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Four Topics for Further
Development of DEM to
Deal with Industrial
Fluidization Issues
Masayuki Horio and Wenbin Zhang
Department of Chemical Engineering,
Tokyo University of Agriculture and
Technology,
Koganei Tokyo, 184-8588 Japan,
masa@cc.tuat.ac.jp
Come & Visit Tokyo Univ. A&T
at Koganei (25min from Shinjuku)
渦
Chemical Engineers in ICMF
From Burton to Fluid Cat. Cracking
                              Chemical Engineers’ Unforgettable
                                           Memory
                               The FCC Development (1940-50)
Capacity in world total [%]
product
                Competition and Evolution      product          product
                of Fluid Catalytic Plants in
                1940-50
                                product


                                                                           steam


                                     steam

                                    air
              kerocene
kerocene      & steam                          air
& steam product                                      kerocene             air
                                                     & steam



                               FCC Plant development
                    air        in Catalytic Cracking of
kerocene
& steam
                    air
                       steam   Kerocene(1940-50)
Post
                                                          cloud
 mdern
  Era:
                 Natural Science and
                 Engineering Science

  The presence of
  column wall makes
  research much
  easier
                                                  hail

 artificial
 plant                                 volcanic plateau
AIChE Fluor Daniel Lectureship Award
Lecture (2001)
My background
-1974 Fixed/Moving Bed Reactors
      and iron-making Processes
1974- Fluidization Engineering
      75-99 Pressurized Fluidized Bed Combustion
            Jets, Turbulent Transport in Freeboard
      82-89 Scaling Law of Bubbling Fluidized Bed
      89-92 Scaling Law of Clustering Suspensions
      93-   DEM Simulation
            Waste Management, Material Processes
1997- Sustainability and Survival Issues
      Biomass Utilization, Appropriate Technology
When Professor Tsuji et al. 1993 proposed an
excellent idea of applying the concept of
discrete/distinct element method of Cundall et al.
(1979) to fluidized beds borrowing the fluid phase
formulation from the two phase model,
I (Horio) almost immediately decided to join in the
simulation business of fluidized beds from
chemical engineers' view points.
This was because with his approach the real
industrial issues, such as agglomeration, gas
solid reactions and/or heat transfer, can be
directly incorporated into the model without the
tedious derivation of stochastic mechanics,
which is not only indirect but also sometimes
impossible from analytical reasons.
DEM, the last 10 years
DEM: Discrete Element Method
    Fluid phase: local averaging
    Particles: semi-rigorous treatment
     User friendly compared to Two Fluid Model & Direct
     Navier-Stokes Simulation
•A new pressure/tool to reconstruct particle
     reaction engineering based on individual
     particle behavior
•Potential for more realistic problem definition/
     solution
Our code development: SAFIRE
     Simulation of Agglomerating Fluidization for Industrial
     Reaction Engineering
Normal and tangential component of Fcollision
                                               and Fwall
 Fn = k nD x n - h                                     dx    n
                                                   n
                                                        dt
 Ft = m Fn x t                                                              Ft     > m Fn
              x t
 Ft = k tD x                         - h               dx    t
                                                                                    m Fn
                                t                  t                        Ft
                                                        dt
 h = 2g                                                g =           ( ln e ) 2
                            km
                                                                 ( ln e ) 2 + p 2
                                                                 SAFIRE (Horio et al.,1998~)
        Rupture joint                      h   c
        Attractive force                   Fc                         Surface/bridge force
       (Non-linear spring)
                                      kn                 Normal dumping h n      w/wo Normal Lubrication
             Normal elasticity
                     No tension joint                                  Tangential dumping h t
                                                                         Tangential elasticity k t
SAFIRE is an extended Tsuji-Tanaka model
developed by TUAT Horio group
                                                                         Friction slider m
                                                                          w/wo Tangential Lubrication


    Soft Sphere Model with Cohesive Interactions
COMBUSTION                  Spray                                     Agglomerating      AGGLOMERATION
                            Granulation/Coating                       Fluidization
      FB
 w/ Immersed                                                                    Ash
    Tubes :                                                                     Melting
                                             FB of               Particles w/
Pressure Effect                                                                       I-H
                                         Solid Bridging         van der Waals
  Rong-Horio                                                                          1998        Tangential
      2000             FB w/                                      Interaction
                                          Kuwagi-Horio                                            Lubrication
                     Immersed                                   Iwadate-Horio                       Effect
                                             1999
Coal/Waste             Tubes                                         1998
                                                                                                 Kuwagi-Horio
Combustion                                                                       Parmanently
                     Rong-Horio                                                                     2000
  in FBC                                                                           Wet FB
                        1999
                                                                                Mikami,Kamiya,
                                              Fluidized Bed DEM                     Horio
                                                 Started from                       1998
                   Particle-Particle         Dry-Noncohesive Bed
 Single Char        Heat Transfer
                                                  Tsuji et al. 1993
 Combustion          Rong-Horio                                                              Natural Phenomena
   in FBC               1999
 Rong-Horio
                                                                                                     OTHER
   1999                                                Lubrication
                                                       Force Effect
   SAFIRE                     Olefine                                      Scaling Law
Achievements                Polymerization       Noda-Horio                  for DEM          Scaling Law
                                                                                                for DEM
                               PP, PE        Structure of
                                                     2002                  Computation
                                                                                             Computation
                             Kaneko et al. Emulsion Phase                 Kajikawa-Horio
                                                                              2000~          Kuwagi-Horio
                                1999                                                             2002~
                                           Kajikawa-Horio
      Catalytic Reactions
                                                2001
CHEMICAL REACTIONS                        FUNDAMENTAL                     LARGE SCALE SIMULATION
AGGLOMERATION
                      Industrial Issues & DEM
■ Agglomerating Fluidization
    by Liquid Bridging
    by van der Waals Interaction
    by Solid Bridging       through surface diffusion
                            through viscous sintering
                            by solidified liquid bridge
    Coulomb Interaction
■ Size Enlargement
     by Spray Granulation (Spraying, Bridging, Drying)
     by Binderless Granulation (PSG)
■ Sinter/Clinker Formation
     in Combustors / Incinerators (Ash melting)
     in Polyolefine Reactors (Plastic melting)
     in Fluidized Bed of Particles (Sintering of Fe, Si, etc.)
     in Fluidized Bed CVD (Fines deposition and Sintering)
CHEMICAL REACTORS
                         Industrial Issues & DEM
    Heat and Mass Transfer           gas-particle
                                     particle-particle
     Heterogeneous Reactions
     Homogeneous Reactions
     Polymerization
     Catalytic Cracking (with a big gas volume increase)
     Partial Combustion (high velocity jet)


COMBUSTION / INCINERATION
     Boiler Tube Immersion Effect
     Particle-to-Particle Heat Transfer
     Char Combustion
     Volatile Combustion (Gas Phase mixing / Reaction)
     Combustor Simulation
10m m
   Sintering of




                                                                                                  2xneck
                                                                 2xneck
   steel particles




                                                                                                     neck diameter, 2
                                                                   neck diameter
   in Fluidized
   Bed Reduction
                                                                                    (a) 923K                            (b) 1123K


Steel shot :dp=200m m, H2, 3600s                                                               SEM images of necks
                     30
                                  Calculated from
                                                                                               after 3600s contact
                     25           surface diffusion model
                     20
  Neck diameter 2x




                     15
                     10           d p=200 m m
                                                               d p=20 m m
                      5
                      0
                      700   800        900    1000      1100   1200                1300
                                        Temperature [K]
          Neck diameter determined from SEM images
              after heat treatment in H2 atmosphere


 Solid Bridging Particles (Mikami et al , 1996)
Model for Solid Bridging Particles
1. Spring constant: Hooke type (k=800N/m)
   Duration of collision: Hertz type
2. Neck growth: Kuczynski’s surface diffusion model
                                     1/ 7
                       4
                56gd            3
     x neck =              DS rg t
                kBT
      Ds = D0,s exp (-Es /RT)
                   -2             5
      D0,s =5.2x10 m/s, E =2.21x10 J/mol (T>1180K)
3. Neck breakage
     Fnc = s neck  Aneck
     Ftc = t neck  Aneck                   Kuwagi-Horio
                                              Kuwagi-Horio 1999
Kuwagi-Horio
      Steel shot         Cross section   6mm

