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PHYSICS- (12th & 13th) Paper 2.pdf

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Class : XII & XIII PAPER CODE : A Time : 3 hour Max. Marks : 210 INSTRUCTIONS 1. The question paper contain 7 pages and 2-parts. Part-B contains 6 questions of "Match the Column" type and Part-C contains 18. All questions are compulsory. Please ensure that the Question Paper you have received contains all the QUESTIONS and Pages. If you found some mistake like missing questions or pages then contact immediately to the Invigilator. PART-B (i) Q.1 to Q.6 are "Match the Column" type which may have one or more than one matching options and carry 8 marks for each question. 2 marks will be awarded for each correct match within a question. ThereisNEGATIVE marking. 0.5 Marks will be deducted for each wrong match. Marks will be awarded only if all the correct alternatives are selected. PART-C (ii) Q.1 to Q.17 are "Subjective" questions. There is NO NEGATIVE marking. Marks will be awarded only if all the correct bubbles are filled in your OMR sheet. PART-D (iii) Q.1 to Q.2 are "Subjective" questions. There is NO NEGATIVE marking. Marks will be awarded only if all the correct bubbles are filled in your OMR sheet. 2. Indicate the correct answer for each question by filling appropriate bubble(s) in your answer sheet. 3. Use only HB pencil for darkening the bubble(s). P Q R S leading zero(s) if required after (A) rounding the result to 2 decimal places. (B) e.g. 86 should be filled as 0086.00 (C) . . (D) . . . . . . . . USEFUL DATA: Atomic Mass: Al = 27, Mg = 24, Cu = 63.5, Mn = 55, Cl = 35.5, O = 16, H = 1, P = 31, Ag = 108, N = 14, Li = 7, I = 127, Cr = 52, K=39, S = 32, Na = 23, C = 12, Br = 80, Fe = 56, Ca = 40, Zn = 65.4, Ba = 137, Co = 59, Hg = 200, Pb = 207, He = 4, F=19. Radius of nucleus =10–14 m; h = 6.626 ×10–34 Js; me = 9.1 ×10–31 kg, R = 109637 cm–1. Take g = 10 m/s2 where ever required. (C) 0 KA0 0 d KC0V0 KC0 V0 KC0V0 KC0 V0 KC0V0 KC0 K +1 (K+1)V0 (D) C0V0 C0 V0 KC0V0 KC0 V0 KC0V0 K +1 KC0V0 K +1 KC0 V K +1 0 KC0 V ] K +1 0 Q.2 Column I has some conductor accrosswhich battery is connected as shown. Variation of resisitivity is also indicated. Which of the quantities in column II remain constant throughout the volume of conductor. Column I Column II (A) (P) Magnitude of electric field (B) (Q) Magnitude of current density (C) (R) Electric power dissipated per unit volume (D) (S) Drift speed of free electron [Ans. A-QS, B-P, C-P, D-bonus] VC= 3VA ; VB = VA T = PAVA A nR .....(II) from A to B ; sochoric P T so TB > TA for C to A ; both (P, V) so T Thus from B to C ( we could have maximum temperature) P = aV + b 6PA 3P V P = + 12 P P = – A V + 12 PA PV = nRT A A 3PAV VA +12PA V = nRT dT for Tmax dV = 0 – 6PA V + 12PA = 0 A V = 2VA P = 6PA T = 6PA (2VA ) nR = 12PAVA nR Tmax = 12 TA = 2400 K ] Q.3fl Two objects of equal volume V=1m3 and differen

