Correlation18october

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MANAGEMENT APTITUDE
TEST
Dr. T.K. Jain.
AFTERSCHO☺OL
Centre for social entrepreneurship
Bikaner M: 9414430763
tkjainbkn@yahoo.co.in
www.afterschool.tk, www.afterschoool.tk

The ratio of the rate of flow of water
in pipes varies inversly as the
square of the radius of the pipes.
What is the ratio of the rates of flow
in 2 pipes of diameter 2 cm
and 4 cm
• Solution : ratio (1/2)^2 : (1/4)^2 = ¼: 1/16
• Thus their ratio is 4:1 answer.

Salaries of A, B and C were in the
ratio 3 : 5: 7,
respectively. If their salaries were
increased by 50%, 60%
and 40% respectively, what will be
the new ratio of their respective
salaries?
• Let us assume that their salaries are :
300,500, 700. New salaries are :
450,800,980. Their new ratio is 45:80:98

Solve it …
• When a bus started from the first stop, the
number of male passengers to the number
of female passengers was 3 : 1. At the first
stop 16 passengers got down and 6 more
female passengers got in. The ratio of the
male to female passengers now became
2: 1. What was the total number of
passengers in the bus when it started from
the first stop?

Solution
• Let us assume the number of females in
the beginning to be X.
• So : (3X -16)/ (X +6) = 2/1
• 3X -16 = 2X +12
• X = 28
• Thus total passengers was : 28*4 = 112
answer.

Solve it
• Given that 24 carat gold is pure gold, 18
carat gold is ¾ gold and 20 carat gold is
5/6 gold, the ratio of the pure gold in 18
carat gold to the pure gold in 20 carat gold
is
• Soluton…
• ¾ : 5/6 = 18: 20 or 9:10 answer.

A started a business with $ 4500
and another person B joined after
some period with $ 3000. Detemine
this period before B joined the
business if the profit at the end of
the year is divided in the ratio 2 : 1
• Capital * period for A = 4500 * 12 = 54000
• For B it is half of it 27000, dividing it by
3000 gives 9 months. Thus B joined after
3 months. (answer).

A began a business with $ 4,500
and was joined.afterwards by B
with $ 5,400. If the profits at the
end of the year were divided in the
ratio 2 : 1, B joined the business
after … months??
• Like the last question: 4500*12 = 54000
• B has ½ of it: 27000
• 27000/5400 = 5 months. Thus B joined
after 7 months. Answer.

The monthly incomes of two
persons are in the ratio of 4:
5 and their monthly expenditures
are in the ratio of 7: 8. If
each saves Rs. 50 a month then
what are their monthly
incomes?
• 4X – 7Y = 50 or 20 X – 35Y = 250
• 5X –8 Y = 50or 20 X -32 Y = 200
• Y = 50/3 = 16.6. Thus expenses of first person is 116 and
income is 166. Similarly income of 2nd person can be
identified.

A salesman averages Rs. 240
during a normal 40 hour
week. During a sale, his rates are
increased by 50%. What
Is his commission if he puts in 60
hours during the sale?
• Commission during 40 hours 240, so it should be 60/40
*240 = 360 during 60 hours.
• It is further increased by 50%, so it should be 540 instead
of 360. (360 *1.5) Answer.

A machine is sold at a profit of
10%. Had it been sold for
Rs. 40 less, there would have been
a loss of 10%. What was
the cost price?
• Let us assume that the cost of machine is
100, it is sold at 110. when it is sold in loss, it
will sale at 90. The difference is Rs. 20 i.e.
(110-90)
• If the difference is 20, cost is 100, if the
difference is 40, cost should be 200. Answer.

If 50% of the 2 : 3 solution of milk
and water is replaced
with water, then the concentration
of the solution is
reduced by:
• Let us assume that total mixture is 10 liters. Now we
reduce it to 5 liters and add 5 lt. water. Total water
now becomes (3+5) = 8 liters and concentration is
reduced from 40% (4 liters out of 10 liters) to 20%
(2liters out of 10 liters). Thus there is reduction of
50%. Answer.

Normally, numbers are written with
a base of 10. Binary number have a
base of 2. In which base can 19257
be written
as 110100?
(1) 3 (2) 5
(3) 7 (4) 8

Solution –dividing by 7

19257

2751 0

393 0

56 1

8 0

7 1

1

Let A=0.a1a2… and R = 0.r1r2..
Where a1,a2,r1,r2 etc are integers
between I to 9
in random order, Then which of
the following is an
integer?
• (1) 1089 x (A + R) (2) 10989 x (A ÷ R)
• (3) 100989 x (A + R) (4) None of these

Solution …
• A1,a2,a3 and r1,r2,r3 etc. are integers
which are in continuous order. Thus these
numbers are such that we can express
them as divided by 999…..
• Thus we have a number like:
• (a) 1089 * (1/99… + 1/99…)
• In this option, we find that 1089 is
dividisble by both 11 and 9 (11*9=99),
therefore this is the answer.

I a farmer is having 5 acres of land and only
50 kg of fertilizers, how much should he use
per hectare to get best yield ?

Solution
• He should use 16 kg per acre in 2 acres.
Remaining 18 kg should be used in in
remaining 3 acres. The total yield will be :
• 18+18+5+5+5 = 51 answer.

A number when divided by 5
leaves the remainder 3 what
is the remainder when the square
of this number is divided
by 5?