     200mm
                                               rg = 10mm
                                                  neck




Surface Roughness and Multi-point Contact
                                               Kuwagi-Horio 1999
1273K, u 0 = 0.26 m/s, Dt=0.313s


                 Kuwagi-Horio


t= 0.438s   0.750s   1.06s       1.38s       1.69s




  2.00s     2.31s    2.63s       2.94s        3.25s
  Snapshots of Solid Bridging Particles
      without Surface Roughness
                                         Kuwagi-Horio 1999
dp =200mm, T=1273K, u0 =0.26m/s


                                                          Kuwag
                                                          i-Horio




(a) Smooth surface      (b) 3 micro-contact points (c) 9 micro-contact points
      (Case 1)                   (Case 2)                   (Case 3)


Agglomerates (or “dead "dead zones") grown on the wallthe1.21 s). (t = 1.21 s).
        Fig.7 Agglomerates (or zones”) grown on (t = wall


                                                           Kuwagi-Horio 2000
Intermediate condition   Weakest sintering   Strongest sintering
                            condition             condition




(a) Smooth surface
                 (b) 3 micro-contact     (c) 9 micro-contact
                     points                  points
    Kuwagi-Horio            d p =200mm, T=1273K, u 0=0.26m/s

  Agglomerates Sampled at t = 1.21s
                                             Kuwagi-Horio 1999
Poly-Olefine Reactor Simulation,
        Kaneko et al. (1999)
                                                                                         fluid cell
                                                                               uy
Energy balance
Gas phase :
    ( ) ∂εu T )
  ∂ Tg
   ε     (          i g       1                                       particle
           +              =      Q
    ∂t          ∂i
                 x          ρcp,g g
                             g
                                                                                                  ux
Particle :                                                             vy   ε Tg
           dTp
  Vpcp,pρp
            dt
                         H        (
               = Rp (- Δ r ) - hp Tp - Tg S    )                                Qg
                                                                                vx
                                                                      Tpn
               6(1- ε  )
        Qg =
                 dp
                              (
                          hp Tp - Tg       )                                        external gas film
                           E                       heat transfer hpn
        Rp = k exp (            ) w cPr
                         RTp                       coefficient
                             1
                                                   (different for each particle)
                                       1
       Nu = 2.0 + 0.6 Pr Rep 3         2   (Ranz-Marshall equation)

                Nu = hpdp / kg        Pr = cp,gμ / kg
                                                g       Rep = u - v ρdp / μ
                                                                     g     g
Particle circulation                                         Kaneko et al. 1999
(artificially generated by feeding gas nonuniformly from distributor nozzles)

                    t=9.1 sec                      t=6.0 sec              t=8.2 sec
       393
       (120℃)



       343




      293
 T [K] (20℃)                                       2.5umf        2.5umf
                                                                            2umf          2umf
                     3umf 3umf 3umf
                                                            9.3umf
   Ethylene polymerization                                                       15.7umf
   Number of particles=14000
   Gas inlet temp.=293 K                                             Hot spot
   u0=3 umf
    Tokyo University of Agriculture & Technology                          Idemitsu Petrochemical Co.,Ltd.
Uniform gas feeding                               Nonuniform gas feeding
 particle temp. particle velocity                   particle temp. particle velocity
                     vector                                             vector
   t=9.1 sec                                         t=8.2 sec




                                  : Upward motion    2umf     2umf
  3umf 3umf 3umf
                                 : Downward motion       15.7umf
                                                                            Stationary
                                                                            circulation
                 Stationary solid revolution helps Petrochemical Co.,Ltd.
   Tokyo University of Agriculture & Technology  Idemitsu

                    the formation of hot spots.
A Rough Evaluation of
  Heat Transfer Between Particles
radiation

                                                       A     B
                                                               0.4 nm


                                           contact point heat transfer




                                                   A          B
convection

                                        particle-thinned film-particle
            Rong-Horio 1999             heat transfer
                        when l AB < 2r + d : particle-particle heat conduction
Four Topics for Further
  Development of DEM
1. PSD
2. Large Scale Computation via
  Similar Particle Assemblage Model
3. Surface Characterization and
  Reactor Simulation
4. Lubrication Force and Effective
  Restitution Coefficient
PSD Issue
Derivation of CD
corresponding to Ergun
Correlation and A Case Study
Master Thesis
by Nobuyuki Tagami
1. PSD
      What We need for moving
        from Uniform Particle
    Systems to Non-uniform Ones

  ○ 3D Computation
  ○ Contact Model with Particle Size Effect
    Fookean to Herzean Spring
  ○ Fluid-Particle Interactions        Today’s topic
       1) not from Ergun (1952) Correlation
       2) not indifferent to particle arrangement
1. PSD
              Apparent Drag Coefficient
              that corresponds to Ergun
                     Correlation
   (1) Bed Pressure Drop Correlation (Ergun(1952))
          ΔP * /DL = ΔP/ΔL - ρ f g

          =
            (1 - ε ) 150 (1 - ε )μ f                       ( )
                                                            
                                            + 1.75ρ f u - v  u - v
                                                                                  d p : Particle diameter
                                                                                 ε : Void fraction
            d p 
                            d p                           
                                                                                 ρ f : Fluid density
  (2) Equation of motion for fluid (1D)                                           u : Fluid velocity
         ΔP
                                                               (       )
                                                                                  v : Particle velocity
      -ε    - nFpf + ερ f g = 0 n = (1 - ε )/ πd p 3 /6
         ΔL
  (3) Drag Coeff.
                       8 F pf                       → Apparent Drag Coeff.
         CD                                                          200(1 - ε )μ f
                p d p ρf u - v
                       2                2
                                                   C D, Ergun =                        + 2.33
                                                                      d pρ f ε u - v
1. PSD

          Extension of CD,Ergun

                200(1 - ε )μ f
  C D,Ergun =                    + 2.33
                d pρ f ε u - v




                                    200(1 - ε )μ f
                      C D,Ergun   =                + 2.33
                                    d pρ f ε u - v
1. PSD
  The Sum of Drag Force Consistent
      with Ergun Correlation ?
                                Error was within the Accuracy of
dp1/dp2 Number of               Ergun Correlation ±25%.        F
                                                               i,C D,Ergun
[mm/mm]  particles Binary System
                                                               Fi,Ergun
1.00      30000
1.50 /   4444 /
0.750     35556                                                1.25

  ρ p = 2650kg/m 3
                                                               1.00
  ρ f = 1.204kg/m   3

  μ f = 18 μ Pa s
                                                               0.75
  u 0 = 0.811
         1.122m/s (t  0.5s)
     = 1.122m/s (t  0.5s)
1. PSD

      PSD Effect: A Case Study
                     Run1               Run2                  Run3
 Diameter [mm]        3.00         4.50/3.00/2.25           4.50/2.25
   Number [#]        30000       2963/10000/23703          4444/35556
  Vol. Fraction         1        0.333/0.333/0.333         0.500/0.500
              Surface to Volume Mean Diameter:
                dsv=Σ(Ndp3)/Σ(Ndp2) = 3.00 mm
            Total solid volume       = 4.24×10-4m3,
            Total solid surface area = 8.48×10-1m2
Young’s modulus: 80GPa, Poisson ratio: 0.3, friction coefficient: 0.3
(Glass beads)
  Contact Force Model Normal:Hertz’ Model
              Tangential: ‘no-slip’ Solution of Mindlin,
                           and Deresiewicz (1953)
Comparison of the three cases




       Run 1              Run 2              Run 3
      3.00mm        4.50 / 3.00 / 2.25  4.50 / 2.25 mm
                           mm
u0 = 1.438→2.938m/s (t<1sec), u0 = 2.938m/s (t≧1sec)
1. PSD

                   Run3




     Large particles become more mobile
      receiving forces from smaller ones
2. SPA                                Fluidization XI, May 9-14, 2004,
                                                 Ischia (Naples), Italy


  The Similar Particle Assembly (SPA)
                Model,
  An Approach to Large-Scale Discrete
       Element (DEM) Simulation
             Kuwagi K.a, Takeda H.b and Horio M.c,*
   aDept.   of Mech. Eng., Okayama University of Science,
                  Okayama 700-0005, Japan
         bRflow   Co., Ltd., Soka, Saitama 340-0015, Japan
cDept.   of Chem. Eng., Tokyo University of Agri. and Technol.,
                Koganei, Tokyo 184-8588, Japan
Development of Computer Pormance
                         1.0E+16
                                     Fastest computer models
                                       Nishikawa et al. (1995)
  Performance [MFLOPS]



