This document discusses factoring polynomials and finding the roots of polynomials. It defines factoring as writing a polynomial as the product of two or more polynomials. Roots are numbers that make a polynomial equal to zero when substituted into the polynomial. The document explains that finding a root of a polynomial is equivalent to having that root be a linear factor of the polynomial. It provides examples of finding real roots graphically by looking at the x-intercepts of a polynomial graph and finding both real and complex roots numerically using software.

1. Factoring and Roots of Polynomials<br />What is factoring?<br />If you write a polynomial as the product of two or more polynomials, you have factored the polynomial. Here is an example: <br />The polynomials x-3 and are called factors of the polynomial . Note that the degrees of the factors, 1 and 2, respectively, add up to the degree 3 of the polynomial we started with. Thus factoring breaks up a complicated polynomial into easier, lower degree pieces. <br />We are not completely done; we can do better: we can factor <br />We have now factored the polynomial into three linear (=degree 1) polynomials. Linear polynomials are the easiest polynomials. We can't do any better. Whenever we cannot factor any further, we say we have factored the polynomial completely. <br />Roots of polynomials.<br />An intimately related concept is that of a root, also called a zero, of a polynomial. A number x=a is called a root of the polynomial f(x), if <br />Once again consider the polynomial <br />Let's plug in x=3 into the polynomial. <br />Consequently x=3 is a root of the polynomial . Note that (x-3) is a factor of . <br />Let's plug in into the polynomial: <br />Thus, is a root of the polynomial . Note that is a factor of . <br />Roots and factoring.<br />This is no coincidence! When an expression (x-a) is a factor of a polynomial f(x), then f(a)=0. <br />Since we have already factored <br />there is an easier way to check that x=3 and are roots of f(x), using the right-hand side: <br />Does this work the other way round? Let's look at an example: consider the polynomial . Note that x=2 is a root of f(x), since <br />Is (x-2) a factor of ? You bet! We can check this by using long polynomial division: <br />So we can factor <br />Let's sum up: Finding a root x=a of a polynomial f(x) is the same as having (x-a) as a linear factor of f(x). More precisely: <br />Given a polynomial f(x) of degree n, and a number a, then <br />if and only if there is a polynomial q(x) of degree n-1 so that <br />Finding Roots of Polynomials Graphically and Numerically<br />Finding real roots graphically.<br />The real number x=a is a root of the polynomial f(x) if and only if <br />When we see a graph of a polynomial, real roots are x-intercepts of the graph of f(x). <br />Let's look at an example: <br />The graph of the polynomial above intersects the x-axis at (or close to) x=-2, at (or close to) x=0 and at (or close to) x=1. Thus it has roots at (or close to) x=-2, at (or close to) x=0 and at (or close to) x=1. <br />The polynomial will also have linear factors (x+2), x and (x-1). Be careful: This does not determine the polynomial! It is not true that the picture above is the graph of (x+2)x(x-1); in fact, the picture shows the graph of f(x)=-.3(x+2)x(x-1). <br />Here is another example: <br />The graph of the polynomial above intersects the x-axis at x=-1, and at x=2. Thus it has roots at x=-1 and at x=2. <br />The polynomial will thus have linear factors (x+1), and (x-2). Be careful: This does not determine the polynomial! It is not true that the picture above is the graph of (x+1)(x-2); in fact, the picture shows the graph of . It is not even true that the number of real roots determines the degree of the polynomial. In fact, as you will see shortly, , a polynomial of degree 4, has indeed only the two real roots -1 and 2. <br />Finding real roots numerically.<br />The roots of large degree polynomials can in general only be found by numerical methods. If you have a programmable or graphing calculator, it will most likely have a built-in program to find the roots of polynomials. <br />Here is an example, run on the software package Mathematica: Find the roots of the polynomial <br />Using the quot;
Solvequot;
command, Mathematica lists approximations to the nine real roots as <br />Here is another example, run on Mathematica: Find the roots of the polynomial <br />Mathematica lists approximations to the seven roots as <br />Only one of the roots is real, all the other six roots contain the symbol i, and are thus complex roots (more about those later on). Note that the complex roots show up quot;
in pairsquot;
! <br />Numerical programs usually find approximations to both real and complex roots. <br />Numerical methods are error-prone, and will get false answers! They are good for checking your algebraic answers; they also are a last resort if nothing else quot;
worksquot;
. <br />