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For the circuit shown, find:
(a)The resonant frequency of the circuit
(b)The total current taken by the circuit
 at resonance
fR = 
 1       


   2 π √ (L C)
fR = 
            1                 


    6.28 √ (25 x 10¯³) x (1 x 10¯⁶)
fR = 
            1            = 
 1007.1 Hz

    6.28 x (1.5811 x 10¯⁴)
Answer = 1007.1 Hz (or about 1kHz)
Note: At resonance, the impedance of the
inductor and capacitor can be ignored
IT = 
V

     R
IT = 
 100
      2.2 x 10³
= 0.0455 A = 45.5 mA
Answer: IT = 45.5 mA

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9.8.3 Calculations Para Resonant

  • 1. For the circuit shown, find: (a)The resonant frequency of the circuit (b)The total current taken by the circuit at resonance
  • 2.
  • 3. fR = 1 2 π √ (L C) fR = 1 6.28 √ (25 x 10¯³) x (1 x 10¯⁶) fR = 1 = 1007.1 Hz 6.28 x (1.5811 x 10¯⁴) Answer = 1007.1 Hz (or about 1kHz)
  • 4. Note: At resonance, the impedance of the inductor and capacitor can be ignored
  • 5. IT = V R IT = 100 2.2 x 10³ = 0.0455 A = 45.5 mA Answer: IT = 45.5 mA