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Trigonometric Ratios
 MM2G2. Students will define and
apply sine, cosine, and tangent
ratios to right triangles.
 MM2G2a: Discover the relationship of
the trigonometric ratios for
similar triangles.
Trigonometric Ratios
 MM2G2b: Explain the relationship
between the trigonometric ratios of
complementary angles.
 MM2G2c: Solve application
problems using the
trigonometric ratios.
The following slides have been
come from the following sources:
www.mccd.edu/faculty/bruleym/.../trigonome
http://ux.brookdalecc.edu/fac/cos/lsch
melz/Math%20151/
www.scarsdaleschools.k12.ny.us /
202120915213753693/lib/…/trig.ppt
Emily Freeman
McEachern High School
Warm Up
Put 4 30-60-90 triangles with the following
sides listed and have students determine
the missing lengths.
30 S 5 2 7√3 √2
90 H 10 4 14√3 2√2
60 L 5√3 2√3 21 √6
Trigonometric Ratios
 Talk about adjacent and opposite sides:
have the kids line up on the wall and
pass something from one to another
adjacent and opposite in the room.
 Make a string triangle and talk about
adjacent and opposite some more
Trigonometric Ratios
 Determine the ratios of all the triangles
on the board and realize there are only
3 (6?) different ratios.
 Talk about what it means for shapes to
be similar.
 Make more similar right triangles on dot
paper, measure the sides, and calculate
the ratios.
Trigonometric Ratios
 Try to have the students measure the
angles of the triangles they made on
dot paper.
 Do a Geosketch of all possible triangles
and show the ratios are the same for
similar triangles
 Finally: name the ratios
Warm Up
 Pick up a sheet of dot paper, a ruler,
and protractor from the front desk.
 Draw two triangles, one with sides 3 &
4, and the other with sides 12 & 5
 Calculate the hypotenuse
 Calculate sine, cosine, and tangent for
the acute angles.
 Measure the acute angles to the
nearest degree.
 Show how to find sine, cosine, &
tangent of angles in the calculator
Yesterday
 We learned the sine, cosine, and
tangent of the same angle of similar
triangles are the same
 Another way of saying this is: The sine,
cosine, tangent of congruent angles are
the same
Trigonometric Ratios
in Right Triangles
M. Bruley
Trigonometric Ratios are
based on the Concept of
Similar Triangles!
All 45º- 45º- 90º Triangles are Similar!
45 º
2
2
22
45 º
1
1
2
45 º
1
2
1
2
1
All 30º- 60º- 90º Triangles are Similar!
1
60º
30º
½
2
3
32
60º
30º
2
4
2
60º
30º
1
3
All 30º- 60º- 90º Triangles are Similar!
10 60º
30º
5
35
2 60º
30º
1
3
1
60º
30º
2
1
2
3
hypotenuse
leg
leg
In a right triangle, the shorter sides are called legs and the longest side
(which is the one opposite the right angle) is called the hypotenuse
a
b
c
We’ll label them a, b, and c and the angles α
and β. Trigonometric functions are defined by
taking the ratios of sides of a right triangle.
β
α
First let’s look at the three basic functions.
SINE
COSINE
TANGENT
They are abbreviated using their first 3 letters
c
a
==
hypotenuse
opposite
sinα
opposite
c
b
==
hypotenuse
adjacent
cosα
adjacent
b
a
==
adjacent
opposite
tanα
The Trigonometric Functions
SINE
COSINE
TANGENT
SINE
Prounounced
“sign”
Prounounced
“co-sign”
COSINE
Prounounced
“tan-gent”
TANGENT
Pronounced
“theta”
Greek Letter
θ
Represents an unknown
angle
Pronounced
“alpha”
Greek Letter
α
Represents an unknown
angle
Pronounced
“Beta”
Greek Letter
β
Represents an unknown
angle
θ
opposite
hypotenuse
Sin
Opp
Hyp
=
adjacent
Cos
Adj
Hyp
=
Tan
Opp
Adj
=
hypotenuse
opposite
adjacent
We could ask for the trig functions of the angle β by using the definitions.
a
b
c
You MUST get them memorized. Here is a
mnemonic to help you.
