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9.8.3 Calculations Para Resonant
1.
For the circuit
shown, find: (a)The resonant frequency of the circuit (b)The total current taken by the circuit at resonance
2.
3.
fR =
1 2 π √ (L C) fR = 1 6.28 √ (25 x 10¯³) x (1 x 10¯⁶) fR = 1 = 1007.1 Hz 6.28 x (1.5811 x 10¯⁴) Answer = 1007.1 Hz (or about 1kHz)
4.
Note: At resonance,
the impedance of the inductor and capacitor can be ignored
5.
IT = V
R IT = 100 2.2 x 10³ = 0.0455 A = 45.5 mA Answer: IT = 45.5 mA