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JEE MAIN APRIL 2021 : MATH 30 Qs. in 45 mins.
WORK
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WORK
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Let the MAGIC BEGIN !!
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WORK
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WORK
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WORK
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WORK
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Let the MAGIC BEGIN !!
FOUNDATION SERIES MATH : LOGARITHMS
WORK
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We know that
100 = 102
1000 = 103
What if you are asked Find ‘x’, if 39 = 10x
?
FOUNDATION SERIES MATH : LOGARITHMS
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x = log10
39
10y
= x ⇔ y = log 10
x
Base of
logarithm
The ‘x’ value in above question is
FOUNDATION SERIES MATH : LOGARITHMS
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loga
x = y
log2
32 = k
⇔ x = ay
Example
FOUNDATION SERIES MATH : LOGARITHMS
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loga
x = y
log2
32 = k
⇒ 32 = 2k
⇒ 25
= 2k
⇒ k = 5
⇔ x = ay
Example
FOUNDATION SERIES MATH : LOGARITHMS
WORK
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Note
Common Logarithms:
Logarithm with base ‘10’. In all science
applications the base is taken as ‘10’.
Natural Logarithms:
The logarithms with base ‘e’
(e = 2.718. . ) which is also an irrational
number like ‘π’
1)
2)
loge
x = ln x
FOUNDATION SERIES MATH : LOGARITHMS
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1) x > 0
2) a > 0
3) a ≠ 1
y = loga
x
The necessary conditions for to
exist are
loga
x
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 1
(a ≠ 1, a > 0)
log a
1 = 0
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 1
log a
1 = 0
(a ≠ 1, a > 0)
1 = ak
a0
= ak
⇒ k = 0
Proof
log a
1 = k
Let
log a
1 = 0
Logarithm of ‘1’ is always zero
FOUNDATION SERIES MATH : LOGARITHMS
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log4
1 = y
?
FOUNDATION SERIES MATH : LOGARITHMS
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log4
1 = y
?
Answer : y = 0
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 2
log a
a = 1 (a ≠ 1, a > 0)
FOUNDATION SERIES MATH : LOGARITHMS
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log20
20 = y
?
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 2
log a
a = 1 (a ≠ 1, a > 0)
Let log a
a = k
⇒ a = ak
⇒ k = 1
Example
log2
2 = log3
3 =1
log0.1
0.1 = 1
Proof
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 3
loga
x1
+ loga
x2
= loga
(x1
x2
)
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 3
loga
x1
+ loga
x2
= loga
(x1
x2
)
Proof
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 3
loga
x1
+ loga
x2
= loga
(x1
x2
)
Let loga
x1
= k1
⇒ x1
x2
= ak1 + k2
loga
(x1
x2
) = k1
+ k2
loga
x2
= k2
x1
= ak1
x2
= ak2
= loga
x1
+loga
x2
&
&
Proof
FOUNDATION SERIES MATH : LOGARITHMS
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log10
30 + log10
20= x
?
FOUNDATION SERIES MATH : LOGARITHMS
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Property - 4
loga
x1
– loga
x2
=
loga
x1
x2
FOUNDATION SERIES MATH : LOGARITHMS
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log10
30 - log10
20= x
?
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Property 5
log a
(xn
) = n log a
x (x > 0, a > 0, a ≠ 1)
FOUNDATION SERIES MATH : LOGARITHMS
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log10
100 2
= x
?
FOUNDATION SERIES MATH : LOGARITHMS
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Property 5
log a
(xn
) = n log a
x (x > 0, a > 0, a ≠ 1)
Let loga
(xn
) = k
xn
= ak
x = a(k/n)
k
n
= loga
x
k = n loga
x
Proof
FOUNDATION SERIES MATH : LOGARITHMS
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Property 6
FOUNDATION SERIES MATH : LOGARITHMS
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Property 6
Proof
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Property-7
a log b
= b log
a
FOUNDATION SERIES MATH : LOGARITHMS
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Property-7
a log b
= b log
a
a log b
=
k1
⇒ log b = loga
k1
b log a
= k2
⇒ log a = logb
k2
log b =
log k1
log a
⇒ log k1
= (log a) (logb)
⇒ log k2
(log a) (logb)
log a =
log k2
log b
log k1
log k2
=
⇒ k1
k2
=
Proof
=
⇒
FOUNDATION SERIES MATH : LOGARITHMS
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Property-8
FOUNDATION SERIES MATH : LOGARITHMS
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Q. Find
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L.H.S = (x)log
y
z (y)log
z
x (z) log
x
y
= x
log y – log z
y
log z – log x
z
log x – log y
x
log y
x
log z
=
y
log z
y
log x
×
z
log x
z
log y
×
= 1
Solution :
FOUNDATION SERIES MATH : LOGARITHMS
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Property-9
FOUNDATION SERIES MATH : LOGARITHMS
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Property-10
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WORK
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Let the MAGIC BEGIN !!
