A Journalist took a simple random sample of 725 voters in a region that has a population of 12,457. She recorded that 338 of the persons polled favored Issue 1 on the ballot. how to construct a 95% confidence interval for the proportion that favor the issue. What are things that cannot be said in her report before she publishes it. If you were the editor of a newspaper reporting on the results, what questions would you have of the journalist before you printed her story? Solution He could say that he was confident that the issue is close but a majority of people probably didn\'t favor issue 1. In short he really couldn\'t say one way or another as to whether the majority of people favor issue 1. He can\'t speak to the probability of issue 1 being voted on in the ballot at all. proportion that favor issue 1 = 338/725 = 0.46620689655172413793103448275862 var p = 3.4325244987494362212472836114642e-4 std p = 0.018527073429847025414005307365008 thus 95% confidence interval is approximately (0.42915274969203008710302386802798, 0.50326104341141818875904509748703) --- If I where the editor I would ask how he conducted the sample. The sample should be taken randomly with a diverse distribution of the target population having a chance in the sample..