At what point(s) does the graph of the function shown below have a horizontal tangent? x^2+ y^2=2x There is a horizontal tangent at the point(s) . (Type an ordered pair. Use a comma to separate answers as needed.) Solution x^2 + y^2 = 2x by differentiating with respect to x we get 2x + 2y dy/dx = 2 dy/dx= 1-x/y for a horizontl tangent the slope is zero. 1-x =0 x = 1. so at points (1.1) and (1,-1) the tangents are horizontal..