• Let us do the square of the remainder also
= we get 3*3 = 9. When we divide 9 by 5,
we get 4 as remainder, thus 4 is the
answer.

The difference between a three-
digit (with 3 distinct digits) number
and a number obtained by
reversing this number will always
have its middle digit as?
• The middle digit is always nine.

A ground is in the shape of an
isosceles right
triangle, if length of the longest side
of the ground is
sqrt (2), what is perimeter of the
ground?
• We know that sin 45 is equal to : 1/
(sqrt(2)). Thus the other two sides are
each. The perimeter is 1+1+1.4 = 3.4
approx. answer.

Solution ….
• As we can see that the triangle is an
isoscales triangle.

SOLVE IT
• A salesman has a 35 hours per week
normal schedule. During normal hours he
gets Rs.40. per hour and for overtime he
gets 1.5 times his normal charges. What is
his income if he works for 60 hours in a
week?
• SOLUTION :
• 35*40 + 25*60 =1400+1500 = 2900 ANS.


What is the cube root of 571787?

Options :
•
• 47
• 73,
• 83
93
•
Answer :
•
• 83.


3A+2B / 5A-3B =12/15 what is the
ratio of A to B?
• 3A + 2B = 12 5A – 3B = 15
• Multiply the first equation with 5 and 2nd
equation with 3, we get :
• 15A + 10 B = 60 and
• 15A -9 B = 45
• 19 B = 15. thus B = 15/19

Solution …
3A + 2B = 12
•
• B =15/19
• Putting this value in the first equation.
• 3A + 30/19 = 12
3A = 12 -30/19 = 228 -30 / 19
•
3A = 198/19
•
• A = 198/57
• A: B = 198/57 : 15/19 = 22: 5


if p/q 2/3, what is the value
of p+q / p-q
P=2
•
• Q =3
• Answer : (2+3) / (2-3)
• = - 5 answer.


Two dice are tossed
simultaneously. What is the
probability of getting the sum as a
prime number?

• Prime number : 2,3,5,7,11,
• Total possibilities = 6* 6 = 36
• Answer = 16 out of 36 or 16/36. ans.


Solution…
Total of 14 5 6 78 9 10 11
2 12

1 1 2 3 4 5 6543 2


What is the value of * in the given
equation….


Solution
We know that (A –B)^2 = A^2 – 2AB+ B^2
•
• A = 16/7
• B= 9/7, solutoin is 1. (16 -7 = 7,so 7/7)
• Thus the above equation is just expansion
of this equation. Thus the value of * is
2AB, out of which we already have B. thus
the remaining number is 2A = 32/7, we
already have 7, thus answer is 32.


There is a circular park of 20
meters diameter. Inside the circular
park is a path
1 meter wide. Find
the area of the park.

• Area of circle = pi* radius * radius
• = pi * 10^2 – 9^2 { A^2 – B^2=(A+B) (A-b)}
• = pi * 19*1 = 19 pi. Answer.


A can do a piece of work in 8 days,
B can do it in 9 days and C can do
it in 6 days. On the first two days A
& B work together and on the third
day C joins them. What is the total
number of days worked, needed to
complete the work?


Solution
• For the first 2 days – A and B are working
together… (2*1/8) + (2* 1/9) = 34/72
• Now A,B,C will work together:
• 1/8 +1/9 + 1/6 = 29/72
• They will complete the work in 72/29
• Now multiply this by (1- 34/72) * 72/29
• (because 34/72 work is already complete, the
remaining work is 38/72)
• =38/72 *72/29 = 38/29.
• Thus total time required is 2 +38/29 answer.


Surface area of a cube is 150 cm^2
. What is the length of its edge?

Surface area of cube :
•
• Formula = 6 * Side * side
• 6 * side * side = 150
• Side * side = 25
Side = 5 answer.
•


A circular cord of 35 cm is drawn
into a rhombus. what is the length
of its edge?

• Length of cord = 35 Cm
• Edge = 35/4 = 8.75 answer.


The age of the father is 4 times the
son’s age. 5 years ago it was 7
times the son’s age. What is his
age now?
• Let us assume father’s age = X , son’s
age is X /4 .
• (X-5) / (X/4 – 5) =7 or (X-5)/ (X – 20)/4 =7
Or 4X- 20 = 7X – 140
• - 3X = -120, or X = 40 Answer.

What is the difference between a
discount of 40% on Rs. 1000 and
two successive discounts of 35%
and 5% on the same amount?

• =1000*.35*.05 = discount of 350+32.5
• v/s discount of 400. the difference is : 17.5
answer.

A man sold a horse at a loss of 7%.
Had he been able to sell it at a gain
of 9%, it would have fetched Rs.64
more than it did. What is the cost
price of the horse?
• 64 *100/16 = 400 answer


Solve it ..
• On an article marked Rs.20000, a
customer has a choice between three
successive discounts of 20%, 2O% and
l0% and three successive discounts of
40%, 5% and 5%. By choosing the better
offer, determine the amount he can save.
• Solution :
• 20000*.8*.8*.9 v/s 20000*.6*.95*.95
• =12000 v/s 10300. thus savings are 1700.


A manufacturer sells a vehicle to a
dealer at a profit of
40%, the dealer sells it to a
customer at a profit of 30% and the
customer sells it to a friend for
Rs.7280 at a loss of 2O%. Find the
cost price of the vehicle for the
manufacturer?
• 7280*100/80*100/130*100/140 = 5000.
ans.

