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Solving Linear Equations Using Graphing Substitution and Elimination Introduction to Unit Six
What’s the Deal? ,[object Object],[object Object]
Three Parts (over the next few days) ,[object Object],[object Object],[object Object]
Solving for linear equations answers the question: ,[object Object],[object Object]
Remember - Slope intercept form:  y = mx + b ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
If the slope is ½ ,[object Object],[object Object],[object Object],[object Object]
Graphing Systems of equations ,[object Object],[object Object],[object Object],[object Object]
Graph on the board Graph y = 3x + 1 y = -x + 5
Graphs y = 3x + 1 y = -x + 5
Solving By Graphing Which point or points can fit into both equations? The result is the ( x,y ) coordinates of the intersection.
The coordinates of the intersecting point is your solution. The lines inter- cept at (1, 4) so the solution is x=1, y =4. The lines inter- cept at (1, 4) so the solution is x=1, y =4.
Solve by graphing ,[object Object],[object Object],[object Object]
The coordinates of the intersecting point is your solution. The lines inter- cept at (-20,-12) so the solution is x= -20, y = -12.
Now solve equations in standard form. ,[object Object],[object Object],[object Object],[object Object]
Change 3x + 2y = -6 to y-intercept form ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Subtract -3x  from both sides
Change -3x + 2y = 6 to y-intercept form ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Add 3x  to both sides
Graph the equations: y = - 3 / 2 x -3 and  y =  3 / 2 x + 3 x = 2, y = 0 The solution is (2,0)
Math is NOT a Spectator Sport Write it Out!
End of Part One Assignment: pg. 323-4: 10 - 27
Extras for presentation x   y -4 -2 0 +2 +4 -6  -4  -2  0  +2  +4  +6

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7 1solve By Graphing

  • 1. Solving Linear Equations Using Graphing Substitution and Elimination Introduction to Unit Six
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 8. Graph on the board Graph y = 3x + 1 y = -x + 5
  • 9. Graphs y = 3x + 1 y = -x + 5
  • 10. Solving By Graphing Which point or points can fit into both equations? The result is the ( x,y ) coordinates of the intersection.
  • 11. The coordinates of the intersecting point is your solution. The lines inter- cept at (1, 4) so the solution is x=1, y =4. The lines inter- cept at (1, 4) so the solution is x=1, y =4.
  • 12.
  • 13. The coordinates of the intersecting point is your solution. The lines inter- cept at (-20,-12) so the solution is x= -20, y = -12.
  • 14.
  • 15.
  • 16.
  • 17. Graph the equations: y = - 3 / 2 x -3 and y = 3 / 2 x + 3 x = 2, y = 0 The solution is (2,0)
  • 18. Math is NOT a Spectator Sport Write it Out!
  • 19. End of Part One Assignment: pg. 323-4: 10 - 27
  • 20. Extras for presentation x y -4 -2 0 +2 +4 -6 -4 -2 0 +2 +4 +6