7. How tall can we build a column before it buckles? (due to its own
weight)
8. Critical buckling length due to self-weight
3
2
25,1
rE
Lcr
E: column’s E-modul
r: radius of column’s cross section
: column specific weight(r*g)
9. Specific strength and stiffness and material efficiency
(1) In case of compression, the values are usable only for members restrained against buckling
(2) Applies only for members in compression
(3) Applies only for member in tension
10. It is not a coincidence that among the largest spans, for roof
structures, are made by timber
11. Geodetisk kupol
Arena i Northern Michigan
University, Michigan, USA.
Diameter: 163 m
Pilhöjd: 49 m
Byggår: 1995
The superior dome
12. Two geodesic domes (coal power supply)
Brindisi, Italy
Diameter: 143 m (largest in Europe)
Rise: 44 m
Built in: 2014
The domes in Brindisi
15. Efficient shapes
W
d
C
T
The efficiency of the beam is not too high because:
- The parts of the beam close to neutral axis are almost unstressed
- The lever arm is small (depth of the beam is approx. 1/20 of span)
21. Suppose that a force “F” acts in between the two supports
L/2
F
Support 1 Support 2
L/2
22. Suppose that the force can be taken by means of the 2
structures below
L
f
F
b
h1
L
F b
h2
1 2
Hypothesis:
- Bending strength = compression strength = f
- Disregard bending in structure (1) (immovable
supports) and assume that buckling is not an issue
- For the beam case, assume L/(h2)=20
Determine :
1. The ratio of (Volume 1)/ (Volume 2) as a function of the
slope a
2. What is the value of that ratio when f/L=0,15?
23. Efficient shapes: observe this
Structural Engineering - Lund University 23
The shape of a hanging cable subjected to a set o load is similar to the shape of
the bending moment of a corresponding beam subjected to the same set of loads.
25. Cable shape vs bending moment diagram
Structural Engineering - Lund University 25
26. Structural Engineering - Lund University 26
The shape of a hanging cable subjected to a set o load is
similar to the shape of the bending moment of a corresponding
beam subjected to the same set of loads.
OK, so what?
27. Structural Engineering - Lund University 27
If we give the structure the same shape as the hanging cable (or the same shape as the
bending moment of the corresponding beam), then we will have only tension in the
structure! (Or only compression if we turn the structure upside down)
28. Hanging rope subjected to “uniformly” distributed load
Thrust exerts
a “pull” in the
hands
This shape
gives no
bending
moments!
29. Upside down rope (arch) subjected to “uniformly” distributed
load
Thrust exerts a
“push” in the
hands
This shape
gives no
bending
moments
either!
55. 55
Model 1: Diagonals hinged to chords
In this case the bending moment in the diagonals is obviously zero
56. 56
Model 2: Diagonals clamped to chords
In this case the bending moment in the diagonals is ≠ 0
N M
57. 57
Model 2: Diagonals clamped to chords
Note
1. The ratio above is not influenced by the width of the diagonal members
2. In timber structures the diagonals will never be completely clamped, thus bending
moment (and thus bending stresses) will be lower in practice
0,0
5,0
10,0
15,0
20,0
25,0
30,0
0 100 200 300 400 500 600 700
Depth of the diagonal h [mm]
100
MN
M
h
F
58. Structural Engineering - Lund University 58
How do we design the truss in practice?
- Model the truss with continuous upper and lower chords and hinged web members
- Determine the Axial forces and the bending moments
- The nodes can be designed by considering pure axial force increase by approx. 15-20% in order to take into
consideration the presence of moment and shear
98. Different types of buckling analysis
The buckling load can be determined by 2nd- order analysis, by giving the arch initial
imperfection and increasing the load stepwise until instability is reached
By using simplified formulas to determine the buckling load. In this case the arch is
considered as a compressed strut with an appropriate buckling length
124. Prerequisites for stability
• Wall bracings must be able to resist horizontal
forces along three different directions in the plane
• The three directions shall not converge in the same
point
• At least two of the three directions shall not be
parallel one to another
127. Bracing of high walls
System (b) is in general more efficient than system (a), due to ab < aa
40o<a<55o is a good compromise between economy and efficiency
System (b) is however more expensive than system (a)
139. Assumed initial deformation: parabolic shape
DT
x
y
L
R
2
4
D
L
x
y T
Assumed shape
2
2
1
dx
yd
R
2
2
2
2
2
2
8
4
1
LL
x
dx
d
dx
yd
R
T
T
D
D
141. Estimation of lateral loads for glulam structures
• Initial out-of-straightness: D0=L/500
• Additional deformation D (e.g. due to wind load) shall not exceed
L/500.
• This means that the final deformation shall be (maximum value)
250
)( 0
L
T DDD
144. EC5 approach
crit
f
d
h k
LHk
M
nq
1
3,
Md= design moment in the beam
H = depth of beam
L= span of the beam
n= number of laterally braced beams
kf,3= modification factor (kf,3=30-80)
kcrit= reduction factor for lateral buckling when the beam is unbraced