What profit percent is made by
selling an article at a certain price,
if by selling it at two-thirds of that
price, there would be a loss of
20%?
• 80 *3/2 = 120 thus there will be profit of
20%. Answer.


Two articles are sold at Rs.198
each such that a prof1t of 10% is
made on the first while a loss of
10% is incurred on the other. What
would be the net profit/loss on the
two transactions combined?


Solution
Sold
•
• Profit on first 198 *10/110 =18
• Loss on 2nd = 198 * 10/90 =22
• There is net loss of Rs. 4


.A person purchases 50 dozen toys
at Rs.4 per dozen. Of these, 40
toys were found broken. At what
price should he
sell the remaining toys in order to
make a profit of 5%?


Solution
No. toys : 50 * 12 = 600
•
• Defective = 40
• Net = 560
• Cost : 4 * 50 = 200
add profit = 5% = 10
•
Selling price = 210
•
• No. of dozens = 560/12 = 46.66 dozens
• New sale price per dozen= 4.5 answwer.


.A fruit vendor sells apples at cost
price but uses false weight
of 960 gm instead of 1 kg. Find the
gain %.
• Profit = 1000 grams – 960 grams
• = 40
• Cost = 960
• Profit = 40/960 *100 = 4.16% answer.

• A engaged 40 labourers on a job. He was
paid Rs.1,050 for the work. After retaining
20% of it, he distributed the remaining
amount amongst the labourers. If the
number of men to women labourers was
as 5: 3 and their wages were as 3 : 2,
then how much did a man get as wages?


Solution
No . Of men = 5/ (5+3) *40 = 25
•
• 25 men were working
• Total payments to men:
• 5*3 = 15, women : 3*2 = 6
Thus payment received was 15/21 *
•
(1050*.8)
• =total payment received = 600
• Payment per man – 600/25 = 24 answer.


arrange eight of the nine numbers 2,3,4,5,
7,10, 11,12,13 in the vacant squares of 3X4
array shown below so that the arithmetic
average of the numbers in each row and
column is the same integer.
What is their average?


Solution
• Let us add these numbers:
• Sum( 1,2,3,4,5, 7,9,10, 11,12,13,14,15, - X)
• X = left out number
• =106-X
• Let us assume average = Y
• The average is same, so total of columns
should be 4Y.
• 3*(4Y) = 106-X
• 12Y = 106 – X, by hit and trial, we know that X
should be 10. Thus Y = 8.
• Thus average is 8 and left out number is 10.
• Answer.

For how many integers N,
N/(20—n) is the square of an
integer?
(a) 0 (b) 1
•
• (c) 2 (d) 3
• (e) 4
• Solution : square cannot be negative, so
20-N must be positive. Therefore N can be
upto 19 only. By trial, we can see that
when N = 16, this is square, there is no
other option, Thus answer is B.

Puzzle
• A truck tra veiled from town A to town B over several
days. During the first day, it covered 1/p of the total
distance, where p is a natural number. During the
second day, it travelled 1/q of the remaining distance,
where q is a natural number. Duthig the third day, it
travelled i/p of the distance remaining after the
second day, and during the fourth day, l/q of the
distance remaining after third day. By the end of the
fourth day the truck had travelled 3/4 of the distance
between A and B.
• The value of p+q is
• (a) 4 0) 5
• (c) 6 (d) 7
• (e) 8


Solution
• Try from options, it cannot be 5 or 6, it has to
be higher value 7 or 8. Let us try for 7.
• Let us assume that the number is 144 (we
have assumed it because 4*3*4*3 = 144)
• First day: 36 is used, left out is 108. 2nd day:
36 is used and left out is 72. 3rd day: 18 is
used and left out is 54. 4th day 18 is used and
left out is 36.
• We know that now 1/4 th is left out, so our
condition is fulfilled. Thus this is the answer.
•


In a certain factoiy, each day the expected
number of accidents is related to the number of
overtime hour by a linear equation. Suppose
that on one day there were 1000 overtime
hours logged and 8 accidents reported, and on
another day there were 400 overtime hours
logged and 5 accidents. What are the expected
numbers of accidents when no overtime hours
are logged?
• (a) 2 (b) 3
• (c) 4 (d) 5


Solution
• Let us frame 2 equations and use them to solve
this question:
• 8 = 1000X +Y
• 5 = 400 X +Y
• Solving these we get : 3 = 600X
• X = 1/200; putting this value, we get Y.
• Y = 3.
• Thus when there is no overtime, the number of
accident is 3. Answer.


In which year did the firm pay
maximum tax?


Solution
• Since all the figures are in %, we cannot
calculate the value of taxes paid as
absolute value. We are not aware of
change in sales also. So answer : cannot
be determined.


Solve it :
• Seven integers A, B, C,D, E, Fand G arc to be
arranged in an increasiug order such that
• i. First four numbers are in arithmetic progression.
• ii. Last four numbers are in geometric progression.
• iii. There exists one number between E and G.
• iv. There exist no numbers between A and B.
• v. D is the smallest number and E is the greatest.
• Vi. A / D = G /C = F / A >1
• vii. E= 960
• What is E / A?