                                       Seki (2000)
                         1.0E+13       Oyanagi(2002)                 15 to 20 years
                                      Single processor for PC
                         1.0E+10       Moore's Law


                          1.0E+7


                          1.0E+4


                          1.0E+1
                                   1,940    1,960     1,980      2,000    2,020
                                                     Year
2. SPA

 How to deal with billions of particles?
 TFM (Two-fluid model)
 DSMC (Direct Simulation Monte Carlo)
    Difficult to deal with realistic particle-particle and
    particle-fluid interactions including cohesiveness
 DEM (Discrete Element Method)
    One million or less particles with PC in a practical
    computation time


 Hybrid model of DEM and TFM (Takeda & Horio, 2001)
 Similarity condition for particle motion (Kazari et al., 1995)
 Imaginary sphere model (Sakano et al., 2000)
2. SPA

 Similar Particle Assembly (SPA) Model
Assumptions
(0. Particles are spherical)
1. A bed consists of particles of different species
   having different properties, i.e. particle size,
   density and chemical composition, and it has
   some local structure of their assembly.
2. Of each group (species) N particles are supposed
   to be represented by one particle at the center of
   them. This center particle is called a
   representative particle for the group.
3. The representative particles for different groups
   can conserve the local particle assembly similar.
m times larger system
(a)                             (b)             of the same particles
                                                 as the smaller bed




                A particle                        Represented volume
                                                    for N particles
                         Similar structure
 (c)               +                  (d)
        +
            +     +                               +
            i
       +x +      +
              x+Dx                                    i’
                                            x       x+mDx
       original system                m times larger system
       Particle Coordination Scaling
2. SPA

Preparation

(1) All particles are numbered: i=1~NT.

(2) Subspace:           (
                  Gk  d p ,  p   )
(3) Group number of particles:                 ((        )
                                        ki  k d pi ,  pi  Gk   )
(4) Equation of motion for particle i:
                       p 3  dv i                       p 3 
                  pi  d pi      = Ffi +  Fpij +  pi  d pi g
                      6      dt          j i          6     

                     Ffi: particle-fluid interaction force
                     Fpij: particle-particle interaction force
2. SPA
                          Governing Equations
  Equation of motion for original particle:
           p 3  dv i                       p 3 
      pi  d pi      = Ffi +  Fpij +  pi  d pi g
          6      dt          j i          6     
  Equation of motion for m-times larger volume:
             p 3  dv i '                                 p 3 
      pi '  d pi '      = Ffi ' +  F pi ' j ' +  pi '  d pi '  g
                               *                   *

            6        dt             j ' i '             6       
           where d pi ' = md pi
                p 3  dv i '                                     p 3 
     m  pi '  d pi ' 
        3
                              = Ffi ' +  F pi ' j ' + m  pi '  d pi ' g
                                    *                   *    3

               6        dt                   j ' i '           6     
                                                                
   If       F +*
              fi '   F         *
                                pi ' j '
                                           = m  Ffi +  F pij
                                               3
                                               
                                                                 
                                                                    ,    v i' = v i
                     j ' i '                         j i      
              
                  (1 -  )2 m f (u - v)                f (u - v) u - v 
                                                                         
        FPi = 150                       + 1.75(1 - )                    Ncell
              
                                 2
                                 d pi                         d pi       
                                                                         
              p
     Fpi =       
                CD f  2 (u - v l ) u - v l d pi
                                               2

              8
Computation Conditions for Case 1
Particles                     Geldart Group: D
Particle diameter: dp [mm ] (a) 1.0 (b) 3.0 (c) 6.0
Particle density: p [ kg/m3 ] 2650
Number of Particles           (a) 270,000 (b) 30,000 (c) 7,500
Restitution coefficient       0.9
Friction coefficient          0.3
Spring constant: k [ N/m ]    800 (Dt=2.58x10-5s)
Bed
Column size                   0.5×1.5m
Distributor                   Porous medium
Gas                           Air
Viscosity: mf [Pa.s ]         1.75x10-5
Density: f [kg/m3 ]          1.15
0.262s 0.528s 0.790s 1.05s   1.31s   1.58s   1.84s   2.10s     2.36s   2.62s




                      (a) Original bed (dp=1.0mm)




           (b) SPA bed (representative particle, dp’=3.0mm)




            (c) SPA bed (representative particle, dp’=6.0mm)

           Snapshots of Dry Particles
p=2650kg/m3, Column : 0.5×1.5m, u0=1.2m/s
of lower half set particles [m]   0.4
                                            d p =1.0mm (Original bed)                        Dry
                                            (fluid cell: 134x333)

                                  0.3
       Average height




                                  0.2                               d p =1.0mm (Original bed)
                                                                    d p' =3.0mm (SPA bed)
                                                                    d p' =6.0mm (SPA bed)
                                  0.1                                  (fluid cell: 22x56)

                                        u0: increasing                        u0: decreasing0
                                                                              decreasing U         +
                                   0
                                        0            1         2         3          4          5
                                                               Time [s]

                     Average height of dry particles
                initially located in the half lower region
0.262s 0.528s 0.790s 1.05s   1.31s   1.58s   1.84s   2.10s    2.36s   2.62s




                     (a) Original bed (dp=1.0mm)




           (b) SPA bed (representative particle, dp’=3.0mm)




           (c) SPA bed (representative particles, dp’=6.0mm)

Snapshots of Wet Particles (V=1.0x10-2)
p=2650kg/m3, Column : 0.5×1.5m, u0=1.2m/s
of lower half set particles [m]   0.4
                                            d p =1.0mm (Original bed)                        Wet
                                            (fluid cell: 134x333)

                                  0.3
       Average height




                                  0.2
                                                                    d p' =6.0mm (SPA bed)
                                                                    d p' =3.0mm (SPA bed)
                                  0.1                               d p =1.0mm (Original bed)
                                                                       (fluid cell: 22x56)

                                        u0: increasing                         decreasing U
                                                                              u0: decreasing0      +
                                   0
                                        0           1          2         3          4          5
                                                               Time [s]

                     Average height of wet particles
                initially located in the half lower region
2. SPA


          10,000                                                             10,000
                                Umf = 0.72m/s           dry                                                wet (V=1.0x10-2)
           8,000                                                              8,000
                                                                                                Umf = 0.70m/s
DP [Pa]




                                                                   DP [Pa]
           6,000                                                              6,000


           4,000                                 d p =1.0mm                   4,000                                   d p =1.0mm
                                                d p'=3.0mm                                                          d p' =3.0mm
           2,000                                                              2,000
                                            d p' =6.0mm                                                        d p' =6.0mm
              0                                                                  0
                   0    0.2   0.4   0.6   0.8    1    1.2    1.4                      0   0.2     0.4   0.6   0.8     1    1.2    1.4

                                    U0 [m/s]                                                            U0 [m/s]

                       (a) Dry particles                                              (b) Wet particles

                                      Umf from Wen-Yu correlation = 0.57m/s

                                      Comparisons of umf
2. SPA

  CPU time for real 1s on Pentium 4 2.66GHz

                  Dry [s]              Wet [s]
 Original bed       27,300                27,600
 (dp=1mm)     (7hrs 34min)          (7hrs 39min)
 SPA bed             1,760                 1,870
 (dp’=3mm)         (29min)
                             1/15        (31min)   1/15
 SPA bed               426                  508
 (dp’=6mm)          (7min)   1/64        (8min)    1/55
Computation Conditions for Case 2
Single bubble fluidization of two-density mixed particles

Column                0.156x0.390m          p=3000kg/m3
Nozzle width          4mm                   p=2000kg/m3
Particle (original)
 dp                   1.0mm
 p                   2000, 3000 kg/m3
Gas                   Air
 f                   1.15kg/m3            0.7m/s  0.7m/s
 mf                   1.75x10-5Pa.s           15m/s (0.482s)



                                             Fig: Initial state
p=3000kg/m3     p=2000kg/m3
t=0.056s   t=0.111s    t=0.167s    t=0.223s   t=0.278s




              (a) dp=1.0mm (original bed)




               (b) dp’=2.0mm (SPA bed)


Single Bubble Behavior of Two-Density Particles
p=3000kg/m3     p=2000kg/m3
t=0.278s   t=0.557s    t=0.835s    t=1.114s   t=1.392s




              (a) dp=1.0mm (original bed)




               (b) dp’=2.0mm (SPA bed)


Single Bubble Behavior of Two-Density Particles
Z                             0.14               SPA model                           0.14
                                                                                                        SPA model
 [m]
 0.12                          0.12                                                   0.12


 0.10                           0.1                                                    0.1


 0.08                          0.08                                                   0.08
                                                                                                 Original bed




                       z [m]
                                          Original bed
 0.06                          0.06                                                   0.06


 0.04                          0.04                                                   0.04
                                                                                                    Bubble region
 0.02                          0.02                                                   0.02          (No particles exist.)

