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3 -1
Activity Cost
Behavior
CHAPTER
3 -2
Cost Behavior
• describing whether costs change
as output changes
• Costs react to output changes in
many different ways.
3 -3
Fixed Costs
A cost that stays the
same as output changes
is a fixed cost.
3 -4
Cutting machines are
leased for $60,000 per
year and have the
capacity to produce up
to 240,000 units a year.
Fixed Costs
3 -5
Lease of
Machines
Number
of Units
$60,000 0 N/A
60,000 60,000 $1.00
60,000 120,000 0.50
60,000 180,000 0.33
60,000 240,000 0.25
Units
Cost
Fixed Costs
Total Fixed Cost Graph
Total
Costs
$120,000
$100,000
$80,000
$60,000
$40,000
$20,000
60 120 180 240
0
Units Produced (000)
F = $60,000
3 -6
Lease of
Machines
Number
of Units
$60,000 0 N/A
60,000 60,000 $1.00
60,000 120,000 0.50
60,000 180,000 0.33
60,000 240,000 0.25
Units
Cost
Fixed Costs
Unit Fixed Cost Graph
Cost
per
Unit
$1.00
$0.50
$0.33
$0.25
60 120 180 240
0
Units Produced (000)
3 -7
Variable
Cost
A variable cost is a cost
that, in total, varies in
direct proportion to
changes in output.
3 -8
As the cutting machines cut each unit,
they use 0.1 kilowatt-hour at $2.00 per
kilowatt hour. Thus, the cost of each
unit is $0.20 ($2 x 0.1).
Variable Cost
3 -9
Total Variable Cost Graph
Cost of
Power
Number
of Units
$ 0 0 $ 0
12,000 60,000 0.20
24,000 120,000 0.20
36,000 180,000 0.20
48,000 240,000 0.20
Units
Cost
Total
Costs
0
Units Produced (000)
$48,000
$36,000
$24,000
$12,000
60 120 180 240
Variable Cost
Yv = .20x
3 -10
Cost of
Power
Number
of Units
$ 0 0 $ 0
12,000 60,000 0.20
24,000 120,000 0.20
36,000 180,000 0.20
48,000 240,000 0.20
Units
Cost
Variable Cost
Unit Variable Cost Graph
60 120 180 240
Units Produced (000)
$0.40
$0.30
$0.20
$0.10
0
Cost
per
Unit
3 -11
A mixed cost is a cost
that has both a fixed
and a variable
component.
3 -12
Sales representatives
often are paid a
salary plus a
commission on sales.
3 -13
Inserts
Sold
Variable
Cost of
Selling
40,000 $ 20,000 $30,000 $ 50,000 $1.25
80,000 40,000 30,000 70,000 0.86
120,000 60,000 30,000 90,000 0.75
160,000 80,000 30,000 110,000 0.69
200,000 100,000 30,000 130,000 0.65
Total
Selling
Cost
Fixed
Cost of
Selling
Selling
Cost per
Unit
Mixed Cost Behavior
Total
Costs
0
Units Sold (000)
$130,000
$110,000
$90,000
$70,000
$50,000
$30,000
40 80 120 160 180 200
3 -14
• in the long run, all costs are variable; short run, at least one cost
is fixed.
Time Horizon
• Every activity needs resources (e.g energy/fuel, labor, and capital)
as input, combined to produce output
Resources Needed and Output Activity
• E.g. if the activity: moving materials, the inputs: crates
(materials), fuel (energy), a forklift operator (labor), and a forklift
(capital). The output = moved materials, i.e. the number of moves.
The more moves that are made, the higher the cost of moving
Measure the inputs & outputs and determine the
impact of output changes on the activity cost.
Classifying Costs According to Behavior
3 -15
Activity Cost Behavior Model
Input:
Materials
Energy
Labor
Capital
Activities
Activity
Output
Cost Behavior
Changes
in Output
Changes
in Input
Cost
3 -16
Flexible resources are resources
acquired as used and needed. Materials
and energy are examples.
“the quantity of the resource supplied
(purchased) equals the quantity demanded”
no unused capacity
Activities, Resource Usage, and Cost Behavior
For example,
direct materials are frequently
purchased at the time and in the
amount needed.
3 -17
Committed resources are supplied in
advance of usage. Buying or leasing a
building is an example of this form of
advance resource acquisition.
3 -18
A step cost displays a constant level
of cost for a range of output and then
jumps to a higher level of cost at
some point.