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- PAPER CODE : A PART-B For example if Correct match for (A) is P, Q; for (B) is P, R; for (C) is P and for (D) is S then the correct method for filling the bubble is P Q R S (A) (B) (C) (D) PART-C Ensure that all columns (4 before decimal and 2 after decimal) are filled. Answer having blank column will be treated as incorrect. Insert leadingzero(s)ifrequiredafter rounding the result to 2 decimal places. e.g. 86 should be filled as 0086.00 . . . . . . . . . . PART-D Ensure that all columns {1 before decimal and 2 after decimal with proper sign (+) or (–)} arefilledand columns after 'E'usedfor fillingpower of 10 with proper sign (+) or (–). Answer having blank column will be treated as incorrect. e.g. – 4.19 × 1027 should be filled as – 4.19 E + 27 P A P E R - 2 USEFULDATA: Atomic Mass:Al = 27, Mg = 24, Cu = 63.5, Mn = 55, Cl = 35.5, O = 16, H = 1, P = 31, Ag = 108, N = 14, Li = 7, I = 127, Cr = 52, K=39, S = 32, Na = 23, C = 12, Br = 80, Fe = 56, Ca = 40, Zn = 65.4, Ba = 137, Co = 59, Hg = 200, Pb = 207, He = 4, F=19. Radius of nucleus =10–14 m; h = 6.626 ×10–34 Js; me = 9.1 ×10–31 kg, R = 109637 cm–1. Take g = 10 m/s2 where ever required. Class : XII & XIII Time : 3 hour Max. Marks : 210 INSTRUCTIONS 1. The question paper contain 7 pages and 2-parts. Part-B contains 6 questions of "Match the Column" type and Part-C contains 18. All questions are compulsory. Please ensure that the Question Paper you have received contains all the QUESTIONS and Pages. If you found some mistake like missing questions or pages then contact immediately to the Invigilator. PART-B (i) Q.1 to Q.6 are "Match the Column" type which may have one or more than one matching options and carry 8 marks for each question. 2 marks will be awarded for each correct match within a question. ThereisNEGATIVE marking. 0.5 Marks will be deducted for each wrong match. Marks will be awarded onlyif all the correct alternatives are selected. PART-C (ii) Q.1 to Q.17 are "Subjective" questions. There is NO NEGATIVE marking. Marks will be awarded onlyifall the correct bubbles are filled in your OMR sheet. PART-D (iii) Q.1 to Q.2 are "Subjective" questions. There is NO NEGATIVE marking. Marks will be awarded only if all the correct bubbles are filled in your OMR sheet. 2. Indicate the correct answer for each question by filling appropriate bubble(s) in your answer sheet. 3. Use only HB pencil for darkening the bubble(s).
- (C) 0 d KA 0 0 KC0V0 KC0 V0 KC0V0 KC0 V0 KC0V0 1 K KC0 (K+1)V0 (D) C0V0 C0 V0 KC0V0 KC0 V0 1 K V KC 0 0 1 K KC0 V0 1 K V KC 0 0 1 K KC0 V0 ] Q.2 Column I hassomeconductor accrosswhich battery isconnected asshown. Variation of resisitivity is alsoindicated.WhichofthequantitiesincolumnIIremainconstantthroughout thevolumeofconductor. ColumnI ColumnII (A) (P)Magnitudeofelectricfield (B) (Q) Magnitudeofcurrent density (C) (R)Electricpowerdissipated perunit volume (D) (S) Drift speed of free electron [Ans.A-QS, B-P, C-P, D-bonus]
- VC= 3VA ; VB = VA TA = nR V P A A .....(II) fromAto B ; sochoric P T so TB > TA for C toA; both (P, V) so T Thus from BtoC (we couldhavemaximum temperature) P = aV + b P = A A V 2 P 6 + 12 PA P = – A A V V P 3 + 12 PA PV = nRT V P 12 V V P 3 A A A = nRT T for Tmax dV dT = 0 A A V P 6 V + 12PA = 0 V = 2VA P = 6PA T = nR ) V 2 ( P 6 A A = nR V P 12 A A Tmax = 12 TA = 2400 K ] Q.3fl TwoobjectsofequalvolumeV=1m3 anddifferent densities d1=500kg/m3and d2 = 1000 kg/m3 areglued to eachother so that theircontact surface is flat and has an areaA= 0.1 m2. When the objects are submerged in a certain liquid, theyfloatinstableequilibrium, thecontact surface beingparallelto thesurface oftheliquid(seethediagram). How deep (Hin meters) canthecontact surface be inthe liquid so that the objects are not torn apart? The maximum force that the glue can withstand is F=250 N. [Ans H =3m] [Sol. Atthe"critical"depthH,theequilibrium conditionforthecompound object suggests thatthedensityof theliquidisd=(d1 +d2)/2.Forthetopandthebottomobjecttakenseparately,theequilibriumconditions are,respectively: d1Vg + F – (dVg – dgAH) = 0 d2Vg – F – (dVg + dgAH) = 0 (For eachobject, the term inparentheses indicates the "effective" buoyancyforce.) Combining the last two equations yields the answer : H = [(d2–d1)Vg – 2F] / [(d1 + d2) gA] ] Q.4 An inclined plane is placed on a horizontal smooth surface. The plane is struck byan small elastic ball whose velocityis horizontal just before the impact.Theballbouncesofftheinclinedplaneand thenlandsonitagainat the point of first impact. Findthe ratio of themasses of the ball and the inclined plane.(Angle =30°) [Sol. This happens ofafter collisionbothball and inclinedplanehave same horizontal velocities sayV2 say V1 beinitialvelocityofballVy beverticalvelocityofballaftercollision,m1 –mass ofball,m2 –mass of
- = 4.8 k̂ 2 1 8 3 = 4.8 k̂ 8 4 3 = 6 k̂ 4 3 = 13.6 or 13.61 or 13.62 ] Q.6 Initially switch S was closed for long time. Switch is opened at t = 0. Find the current (in ampere) through battery at time t = RC ln2. Take V = 12 V, R = 4 ohm, C = 1.0 F. [Ans.1.3 or 1.34A] [Sol. WhenS isclosedforlongtime fromKVL I(2R) + IR = V I = R 3 V charge on 2C capacitor C 2 q 0 2 = IR 0 2 q = 3 VC 2 charge on C C q 0 1 = I(2R) 0 1 q = 3 VC 2 when S is opened then at t = t I2 = dt dq2 = R 2 V e–t ]

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