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Hydrocarbons.pptx

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Hydrocarbons.pptx

  1. 1. HYDROCARBONS
  2. 2. HYDROCARBONS ALKANES ALKENES ALKYNES
  3. 3. Preparation of alkyne 1. From calcium carbide 2. By dehalogenation of tetrahalides (zn / ) 3. By chloroform & silver powder 4. From vicinal dihalides (alcoholic KOH + KNH2) OR (alcoholic NaOH + NaNH2 Sodamide) 5. From germinal dihalides 6. By kolbe’s electrolysis fumaric or maleic acid
  4. 4. ALKANES PREPARATION 1.REDUCTION OF ALKENE OR ALKYNE 1I .ALKYL HALIDES WURTZ REACTION KOLBE’S ELECTROLYSIS
  5. 5. ALKANES PREPARATION SODA LIME DECARBOXYLATION CLEMMENSON AND WOLF KISHNER COREY HOUSE SYNTHESIS
  6. 6. ALKANES PROPERTIES HALOGENATION OF ALKANE NITRATION SULPHONATION
  7. 7. ALKANES PROPERTIES POLYMERISATION PYROLYSIS AROMATISATION
  8. 8. ALKANES PROPERTIES OXIDATION OF ALKANE Combustion Catalytic oxidation
  9. 9. 2.ALKENES PREPARATION 1.DEHYDRATION OF ALCOHOL 2.DEHALOGENATION OF ALKYL HALIDE REDUCTION OF ALKYNES 1.BIRCH REDUCTION 2.LINDLAR’S CATALYST KOLBE’S ELECTROLYSIS
  10. 10. PREPARATION OF ALKENES #2 1. DEHYDRATION OF ALCOHOLS 2.DEHYDROHALOGENATION OF ALKYL HALIDE
  11. 11. PREPARATION OF ALKENES #2 1. FROM ALKYNES BIRCH REDUCTION LINDLAR’S CATALYST BY KOLBE’S ELECTROLYSIS
  12. 12. Preparation of alkene: complete reduction  From alkyne C = C C = C Reduction or hydrogenation  R-C=CH R-CH=CH2 R-CH2-CH3  CATALYST : Ni / H2 or Pd / H2  If we use normal strong reducing agents we get alkanes not alkenes.
  13. 13. Partial reduction  So for partial reduction upto alkene we require special catalysts.
  14. 14. BIRCH REDUCTION
  15. 15. Catalyst for trans- alkene (BIRCH REDUCTION) Na / liquid NH3 Li / liquid NH3
  16. 16. CONDITION FOR BIRCH REDUCTION Alkynes with terminal triple bond cannot be used for birch reduction.
  17. 17. BIRCH REDUCTION CH3 H Na / liq NH3  CH3-C=C-CH3 or C = C Li / Liq NH3 H CH3 Trans alkene
  18. 18. MECHANISM 1. Li Li+ + e – 2. CH3 – C = C – CH3 CH3 - C=C-CH3 CH3 – C=C –CH3 due to e- repulsion we get, CH3 – C=C –CH3
  19. 19. CH3 H CH3 – C=C –CH3 C = C CH3 Strong base CH3 H C=C CH3
  20. 20. PRODUCT CH3 H C = C H CH3
  21. 21. LINDLAR’S CATALYST ( CIS - ALKENE) Alkynes with terminal triple bond cannot be used for lindlar’s catalyst.
  22. 22. LINDLAR’S CATALYST ( CIS - ALKENE) CATALYST : 1. Pd / BaSO4 2.Pd / CaCO3 In presence of quinoline Or Sulphur Or Pb (OAC)2
  23. 23. CIS-ALKENE Pd / BaSO4 CH3 CH3  CH3 –C=C-CH C= C Pd / CaCO3 H H in presence of quinoline or sulphur
  24. 24. Pd acts as good adsorbate of H2.  So two hydrogens are added on the same side , so cis- alkene is formed. H H p Adsorb
  25. 25. P -2 CATALYST  Ni / B  Ni 2B  In the presence of P2 catalyst also we get cis alkene.
  26. 26. CIS-ALKENE Ni / B CH3 CH3  CH3 –C=C-CH C= C Ni2B H H
  27. 27. Na / liq NH3  Q) CH3-C=C-CH3 (A) Pd / CaCO3 (B) (CH3COO)2Pb The minimum heat of hydrogenation is in A. (A) B. (B) C. Both have equal D. Cannot predict
  28. 28. Na / liq NH3  Q) CH3-C=C-CH3 (A) Pd / CaCO3 (B) (CH3COO)2Pb The minimum heat of hydrogenation is in A. (A) B. (B) C. Both have equal D. Cannot predict
  29. 29.  Stability 1 heat of hydrogenation
  30. 30.  A) is birch reduction. It gives trans alkene.  B) is lindlar’s catalyst . It gives cis alkene.
  31. 31.  cis-alkene is more stable than trans- alkene.  Since stability is inversely proportional to stability.  More the stability , less will be the heat of hydrogenation.
