt 21)= C4,1*C12,1/C52,2=4*12/(51*51/2)=96/2652=.0362.
Construct the requested confidence interval. From a sample of 1201.pdf
•0 gostou•3 visualizações
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Construct the probability distribution for the value of a 2-card hand dealt from a standard deck of 52 cards (all face cards have a value of 10 and ace has a value of 11). What is the probability of being dealt 21? Solution P(dealt 21)= C4,1*C12,1/C52,2=4*12/(51*51/2)=96/2652=.0362.
![Construct the requested confidence interval.
From a sample of 1201 Americans, it was found that 1139 of them lived in neighborhoods with
acceptable levels of carbon monoxide (from data obtained from the Environmental Protection
Agency). Find a 99% confidence interval for the population proportion of Americans that live in
neighborhoods with acceptable levels of carbon monoxide.
Solution
Given n=1201, p=1139/1201= 0.95
a=0.01, |Z(0.005)|=2.58 (check standard normal table)
So 99% CI is
p±Z*[p*(1-p)/n]
--> 0.95 ± 2.58*sqrt(0.95*0.05/1201)
--> ( 0.9337746, 0.9662254)](https://image.slidesharecdn.com/constructtherequestedconfidenceinterval-230327052354-f162e4b2/75/construct-the-requested-confidence-interval-from-a-sample-of-1201pdf-1-2048.jpg?cb=1679896652)
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Construct the requested confidence interval. From a sample of 1201.pdf
- 1. Construct the requested confidence interval. From a sample of 1201 Americans, it was found that 1139 of them lived in neighborhoods with acceptable levels of carbon monoxide (from data obtained from the Environmental Protection Agency). Find a 99% confidence interval for the population proportion of Americans that live in neighborhoods with acceptable levels of carbon monoxide. Solution Given n=1201, p=1139/1201= 0.95 a=0.01, |Z(0.005)|=2.58 (check standard normal table) So 99% CI is p±Z*[p*(1-p)/n] --> 0.95 ± 2.58*sqrt(0.95*0.05/1201) --> ( 0.9337746, 0.9662254)