SOLUTION
• F is more than A and A is more than D
and G is more than C.
• D is smallest :D - - - - - - E (G will come
one less than E, A and B are close. C has
to be near D.
• DC BAGFE
• The last four are in GP.
• Thus E = A *r^3 (because it is GP) and A
= D +3(common difference)

Continued…
• E = 960
• Let us find factors of 960
• 2*2*2*2*2*2*3*5
• Thus A must be 15 and ratio must be 4
• The numbers will be : 15,60,240,960.
• Or A may be 120 and ratio may be 2, the numbers will
be 120,240,480 and 960
• Thus F/A = 240/15 = 16 or 480/120 = 2.
• The 2nd option is better. Thus A/D = 2 and D = 60
• We can write that A = D + (3*common difference)
• =120=60 +(3*common difference).


Continued…
120=60 +(3*common difference).
•
• Common difference is 20
• Thus the numbers are :
• 60,80,100,120,240,480,960
Thus we can find answer to the question:
•
E/A
• =960/120 = 8 answer.


Goti and Nitin could do a piece of
work in 12 days. Nitin and Kap
together
do lt In 15 days. If Goti is twice as
good a workman as Kap, find
in how many days Goti alone will
do it?


Solution
G = 2K (now add the two equations)
•
• 2K+N+N+K = 1/12+1/15 = 27/180,
• K+N = 1/15 or 2 (K+N) = 2/15
• 3K +2N = 3/20
K = 3/20 – 2/15 = 1/60
•
Thus Kap can do it in 60 days.
•
• Goti being twice fast, can do it in 30 days
alone. Answer.


Goti car paint a fence 100 metres
long in 6 days,
then how much time will both
Goti and his friend Kap
take, if Kap is thrice as efficient
as Goti?
• Goti’s one day work = 1/6, Kap=3*1/6
• 1/6 + 3/6 = 4/6
• Thus they will take 6/4 = 1.5 days to
complete theFOR PGPSE PARTICIPANTS
work.

Two pipes A and B can fill a cistern
in 10 and 15 minutes
respectively. Both pipes are
opened together but at the end of 3
minutes, ‘B’ is turned off. How
much time will the cistern take to
fill?
• 3/10 +3/15 = 75/150 thus the remaining
pipe A will take 5 minutes to fill up the
tank. Total time: 2+5 = 7 minutes. Ans.

Explanation
• 75/150 = is half of the total pip3 thus the
pipe is helf illed. Thus A can fill the
remaining portion in 5 minutes (it takes 10
minutes to fill completely).


A is twice as good a workman as B;
and together they finish
a work in 14 days. In how many
days can it be done by each
separately?
• Let us assume that A takes X and B takes 2X days.
1/2x + 1/x = 1/14
• Let us assume 1/x = Y
• Y/2 + Y = 1/14
• 3/2Y = 1/14 or Y = 2/42 or 1/21
• Thus A can do it in 21 days and B in 42 days. Answer.


If 20 men complete one-third of a
piece of work in 20 days, how many
more men should be employed to
finish the rest of the work in 25
days?

Total work left = 2*20 = 40 days.
•
• Total mandays required = 40*20 = 800
• Thus no. of persons required = 800/25=32
• Additional persons required = 32-20=12
persons. Answer.

Goti can copy 75 pages in 25 hours
Goti and Kap together can copy
135 pages in 27 hours In what time
can Kap copy 42 pages?

• Goti copies 3 pages in one hour. Thus he
copies 27*3 = 81 pages. Kap copies
(135-81) = 54 pages in 27 hours, or 2
pages in one hour. Thus 42/2 = 21 hours
will be taken by Kap Sa. Answer.


goti & Kap can do a piece of work
in 4.8 days, Kap and
Jitu together can do it in 8 days and
the three together in 4
days. How long would Goti & Jitu
together take to do it’


Solution
• (calculate for 1 day and add them to get the
ans.)
• G+K +K +J= 1 / (4.8) + 1/8
• GKKJ = 12.8 / 38.4
• GKJ = ¼
• K = 12.8 / 38.4 - ¼
• = (12.8 – 9.6) / 38.4
• = 3.2 / 38.4 = 1/12
• Thus G+J = ¼ - 1/12 = 2/12 = 1/6
• G + J will do it in 6 days. Answer.


A person works twice as fast as a
woman. A woman works twice as
fast as a child. If 16 persons can
complete a job in 12 days, then
how many days would be required
for 32 women and 64 children
together to complete the same job?

• 32 women = 16 men
• 64 children = 16 men.
• Thus they will together do it in 6 days.
Ans.

3 pipes A, B and C can fill a cistern
in 15, 20 and 30 min. respectively.
They were all turned on at the
same time. After 5 minutes the first
two pipes were turned off. In what
time will the cistern be filled?


Solution
• 5/15 + 5/20 5/30
• = (20+15+10) / 60 = 45/60 or ¾
• Thus remaining ¼ of the cistern can be
filled by C in 7.5 minutes only.
• Thus total time taken is 5 + 7.5 =12.5
minutes


A certain number of men can
finish a piece of work in 100
days. If, however, there are 10 men
less, it would take 10
days more for the work to finish.
How many men were there?

• Let the number of men = X
• Total work = 100X
• (X-10) 110 = 100X or 110X -1100 = 100X
• 10X = 1100 or X = 110.

A, B and C can do a piece of work
in 20, 20 and 40 days
respectively. They began the work
together but C left 2
days before the completion of work.
In how many days would
the work have been completed?


Solution
For 2 days only A and B worked
•
• 2/20 + 2/20 = 4/20 or 1/5
• Together (all three) :
• 1/20+1/20+1/40 = (2+2+1) / 40 = 1/8
Thus they take 8 days to complete the
•
work, but they completed only 4/5 work
together, so 8*4/5 = 6.4 days were taken
by them. Thus total days : 8.4 days.
Answer.