β
α
The sacred Jedi word:
SOHCAHTOA
c
b
==
hypotenuse
opposite
sin β
adjacent
cos
hypotenuse
a
c
β = = opposite
tan
adjacent
b
a
β = =
opposite
adjacent
SOHCAHTOA
It is important to note WHICH angle you are talking
about when you find the value of the trig function.
a
b
c
α Let's try finding some trig functions
with some numbers. Remember that
sides of a right triangle follow the
Pythagorean Theorem so
222
cba =+
Let's choose:
222
543 =+3
4
5
sin α = Use a mnemonic and
figure out which sides
of the triangle you
need for sine.
h
o
5
3
=
opposite
hypotenuse
tan β =
a
o
3
4
=
opposite
adjacent
Use a mnemonic and
figure out which sides
of the triangle you
need for tangent.
β
You need to pay attention to which angle you want the trig function
of so you know which side is opposite that angle and which side is
adjacent to it. The hypotenuse will always be the longest side and
will always be opposite the right angle.
α
This method only applies if you have
a right triangle and is only for the
acute angles (angles less than 90°)
in the triangle.
3
4
5
β
Oh,
I'm
acute!
So
am I!
We need a way
to remember
all of these
ratios…
What is
SohCahToa?
Is it in a tree, is it in a car, is it in the sky
or is it from the deep blue sea ?
This is an example of a sentence
using the word SohCahToa.
I kicked a chair in the middle of
the night and my first thought was
I need to SohCahToa.
An example of an acronym for SohCahToa.
Seven
old
horses
Crawled
a
hill
To
our
attic..
Old Hippie
Some
Old
Hippie
Came
A
Hoppin’
Through
Our
Apartmen
SOHCAHTOA
Old Hippie
Sin
Opp
Hyp
Cos
Adj
Hyp
Tan
Opp
Adj
Other ways to remember SOH CAH TOA
1.Some Of Her Children Are Having Trouble
Over Algebra.
2.Some Out-Houses Can Actually Have
Totally Odorless Aromas.
3.She Offered Her Cat A Heaping Teaspoon
Of Acid.
4.Soaring Over Haiti, Courageous Amelia Hit
The Ocean And ...
5.Tom's Old Aunt Sat On Her Chair And
Hollered. -- (from Ann Azevedo)
Other ways to remember SOH CAH TOA
1.Stamp Out Homework Carefully, As Having
Teachers Omit Assignments.
2.Some Old Horse Caught Another Horse
Taking Oats Away.
3.Some Old Hippie Caught Another Hippie
Tripping On Apples.
4.School! Oh How Can Anyone Have Trouble
Over Academics.
A
Trigonometry Ratios
Tangent A =
opposite
adjacent
Sine A =
opposite
hypotenuse
Cosine A =
adjacent
hypotenuse
Soh Cah Toa
14º
24º
60.5º
46º 82º
1.9 cm
7.7 cm
14º
1.9
7.7
≈0.25 Tangent 14º ≈0.25
The Tangent of an angle is the ratio of the
opposite side of a triangle to its adjacent side.
opposite
adjacent
hypotenuse
3.2 cm
7.2 cm
24º
3.2
7.2
≈0.45 Tangent 24º ≈0.45
Tangent A =
opposite
adjacent
5.5 cm
5.3 cm
46º
5.5
5.3
≈1.04 Tangent 46º ≈1.04
Tangent A =
opposite
adjacent
6.7 cm
3.8 cm
60.5º
6.7
3.8
≈1.76
Tangent 60.5º ≈1.76
Tangent A =
opposite
adjacent
As an acute angle of a triangle
approaches 90º, its tangent
becomes infinitely large
Tan 89.9º = 573
Tan 89.99º = 5,730
Tangent A =
opposite
adjacent
etc.
very
large
very small
Since the sine and cosine functions always
have the hypotenuse as the denominator,
and since the hypotenuse is the longest side,
these two functions will always be less than 1.
Sine A =
opposite
hypotenuse
Cosine A =
adjacent
hypotenuse
A
Sine 89º = .9998
Sine 89.9º = .999998
3.2 cm
7.9 cm
24º
9.7
2.3
≈0.41 Sin 24º ≈0.41
Sin α =
hypotenuse
opposite
5.5 cm
7.9 cm
46º
9.7
5.5
≈0.70 Cos 46º ≈0.70
Cosine β =
hypotenuse
adjacent
A plane takes off from an airport an an angle of 18º and
a speed of 240 mph. Continuing at this speed and angle,
what is the altitude of the plane after 1 minute?
18º
x
After 60 sec., at 240 mph, the plane
has traveled 4 miles
4
18º
x
4opposite
hypotenuse
SohCahToa
Sine A =
opposite
hypotenuse Sine 18 =
x
4
0.3090 =
x
4
x = 1.236 miles
or
6,526 feet
1
Soh
An explorer is standing 14.3 miles from the base of
Mount Everest below its highest peak. His angle of
elevation to the peak is 21º. What is the number of feet
from the base of Mount Everest to its peak?