FOUNDATION SERIES MATH : LOGARITHMS
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FOUNDATION SERIES MATH : LOGARITHMS
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Q1. Find the value of log2
FOUNDATION SERIES MATH : LOGARITHMS
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=
=
=
2
3
log2
2
=
2
3
Solution:
FOUNDATION SERIES MATH : LOGARITHMS
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Q2. Find the value of log 0.01
1000
FOUNDATION SERIES MATH : LOGARITHMS
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=
log 0.01
1000 log 1
100
103
= 3 log
10
–2
10
=
3
–2
log10
10
=
– 3
2
Solution:
FOUNDATION SERIES MATH : LOGARITHMS
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Q3. If then what is x?
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Solution:
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Q4. If ,
then,
2a = b
A
B
D
C
a = 2b
a = b
2a = 3b
FOUNDATION SERIES MATH : LOGARITHMS
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Solution:
FOUNDATION SERIES MATH : LOGARITHMS
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Q4. If ,
then,
2a = b
A
B
D
C
a = 2b
a = b
2a = 3b
FOUNDATION SERIES MATH : LOGARITHMS
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3( log a + log b + log c)
3 log a
0
-3(log b + log c)
Q5.
is equal to
A
B
D
C
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Solution:
FOUNDATION SERIES MATH : LOGARITHMS
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3( log a + log b + log c)
3 log a
0
-3(log b + log c)
Q5.
is equal to
A
B
D
C
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4
8
64
16
A
B
D
C
Q6. If xy2
= 4 and
then x equals
FOUNDATION SERIES MATH : LOGARITHMS
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W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Solution:
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
4
8
64
16
Q6. If xy2
= 4 and
then x equals
A
B
D
C
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
WORK
4 U!
Let the MAGIC BEGIN !!
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Q7.
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Q7.
Answer : 0
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Q8.
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Q8.
Answer : 0
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Q9. find M.
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Answer : M = 24
Q9. find M.
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
A
B
D
C
Q10. If a = log2, b = log3, c = log7
6x
= 7x+4
, then x =
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
A
B
D
C
Q10. If a = log2, b = log3, c = log7
6x
= 7x+4
, then x =
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
A
B
D
C
Q11. If n=(2017)! then
is
0
1
n
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
A
B
D
C
Q11. If n=(2017)! then
is
0
1
n
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Q12. Solve
FOUNDATION SERIES MATH : LOGARITHMS
WORK
4 U!
N
E
H
A
A
G
R
A
W
A
L
M
A
T
H
E
M
A
T
I
C
A
L
L
Y
I
N
C
L
I
N
E
D
Solution :

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Quadratic degen theorem logarithms

  • 1. JEE MAIN APRIL 2021 : MATH 30 Qs. in 45 mins. WORK 4 U! M A T H E M A T I C A L L Y I N C L I N E D N E H A A G R A W A L
  • 8. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D We know that 100 = 102 1000 = 103 What if you are asked Find ‘x’, if 39 = 10x ?
  • 9. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D x = log10 39 10y = x ⇔ y = log 10 x Base of logarithm The ‘x’ value in above question is
  • 10. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D loga x = y log2 32 = k ⇔ x = ay Example
  • 11. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D loga x = y log2 32 = k ⇒ 32 = 2k ⇒ 25 = 2k ⇒ k = 5 ⇔ x = ay Example
  • 12. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Note Common Logarithms: Logarithm with base ‘10’. In all science applications the base is taken as ‘10’. Natural Logarithms: The logarithms with base ‘e’ (e = 2.718. . ) which is also an irrational number like ‘π’ 1) 2) loge x = ln x
  • 13. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D 1) x > 0 2) a > 0 3) a ≠ 1 y = loga x The necessary conditions for to exist are loga x
  • 14. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 1 (a ≠ 1, a > 0) log a 1 = 0
  • 15. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 1 log a 1 = 0 (a ≠ 1, a > 0) 1 = ak a0 = ak ⇒ k = 0 Proof log a 1 = k Let log a 1 = 0 Logarithm of ‘1’ is always zero
  • 16. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D log4 1 = y ?