Step-Cost Behavior
3 -19
Cost
Activity Output (units)
$500
400
300
200
100
10 20 30 40 50
Step-Cost Behavior
3 -20
Normal
Operating
Range
(Relevant
Range)
Step-Fixed Costs
Cost
$150,000
100,000
50,000
2,500 5,000 7,500
Activity Usage
3 -21
 Three engineers hired at $50,000 each
 Each engineer is capable of processing 2,500
change orders
 $90,000 was spent on supplies for the
engineering activity
 There were 6,000 orders processed
 The company could process as many as 7,500
orders
Step-Cost Behavior
3 -22
Available orders = Orders used + Orders unused
7,500 orders = 6,000 orders + 1,500 orders
Fixed engineering rate = $150,000/7,500
= $20 per change order
Variable engineering rate = $90,000/6,000
= $15 per change order
Step-Cost Behavior
3 -23
The relationship between resources supplied and
resources used is expressed by the following
equation:
Resources available = Resources used + Unused
capacity
Step-Cost Behavior
3 -24
Cost of orders supplied = Cost of orders used +
Cost of unused orders
= [($20 + $15) x 6,000] + ($20
x 1,500)
= $240,000
Equal to the $150,000 spent on
engineers and the $90,000
spent on supplies.
The $30,000 of excess engineering capacity
means that a new product could be
introduced without increasing current
spending on engineering.
Step-Cost Behavior
3 -25
The High-Low Method
The Scatterplot Method
The Method of Least Squares
Methods for Separating Mixed Costs
Variable
Component
Fixed
Component
3 -26
The linearity assumption
assumes that variable costs
increase in direct proportion to
the number of units produced
(or activity units used).
3 -27
Methods for Separating Mixed Costs
Y = a + bx
Total Cost
Total Fixed
Cost
Variable
Cost per
Unit
Number of
Units
3 -28
Month Setup Costs Setup Hours
January $1,000 100
February 1,250 200
March 2,250 300
April 2,500 400
May 3,750 500
The High-Low Method
Step 1: Solve for variable cost (b)
3 -29
Month Setup Costs Setup Hours
January $1,000 100
February 1,250 200
March 2,250 300
April 2,500 400
May 3,750 500
b =
High Cost – Low Cost
High Units – Low Units
The High-Low Method
3 -30
b =
High Cost – Low Cost
High Units – Low Units
Month Setup Costs Setup Hours
January $1,000 100
February 1,250 200
March 2,250 300
April 2,500 400
May 3,750 500
The High-Low Method
b =
$3,750 – Low Cost
500 – Low Units
3 -31
Month Setup Costs Setup Hours
January $1,000 100
February 1,250 200
March 2,250 300
April 2,500 400
May 3,750 500
b =
$3,750 – Low Cost
500 – Low Units
b =
$3,750 – $1,000
500 – 100
The High-Low Method
3 -32
b =
$3,750 – $1,000
500 – 100
b = $6.875
Step 2: Using either the high cost or low cost,
solve for the total fixed cost (a).
The High-Low Method
3 -33
Y = a + b (x)
$3,750 = a + $6.875(500)
$312.50 = a
High
End
Y = a + b (x)
$1,000 = a + $6.875(100)
$312.50 = a
Low
End
The cost formula using the high-low method is:
Total cost = $312.50 + ($6.875 x Setup hours)
The High-Low Method
3 -34
The Scatterplot Method
3 -35
Activity
Cost
0 Activity Output
*
*
*
*
*
The Scatterplot Method
Nonlinear Relationship
3 -36
Activity
Cost
0 Activity Output
*
*
*
*
*
*
The Scatterplot Method
Upward Shift in Cost Relationship
3 -37
Activity
Cost
0 Activity Output
*
*
*
*
*
*
The Scatterplot Method
Presence of Outliers
Estimated
regression
line
Estimated
fixed cost
3 -38
The Method of Least Squares
Month Setup Costs Setup Hours
Jan 1,000 100
Feb 1,250 200
Mar 2,250 300
Apr 2,500 400
May 3,750 500
Spreadsheet Data for
Larson Company
3 -39
The Method of Least Squares
Regression Output for
Larson Company
Regression Output:
Constant 125
Std. Err of Y Est 299.304749934466
R Squared 0.944300518134715
No. of Observation 5
Degrees of Freedom 3
X Coefficient(s) 6.75
Std. Err of Coef. 0.9464847243
3 -40
The Method of Least Squares
The results give rise to the following equation:
Setup costs = $125 + ($6.75 x Setup hours)
R2 = .944, or 94.4 percent of the variation in
setup costs is explained by the number of setup
hours variable.
