a student nee 10% hydrochloric acid for a chemistry experiment. how much 5% acid should be mixed with 60 ml of 20% acid to get 10% solution. Solution We know that 5% of beaker X is acid, and 20% of beaker Y is acid. Beaker Y is 60ml. We don\'t know he amount of overall liquid in X, so we will say that the is x ml in it. If we are dumping the entire contents of X and of beaker Y together then the final amount of liquid will be (x + 60)ml If we think about this in terms of acid: 5%x +20%(60ml) = the acid we need, since acid +acid = acid, which is then 5%x +20%(60ml) =10%(x+60) change percents to usable decimals 0.05x + 0.2(60) = 0.1(x + 60) and then solve for x..

1. a student nee 10% hydrochloric acid for a chemistry experiment. how much 5% acid should be
mixed with 60 ml of 20% acid to get 10% solution.
Solution
We know that 5% of beaker X is acid, and 20% of beaker Y is acid.
Beaker Y is 60ml.
We don't know he amount of overall liquid in X, so we will say that the is x ml in it.
If we are dumping the entire contents of X and of beaker Y together then the final amount of
liquid will be
(x + 60)ml
If we think about this in terms of acid:
5%x +20%(60ml) = the acid we need, since acid +acid = acid, which is then
5%x +20%(60ml) =10%(x+60)
change percents to usable decimals
0.05x + 0.2(60) = 0.1(x + 60) and then solve for x.