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The wonder of addition and 
multiplication 
~ Disclosure of the trick ~
I will show you the trick of the wonder of 
addition and multiplication.
3 
4 
5 
3 4 5 
In this case, I took three positive integers, 3, 4 and 5. 
Imagine a rectangular solid of 3×4×5.
3 
4 
5 
3 4 5 
In fact, the operation ( choose a number on the left-hand 
side, write the product of the numbers that were not 
chosen and subtract 1 from the number chosen ) means 
slicing the rectangular solid.
3 
4 
5 
3 4 5
3 4 5 
3 
3×5 (×1) = 15 
3 
3 
5 5 
3 
1
3 4 5 
3 
3×5 = 15 
3 
3 
5 5 
3 
1
3 4 5 
3 4 
3×5 = 15 
3×3 = 9 
3 
3 
4 
5 
3 
1 
1 
3 
3
3 4 5 
3 4 
3 
3×5 = 15 
3×3 = 9 
3×3 = 9 
3 
3 
3 
5 
3 
1 
1 
3 
3 
3 
3 
1 
The sum of the numbers on the right-hand side plus 
the product of the numbers on the left-hand side 
equals the volume of the first rectangular solid at 
anytime.
3 4 5 
2 3 4 
1 2 3 
0 
15 
9 
9 
9 
6 
6 
6 
+ 
( 3×4×5 = ) 60 
Thus, when 0 appears on the left-hand side, the sum 
of the numbers on the right-hand side equals the 
product of the numbers that were chosen at first.
In this case, we imagined the three-dimensional 
rectangular solid. 
If you chose 푛 positive integer at first, imagine 
a 푛-dimensional rectangular solid.
If you want to prove this wonder by formulas, 
the formula 
푎1푎2 … 푎푖−1 푎푖 − 1 푎푖+1 … 푎푛 
+ 푎1푎2 … 푎푖−1푎푖+1 … 푎푛 = 푎1푎2 … 푎푛 
is important. 
Thank you for watching!

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Disclosure of the trick - the wonder of addition and multiplication

  • 1. The wonder of addition and multiplication ~ Disclosure of the trick ~
  • 2. I will show you the trick of the wonder of addition and multiplication.
  • 3. 3 4 5 3 4 5 In this case, I took three positive integers, 3, 4 and 5. Imagine a rectangular solid of 3×4×5.
  • 4. 3 4 5 3 4 5 In fact, the operation ( choose a number on the left-hand side, write the product of the numbers that were not chosen and subtract 1 from the number chosen ) means slicing the rectangular solid.
  • 5. 3 4 5 3 4 5
  • 6. 3 4 5 3 3×5 (×1) = 15 3 3 5 5 3 1
  • 7. 3 4 5 3 3×5 = 15 3 3 5 5 3 1
  • 8. 3 4 5 3 4 3×5 = 15 3×3 = 9 3 3 4 5 3 1 1 3 3
  • 9. 3 4 5 3 4 3 3×5 = 15 3×3 = 9 3×3 = 9 3 3 3 5 3 1 1 3 3 3 3 1 The sum of the numbers on the right-hand side plus the product of the numbers on the left-hand side equals the volume of the first rectangular solid at anytime.
  • 10. 3 4 5 2 3 4 1 2 3 0 15 9 9 9 6 6 6 + ( 3×4×5 = ) 60 Thus, when 0 appears on the left-hand side, the sum of the numbers on the right-hand side equals the product of the numbers that were chosen at first.
  • 11. In this case, we imagined the three-dimensional rectangular solid. If you chose 푛 positive integer at first, imagine a 푛-dimensional rectangular solid.
  • 12. If you want to prove this wonder by formulas, the formula 푎1푎2 … 푎푖−1 푎푖 − 1 푎푖+1 … 푎푛 + 푎1푎2 … 푎푖−1푎푖+1 … 푎푛 = 푎1푎2 … 푎푛 is important. Thank you for watching!