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Cards Probability
Example 1
A card is drawn at random from a well shuffled pack of 52 cards. What is the
probability that the drawn card is king ?
Solution:
The number of outcomes in a deck of cards=52
 n(S) = 52
Let A be the event of drawing a king card.
There are 4 king cards in total.
Then, n(A) = 4
Required probability is
P(A) = n(A) / n(S)
P(A) = 4/52 = 1/13
Example 2
A card is drawn at random from a well shuffled pack of 52 cards. What
is the probability that the card is neither a spade nor a Jack ?
Solution:
Let A be the event of drawing a card that is neither spade nor Jack.
There are 13 spade cards in a pack of 52 cards.
(Jack in spade is already included in these 13 cards)
In the remaining 3 types (club, heart, diamond), there are 3 jack cards.
Number of spade cards and jack cards is
= 13 + 3
= 16
So, no. of cards which are neither spade nor Jack are
= 52 – 16
= 36
Then, n(A) = 36
n(S) = 52
Required probability is
P(A) = n(A) / n(S)
P(A) = 36/52
P(A) = 9/13
So, the required probability is 9/13.
Example 3
What is the probability of drawing a black card from a pack of cards?
Solution:
The number of outcomes in a deck of cards=52
 n(S) = 52
Let B be the event of drawing a black card from a pack of cards.
There are 26 black cards in total.
Then, n(B) = 26
Required probability is
P(B) = n(B) / n(S)
P(B) = 26/52 = 1/2

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Cards probability

  • 2. Example 1 A card is drawn at random from a well shuffled pack of 52 cards. What is the probability that the drawn card is king ? Solution: The number of outcomes in a deck of cards=52  n(S) = 52 Let A be the event of drawing a king card. There are 4 king cards in total. Then, n(A) = 4 Required probability is P(A) = n(A) / n(S) P(A) = 4/52 = 1/13
  • 3. Example 2 A card is drawn at random from a well shuffled pack of 52 cards. What is the probability that the card is neither a spade nor a Jack ? Solution: Let A be the event of drawing a card that is neither spade nor Jack. There are 13 spade cards in a pack of 52 cards. (Jack in spade is already included in these 13 cards) In the remaining 3 types (club, heart, diamond), there are 3 jack cards.
  • 4. Number of spade cards and jack cards is = 13 + 3 = 16 So, no. of cards which are neither spade nor Jack are = 52 – 16 = 36 Then, n(A) = 36 n(S) = 52
  • 5. Required probability is P(A) = n(A) / n(S) P(A) = 36/52 P(A) = 9/13 So, the required probability is 9/13.
  • 6. Example 3 What is the probability of drawing a black card from a pack of cards? Solution: The number of outcomes in a deck of cards=52  n(S) = 52 Let B be the event of drawing a black card from a pack of cards. There are 26 black cards in total. Then, n(B) = 26 Required probability is P(B) = n(B) / n(S) P(B) = 26/52 = 1/2