21º
x
Tan 21 =
x
14.3
0.3839 =
x
14.3
x = 5.49 miles
= 29,000 feet
1
A swimmer sees the top of a lighthouse on the
edge of shore at an 18º angle. The lighthouse is
150 feet high. What is the number of feet from the
swimmer to the shore?
18º
150
Tan 18 =
x
150
x
0.3249 = 150
x
0.3249x = 150
0.3249 0.3249
X = 461.7 ft1
A dragon sits atop a castle 60 feet high. An archer
stands 120 feet from the point on the ground directly
below the dragon. At what angle does the archer
need to aim his arrow to slay the dragon?
x
60
120
Tan x = 60
120
Tan x = 0.5
Tan-1
(0.5) = 26.6º
Solving a Problem with
the Tangent Ratio
60º
53 ft
h = ?
We know the angle and theWe know the angle and the
side adjacent to 60º. We want toside adjacent to 60º. We want to
know the opposite side. Use theknow the opposite side. Use the
tangent ratio:tangent ratio:
ft92353
531
3
53
60tan
≈=
=
==
h
h
h
adj
opp
1
2
3
Why?
A surveyor is standing 50 feet from the base
of a large tree. The surveyor measures the
angle of elevation to the top of the tree as
71.5°. How tall is the tree?
50
71.5
°
?
tan
71.5°
tan
71.5°
50
y
=
y = 50 (tan 71.5°)
y = 50 (2.98868)
149.4y ft≈
Ex.
=
Opp
Hyp
A person is 200 yards from a river. Rather than
walk directly to the river, the person walks along a
straight path to the river’s edge at a 60° angle.
How far must the person walk to reach the river’s
edge?
200
x
Ex. 5
60°
cos 60°
x (cos 60°) = 200
x
X = 400 yards
2 trigonometric ratios conglomerate   keep
2 trigonometric ratios conglomerate   keep
2 trigonometric ratios conglomerate   keep
2 trigonometric ratios conglomerate   keep
2 trigonometric ratios conglomerate   keep
Trigonometric Functions on a
Rectangular Coordinate System
x
y
θθ
Pick a point on the
terminal ray and drop a
perpendicular to the x-axis.
r
y
x
The adjacent side is x
The opposite side is y
The hypotenuse is labeled r
This is called a
REFERENCE TRIANGLE.
y
x
x
y
x
r
r
x
y
r
r
y
==
==
==
θθ
θθ
θθ
cottan
seccos
cscsin
Trigonometric Ratios may be found by:
45 º
1
1
2
Using ratios of special trianglesUsing ratios of special triangles
145tan
2
1
45cos
2
1
45sin
=
=
=
For angles other than 45º, 30º, 60º you will need to use aFor angles other than 45º, 30º, 60º you will need to use a
calculator. (Set it in Degree Mode for now.)calculator. (Set it in Degree Mode for now.)

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2 trigonometric ratios conglomerate keep

  • 1. Trigonometric Ratios  MM2G2. Students will define and apply sine, cosine, and tangent ratios to right triangles.  MM2G2a: Discover the relationship of the trigonometric ratios for similar triangles.
  • 2. Trigonometric Ratios  MM2G2b: Explain the relationship between the trigonometric ratios of complementary angles.  MM2G2c: Solve application problems using the trigonometric ratios.
  • 3. The following slides have been come from the following sources: www.mccd.edu/faculty/bruleym/.../trigonome http://ux.brookdalecc.edu/fac/cos/lsch melz/Math%20151/ www.scarsdaleschools.k12.ny.us / 202120915213753693/lib/…/trig.ppt Emily Freeman McEachern High School
  • 4. Warm Up Put 4 30-60-90 triangles with the following sides listed and have students determine the missing lengths. 30 S 5 2 7√3 √2 90 H 10 4 14√3 2√2 60 L 5√3 2√3 21 √6
  • 5. Trigonometric Ratios  Talk about adjacent and opposite sides: have the kids line up on the wall and pass something from one to another adjacent and opposite in the room.  Make a string triangle and talk about adjacent and opposite some more
  • 6. Trigonometric Ratios  Determine the ratios of all the triangles on the board and realize there are only 3 (6?) different ratios.  Talk about what it means for shapes to be similar.  Make more similar right triangles on dot paper, measure the sides, and calculate the ratios.