    0                            0
                                      0     0.5       1         1.5       2     2.5
                                                                                        0
                                                                                             0    0.05 0.1 0.15 0.2 0.25 0.3


        (a) t=0.056s                      Gas velocity [m/s]                          Particle velocity averaged
                                                                                      in each fluid cell [m/s]

 Z                             0.14                                                   0.14
 [m]                                              SPA model
 0.12                          0.12                                                   0.12                Original bed

 0.10                           0.1                                                    0.1
                                          Original                                                            SPA
 0.08                  z [m]   0.08
                                          bed                                         0.08
                                                                                                              model
 0.06                          0.06                                                   0.06


 0.04                          0.04                                                   0.04


 0.02                          0.02                                                   0.02


   0                             0
                                      0    0.5    1       1.5         2   2.5   3
                                                                                        0
                                                                                        -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1


                                          Gas velocity [m/s]                          Particle velocity averaged
        (b) t=0.111s                                                                  in each fluid cell [m/s]



Vertical velocity distributions of particle
 and gas phases along the center line
2. SPA
                 SPA concept: promising.
            Similar Particle Assembly (SPA) model
               for large-scale DEM simulation
 Validations (comparisons with the original)
 Non-cohesive particles
 >Slug flow occurred at the beginning of fluidization: similar
 >Bubble diameter: almost the same
 >Bubble shape: not clear with large representing volume
 >Umf: fair agreement
 Cohesive particles: the same tendency as the above
 Binary (density) System:
 >Bubble: similar
 >Particle mixing: similar
3. More Realistic Surface Characterization



                Measurement
                     of
   Stress-Deforemation Characteristics
        for a Polypropylene Particle
      of Fluidized Bed Polymerization
             for DEM Simulation


     M. Horio, N. Furukawa*, H. Kamiya and Y. Kaneko

             *) Idemitsu Petrochemicals Co.
Computation conditions
Particles
Number of particles nt          14000
Particle diameter dp         1.0×10-3 m
Restitution coefficient e          0.9
Friction coefficient μ             0.3
Spring constant k            800 N/m
Bed
Bed size                     0.153×0.383 m
Types of distributor         perforated plate
Gas velocity                 0.156 m/s (=3Umf)
Initial temperature          343 K
Pressure                     3.0 MPa
Numerical parameters
Number of fluid cells        41×105
Time step                    1.30×10-5 s
0     7    15 ΔT [K]


Snapshots of temperature distribution in PP bed
        (without van der Waals force)
Ha = 5×10-20 J




Ha = 5×10-19 J




0     7   15 ΔT [K]



    Snapshots of temperature distribution in PP bed
              (with van der Waals force)
3. Surface Characterization




             Experimental
           determination of
            repulsion force
3. Surface Characterization
                         Catalyst          TiCl3                     0.35
                         Pressure          0.98 MPa                   0.3




                                                      Diameter[mm]
                         Temperature       343 K                     0.25
                         Reactor stage     φ14 mm                     0.2
                                                                     0.15
                                                                      0.1
                                                                     0.05
                                                                        0
                                                                            0 10 20 30 40 50 60
                                                                                Time [min]

                                                        PP growth with time
   The micro reactor




     0 min    1 min   2 min   5 min 10 min 15 min 20 min 30 min 60 min

                        Optical microscope images

             Polymerization in a Micro Reactor
3. Surface Characterization


                                 1: material testing machine’s
            10                      stage
                                 2: electric balance
                     9           3: table
        7
                     8           4: polypropylene particle
                                 5: aluminum rod
            6 5                  6: capacitance change
                 1
                 4       3       7: micro meter
                             2   8: nano-stage
                                 9: x-y stage
             1                   10: cross-head of material
                                     testing machine

            Force-displacement meter
k ~100 N/m                                            Fdp0.5x1.5 (Hertzean spring)
            10   -3
                                                                10-3                                               10-3
                      dp = 597μm                                       dp = 597μm                                         dp = 597μm   3rd

            10-4                                                10-4                                               10-4




                                                    Force [N]
Force [N]




                                                                                                       Force [N]
                                                                          2nd
                                                                                                                             3rd

            10-5                                                10-5                                               10-5
                                                                                            2nd                                               2nd
                                                                                                                                        2nd
                                   1st                                               1st                                               1st
            10-6                                                10-6                                               10-6
              10 -8         10-7
                                   10    -6
                                          10   -5
                                                                  10 -8       10-7
                                                                                     10    -6
                                                                                            10    -5
                                                                                                                     10 -8        10 -7  10-6   10-5
                         Displacement [m]                                  Displacement [m]                                    Displacement [m]
                                                                                     x




                                                                          dp=597mm
                                    FE-SEM images: whole grain and its surface
                 Repeated force-displacement characteristics
                        of a polypropylene particle
Fdp0.5x1.5 (Hertzean spring)
            10 -3                                               10-3                                                10-3
                    dp = 487μm                                         dp = 487μm                                          dp = 487μm


            10 -4                                               10-4                                                10-4                         3rd




                                                    Force [N]
Force [N]




                                                                                                        Force [N]
                                                                                                                              3rd
                                                                                             2nd
            10 -5                        1st                    10-5                                                10-5                         2nd
                                                                                             1st                                                 1st
                                                                                       2nd                                                 2nd
                                     1st                                               1st                                                 1st
            10 -6                                               10-6                                                10-6
               10-8      10 -7
                                 10 -6
                                        10     -5                  10 -8     10-7     -6
                                                                                     10     10     -5
                                                                                                                       10-8     10-7    10-6   10 -5
                       Displacement [m]                                    Displacement [m]                                   Displacement [m]
                                                                                x




                                                                        dp=487mm
                                 FE-SEM images: whole grain and its surface
                         Repeated force-displacement
                    characteristics of a polypropylene particle
                                          (maximum load from first cycle)
3. Surface Characterization




      FE-SEM image of the top particle after
             three times pressing
3. Surface Characterization




      Particle surface morphology changes by
      collisions
      Plastic deformation in the case of PP
      Hertz model stands OK
      Experimental Determination of Cohesion
      Force: Now on going
4. Lubrication Force




      Lubrication Force and
      effective Restitution
      Coefficient
      W. Zhang, R. Noda and M. Horio
      Submitted to Powder Technology
4. Lubrication Force
                          Restitution
  Spring constant
                          coefficient

               ?       ?                   Heat transfer, agglomeration

  Realistic collision process                 Fluidization behavior


                                               ‘Near Contact’ force:
       Interparticle forces
                                               Lubrication force



Field force:        Contact force:

Electrostatic       Van der Waals force
force               Liquid and solid bridge force
                    Impact force
4. Lubrication Force
Classical lubrication theory

     For Liquid-Solid Systems; Tribology, filtration etc.


Why not in Gas-solid systems?

  Lubrication force negligible ?
  Introduction of “Stokes Paradox” ?