  • 17. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D log4 1 = y ? Answer : y = 0
  • 18. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 2 log a a = 1 (a ≠ 1, a > 0)
  • 19. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D log20 20 = y ?
  • 20. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 2 log a a = 1 (a ≠ 1, a > 0) Let log a a = k ⇒ a = ak ⇒ k = 1 Example log2 2 = log3 3 =1 log0.1 0.1 = 1 Proof
  • 21. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 3 loga x1 + loga x2 = loga (x1 x2 )
  • 22. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 3 loga x1 + loga x2 = loga (x1 x2 ) Proof
  • 23. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 3 loga x1 + loga x2 = loga (x1 x2 ) Let loga x1 = k1 ⇒ x1 x2 = ak1 + k2 loga (x1 x2 ) = k1 + k2 loga x2 = k2 x1 = ak1 x2 = ak2 = loga x1 +loga x2 & & Proof
  • 24. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D log10 30 + log10 20= x ?
  • 25. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property - 4 loga x1 – loga x2 = loga x1 x2
  • 26. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D log10 30 - log10 20= x ?
  • 27. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property 5 log a (xn ) = n log a x (x > 0, a > 0, a ≠ 1)
  • 28. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D log10 100 2 = x ?
  • 29. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property 5 log a (xn ) = n log a x (x > 0, a > 0, a ≠ 1) Let loga (xn ) = k xn = ak x = a(k/n) k n = loga x k = n loga x Proof
  • 30. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property 6
  • 31. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property 6 Proof
  • 32. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property-7 a log b = b log a
  • 33. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property-7 a log b = b log a a log b = k1 ⇒ log b = loga k1 b log a = k2 ⇒ log a = logb k2 log b = log k1 log a ⇒ log k1 = (log a) (logb) ⇒ log k2 (log a) (logb) log a = log k2 log b log k1 log k2 = ⇒ k1 k2 = Proof = ⇒
  • 34. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property-8
  • 35. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q. Find
  • 36. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D L.H.S = (x)log y z (y)log z x (z) log x y = x log y – log z y log z – log x z log x – log y x log y x log z = y log z y log x × z log x z log y × = 1 Solution :
  • 37. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property-9
  • 38. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Property-10
  • 40. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D
  • 41. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q1. Find the value of log2
  • 42. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D = = = 2 3 log2 2 = 2 3 Solution:
  • 43. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q2. Find the value of log 0.01 1000
  • 44. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D = log 0.01 1000 log 1 100 103 = 3 log 10 –2 10 = 3 –2 log10 10 = – 3 2 Solution:
  • 45. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q3. If then what is x?
  • 46. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Solution:
  • 47. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q4. If , then, 2a = b A B D C a = 2b a = b 2a = 3b
  • 48. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Solution:
  • 49. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q4. If , then, 2a = b A B D C a = 2b a = b 2a = 3b
  • 50. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D 3( log a + log b + log c) 3 log a 0 -3(log b + log c) Q5. is equal to A B D C
  • 51. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Solution:
  • 52. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D 3( log a + log b + log c) 3 log a 0 -3(log b + log c) Q5. is equal to A B D C
  • 53. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D 4 8 64 16 A B D C Q6. If xy2 = 4 and then x equals
  • 54. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Solution:
  • 55. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D 4 8 64 16 Q6. If xy2 = 4 and then x equals A B D C
  • 57. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q7.
  • 58. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q7. Answer : 0
  • 59. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q8.
  • 60. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q8. Answer : 0
  • 61. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q9. find M.
  • 62. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Answer : M = 24 Q9. find M.
  • 63. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D A B D C Q10. If a = log2, b = log3, c = log7 6x = 7x+4 , then x =
  • 64. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D A B D C Q10. If a = log2, b = log3, c = log7 6x = 7x+4 , then x =
  • 65. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D A B D C Q11. If n=(2017)! then is 0 1 n
  • 66. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D A B D C Q11. If n=(2017)! then is 0 1 n
  • 67. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Q12. Solve
  • 68. FOUNDATION SERIES MATH : LOGARITHMS WORK 4 U! N E H A A G R A W A L M A T H E M A T I C A L L Y I N C L I N E D Solution :