Anúncio

Próximos SlideShares

An insurance company found that the number of games pitched per mont.pdf

Carregando em ... 3

25 de Mar de 2023•0 gostou## 0 gostaram

•7 visualizações## visualizações

Seja o primeiro a gostar disto

mostrar mais

Vistos totais

0

No Slideshare

0

De incorporações

0

Número de incorporações

0

Baixar para ler offline

Denunciar

Educação

An instructor has given a short quiz consisting of two parts. For a randomly selected student, let X = the number of points earned on the first part and let Y = the number of points earned on the second part. Suppose that the joint pmf of X and Y is given in the accompanying table: If the score recorded in the grade book is the total number of points earned on the two parts, what is the expected recorded score, E(X+Y)? Solution required = 0*0.02 + 5*(0.06+0.04) + 10*(0.01 + 0.02 + 0.15) + 15*(0.2+0.15 + 0.10) + 20*(0.10+0.14) + 25*(0.01) = 11.4.

BramansinternationalSeguir

Anúncio

Anúncio

Anúncio

An insurance company found that the number of games pitched per mont.pdfBramansinternational

An instructor is trying to determine the amount of time needed to co.pdfBramansinternational

An infinite word is generated ysing the following morphism; letting .pdfBramansinternational

An induction motor turning at 1750 RPM consumes 4750 watts of power .pdfBramansinternational

an independent measures study with n=6, produces a sample mean diffe.pdfBramansinternational

An indenture is Select onethe section of a corporations bylaws .pdfBramansinternational

- An instructor has given a short quiz consisting of two parts. For a randomly selected student, let X = the number of points earned on the first part and let Y = the number of points earned on the second part. Suppose that the joint pmf of X and Y is given in the accompanying table: If the score recorded in the grade book is the total number of points earned on the two parts, what is the expected recorded score, E(X+Y)? Solution required = 0*0.02 + 5*(0.06+0.04) + 10*(0.01 + 0.02 + 0.15) + 15*(0.2+0.15 + 0.10) + 20*(0.10+0.14) + 25*(0.01) = 11.4

Anúncio