        Two solid surfaces can never make contact in a finite
        time in any viscous fluid due to the infinite lubrication
        force when surface distance approaches zero


  Can we avoid the paradox practically or essentially?
Davies’ development of lubrication theory to gas-solid systems
    dh
       = -v(t ) = -(v1 + v2 )                                             v1
    dt
       dv
   m      = -F (t ) = - FL
       dt                                                                                r
                                                        H(r,t)   h(0,t)
                                                                                p(r,t)
    • identical and elastic
    • head-on collision
                                                                          v2
    • rigid during approaching

   Assumptions in classical lubrication theory
   Initial gap size h0 is assumed to be much smaller than particle radius
   Upper limit of integration of pressure for lubrication force is extended to infinity
   Paraboloid approximation of undeformed surface
   Fluid is treated as a continuum
                                                  3mRv                                    3
H (r , t ) = h(0, t ) + r / R
                       2
                                p(r , t ) =                      FL , =  2prp(r , t )dr = pmR 2v / h
                                              2(h + r 2 / R) 2            0                2
Examination of the assumptions in gas-solid systems
                                                                                                                                       R: particle




                                                                  Ratio of lubrication force FL,R/FL,¡Þ
                           10
                                                                                                                                       radius
 Ratio of FL,0 to other forces



                                                                                                          1.0

                                 8                                                                        0.9
                                                   FL,0/Fd
                                 6                                                                        0.8                          h0: initial
                                 4                                                                        0.7                          separation
                                                                                                          0.6
                                 2      FL,0/G
                                                                                                          0.5
                                 0
                                                                                                          0.4
                                     0.01        0.1          1                                              0.0       0.2     0.4      0.6         0.8   1.0
                                                       h0/R                                                             Relative initial distance

                                 Order-of-magnitude estimation                                                     
                                                                                                          FL, =  2prp(r , t )dr
                                                                                                                   0

        • FCC particles: 50mm, v0=ut, at 20C                                                                       R
                                                                                                           FL, R =  2prp(r , t )dr      accurate
                                                                                                                   0
        • Comparison of initial lubrication
        force to other forces
                                                                                                           more reasonable with large
        • Particle radius as “near contact                                                                 lubrication effect area
        area” or “lubrication effect area”
Numerical solutions for pressure distribution
Pressure




                 h0=0.01R                  h0=0. 1R                     h0=R




                         Relative radial distance r/R             numerical
                                                                  analytical with paraboloid
                                                                  approximation


           • Pressure decays to zero much more slowly than that with paraboloid
           approximation
           • Contribution of pressure in the outer region to the lubrication force
           may play an important role
           • Numerical calculations for lubrication force are needed
Avoidance of “Stokes Paradox”

• Assume that minimum surface distance equals to surface roughness
• Whether the fluid remains as a continuum is determined by the relative magnitude
of surface distance to mean free path of fluid molecules

               Case 1: hmin>l0                                                           FL ,num                       h              h
                                                                              K1 (h) =             = 1.041 - 0.281lg     - 0.035 lg 2
                                                                                         FL ,ana                       R              R
                                25
Ratio of lubrication force to




                                                                                                             1  1 
    initial value FL,0 at h0




                                                                                              R       3
                                20            contact                         FL ,ana (h) =  2prpdr = pmR 2v -   
                                                                                             0        2      h h+R
                                15

                                10
                                                    approaching                 Surface roughness of FCC is observed
                                5
                                                                               to be one tenth of particle radius
                                      detaching
                                0
                                0.0      0.2     0.4     0.6    0.8     1.0     Maximum lubrication force is reached
                                 hmin/h0 Ratio of surface distance h/h         when roughness make contact
                                                                      0

              • FCC particle: 50mm, v0=ut/5                                     To realistic particles, stokes paradox is
                                                                               avoided
              • Fluid: Continuum
Avoidance of “Stokes Paradox”

                           Case 2: hmin<l0               • Particles in this case have relatively smaller roughness
                                                         • Non-continuum fluid effect should be
                                                         considered in the last stage of approaching
                                                         • Maxwell slip theory (Hocking 1973) was adopted

                                        v0=ut/2                                              FL ,num, slip                            h              h
                            1E-6                                               K 2 ( h) =                    = 1.309 - 0.082 lg         - 0.009 lg 2
Lubrication force FL (N)




                                                         Non-continuum fluid                 FL ,ana,slip                             R              R
                                            v0=ut/5
                            1E-7                         Continuum fluid
                                                                                                 pmR 2v                   h + 6l0                 h + R + 6l0 
                            1E-8                                               FL ,ana, slip =             (h + 6l0 ) ln  h  - (h + R + 6l0 ) ln  h + R 
                                                                                                                                                               
                                                                                                       2
                                                                                                 12l   0   
                            1E-9                                                                                                      l0>>h
                           1E-10                                                                                               pmR 2v  6l0 
                                                                                                             FL ,ana, slip =          ln    
                                                                                                                                2l0       h 
                           1E-11
                               1E-8     1E-7      1E-6      1E-5       1E-4
                                         Surface distance h (m)                 Increase of lubrication force is slowed
                                                                               down in close approaching distance
                            • GB particle: 50mm, v0=ut/5
                                                                                Treatment of fluid as a non-continuum
                            • Fluid: Non-continuum                             helps us avoid the infinite lubrication force
Avoidance of “Stokes Paradox”

     Case 3: hmin is comparable to Z0

   • When the surface distance can be approached to the dominant range
   of van der Waals force, -----

                    -7       FL                            m
                                                               dv
                                                                  = - F (t ) = -( FL - Fvw )
               2.0x10
                   0.0                                         dt
                    -7   F
                         total                                        AR
               -2.0x10
                               F                           Fvw = -
 Forces F(N)




                                                                               A: Hamaker constant
Forces F (N)




                      -7
               -4.0x10             vw                                12h 2
                      -7
               -6.0x10
               -8.0x10
                      -7
                                                            Magnitude of van der Waals force
                      -6
               -1.0x10                                     increases more rapidly when h -> 0
                      -6
               -1.2x10         hvw
               -1.4x10
                      -6                                    A characteristic distance hvw is
                     1E-10 1E-9 1E-8 1E-7 1E-6 1E-5 1E-4   defined to indicate the adhesive force
                             Surface distance h (m)        dominant region (~10-9m)
               • GB particle: 50mm, v0=ut/10                Consideration of adhesive force in
                                                           the last approaching stage saves us
               • Fluid: Non-continuum                      again from Stokes Paradox
Effective Restitution Coefficient

• Lubrication effect is actually a kind of damping effect, causing kinetic energy
dissipation during both approaching and separating stage
• Restitution coefficient can be regarded as a criterion for evaluating the
lubrication effect on collision process
            *
          Ste                             mv0
   e = 1-               where St =                         Ratio of particle inertia to viscous force
          St                             6pmR 2
                                                 *            *
                                               mvc          mve
   Critical Stokes Number                St =
                                           *
                                                     Ste =
                                                       *
                                                                  = 2Stc
                                                                       *
                                           c
                                              6pmR 2
                                                           6pmR 2




   • vc* is called “critical contact velocity” under which particles cannot make
   contact due to the repulsive lubrication force in the approaching stage
   • ve* is called “critical escape velocity” under which particles cannot escape
   from the lubrication effect area and will cease during the separation stage
                                                   h            2 h            3 h 
                                f1 (h) = 0.962 ln     - 0.079 ln     - 0.004 ln       Case 1
 St = f (h0 ) - f (hmin )
   *
   e
                                                  h+R            h+R            h+R
                                                 2                          2
                                          1   h   6l  1          h+R 
                                                                           ln 1 + 0  - ln 1 +  -
                                                                                   6l            R    R
f(h): characteristic function   f 2 (h) =  6 +  ln 1 + 0  -  6 +
                                                                        h+R                      Case 2,3
                                         36   l0        h  36      l0                   h  6l0
Examples and discussion

                             1.0                                                                     1.0




                                                                         Restitution coefficient e
 Restitution coefficient e




                                         ut                                                                  hmin/h0=1/5
                             0.8                                                                     0.8
                                               ut/5
                             0.6                                                                     0.6
                                      ut/2             ut/20                                                                 hmin/h0=1/10
                                               ut/10
                             0.4                                                                     0.4
                                                          ut/50
                             0.2                              umf                                    0.2                   hmin/h0=1/20
                             0.0                                                                     0.0
                                   20 30 40 50 60 70 80 90 100 110                                     0.1       1          10       100    1000
                                     Diameter of FCC particles dp (mm)                                               Stokes Number St

                                    Case 1: FCC, hmin/h0=1/10                                        Case 1: FCC, different roughness

