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Can we find a and k so the given points are in the graph of the func.pdf
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Can we find a and k so the given points are in the graph of the function (1, 20), (2,5); y = a(x + 1)^2 +k y= ? (X+ 1)^2 + ? Solution y = a(x + 1)^2 +k 20 = a(1+1)^2 + k 4a + k = 20 5 = a(2+1)^2 + k 5 = 9a + k 20 - 4a = 5 - 9a 5a = -15 a = - 3 k = 20 - 4a = 20+12 = 32 Answer is y = -3(x+1)^2 + 32.
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Can we find a and k so the given points are in the graph of the func.pdf
- Can we find a and k so the given points are in the graph of the function (1, 20), (2,5); y = a(x + 1)^2 +k y= ? (X+ 1)^2 + ? Solution y = a(x + 1)^2 +k 20 = a(1+1)^2 + k 4a + k = 20 5 = a(2+1)^2 + k 5 = 9a + k 20 - 4a = 5 - 9a 5a = -15 a = - 3 k = 20 - 4a = 20+12 = 32 Answer is y = -3(x+1)^2 + 32
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