  32. 32. Na / liq NH3  Q) CH3-C=C-CH3 (A) Pd / CaCO3 (B) (CH3COO)2Pb The minimum heat of hydrogenation is in A. (A) B. (B) C. Both have equal D. Cannot predict
  33. 33. Kolbe ‘ s electrolysis :  By electrolysis of aq. sodium or potassium salt of dicarboxylic acids. CH3-COOH K CH3-COOK H2 + CH3-COOH CH3-COOK Butane 1,4 dioic acid di- potassium ( succinic acid ) succcinate
  34. 34. KOLBE’S ELECTROLYSIS CH2-COOK + 2 H2O 2CO2 + H2 CH2-COOK + CH2=CH2 + 2KOH
  35. 35. MECHANISM  CH2-COOK CH2-COO- 2 K+ + CH2 –COOK CH2-COO-  H2O H+ + OH-
  36. 36. ANODE CH2-COO- CH2-COO . 2 e- + CH2-COO- CH2-COO .
  37. 37. CH2-COO . 2 CO2 + CH2-COO . CH2 . CH2 .
  38. 38. CH2 . CH2 . CH2=CH2
  39. 39. CATHODE 2 H+ + 2 e- H2
  40. 40. CH2 . CH2 . CH2 . CH2 .
  41. 41. HYDROBORATION OXIDATION ADDITION OF WATER
  42. 42. Hydroboration / oxidation Catalyst 1. B2H6 / THF( tetra hydro furan ) 2. H2O2 / OH-
  43. 43. Hydroboration reaction follows anti-markonikoff’s rule
  44. 44. IMPORTANT POINTS OF HYDROBORATION REACTION  Water addition in double bond (H+ & OH-).  This is syn-addition (on the same side).  Always anti-markonikoff’s product.
  45. 45. HYDROBORATION 1. B2H6 / THF CH3-CH=CH2 CH3-CH-CH2 2. H2O2 / OH- H OH
  46. 46. MECHANISM OF HYDROBORATION 1. B2H6 2 BH3 ( unstable ) (e-def) H B H H e- deficient (incomplete octet ) 2. THF ------------- It prevents BH3 to dimerize. FURAN THF
  47. 47. THF forms a coordinate bond with BH3 . Since BH3 is highly unstable. BH3
  48. 48. MECHANISM OF HYDROBORATION BH3  CH3-CH=CH2 CH3-CH----CH2 RDS H------B-H H (TRANSITION STATE) VERY SHORT LIVED (SYN ADDITION OF H AND BH2) CH3-CH2-CH2-BH2
  49. 49. AGAIN TRANSITION STATE  CH3-CH-CH2 CH3-CH----CH2 H BH2 CH3 –CH=CH2 H--------B-H CH2CHCH CH3-CH-CH2-B-CH2-CH2-CH3 H H
  50. 50. AGAIN REACTION WITH ALKENE  (CH-CH2-CH2)2BH CH3 –CH=CH2 CH3 –CH-CH2-B(CH2-CH2- CH3)2 H OR (CH3-CH2-CH2)3B TRIALKYL BORANE
  51. 51. PRODUCT OF HYDROBORATION IS  TRIALKYL BORANE OR R3B
  52. 52. 2. SECOND STEP IS OXIDATION WITH H2O2/OH- 1. H2O2 + OH- H2O + O-O-H H-O-O-H + OH- 2. R3B + O-O-H R3B O-O-H + I EFFECT Due to +I effect of the boron, e- repel  so somebody has to leave. O-H is a good leaving group than o-o-H. so it leaves.
  53. 53.  -ve charge on oxygen is highly unstable R2B-O-R again O-O-H attacks R2 B-OR O-O-H R-B-OR O
  54. 54. 1.B2H6  Q) (A) 2.H2O2 / OH- A. (B) B. Both have equal C. Cannot predict
  55. 55. 1.B2H6  Q) (A) 2.H2O2 / OH- A. (B) B. Both have equal C. Cannot predict
  56. 56. RATE  RATE OF HYDROBORATION REACTION DEPENDS ON THE STABILITY OF TRANSITION STATE(ring structure)  Stability 1 sterric hindrance
  57. 57. Q) Which will give more rate towards hydroboration? a) CH3-CH=CH2 b) CH3-CH=CH-CH3 CH3 CH3 c) C=C CH3 CH3 ANS ; a )>b)>c) Reason : becoz in b) & c) there is more sterric hindrance.  If sterric hindrance is more, stability will be less. Hence the rate will be slow.
  58. 58. OXYMERCURATION DEMERCURATION ADDITION OF WATER
  59. 59. OxyMercuration - DeMercuration  CATALYST: 1. ( CH3COO)2Hg or Hg(OAC)2 2. H2O 3. NaBH4 / OH-
  60. 60. OxyMercuration - DeMercuration 1. Hg(OAC)2 CH3-CH=CH2 CH3-CH-CH2 2. H2O 3.NaBH4/ OH- OH H
  61. 61. OxyMercuration - DeMercuration reaction follows markonikoff’s rule
  62. 62. IMPORTANT POINTS OF OxyMercuration - DeMercuration reaction REACTION  Water addition in double bond (H+ & OH-).  This is anti-addition (on the same side).  Always markonikoff’s product.
  63. 63. mechanism

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