 Under same approaching velocity, effect of the lubrication force on larger
particles is less significant than on smaller particles
 The independent effects of particle size and approaching velocity on the
coefficient of restitution can be included in the consideration of Stokes numbers
 Collisions with Stokes numbers less than Ste* result in a restitution coefficient
to be zero, consequently causing cluster and agglomeration to occur
Examples and discussion




                                                                          Restitution coefficient e
Restitution coefficient e




                            1.0                                                                       1.0

                            0.8                                                                       0.8

                            0.6                                                                       0.6

                            0.4                                 ut                                    0.4
                                                                                                                                       ut
                            0.2                                 ut /2                                 0.2                              ut /5
                                                                ut /10
                            0.0                                                                       0.0                              ut /20
                                                                ut /50
                                  20 30 40 50 60 70 80 90 100 110                                           20 30 40 50 60 70 80 90 100 110
                                        Diameter of GB d (mm)                                                  Diameter of smooth GB dp (mm)


       Case 2: GB, solid line: with slip, dotted                         Case 3: GB, solid line: with slip and van der
                 line: without slip                                         Waals force, dotted line: without slip

                     Consideration of non-continuum fluid weakens the lubrication effect and thus
                    increases the values of the restitution coefficient
                     The lubrication effect is more significant in case 3 since particles can approach
                    much more closely so that the effect of non-continuum fluid may be more
                    significant
4. Lubrication Force
  Remarks

 By numerically extending classical lubrication
theory into gas-solid systems, semi-empirical
expressions for lubrication force are proposed.
 Evaluation of lubrication effect on collision
process are made according to restitution
coefficient.
 Stokes Paradox is avoided by considering
surface roughness, non-continuum fluid and van
der Waals force.
 Further research should be aiming at
incorporating lubrication force and an effective
restitution coefficient into DEM simulation in the
near contact area.
Industrial Development and
Fundamental Knowledge
Development need each other


Wishing much frequent
Exchange and Collaboration
between Physical/Mechanical
Scientists and Chemical
Engineers
In Japanese very
old folk song
Ryojin-Hisho:
Asobi-wo sen-to-ya
Umare-kem.
(Were’nt we born
for doing fun?)

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040603 Four topics for further development of dem to deal with industrial fluidization issues, ICMF plenary2004