ERROR SPOTTING
Industrial accidents/(1)usually
result into /(2) ignorance/(3)or
carelessness/(4) No Error (5)
• The correct sentence should be :
• Industrial accidents are caused by
ignorance or carelessness.
• So answer is (2)


Some people are like (1)to do a lot
of social work/(2)even though they
are poor(3)and lack resources

• Correct sentence should be :
• Some people want / are likely to do a lot of
social work, even though they are poor
and lack resources.
• So answer is (1) .

ERROR SPOTTING
Some men (1)have conveniently
believe (2)that women are inferior
to(3) men in respect of abilities.(4)
No Error (5)

• (2) = it should be : have conveniently
believed.


ERROR SPOTTING
His qualities include(1)the ability to
take/(2)right and/(3)quickly
decisions.(4)/ No Error(5)
• ANSWER : (4)
• It should be quick decisions.


ERROR SPOTTING
If you want to (1)ensure prompt
service (2)please be contacted to
us (3) at your earlier convenience.
(4) No Error (5)
• Answer : (3) please contact us OR please
be in contact with us


They founded (1)this institution for/
(2)the welfare of the poor (3) and
the disable people.(4) No Error (5)

• Answer (4) it should be :
• For the disable (there is no need to put
people with disable).


He asked me/U) what had my total
investrnents(2)during the (3) last
five years.(4) No Error. (5)

• Answer : (2) it should be :
• What had my total investments been


He takes the(1) prescribed
medicine regularly(2) and that is
how(3) he has succeed to control
his ailment.(4) No Error (5)
• Answer : (3)
• It should be : this is how


We should take(1) regular
exercises to keep ourself (2) fit and
active.(3) No Error (4)

• (2) it should be : regular exercises to keep
• (there is no need of ourself).


Each time (1) you reached this spot
(2) go back and(3) start your next
(4) round again.(4) No Error (5)

• (2) it should be – you reach this spot.


SENTENCE IMPROVEMENT
• The honourable court had taken a leniency
view because the accused had no previous
criminal record.
• (1) had viewed leniency (2) had taken a
leniency viewing
• (3) had taken a lenient view(4) Noae of these
• (5) No correction required
• Solution:
• (3)


Sentence improvement
• Maintaining global peace is our self-made
commitment to the word.
• (1) self-making commitment
• (2) self-made committee
• (3) made of self-connnitment
• (4) None of these
• Solution (5)


The dinner party hosted by the
President at the club was shifted to
an undisclosed location.
(1) a locality undisciosing
•
• (2) a undisc location
• (3) an undisc location
(5) No correction required
•
Solution
•
• (5)

Sentence improvement
• The government should launch such
projects which should reversible the
destructive cycle of flood and drought.
• (1) should have reversible (2) should be
reverse (3) should have been reverse
• Solution :
• (4) correct answer: should reverse

A comnilttee comprising eminent
experts from various fields were
setting up.
(1) was setup
(2) was setting up
(3) were being set up
(4) None of these

• Solution : (1)

Our foreign exchange reserves
have been increased substantial.
(1) have been increased
substantially
(2) have increased substantially
(3) have substantially increasing
(4) None of these
• Solution : (2)

The key to a competitive economy
is its investment regime.

• (1) competition economy is
• (2) competing economist lays
• (3) economy competition was
•
Solution
•
• (5)

Driving a car in jammed traffic
require extraordinary patience -
especially when other drivers are
not disciplined.
(1) required extraordinary patient
(2) requires extraordinary patience
(3) requiring extraordinary patience
(4) None of these
• Solution (2)

Chinese army possesses highly
sophisticated simulotors on which
their soldiers are training.

• (1) which their soldiers training on
• (2) on which their soldiers have trains
• (3) which their soldiers do train
• Solution : last part : soldiers are getting training.
(so answer is (4))

Every novel activity will be likely to
face resistance from vested
interests.

• (1) is likely to face
• (2) would be like facing
• (4) will be likely facing
(5) None of these
•
Solution : (1)
•

We observed that traders were not
primarily dedicated with art of
selling.

(1) dedicated to the art of(2) None
•
• (3) dedicated in the art by
• (4) dedicated by the art of
Solution (1) preposition error .
•

If expenses per participant during the meeting is Rs.200 in
1995, which keeps on increasing at the rate of 10% per year,
then what are the total expenses (in Rs.thousand) in 1996.
The graph below shows the number of participants coming
from different regions?


Solution
• 200*1.1*360 = 79200 answer.


The following graph shows profits
of 5 companies. What was the
average profit in 1979?


Solution :
A =130
•
• B = 40
• C = 110
• D = 60
E = 90
•
Let us add them and divide by 5:
•
• =430/5 = 86 answer.


Solve it
• A cube with edges equal to 8cm is painted
on all the six faces and is subsequently
cut into 64 identical cubes. The number ct
smaller cubes painted on atleast two faces
is
• (1) 24 (2) 16
• (3) 36
• (4) 32


Solution
• There are four on the top right side. There
are 4 on the opposite side also (4*4*4 =
64).

• Thus we have 4+4+2+2 cubes in front,
same 12 in the back side also. We have 8
in sides also. Thus we have 32 cubes.
• Ans.


