Can someone check this for me, please? I feel we might be very wrong with our answer.
P(the height of a randomly selected student is between 5.5 and 6 feet)
P (5.5 < x < 6) = f(z1) - f (z2) where z = (x - sample mean) / sqrt (sample variance)
= 0.822266 - (-0.94)
= 1.75
5.416666667 5.3333 5.7500 5.8333 5.8333 6.0833 5.7500 5.8333 5.5833 6.5000 5.6667 5.9167
6.2500 6.2500 5.5833 6.0000 5.7500 5.9167 6.0000 5.6250 5.5000 5.6667 6.1667 5.6667 5.6667
6.0833 5.5000 5.9167 5.2500 5.5000 5.8333 5.8333 5.9167 6.0833 6.1667 5.6667 6.0000 5.9167
6.0833 5.6667 6.0003 6.0000 5.8333 5.0000 5.5833 5.5000 5.1667 6.0833 5.8333 5.5000 6.2500
6.2500 5.8333 5.6667 6.1667 5.2500 5.5833 5.9167 5.3333 6.2500 5.9167 6.0833 6.0000 5.9167
6.0000 5.4167 5.8333 5.1667 5.9167 5.9167 5.8333 5.7500 5.6667 5.6667 5.7500 6.0000 5.1667
5.7500 5.7500 5.6667 6.0000 6.0000 5.5833 5.5000 6.1042 5.6667 5.1667 5.8333 6.0000 5.6667
5.5000 5.2500 5.9167 5.6667 6.1667 5.6667 5.5000 5.3750 5.8333 5.7500 5.8333 5.5833 5.8333
5.5833 5.8333 5.9167 5.5833 5.7500 5.9167 5.6667 5.5000 6.2500 6.0000 5.6667 5.6667 5.7500
5.8333 5.4167 5.7500 5.0000 6.0833 6.0000 6.0000 5.9167 5.7500 5.2500
Solution
sample mean= 5.7469, sample variance= 0.4243.. sample std dev= 0.6514... thus the
90th percentile x= 6.5817... feel free to ask doubts.. please rate and reward..:)