  • 1. Four Topics for Further Development of DEM to Deal with Industrial Fluidization Issues Masayuki Horio and Wenbin Zhang Department of Chemical Engineering, Tokyo University of Agriculture and Technology, Koganei Tokyo, 184-8588 Japan, masa@cc.tuat.ac.jp
  • 2. Come & Visit Tokyo Univ. A&T at Koganei (25min from Shinjuku)
  • 4. From Burton to Fluid Cat. Cracking Chemical Engineers’ Unforgettable Memory The FCC Development (1940-50) Capacity in world total [%]
  • 5. product Competition and Evolution product product of Fluid Catalytic Plants in 1940-50 product steam steam air kerocene kerocene & steam air & steam product kerocene air & steam FCC Plant development air in Catalytic Cracking of kerocene & steam air steam Kerocene(1940-50)
  • 6. Post cloud mdern Era: Natural Science and Engineering Science The presence of column wall makes research much easier hail artificial plant volcanic plateau AIChE Fluor Daniel Lectureship Award Lecture (2001)
  • 7. My background -1974 Fixed/Moving Bed Reactors and iron-making Processes 1974- Fluidization Engineering 75-99 Pressurized Fluidized Bed Combustion Jets, Turbulent Transport in Freeboard 82-89 Scaling Law of Bubbling Fluidized Bed 89-92 Scaling Law of Clustering Suspensions 93- DEM Simulation Waste Management, Material Processes 1997- Sustainability and Survival Issues Biomass Utilization, Appropriate Technology
  • 8. When Professor Tsuji et al. 1993 proposed an excellent idea of applying the concept of discrete/distinct element method of Cundall et al. (1979) to fluidized beds borrowing the fluid phase formulation from the two phase model, I (Horio) almost immediately decided to join in the simulation business of fluidized beds from chemical engineers' view points. This was because with his approach the real industrial issues, such as agglomeration, gas solid reactions and/or heat transfer, can be directly incorporated into the model without the tedious derivation of stochastic mechanics, which is not only indirect but also sometimes impossible from analytical reasons.
  • 9. DEM, the last 10 years DEM: Discrete Element Method Fluid phase: local averaging Particles: semi-rigorous treatment User friendly compared to Two Fluid Model & Direct Navier-Stokes Simulation •A new pressure/tool to reconstruct particle reaction engineering based on individual particle behavior •Potential for more realistic problem definition/ solution Our code development: SAFIRE Simulation of Agglomerating Fluidization for Industrial Reaction Engineering
  • 10. Normal and tangential component of Fcollision and Fwall Fn = k nD x n - h dx n n dt Ft = m Fn x t Ft > m Fn x t Ft = k tD x - h dx t  m Fn t t Ft dt h = 2g g = ( ln e ) 2 km ( ln e ) 2 + p 2 SAFIRE (Horio et al.,1998~) Rupture joint h c Attractive force Fc Surface/bridge force (Non-linear spring) kn Normal dumping h n w/wo Normal Lubrication Normal elasticity No tension joint Tangential dumping h t Tangential elasticity k t SAFIRE is an extended Tsuji-Tanaka model developed by TUAT Horio group Friction slider m w/wo Tangential Lubrication Soft Sphere Model with Cohesive Interactions
  • 11. COMBUSTION Spray Agglomerating AGGLOMERATION Granulation/Coating Fluidization FB w/ Immersed Ash Tubes : Melting FB of Particles w/ Pressure Effect I-H Solid Bridging van der Waals Rong-Horio 1998 Tangential 2000 FB w/ Interaction Kuwagi-Horio Lubrication Immersed Iwadate-Horio Effect 1999 Coal/Waste Tubes 1998 Kuwagi-Horio Combustion Parmanently Rong-Horio 2000 in FBC Wet FB 1999 Mikami,Kamiya, Fluidized Bed DEM Horio Started from 1998 Particle-Particle Dry-Noncohesive Bed Single Char Heat Transfer Tsuji et al. 1993 Combustion Rong-Horio Natural Phenomena in FBC 1999 Rong-Horio OTHER 1999 Lubrication Force Effect SAFIRE Olefine Scaling Law Achievements Polymerization Noda-Horio for DEM Scaling Law for DEM PP, PE Structure of 2002 Computation Computation Kaneko et al. Emulsion Phase Kajikawa-Horio 2000~ Kuwagi-Horio 1999 2002~ Kajikawa-Horio Catalytic Reactions 2001 CHEMICAL REACTIONS FUNDAMENTAL LARGE SCALE SIMULATION
  • 12. AGGLOMERATION Industrial Issues & DEM ■ Agglomerating Fluidization by Liquid Bridging by van der Waals Interaction by Solid Bridging through surface diffusion through viscous sintering by solidified liquid bridge Coulomb Interaction ■ Size Enlargement by Spray Granulation (Spraying, Bridging, Drying) by Binderless Granulation (PSG) ■ Sinter/Clinker Formation in Combustors / Incinerators (Ash melting) in Polyolefine Reactors (Plastic melting) in Fluidized Bed of Particles (Sintering of Fe, Si, etc.) in Fluidized Bed CVD (Fines deposition and Sintering)
  • 13. CHEMICAL REACTORS Industrial Issues & DEM Heat and Mass Transfer gas-particle particle-particle Heterogeneous Reactions Homogeneous Reactions Polymerization Catalytic Cracking (with a big gas volume increase) Partial Combustion (high velocity jet) COMBUSTION / INCINERATION Boiler Tube Immersion Effect Particle-to-Particle Heat Transfer Char Combustion Volatile Combustion (Gas Phase mixing / Reaction) Combustor Simulation
  • 14. 10m m Sintering of 2xneck 2xneck steel particles neck diameter, 2 neck diameter in Fluidized Bed Reduction (a) 923K (b) 1123K Steel shot :dp=200m m, H2, 3600s SEM images of necks 30 Calculated from after 3600s contact 25 surface diffusion model 20 Neck diameter 2x 15 10 d p=200 m m d p=20 m m 5 0 700 800 900 1000 1100 1200 1300 Temperature [K] Neck diameter determined from SEM images after heat treatment in H2 atmosphere Solid Bridging Particles (Mikami et al , 1996)
  • 15. Model for Solid Bridging Particles 1. Spring constant: Hooke type (k=800N/m) Duration of collision: Hertz type 2. Neck growth: Kuczynski’s surface diffusion model 1/ 7 4 56gd 3 x neck = DS rg t kBT Ds = D0,s exp (-Es /RT) -2 5 D0,s =5.2x10 m/s, E =2.21x10 J/mol (T>1180K) 3. Neck breakage Fnc = s neck  Aneck Ftc = t neck  Aneck Kuwagi-Horio Kuwagi-Horio 1999
  • 16. Kuwagi-Horio Steel shot Cross section 6mm 200mm rg = 10mm neck Surface Roughness and Multi-point Contact Kuwagi-Horio 1999
  • 17. 1273K, u 0 = 0.26 m/s, Dt=0.313s Kuwagi-Horio t= 0.438s 0.750s 1.06s 1.38s 1.69s 2.00s 2.31s 2.63s 2.94s 3.25s Snapshots of Solid Bridging Particles without Surface Roughness Kuwagi-Horio 1999
  • 18. dp =200mm, T=1273K, u0 =0.26m/s Kuwag i-Horio (a) Smooth surface (b) 3 micro-contact points (c) 9 micro-contact points (Case 1) (Case 2) (Case 3) Agglomerates (or “dead "dead zones") grown on the wallthe1.21 s). (t = 1.21 s). Fig.7 Agglomerates (or zones”) grown on (t = wall Kuwagi-Horio 2000
  • 19. Intermediate condition Weakest sintering Strongest sintering condition condition (a) Smooth surface (b) 3 micro-contact (c) 9 micro-contact points points Kuwagi-Horio d p =200mm, T=1273K, u 0=0.26m/s Agglomerates Sampled at t = 1.21s Kuwagi-Horio 1999
  • 20. Poly-Olefine Reactor Simulation, Kaneko et al. (1999) fluid cell uy Energy balance Gas phase : ( ) ∂εu T ) ∂ Tg ε ( i g 1 particle + = Q ∂t ∂i x ρcp,g g g ux Particle : vy ε Tg dTp Vpcp,pρp dt H ( = Rp (- Δ r ) - hp Tp - Tg S ) Qg vx Tpn 6(1- ε ) Qg = dp ( hp Tp - Tg ) external gas film E heat transfer hpn Rp = k exp ( ) w cPr RTp coefficient 1 (different for each particle) 1 Nu = 2.0 + 0.6 Pr Rep 3 2 (Ranz-Marshall equation) Nu = hpdp / kg Pr = cp,gμ / kg g Rep = u - v ρdp / μ g g
  • 21. Particle circulation Kaneko et al. 1999 (artificially generated by feeding gas nonuniformly from distributor nozzles) t=9.1 sec t=6.0 sec t=8.2 sec 393 (120℃) 343 293 T [K] (20℃) 2.5umf 2.5umf 2umf 2umf 3umf 3umf 3umf 9.3umf Ethylene polymerization 15.7umf Number of particles=14000 Gas inlet temp.=293 K Hot spot u0=3 umf Tokyo University of Agriculture & Technology Idemitsu Petrochemical Co.,Ltd.
  • 22. Uniform gas feeding Nonuniform gas feeding particle temp. particle velocity particle temp. particle velocity vector vector t=9.1 sec t=8.2 sec : Upward motion 2umf 2umf 3umf 3umf 3umf : Downward motion 15.7umf Stationary circulation Stationary solid revolution helps Petrochemical Co.,Ltd. Tokyo University of Agriculture & Technology Idemitsu the formation of hot spots.
  • 23. A Rough Evaluation of Heat Transfer Between Particles radiation A B 0.4 nm contact point heat transfer A B convection particle-thinned film-particle Rong-Horio 1999 heat transfer when l AB < 2r + d : particle-particle heat conduction
  • 24. Four Topics for Further Development of DEM 1. PSD 2. Large Scale Computation via Similar Particle Assemblage Model 3. Surface Characterization and Reactor Simulation 4. Lubrication Force and Effective Restitution Coefficient
  • 25. PSD Issue Derivation of CD corresponding to Ergun Correlation and A Case Study Master Thesis by Nobuyuki Tagami
  • 26. 1. PSD What We need for moving from Uniform Particle Systems to Non-uniform Ones ○ 3D Computation ○ Contact Model with Particle Size Effect Fookean to Herzean Spring ○ Fluid-Particle Interactions Today’s topic 1) not from Ergun (1952) Correlation 2) not indifferent to particle arrangement