  • 7. Trigonometric Ratios  Try to have the students measure the angles of the triangles they made on dot paper.  Do a Geosketch of all possible triangles and show the ratios are the same for similar triangles  Finally: name the ratios
  • 8. Warm Up  Pick up a sheet of dot paper, a ruler, and protractor from the front desk.  Draw two triangles, one with sides 3 & 4, and the other with sides 12 & 5  Calculate the hypotenuse  Calculate sine, cosine, and tangent for the acute angles.  Measure the acute angles to the nearest degree.  Show how to find sine, cosine, & tangent of angles in the calculator
  • 9. Yesterday  We learned the sine, cosine, and tangent of the same angle of similar triangles are the same  Another way of saying this is: The sine, cosine, tangent of congruent angles are the same
  • 10. Trigonometric Ratios in Right Triangles M. Bruley
  • 11. Trigonometric Ratios are based on the Concept of Similar Triangles!
  • 12. All 45º- 45º- 90º Triangles are Similar! 45 º 2 2 22 45 º 1 1 2 45 º 1 2 1 2 1
  • 13. All 30º- 60º- 90º Triangles are Similar! 1 60º 30º ½ 2 3 32 60º 30º 2 4 2 60º 30º 1 3
  • 14. All 30º- 60º- 90º Triangles are Similar! 10 60º 30º 5 35 2 60º 30º 1 3 1 60º 30º 2 1 2 3
  • 15. hypotenuse leg leg In a right triangle, the shorter sides are called legs and the longest side (which is the one opposite the right angle) is called the hypotenuse a b c We’ll label them a, b, and c and the angles α and β. Trigonometric functions are defined by taking the ratios of sides of a right triangle. β α First let’s look at the three basic functions. SINE COSINE TANGENT They are abbreviated using their first 3 letters c a == hypotenuse opposite sinα opposite c b == hypotenuse adjacent cosα adjacent b a == adjacent opposite tanα
  • 24. We could ask for the trig functions of the angle β by using the definitions. a b c You MUST get them memorized. Here is a mnemonic to help you. β α The sacred Jedi word: SOHCAHTOA c b == hypotenuse opposite sin β adjacent cos hypotenuse a c β = = opposite tan adjacent b a β = = opposite adjacent SOHCAHTOA
  • 25. It is important to note WHICH angle you are talking about when you find the value of the trig function. a b c α Let's try finding some trig functions with some numbers. Remember that sides of a right triangle follow the Pythagorean Theorem so 222 cba =+ Let's choose: 222 543 =+3 4 5 sin α = Use a mnemonic and figure out which sides of the triangle you need for sine. h o 5 3 = opposite hypotenuse tan β = a o 3 4 = opposite adjacent Use a mnemonic and figure out which sides of the triangle you need for tangent. β
  • 26. You need to pay attention to which angle you want the trig function of so you know which side is opposite that angle and which side is adjacent to it. The hypotenuse will always be the longest side and will always be opposite the right angle. α This method only applies if you have a right triangle and is only for the acute angles (angles less than 90°) in the triangle. 3 4 5 β Oh, I'm acute! So am I!
  • 27. We need a way to remember all of these ratios…
  • 28. What is SohCahToa? Is it in a tree, is it in a car, is it in the sky or is it from the deep blue sea ?
  • 29. This is an example of a sentence using the word SohCahToa. I kicked a chair in the middle of the night and my first thought was I need to SohCahToa.
  • 30. An example of an acronym for SohCahToa. Seven old horses Crawled a hill To our attic..
  • 33. Other ways to remember SOH CAH TOA 1.Some Of Her Children Are Having Trouble Over Algebra. 2.Some Out-Houses Can Actually Have Totally Odorless Aromas. 3.She Offered Her Cat A Heaping Teaspoon Of Acid. 4.Soaring Over Haiti, Courageous Amelia Hit The Ocean And ... 5.Tom's Old Aunt Sat On Her Chair And Hollered. -- (from Ann Azevedo)
  • 34. Other ways to remember SOH CAH TOA 1.Stamp Out Homework Carefully, As Having Teachers Omit Assignments. 2.Some Old Horse Caught Another Horse Taking Oats Away. 3.Some Old Hippie Caught Another Hippie Tripping On Apples. 4.School! Oh How Can Anyone Have Trouble Over Academics.