3 -41
Coefficient of Correlation
Positive Correlation
Machine
Hours
Utilities
Costs
r approaches +1
Machine
Hours
Utilities
Costs
3 -42
Coefficient of Correlation
Negative Correlation
Hours of
Safety
Training
Industrial
Accidents
r approaches -1
Hours of
Safety
Training
Industrial
Accidents
3 -43
Coefficient of Correlation
No Correlation
Hair
Length
Accounting
Grade
r ~ 0
Hair
Length
Accounting
Grade
3 -44
TC = b0 + ( b1X1) + (b2X2) + . . .
b0 = the fixed cost or intercept
b1 = the variable rate for the first independent variable
X1 = the first independent variable
b2 = the variable rate for the second independent variable
X2 = the second independent variable
Multiple Regression
3 -45
Multiple Regression
Month Mhrs Summer Utilities Cost
Jan 1,340 0 $1,688
Feb 1,298 0 1,636
Mar 1,376 0 1,734
April 1,405 0 1,770
May 1,500 1 2,390
June 1,432 1 2,304
July 1,322 1 2,166
August 1,416 1 2,284
Sept 1,370 1 1,730
Oct 1,580 0 1,991
Nov 1,460 0 1,840
Dec 1,455 0 1,833
Data for Phoenix Factory
Utilities Cost Regression
3 -46
Multiple Regression
Constant 243.1114997159
Std Err of Y Est 55.5082829356447
R Squared 0.96717927255452
No. of Observation 12
Degrees of Freedom 9
X Coefficient(s) 1.0971575051946 510.49073361447
Std Err of Coef. 0.210226332115593 32.5489464532519
Multiple Regression for Phoenix
Factory Utilities Cost
3 -47
The results gives rise to the following equation:
Utilities cost = $243.11 + $1.097(Machine hours) +
($510.49 x Summer)
R2 = .967, or 96.7 percent of the variation in utilities
cost is explained by the machine hours and summer
variables.
Multiple Regression
3 -48
Managerial Judgment
Managerial judgment is critically
important in determining cost behavior,
and it is by far the most widely used
method in practice.
3 -49
The End
Chapter Three
3 -50

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Activity Cost Behavior.ppt

  • 2. 3 -2 Cost Behavior • describing whether costs change as output changes • Costs react to output changes in many different ways.
  • 3. 3 -3 Fixed Costs A cost that stays the same as output changes is a fixed cost.
  • 4. 3 -4 Cutting machines are leased for $60,000 per year and have the capacity to produce up to 240,000 units a year. Fixed Costs
  • 5. 3 -5 Lease of Machines Number of Units $60,000 0 N/A 60,000 60,000 $1.00 60,000 120,000 0.50 60,000 180,000 0.33 60,000 240,000 0.25 Units Cost Fixed Costs Total Fixed Cost Graph Total Costs $120,000 $100,000 $80,000 $60,000 $40,000 $20,000 60 120 180 240 0 Units Produced (000) F = $60,000
  • 6. 3 -6 Lease of Machines Number of Units $60,000 0 N/A 60,000 60,000 $1.00 60,000 120,000 0.50 60,000 180,000 0.33 60,000 240,000 0.25 Units Cost Fixed Costs Unit Fixed Cost Graph Cost per Unit $1.00 $0.50 $0.33 $0.25 60 120 180 240 0 Units Produced (000)
  • 7. 3 -7 Variable Cost A variable cost is a cost that, in total, varies in direct proportion to changes in output.
  • 8. 3 -8 As the cutting machines cut each unit, they use 0.1 kilowatt-hour at $2.00 per kilowatt hour. Thus, the cost of each unit is $0.20 ($2 x 0.1). Variable Cost
  • 9. 3 -9 Total Variable Cost Graph Cost of Power Number of Units $ 0 0 $ 0 12,000 60,000 0.20 24,000 120,000 0.20 36,000 180,000 0.20 48,000 240,000 0.20 Units Cost Total Costs 0 Units Produced (000) $48,000 $36,000 $24,000 $12,000 60 120 180 240 Variable Cost Yv = .20x
  • 10. 3 -10 Cost of Power Number of Units $ 0 0 $ 0 12,000 60,000 0.20 24,000 120,000 0.20 36,000 180,000 0.20 48,000 240,000 0.20 Units Cost Variable Cost Unit Variable Cost Graph 60 120 180 240 Units Produced (000) $0.40 $0.30 $0.20 $0.10 0 Cost per Unit
  • 11. 3 -11 A mixed cost is a cost that has both a fixed and a variable component.