Solve it
• The perimeter of a regular hexagon is 36cm.
The area of the hexagon is
• (1) 54*sqrt(3) sq cm (2) 108*3 sq cm
• (3) 27*3 sq cm (4) 18*3 sq cm
• Solution:
• One side of hexagon = 6
• One triagle = ((sqrt(3)/4 * side )^2 =1.7/4* 36
• Hexagon = 6* equilateral triangle =
6*sqrt(3)/4*36
• =54* sqrt(3) ans


Solve it …
• How many patient does the doctor
examine in a day, if he treats 5 patients in
3 hours with breaks of 10 minutes
between two consecutive patients and
works for 10 hours per day?
• (1) 16 (2) 15
• (3) 12 (4) 20


Solution
3 hours = 180 minutes
•
• Break = 4*10 = 40
• Time per patient = 140 / 5 = 28 minutes
• Total time : 10 hours *60 = 600 minutes
600 – 28 = 572
•
Now dividing 572 / (28+10) = 15
•
• Thus the doctor checks 15+1 = 16
patients.


If the interior angle of a regular
polygon is twice its exterior angle
then the polygon is a
(1) rhombus (2) pentagon
(3) hexagon (4) heptagon

Interior angle = 2X and exterior angle = X
3X = 180 or X = 60
Thus one exterior angle is 60
Thus 360/60 = 6
Thus the shape is hexagon. Answer.

DATA SUFFICIENCY QUESTION.
40 pens were distributed equally
amon all the participants, then how
many participants were there?
(A) The number of participants was
a prime number greater than 10.
(B) The leftover pen was kept by
the Chairman.


Solution
• If we combine both the statements, we
can get the answer. One pen was left
(given to the chairman), so 39 pen were
distributed.
• 39 = 3*13
• Thus the number of participants must be
either 3 or 13. since it had to be above 10,
therefore the answer is 13. (so answer
can be drawn with the help of both the
students together). Ans.

WHAT IS THE VALUE OF X


Data sufficiency question.
Is the series a GP?
•
• (A)If the third term is twice the second.
• (B)The fourth term is eight times the first.
• Solution
Let us start from 1
•
1,2,4,8 = yes it is GP
•
• Thus the answer can be drawn with the
help of both the statements. Ans.


The number of common terms in
the two-seç 17, 21,
25,.. ., 417 and 16, 21, 26,. . ., 466

• Let us start from 21. In the first term the
gap is of 4 and in second series the gap is
of 5. their LCM is 20 so we have to find
the gaps of 20 each.
• Last term is 417. let us deduct 21 from
417, we get 396. now let us divide it by 20.
We get : 19. Thus we have 19+1 = 20
common terms. Answer.

Solution continued. .. .
• The final series is :
• 21,41,61,81,101,121,141,161,181,201,22
1,241,261,281,301,321,341,361,381,401,


What is the total production of
machine no. 3?


Solution
• Production accepted : 100 – 27 = 73%.
• Thus total production
• 100/73 * 438 = 600 units answer.


• The integers 1, 2,..., 40 are written on a
blackboard. The following operation is
then repeated 39 times: In each repetition,
any two numbers, say a and b, currently
on the blackboard are erased and a new
number a + b —1 is written. What will be
the number left on the board at the end?
• Options: (1) 820 (2) 821 (3) 781 (4)
819 (5) 780


Solution ….
• In the first round, we add up 1 and 2 and
get 2. now we take up 2 and 3, we get 4,
now we take up 4 and 4 and get 7. now
we take up 7 and 5 and get 11. Now we
take up 11 and 6 and get 16. We can find
that we have an increasing series :
• 2,4,7,11,16 …. …
• Let us add 1 to 39. =39*40/2 = 780
• Let us add 780 + 1= 781 answer.


What is the total sale (in no. of
units) in the year 1991?


• = 82016 answer.


What is the % increase in the sale
of VCR in 1993 against 1992?
Sale in 1993 =6151
•
• Sale in 1992 = 3006
• Difference = 3145
• Increase in % = 3145/3006 *100
= 105% answer.
•


This graph shows price of 4 shares,
what is the average price of these 4
shares?


Solution
• Let us add them:
• (150+40+120+90)/4 = 100 answer


what is the production of food grains in 1991,
expressed as a percentage
of its production in 1989?


Solution
• 15/20 *100 = 75 % answer.


Which is the most logical idea?
• If an ant were as big as a horse, could it
move mountains?
• No. A giant ant . . . . . (select from a,b,c,d)
• (a) Would be a structural failure.
• (b) Would never be able to move
mountains.
• (c) Would be a mere curiosity.
• (d) Would never be able to hunt for food.

Solution
• A giant Ant would not be able to move
mountains because it is just a curoisity
(we are not sure about what could it do).
Other options are not logical – as logically
we cannot say that it is structural failure or
it cannot hunt for food or it cannot move
mountains.


Puzzle test…
• Nine cricket fans are watching a match in a
stadium. Seated in one row, they are J, K, L,
M, N, 0, P, Q and R. L is at the right of M and
at third place at the right of N. K is at one end
of the row. Q is immediately next to 0 and P.
0 is at the third place at the left of K. J is right
next to left of 0.
• Who is sitting in the centre of the row?
• (a)L (b)O
• (c)J (d)Q


Solution …
• NRMLJOPQK
• J IS IN THE CENTRE


A and B start walking in opposite
directions. A covers 3 km and B
covers 4 km. Then A turns right and
walks 4 km while B turns left and
walks 3 km. How far is each from
the starting point?
• A is 3 KM in one direction and 4 KM in
right. Applying pythogorus, we find that A
is 5 KM from the starting point. Similarly B
is also 5 KM from the starting point. Ans.

