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Electronic configuration of Atom Lecture 7 Week 4
Wave Mechanics ,[object Object],[object Object],[object Object],[object Object],L. de Broglie (1892-1987)    for particles is called  the de Broglie wavelength  From previous lecture we know that,  Light as well as heat energy exhibits both wave and particle nature under suitable conditions  =  Wave mechanical theory Therefore,  mc = h /   and for particles (mass)x(velocity) = h /  
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Uncertainty Principle ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],W. Heisenberg 1901-1976 So, in macroscopic world, a moving particle has a definite location at any instant and a wave is spread out in space.
[object Object],[object Object],E. Schrodinger 1887-1961 Ψ  does NOT describe the exact location of the electron, but  Ψ  2  is proportional to the probability of finding an e- at a given point
ORBITAL  2  is proportional to the probability of finding an e- at a given point. The three dimensional region within which there is higher probability that an e having certain energy will be found is called ORBITAL, The energy of e in an orbital is always same
[object Object],[object Object],[object Object],[object Object],Quantum number of an atomic Orbital
Those   are  principal ( n ) ,  angular ( l ) ,  and   magnetic ( m )  quantum numbers n   l m principal  1, 2, 3, … size and energy angular momentum  0, 1, 2, …, ( n  - 1) shape magnetic - l , …,  l orientation
Quantum number of an atomic Orbital ,[object Object],[object Object],[object Object],[object Object],[object Object],Principal quantum number (n) 1 2 3 4 Max. number of electrons in n’th shell/level 2 8 18 32
n  = 1 l  = 0 = (1s) n  = 2 l  = 0, 1 = (2s, 2p) n  = 3 l  = 0, 1, 2 = (3s, 3p, 3d) n  = 4 l  = 0, 1, 2, 3 = (4s, 4p, 4d, 4f) designated by  letters l  = 0 s  orbital l  = 1 p  orbital l  = 2 d  orbital l  = 3 f  orbital Angular momentum quantum number ( l ) It is an integer from 0 to (n-1) It is related to the shape of the orbital
n  = 1 l  = 0 m  = 0 n  = 2 l  = 0 m  = 0 l  = 1 m  = -1 m  = 0 m  = 1 n  = 3 l  = 0 m  = 0 l  = 2 l  = 1 m  = -1 m  = 0 m  = 1 m  = -2 m  = -1 m  = 0 m  = 1 m  = 2 s s p s p d 1 1 3 3 1 5 Magnetic quantum number ( l ) It is an integer from  –l  through 0 to  +l It is prescribes the orientation of the orbital in space around nucleus
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Shells and Subshells
p Orbital  &  d Orbital ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
1 s  orbital spherical Shape of Atomic Orbital See Fig-7.17 of Silberg Chemistry Page 278
Shape of 2p Orbital dumbbell shape 3 p ,  4 p , 5 p  etc. are similar shapes but larger size
n = 3, l = 1 Orbitals (3p x  3p y  3p z  )
3 d  orbitals cloverleaf larger n same shapes but size larger
Representation of 4f Orbitals
There are n 2 orbitals in  the n th  SHELL Also see Fig - 7.17 & Fig - 7.18 & Fig – 7.19 and Fig - 8.9of your reference Silberg Chemistry Book  2 1 3d n= 3
Spin Quantum Number ( s ) ,[object Object],[object Object],[object Object],[object Object]
Do this math ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],n  l m name a) ? ? 0 4p b) 2 1 0 ? c) 3 2 -2 ? d) ? ? ? 2s
Pauli’s exclusion principle ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Example of Pauli’s Exclusion Principal: ,[object Object],[object Object],2 e are in 2s orbital 2 e are in 2p x  orbital 2 e are in 2p y  orbital 2 e are in 2p z  orbital n l m s 2 0 0 +1/2 2 0 0 -1/2 2 1 +1 +1/2 2 1 +1 -1/2 2 1 -1 +1/2 2 1 -1 -1/2 2 1 0 +1/2 2 1 0 -1/2
Electronic configuration No of e in sub shell Electronic configuration of shell 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 4d 10 4f 14 2 10 6 14 10 2 2 6 6 2
Rules of electronic configuration of atom ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],Rules of electronic configuration of atom ,[object Object]
The relation between orbital filling and the periodic table
Write electron configuration of the following elements ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Electron configurations in the first three periods.
Orbital occupancy for the first 10 elements, H through Ne.
Hund’s rule
 
 
A periodic table of partial ground-state electron configurations
Assignment 1 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Suggestion :  Please prepare your notes at least according to the question banks, you can show me your notes, if any correction needed or suggestion then I can give you that.

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Lecture 7

  • 1. Electronic configuration of Atom Lecture 7 Week 4
  • 2.
  • 3.
  • 4.
  • 5.
  • 6. ORBITAL  2 is proportional to the probability of finding an e- at a given point. The three dimensional region within which there is higher probability that an e having certain energy will be found is called ORBITAL, The energy of e in an orbital is always same
  • 7.
  • 8. Those are principal ( n ) , angular ( l ) , and magnetic ( m ) quantum numbers n l m principal 1, 2, 3, … size and energy angular momentum 0, 1, 2, …, ( n - 1) shape magnetic - l , …, l orientation
  • 9.
  • 10. n = 1 l = 0 = (1s) n = 2 l = 0, 1 = (2s, 2p) n = 3 l = 0, 1, 2 = (3s, 3p, 3d) n = 4 l = 0, 1, 2, 3 = (4s, 4p, 4d, 4f) designated by letters l = 0 s orbital l = 1 p orbital l = 2 d orbital l = 3 f orbital Angular momentum quantum number ( l ) It is an integer from 0 to (n-1) It is related to the shape of the orbital
  • 11. n = 1 l = 0 m = 0 n = 2 l = 0 m = 0 l = 1 m = -1 m = 0 m = 1 n = 3 l = 0 m = 0 l = 2 l = 1 m = -1 m = 0 m = 1 m = -2 m = -1 m = 0 m = 1 m = 2 s s p s p d 1 1 3 3 1 5 Magnetic quantum number ( l ) It is an integer from –l through 0 to +l It is prescribes the orientation of the orbital in space around nucleus
  • 12.
  • 13.
  • 14. 1 s orbital spherical Shape of Atomic Orbital See Fig-7.17 of Silberg Chemistry Page 278
  • 15. Shape of 2p Orbital dumbbell shape 3 p , 4 p , 5 p etc. are similar shapes but larger size
  • 16. n = 3, l = 1 Orbitals (3p x 3p y 3p z )
  • 17. 3 d orbitals cloverleaf larger n same shapes but size larger
  • 19. There are n 2 orbitals in the n th SHELL Also see Fig - 7.17 & Fig - 7.18 & Fig – 7.19 and Fig - 8.9of your reference Silberg Chemistry Book 2 1 3d n= 3
  • 20.
  • 21.
  • 22.
  • 23.
  • 24. Electronic configuration No of e in sub shell Electronic configuration of shell 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 4d 10 4f 14 2 10 6 14 10 2 2 6 6 2
  • 25.
  • 26.
  • 27. The relation between orbital filling and the periodic table
  • 28.
  • 29. Electron configurations in the first three periods.
  • 30. Orbital occupancy for the first 10 elements, H through Ne.
  • 32.  
  • 33.  
  • 34. A periodic table of partial ground-state electron configurations
  • 35.