  • 12. 3 -12 Sales representatives often are paid a salary plus a commission on sales.
  • 13. 3 -13 Inserts Sold Variable Cost of Selling 40,000 $ 20,000 $30,000 $ 50,000 $1.25 80,000 40,000 30,000 70,000 0.86 120,000 60,000 30,000 90,000 0.75 160,000 80,000 30,000 110,000 0.69 200,000 100,000 30,000 130,000 0.65 Total Selling Cost Fixed Cost of Selling Selling Cost per Unit Mixed Cost Behavior Total Costs 0 Units Sold (000) $130,000 $110,000 $90,000 $70,000 $50,000 $30,000 40 80 120 160 180 200
  • 14. 3 -14 • in the long run, all costs are variable; short run, at least one cost is fixed. Time Horizon • Every activity needs resources (e.g energy/fuel, labor, and capital) as input, combined to produce output Resources Needed and Output Activity • E.g. if the activity: moving materials, the inputs: crates (materials), fuel (energy), a forklift operator (labor), and a forklift (capital). The output = moved materials, i.e. the number of moves. The more moves that are made, the higher the cost of moving Measure the inputs & outputs and determine the impact of output changes on the activity cost. Classifying Costs According to Behavior
  • 15. 3 -15 Activity Cost Behavior Model Input: Materials Energy Labor Capital Activities Activity Output Cost Behavior Changes in Output Changes in Input Cost
  • 16. 3 -16 Flexible resources are resources acquired as used and needed. Materials and energy are examples. “the quantity of the resource supplied (purchased) equals the quantity demanded” no unused capacity Activities, Resource Usage, and Cost Behavior For example, direct materials are frequently purchased at the time and in the amount needed.
  • 17. 3 -17 Committed resources are supplied in advance of usage. Buying or leasing a building is an example of this form of advance resource acquisition.
  • 18. 3 -18 A step cost displays a constant level of cost for a range of output and then jumps to a higher level of cost at some point. Step-Cost Behavior
  • 19. 3 -19 Cost Activity Output (units) $500 400 300 200 100 10 20 30 40 50 Step-Cost Behavior
  • 21. 3 -21  Three engineers hired at $50,000 each  Each engineer is capable of processing 2,500 change orders  $90,000 was spent on supplies for the engineering activity  There were 6,000 orders processed  The company could process as many as 7,500 orders Step-Cost Behavior
  • 22. 3 -22 Available orders = Orders used + Orders unused 7,500 orders = 6,000 orders + 1,500 orders Fixed engineering rate = $150,000/7,500 = $20 per change order Variable engineering rate = $90,000/6,000 = $15 per change order Step-Cost Behavior
  • 23. 3 -23 The relationship between resources supplied and resources used is expressed by the following equation: Resources available = Resources used + Unused capacity Step-Cost Behavior
  • 24. 3 -24 Cost of orders supplied = Cost of orders used + Cost of unused orders = [($20 + $15) x 6,000] + ($20 x 1,500) = $240,000 Equal to the $150,000 spent on engineers and the $90,000 spent on supplies. The $30,000 of excess engineering capacity means that a new product could be introduced without increasing current spending on engineering. Step-Cost Behavior
  • 25. 3 -25 The High-Low Method The Scatterplot Method The Method of Least Squares Methods for Separating Mixed Costs Variable Component Fixed Component
  • 26. 3 -26 The linearity assumption assumes that variable costs increase in direct proportion to the number of units produced (or activity units used).