Ram walks 10 m south from his
house, turns left and walks
25 m, again turns left and walks 40
m, then turns right and. walks 5 m
to reach to school. In which
direction the school
is from his house?
• Draw a map and get the answer = north-
east.


In a class of 35 students Kiran is
placed 7th from the bottom
whereas Sohan is placed 9th from
the top. Mohan is placed exactly in
between the two. What is Kiran’s
position from Mohan?
• 10th
• From 9th to the top and 7th to the bottom,
we have 21 candidates (35-(6+8) ). Mohan
is just in the centre. So from Mohan, Kiran
is at 10th place. Answer.

A watch reads 4 If the minute hand
points towards the East, in which
direction does the hour hand point?

• The hour hand is towards South West.


Puzzle
• Goti and I started walking towards each
other from two places lOO m apart. After
walking 30m, Goti turns left and goes lO
m, then he turns right and goes 20m then
turns right again and comes back to the
road and starts walking. If we walk with
the same speed, what is the distance
between us at this point of time


Solution
• (Goti walks 70 meters in all), so I walk 70
meters towards Goti’s starting point and
now I am 30 meters from that. Goti takes
only 30+20 meters on the road. Thus Goti
is 50 meters from my starting point. Thus
there is a gap of 20 meters between me
and Goti. Answer.


Sum of 1st to 30th terms of a series
in arithmetic
progèssion is 150. if the first term is
A, what is 30th term of the series?
• Sum = 30/2 (2a + (29)D) = 150
• 2a + 29d =150*2/30 = or 29 D = 10 – 2A
• 30th term = A + 29D
• 29 D = 10 – 2A, putting the value, we get the answer =
10 – A answer


Question on number system
• Convert 252 into binary system
• 252 / 2 = 126 / 2 = 63/2 = 31/2 = 15/2 =
7/2 = 3/2 =1 (starting from last remainder
to the first)
• 11111100 answer.
• Convert it again to decimal system:
• 1*2^7+1*2^6+1*2^5+1*2^4+1*2^3+1*2^2+
0*2^1+0*2^0 = 128+64+32+16+8+4 = 252


Multiply 12 to 13 ( note - both are
octal numbers, your outcomes must
also be in octal numbers)?
• Let us first convert them into decimal
numbers: 12= 1*8^1 + 2*8^0 =10
• 13 = 1*8^1 + 3*8^0 =11
• Now multiply 10 to 11 = 110
• Now convert it into octal number:
• 110/8 = 13 / 8
• =156
• Test = now convert 156 to decimal
number

Convert 156 (octal) to decimal
number …..
• 1*8^2 + 5*8^1 + 6*8^0
• =64+40+6
• =110 answer.


Multiply 5 (base 16) to 12 (base 7)
and get the outcome in binary?
• (5*16^0 ) * (1*7^1 +2*7^0)
• 5 *9 = 45
• 45/2 = 22/2 = 11/2 = 5/2 =2/2 1
• =101101 answer.


78.8% of a common medicine for
stomach-upsets is absolute alcohol;
3.3% of it is mentha oil; 0.07%
spear mint oil; and 0.177%
chloroform. How much of each of
these compounds is there in a pack
of 30 ml?
solution
alchol = 23.6 ml, 1 ml of menthol
oil and so. On.

What is the sum of cubes of the
first 5 natural numbers?
Formula
•
• = [N (N+1)/2 ]^2
• = [5*6 / 2 ]^2
• =225 answer.


What is the sum of squares of the
first 13 natural numbers?
Formula
•
• =[n(n+1)(2n+1) ] /6
• =(13*14*27)/6
• =819 answer.


In a Class of 80 pupils, the number
of boys is three-fifths the number of
girls. Determine the number of girls
in the class.
Let the number of girls be X
•
• X + 3/5X = 80
• 8/5 X = 80
• X = 80 *5/8
• X = 50 (the number of girls is 50, boys are
30) answer.

The difference between two
numbers is 30. On dividing the
greater by the smller the quotient is
3. Find the numbers.
Let the smaller number be X.
•
• 3X – X = 30
• 2X =30; X = 15,
• Thus 2 numbers are 15 and 45 answer.


Gunpowder contains 75% nitre and
10% sulphur. The rest of it is
charcoal. What is the amount of
charcoal in 9 kg of gunpowder.

• Charcoal is (100 – 75 – 10) = 15%
• 9 KG = 9000 Grams
• 9000*15/100
• =1350 grams answer.


Question on profit
• At what percentage alove the Cost price
must an article be marked so as to gain
33% after allowing the customer a
discount of 5%?
• (a) 48% (b) 43%
• (c) 40% (d) 38%
• (e) None of the above


Solution …
• Let the cost be 100
• Final price being realised 133
• It is after discount, so price before
discount (marked price) is :
• 133*100/95 =140 , so 40 is the answer.


A vertical pole PO is standing at the
centre 0 of a square ABCD. If AC
subtends an angle 90° at point P of
the pole then the angle subtended
by a side of the square
at Pis
(a) 35° (b) 45°
(c) 30° (d) 60°
(e) None of the above

Solution
• When diagonal (in a square) makes angle
of 90 degree in a pyrimidical shape, then
sides make angles of 60 degree. (rule).
• So answer is 60 degrees.


