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OOP 2012 - Hint: Dynamic allocation in c++
1.
Dynamic Allocation in
C++ allan914.120418 (update: 120420)
2.
Example 1 #include<iostream> using namespace
std; int main() { int* a; int n; cin >> n; a=new int [n]; for(int i=0;i<n;i++) a[i]=i+1; for(int i=0;i<n;i++) cout << a[i] << " "; delete [] a; return 0; }
3.
Example 1: Result Sample
Input 10 Sample Output 1 2 3 4 5 6 7 8 9 10
4.
Example 2 #include<iostream> using namespace
std; int main() { int** a; int n,m; cin >> n; cin >> m; a=new int* [n]; for(int i=0;i<n;i++) a[i]=new int [m]; for(int i=0;i<n;i++) for(int j=0;j<m;j++) a[i][j]=i+j+1; for(int i=0;i<n;i++) { for(int j=0;j<m;j++) cout << a[i][j] << " "; cout << endl; } for(int i=0;i<n;i++) delete [] a[i]; delete [] a; return 0; }
5.
Example 2: Result
Sample Input 5 4 Sample Output 1234 2345 3456 4567 5678
6.
Example 3 #include<iostream> using namespace
std; int main() { int* a; int n,m; cin >> n; cin >> m; a=new int [n*m]; int** b; b=new int* [n]; for(int i=0;i<n;i++) b[i]=&(a[n*i]); for(int i=0;i<n;i++) for(int j=0;j<m;j++) b[i][j]=i+j+1; for(int i=0;i<n;i++) { for(int j=0;j<m;j++) cout << b[i][j] << " "; //cautious with CodeBlocks ! cout << endl; } delete [] b; delete [] a; return 0; }
7.
Example 3: Result
Sample Input 5 4 Sample Output 1234 2345 3456 4567 5678
8.
Example 4 // Headers
emitted, cautious with CodeBlocks ! void* new2d(int n,int m,int size) { void **a = new void* [m*sizeof(void*) + n*m*size]; for(int j=0;j<m;j++) a[j] = ((char *)(a+m)) + j*n*size; return a; } int main() { int** a; int n,m; cin >> n; cin >> m; a = (int**)new2d(n,n,sizeof(int)); for(int i=0;i<n;i++) for(int j=0;j<m;j++) a[i][j]=i+j+1; for(int i=0;i<n;i++) { for(int j=0;j<m;j++) cout << a[i][j] << " "; cout << endl; } delete [] a; return 0; }
9.
Example 4: Result
Sample Input 5 4 Sample Output 1234 2345 3456 4567 5678
10.
Example 5 #include<iostream> #include<vector> using namespace
std; int main() { int n,m; cin >> n; cin >> m; vector<vector<int> > a(n, vector<int>(m)); for(int i=0;i<n;i++) for(int j=0;j<m;j++) a[i][j]=i+j+1; for(int i=0;i<n;i++) { for(int j=0;j<m;j++) cout << a[i][j] << " "; cout << endl; } return 0; }
11.
Example 5: Result
Sample Input 5 4 Sample Output 1234 2345 3456 4567 5678
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