Q.#1 On a certain examination the average score is 53 and the standard deviation is 6. Find a range of values within which at least 75% of the scores will fall. Solution Answer: Range of values = [41 to 65] Explanation: Mean = 53 and Standard Deviation = 6 According to Cheyshev\'s Inequality, PX(|X-| >= k) <= 1/k2 PX(-k < X < +k) >= 1-1/k2 Since at least 75% of the scores should within the range, 1-1/k2 = 3/4 => k = 2. So ±k gives 53±2(6) or [41 points to 65 points].