  • 35. A Trigonometry Ratios Tangent A = opposite adjacent Sine A = opposite hypotenuse Cosine A = adjacent hypotenuse Soh Cah Toa
  • 37. 1.9 cm 7.7 cm 14º 1.9 7.7 ≈0.25 Tangent 14º ≈0.25 The Tangent of an angle is the ratio of the opposite side of a triangle to its adjacent side. opposite adjacent hypotenuse
  • 38. 3.2 cm 7.2 cm 24º 3.2 7.2 ≈0.45 Tangent 24º ≈0.45 Tangent A = opposite adjacent
  • 39. 5.5 cm 5.3 cm 46º 5.5 5.3 ≈1.04 Tangent 46º ≈1.04 Tangent A = opposite adjacent
  • 40. 6.7 cm 3.8 cm 60.5º 6.7 3.8 ≈1.76 Tangent 60.5º ≈1.76 Tangent A = opposite adjacent
  • 41. As an acute angle of a triangle approaches 90º, its tangent becomes infinitely large Tan 89.9º = 573 Tan 89.99º = 5,730 Tangent A = opposite adjacent etc. very large very small
  • 42. Since the sine and cosine functions always have the hypotenuse as the denominator, and since the hypotenuse is the longest side, these two functions will always be less than 1. Sine A = opposite hypotenuse Cosine A = adjacent hypotenuse A Sine 89º = .9998 Sine 89.9º = .999998
  • 43. 3.2 cm 7.9 cm 24º 9.7 2.3 ≈0.41 Sin 24º ≈0.41 Sin α = hypotenuse opposite
  • 44. 5.5 cm 7.9 cm 46º 9.7 5.5 ≈0.70 Cos 46º ≈0.70 Cosine β = hypotenuse adjacent
  • 45. A plane takes off from an airport an an angle of 18º and a speed of 240 mph. Continuing at this speed and angle, what is the altitude of the plane after 1 minute? 18º x After 60 sec., at 240 mph, the plane has traveled 4 miles 4
  • 46. 18º x 4opposite hypotenuse SohCahToa Sine A = opposite hypotenuse Sine 18 = x 4 0.3090 = x 4 x = 1.236 miles or 6,526 feet 1 Soh
  • 47. An explorer is standing 14.3 miles from the base of Mount Everest below its highest peak. His angle of elevation to the peak is 21º. What is the number of feet from the base of Mount Everest to its peak? 21º x Tan 21 = x 14.3 0.3839 = x 14.3 x = 5.49 miles = 29,000 feet 1
  • 48. A swimmer sees the top of a lighthouse on the edge of shore at an 18º angle. The lighthouse is 150 feet high. What is the number of feet from the swimmer to the shore? 18º 150 Tan 18 = x 150 x 0.3249 = 150 x 0.3249x = 150 0.3249 0.3249 X = 461.7 ft1
  • 49. A dragon sits atop a castle 60 feet high. An archer stands 120 feet from the point on the ground directly below the dragon. At what angle does the archer need to aim his arrow to slay the dragon? x 60 120 Tan x = 60 120 Tan x = 0.5 Tan-1 (0.5) = 26.6º
  • 50. Solving a Problem with the Tangent Ratio 60º 53 ft h = ? We know the angle and theWe know the angle and the side adjacent to 60º. We want toside adjacent to 60º. We want to know the opposite side. Use theknow the opposite side. Use the tangent ratio:tangent ratio: ft92353 531 3 53 60tan ≈= = == h h h adj opp 1 2 3 Why?
  • 51. A surveyor is standing 50 feet from the base of a large tree. The surveyor measures the angle of elevation to the top of the tree as 71.5°. How tall is the tree? 50 71.5 ° ? tan 71.5° tan 71.5° 50 y = y = 50 (tan 71.5°) y = 50 (2.98868) 149.4y ft≈ Ex. = Opp Hyp
  • 52. A person is 200 yards from a river. Rather than walk directly to the river, the person walks along a straight path to the river’s edge at a 60° angle. How far must the person walk to reach the river’s edge? 200 x Ex. 5 60° cos 60° x (cos 60°) = 200 x X = 400 yards
  • 58. Trigonometric Functions on a Rectangular Coordinate System x y θθ Pick a point on the terminal ray and drop a perpendicular to the x-axis. r y x The adjacent side is x The opposite side is y The hypotenuse is labeled r This is called a REFERENCE TRIANGLE. y x x y x r r x y r r y == == == θθ θθ θθ cottan seccos cscsin
  • 59. Trigonometric Ratios may be found by: 45 º 1 1 2 Using ratios of special trianglesUsing ratios of special triangles 145tan 2 1 45cos 2 1 45sin = = = For angles other than 45º, 30º, 60º you will need to use aFor angles other than 45º, 30º, 60º you will need to use a calculator. (Set it in Degree Mode for now.)calculator. (Set it in Degree Mode for now.)