Find the per cent of pure gold in 22
carat gold, if 24 carat gold is cent
per cent pure gold.

• 22/24 *100
• =91.67 % answer.


In the diagram the two circles pass
through each other’s centre. If the
radius of each circle is 2, what is
the perimeter of the region marked
B?


Solution
• Permieter of one circle is 2/3 now
because, it is being cut by other circle.
• Thus 2/3 + 2/3 of perimeters added :
• 2 * 2/3 * (formula of perimeter = 2pi *r)
• =(8 * pi * r) /3 answer.


What is angle C?


Solution
• Angle O is double the angle A. Thus it is
100 degree. Thus C is (180 -100)/2 = 40
degrees answer.


What is angle a?


Solution
• Angles from D and C are equal .
• 180 – 60 – 37 – x
• =83 – x
• Let us sum up for two angles:
• (180+180 ) = 360
• 83-x + 83 – x + 180+2X = 360
• 2Y +2X = 180 let us assume Y = 53
• 2X = 72 or X = 36 answer (solve by options,
so angle A = 53 ) answer.


ABOUT AFTERSCHO☺OL
Afterschoool conducts three year integrated PGPSE
(after class 12th along with IAS / CA / CS) and 18 month
PGPSE (Post Graduate Programme in Social
Entrepreneurship) along with preparation for CS / CFP /
CFA /CMA / FRM. This course is also available online
also. It also conducts workshops on social
entrepreneurship in schools and colleges all over India –
start social entrepreneurship club in your institution today
with the help from afterschoool and help us in developing
society.


Why such a programme?
• To promote people to take up entrepreneurship
and help develop the society
• To enable people to take up franchising and
other such options to start a business / social
development project
• To enable people to take up social development
as their mission
• To enable people to promote spirituality and
positive thinking in the world


Who are our supporters?
• Afterschoolians, our past beneficiaries,
entrepreneurs and social entrepreneurs
are supporting us.
• You can also support us – not necessarily
by money – but by being promotor of our
concept and our ideas.


About AFTERSCHO☺OL PGPSE – the
best programme for developing great
entrepreneurs
• Most flexible, adaptive but rigorous programme
• Available in distance learning mode
• Case study focused- latest cases
• Industry oriented practical curriculum
• Designed to make you entrepreneurs – not just
an employee
• Option to take up part time job – so earn while
you learn
• The only absolutely free course on internet


Workshops from
AFTERSCHO☺OL
• IIF, Delhi
• CIPS, Jaipur
• ICSI Hyderabad Branch
• Gyan Vihar, Jaipur
• Apex Institute of Management, Jaipur
• Aravali Institute of Management, Jodhpur
• Xavier Institute of Management, Bhubaneshwar
• Pacific Institute, Udaipur
• Engineering College, Hyderabad


Flexible Specialisations:
• Spiritualising business and society
• Rural development and transformation
• HRD and Education, Social Development
• NGO and voluntary work
• Investment analysis,microfinance and inclusion
• Retail sector, BPO, KPO
• Accounting & Information system (with CA / CS /CMA)
• Hospital management and Health care
• Hospitality sector and culture and heritage
• Other sectors of high growth, high technology and social
relevance


Salient features:
• The only programme of its kind (in the whole world)
• No publicity and low profile course
• For those who want to achieve success in life – not just a
degree
• Flexible – you may stay for a month and continue the rest of
the education by distance mode. / you may attend weekend
classes
• Scholarships for those from poor economic background
• Latest and constantly changing curriculum – keeping pace
with the time
• Placement for those who are interested
• Admissions open throughout the year
• Latest and most advanced technologies, books and study
material


Components
• Pedagogy curriculum and approach based on IIM Ahmedabad and ISB
Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad)
• Meditation, spiritualisation, and self development
• EsGotitial softwares for business
• Business plan, Research projects
• Participation in conferences / seminars
• Workshops on leadership, team building etc.
• Written submissions of research projects/articles / papers
• Interview of entrepreneurs, writing biographies of entrepreneurs
• Editing of journals / newsletters
• Consultancy / research projects
• Assignments, communication skill workshops
• Participation in conferences and seminars
• Group discussions, mock interviews, self development diaryng
• Mind Power Training & writing workshop (by Dr. T.K.Jain)


Pedagogy
• Case analysis,
• Articles from Harvard Business Review
• Quiz, seminars, workshops, games,
• Visits to entrepreneurs and industrial visits
• PreGotitations, Latest audio-visuals
• Group discussions and group projects
• Periodic self assessment
• Mentoring and counselling
• Study exchange programme (with institutions out of India)
• Rural development / Social welfare projects


Branches
• AFTERSCHO☺OL will shortly open its
branches in important cities in India
including Delhi, Kota, Mumbai, Gurgaon
and other important cities.
Afterschooolians will be responsible for
managing and developing these branches
– and for promoting social entrepreneurs.


Case Studies
• We want to write case studies on social
entrepreneurs, first generation
entrepreneurs, ethical entrepreneurs.
Please help us in this process. Help us to
be in touch with entrepreneurs, so that we
may develop entrepreneurs.


Basic values at AFTERSCHO☺OL
• Share to learn more
• Interact to develop yourself
• Fear is your worst enemy
• Make mistakes to learn
• Study & discuss in a group
• Criticism is the healthy route to mutual support
and help
• Ask fundamental questions : why, when, how &
where?
• Embrace change – and compete with yourself
only


www.afterschoool.tk
social entrepreneurship for better
society


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