  • 27. 3 -27 Methods for Separating Mixed Costs Y = a + bx Total Cost Total Fixed Cost Variable Cost per Unit Number of Units
  • 28. 3 -28 Month Setup Costs Setup Hours January $1,000 100 February 1,250 200 March 2,250 300 April 2,500 400 May 3,750 500 The High-Low Method Step 1: Solve for variable cost (b)
  • 29. 3 -29 Month Setup Costs Setup Hours January $1,000 100 February 1,250 200 March 2,250 300 April 2,500 400 May 3,750 500 b = High Cost – Low Cost High Units – Low Units The High-Low Method
  • 30. 3 -30 b = High Cost – Low Cost High Units – Low Units Month Setup Costs Setup Hours January $1,000 100 February 1,250 200 March 2,250 300 April 2,500 400 May 3,750 500 The High-Low Method b = $3,750 – Low Cost 500 – Low Units
  • 31. 3 -31 Month Setup Costs Setup Hours January $1,000 100 February 1,250 200 March 2,250 300 April 2,500 400 May 3,750 500 b = $3,750 – Low Cost 500 – Low Units b = $3,750 – $1,000 500 – 100 The High-Low Method
  • 32. 3 -32 b = $3,750 – $1,000 500 – 100 b = $6.875 Step 2: Using either the high cost or low cost, solve for the total fixed cost (a). The High-Low Method
  • 33. 3 -33 Y = a + b (x) $3,750 = a + $6.875(500) $312.50 = a High End Y = a + b (x) $1,000 = a + $6.875(100) $312.50 = a Low End The cost formula using the high-low method is: Total cost = $312.50 + ($6.875 x Setup hours) The High-Low Method
  • 35. 3 -35 Activity Cost 0 Activity Output * * * * * The Scatterplot Method Nonlinear Relationship
  • 36. 3 -36 Activity Cost 0 Activity Output * * * * * * The Scatterplot Method Upward Shift in Cost Relationship
  • 37. 3 -37 Activity Cost 0 Activity Output * * * * * * The Scatterplot Method Presence of Outliers Estimated regression line Estimated fixed cost
  • 38. 3 -38 The Method of Least Squares Month Setup Costs Setup Hours Jan 1,000 100 Feb 1,250 200 Mar 2,250 300 Apr 2,500 400 May 3,750 500 Spreadsheet Data for Larson Company
  • 39. 3 -39 The Method of Least Squares Regression Output for Larson Company Regression Output: Constant 125 Std. Err of Y Est 299.304749934466 R Squared 0.944300518134715 No. of Observation 5 Degrees of Freedom 3 X Coefficient(s) 6.75 Std. Err of Coef. 0.9464847243
  • 40. 3 -40 The Method of Least Squares The results give rise to the following equation: Setup costs = $125 + ($6.75 x Setup hours) R2 = .944, or 94.4 percent of the variation in setup costs is explained by the number of setup hours variable.
  • 41. 3 -41 Coefficient of Correlation Positive Correlation Machine Hours Utilities Costs r approaches +1 Machine Hours Utilities Costs
  • 42. 3 -42 Coefficient of Correlation Negative Correlation Hours of Safety Training Industrial Accidents r approaches -1 Hours of Safety Training Industrial Accidents
  • 43. 3 -43 Coefficient of Correlation No Correlation Hair Length Accounting Grade r ~ 0 Hair Length Accounting Grade
  • 44. 3 -44 TC = b0 + ( b1X1) + (b2X2) + . . . b0 = the fixed cost or intercept b1 = the variable rate for the first independent variable X1 = the first independent variable b2 = the variable rate for the second independent variable X2 = the second independent variable Multiple Regression
  • 45. 3 -45 Multiple Regression Month Mhrs Summer Utilities Cost Jan 1,340 0 $1,688 Feb 1,298 0 1,636 Mar 1,376 0 1,734 April 1,405 0 1,770 May 1,500 1 2,390 June 1,432 1 2,304 July 1,322 1 2,166 August 1,416 1 2,284 Sept 1,370 1 1,730 Oct 1,580 0 1,991 Nov 1,460 0 1,840 Dec 1,455 0 1,833 Data for Phoenix Factory Utilities Cost Regression
  • 46. 3 -46 Multiple Regression Constant 243.1114997159 Std Err of Y Est 55.5082829356447 R Squared 0.96717927255452 No. of Observation 12 Degrees of Freedom 9 X Coefficient(s) 1.0971575051946 510.49073361447 Std Err of Coef. 0.210226332115593 32.5489464532519 Multiple Regression for Phoenix Factory Utilities Cost
  • 47. 3 -47 The results gives rise to the following equation: Utilities cost = $243.11 + $1.097(Machine hours) + ($510.49 x Summer) R2 = .967, or 96.7 percent of the variation in utilities cost is explained by the machine hours and summer variables. Multiple Regression
  • 48. 3 -48 Managerial Judgment Managerial judgment is critically important in determining cost behavior, and it is by far the most widely used method in practice.
  • 50. 3 -50