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p(x)= (x+x^(5)+x^(7))^(10)(1+x^(2))^(11)(x^(3)+x^(5)+x^(7))
Solution
The ans is 0
because the the highest term of x + x5 +x7 to the power 10 when expanded will be x70
for the highest term for 1+x2 to the power 11 when expended will be x22
and the highest tem in x3 + x5 + x7 is x7
Multiplying the 3 the highest of the total will be x99
Hence the 100th derivative will be 0

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p(x)= (x+x^(5)+x^(7))^(10)(1+x^(2))^(11)(x^(3)+x^(5)+x^(7))Solut.pdf