  • 27. 1. PSD Apparent Drag Coefficient that corresponds to Ergun Correlation (1) Bed Pressure Drop Correlation (Ergun(1952)) ΔP * /DL = ΔP/ΔL - ρ f g = (1 - ε ) 150 (1 - ε )μ f ( )  + 1.75ρ f u - v  u - v d p : Particle diameter  ε : Void fraction d p   d p   ρ f : Fluid density (2) Equation of motion for fluid (1D) u : Fluid velocity ΔP ( ) v : Particle velocity -ε - nFpf + ερ f g = 0 n = (1 - ε )/ πd p 3 /6 ΔL (3) Drag Coeff. 8 F pf → Apparent Drag Coeff. CD  200(1 - ε )μ f p d p ρf u - v 2 2 C D, Ergun = + 2.33 d pρ f ε u - v
  • 28. 1. PSD Extension of CD,Ergun 200(1 - ε )μ f C D,Ergun = + 2.33 d pρ f ε u - v 200(1 - ε )μ f C D,Ergun = + 2.33 d pρ f ε u - v
  • 29. 1. PSD The Sum of Drag Force Consistent with Ergun Correlation ? Error was within the Accuracy of dp1/dp2 Number of Ergun Correlation ±25%. F i,C D,Ergun [mm/mm] particles Binary System Fi,Ergun 1.00 30000 1.50 / 4444 / 0.750 35556 1.25 ρ p = 2650kg/m 3 1.00 ρ f = 1.204kg/m 3 μ f = 18 μ Pa s 0.75 u 0 = 0.811  1.122m/s (t  0.5s) = 1.122m/s (t  0.5s)
  • 30. 1. PSD PSD Effect: A Case Study Run1 Run2 Run3 Diameter [mm] 3.00 4.50/3.00/2.25 4.50/2.25 Number [#] 30000 2963/10000/23703 4444/35556 Vol. Fraction 1 0.333/0.333/0.333 0.500/0.500 Surface to Volume Mean Diameter: dsv=Σ(Ndp3)/Σ(Ndp2) = 3.00 mm Total solid volume = 4.24×10-4m3, Total solid surface area = 8.48×10-1m2 Young’s modulus: 80GPa, Poisson ratio: 0.3, friction coefficient: 0.3 (Glass beads) Contact Force Model Normal:Hertz’ Model Tangential: ‘no-slip’ Solution of Mindlin, and Deresiewicz (1953)
  • 31. Comparison of the three cases Run 1 Run 2 Run 3 3.00mm 4.50 / 3.00 / 2.25 4.50 / 2.25 mm mm u0 = 1.438→2.938m/s (t<1sec), u0 = 2.938m/s (t≧1sec)
  • 32. 1. PSD Run3 Large particles become more mobile receiving forces from smaller ones
  • 33. 2. SPA Fluidization XI, May 9-14, 2004, Ischia (Naples), Italy The Similar Particle Assembly (SPA) Model, An Approach to Large-Scale Discrete Element (DEM) Simulation Kuwagi K.a, Takeda H.b and Horio M.c,* aDept. of Mech. Eng., Okayama University of Science, Okayama 700-0005, Japan bRflow Co., Ltd., Soka, Saitama 340-0015, Japan cDept. of Chem. Eng., Tokyo University of Agri. and Technol., Koganei, Tokyo 184-8588, Japan
  • 34. Development of Computer Pormance 1.0E+16 Fastest computer models Nishikawa et al. (1995) Performance [MFLOPS] Seki (2000) 1.0E+13 Oyanagi(2002) 15 to 20 years Single processor for PC 1.0E+10 Moore's Law 1.0E+7 1.0E+4 1.0E+1 1,940 1,960 1,980 2,000 2,020 Year
  • 35. 2. SPA How to deal with billions of particles? TFM (Two-fluid model) DSMC (Direct Simulation Monte Carlo) Difficult to deal with realistic particle-particle and particle-fluid interactions including cohesiveness DEM (Discrete Element Method) One million or less particles with PC in a practical computation time Hybrid model of DEM and TFM (Takeda & Horio, 2001) Similarity condition for particle motion (Kazari et al., 1995) Imaginary sphere model (Sakano et al., 2000)
  • 36. 2. SPA Similar Particle Assembly (SPA) Model Assumptions (0. Particles are spherical) 1. A bed consists of particles of different species having different properties, i.e. particle size, density and chemical composition, and it has some local structure of their assembly. 2. Of each group (species) N particles are supposed to be represented by one particle at the center of them. This center particle is called a representative particle for the group. 3. The representative particles for different groups can conserve the local particle assembly similar.
  • 37. m times larger system (a) (b) of the same particles as the smaller bed A particle Represented volume for N particles Similar structure (c) + (d) + + + + i +x + + x+Dx i’ x x+mDx original system m times larger system Particle Coordination Scaling
  • 38. 2. SPA Preparation (1) All particles are numbered: i=1~NT. (2) Subspace: ( Gk  d p ,  p ) (3) Group number of particles: (( ) ki  k d pi ,  pi  Gk ) (4) Equation of motion for particle i:  p 3  dv i p 3   pi  d pi  = Ffi +  Fpij +  pi  d pi g 6  dt j i 6  Ffi: particle-fluid interaction force Fpij: particle-particle interaction force
  • 39. 2. SPA Governing Equations Equation of motion for original particle:  p 3  dv i p 3   pi  d pi  = Ffi +  Fpij +  pi  d pi g 6  dt j i 6  Equation of motion for m-times larger volume:  p 3  dv i ' p 3   pi '  d pi '  = Ffi ' +  F pi ' j ' +  pi '  d pi '  g * * 6  dt j ' i ' 6  where d pi ' = md pi  p 3  dv i ' p 3  m  pi '  d pi '  3 = Ffi ' +  F pi ' j ' + m  pi '  d pi ' g * * 3 6  dt j ' i ' 6    If F +* fi ' F * pi ' j ' = m  Ffi +  F pij 3    , v i' = v i j ' i '  j i    (1 -  )2 m f (u - v)  f (u - v) u - v   FPi = 150 + 1.75(1 - )  Ncell    2 d pi d pi   p Fpi =  CD f  2 (u - v l ) u - v l d pi 2 8
  • 40. Computation Conditions for Case 1 Particles Geldart Group: D Particle diameter: dp [mm ] (a) 1.0 (b) 3.0 (c) 6.0 Particle density: p [ kg/m3 ] 2650 Number of Particles (a) 270,000 (b) 30,000 (c) 7,500 Restitution coefficient 0.9 Friction coefficient 0.3 Spring constant: k [ N/m ] 800 (Dt=2.58x10-5s) Bed Column size 0.5×1.5m Distributor Porous medium Gas Air Viscosity: mf [Pa.s ] 1.75x10-5 Density: f [kg/m3 ] 1.15
  • 41. 0.262s 0.528s 0.790s 1.05s 1.31s 1.58s 1.84s 2.10s 2.36s 2.62s (a) Original bed (dp=1.0mm) (b) SPA bed (representative particle, dp’=3.0mm) (c) SPA bed (representative particle, dp’=6.0mm) Snapshots of Dry Particles
  • 42. p=2650kg/m3, Column : 0.5×1.5m, u0=1.2m/s of lower half set particles [m] 0.4 d p =1.0mm (Original bed) Dry (fluid cell: 134x333) 0.3 Average height 0.2 d p =1.0mm (Original bed) d p' =3.0mm (SPA bed) d p' =6.0mm (SPA bed) 0.1 (fluid cell: 22x56) u0: increasing u0: decreasing0 decreasing U + 0 0 1 2 3 4 5 Time [s] Average height of dry particles initially located in the half lower region
  • 43. 0.262s 0.528s 0.790s 1.05s 1.31s 1.58s 1.84s 2.10s 2.36s 2.62s (a) Original bed (dp=1.0mm) (b) SPA bed (representative particle, dp’=3.0mm) (c) SPA bed (representative particles, dp’=6.0mm) Snapshots of Wet Particles (V=1.0x10-2)
  • 44. p=2650kg/m3, Column : 0.5×1.5m, u0=1.2m/s of lower half set particles [m] 0.4 d p =1.0mm (Original bed) Wet (fluid cell: 134x333) 0.3 Average height 0.2 d p' =6.0mm (SPA bed) d p' =3.0mm (SPA bed) 0.1 d p =1.0mm (Original bed) (fluid cell: 22x56) u0: increasing decreasing U u0: decreasing0 + 0 0 1 2 3 4 5 Time [s] Average height of wet particles initially located in the half lower region
  • 45. 2. SPA 10,000 10,000 Umf = 0.72m/s dry wet (V=1.0x10-2) 8,000 8,000 Umf = 0.70m/s DP [Pa] DP [Pa] 6,000 6,000 4,000 d p =1.0mm 4,000 d p =1.0mm d p'=3.0mm d p' =3.0mm 2,000 2,000 d p' =6.0mm d p' =6.0mm 0 0 0 0.2 0.4 0.6 0.8 1 1.2 1.4 0 0.2 0.4 0.6 0.8 1 1.2 1.4 U0 [m/s] U0 [m/s] (a) Dry particles (b) Wet particles Umf from Wen-Yu correlation = 0.57m/s Comparisons of umf
  • 46. 2. SPA CPU time for real 1s on Pentium 4 2.66GHz Dry [s] Wet [s] Original bed 27,300 27,600 (dp=1mm) (7hrs 34min) (7hrs 39min) SPA bed 1,760 1,870 (dp’=3mm) (29min) 1/15 (31min) 1/15 SPA bed 426 508 (dp’=6mm) (7min) 1/64 (8min) 1/55
  • 47. Computation Conditions for Case 2 Single bubble fluidization of two-density mixed particles Column 0.156x0.390m p=3000kg/m3 Nozzle width 4mm p=2000kg/m3 Particle (original) dp 1.0mm p 2000, 3000 kg/m3 Gas Air f 1.15kg/m3 0.7m/s 0.7m/s mf 1.75x10-5Pa.s 15m/s (0.482s) Fig: Initial state
  • 48. p=3000kg/m3 p=2000kg/m3 t=0.056s t=0.111s t=0.167s t=0.223s t=0.278s (a) dp=1.0mm (original bed) (b) dp’=2.0mm (SPA bed) Single Bubble Behavior of Two-Density Particles
  • 49. p=3000kg/m3 p=2000kg/m3 t=0.278s t=0.557s t=0.835s t=1.114s t=1.392s (a) dp=1.0mm (original bed) (b) dp’=2.0mm (SPA bed) Single Bubble Behavior of Two-Density Particles
  • 50. Z 0.14 SPA model 0.14 SPA model [m] 0.12 0.12 0.12 0.10 0.1 0.1 0.08 0.08 0.08 Original bed z [m] Original bed 0.06 0.06 0.06 0.04 0.04 0.04 Bubble region 0.02 0.02 0.02 (No particles exist.) 0 0 0 0.5 1 1.5 2 2.5 0 0 0.05 0.1 0.15 0.2 0.25 0.3 (a) t=0.056s Gas velocity [m/s] Particle velocity averaged in each fluid cell [m/s] Z 0.14 0.14 [m] SPA model 0.12 0.12 0.12 Original bed 0.10 0.1 0.1 Original SPA 0.08 z [m] 0.08 bed 0.08 model 0.06 0.06 0.06 0.04 0.04 0.04 0.02 0.02 0.02 0 0 0 0.5 1 1.5 2 2.5 3 0 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 Gas velocity [m/s] Particle velocity averaged (b) t=0.111s in each fluid cell [m/s] Vertical velocity distributions of particle and gas phases along the center line
  • 51. 2. SPA SPA concept: promising. Similar Particle Assembly (SPA) model for large-scale DEM simulation Validations (comparisons with the original) Non-cohesive particles >Slug flow occurred at the beginning of fluidization: similar >Bubble diameter: almost the same >Bubble shape: not clear with large representing volume >Umf: fair agreement Cohesive particles: the same tendency as the above Binary (density) System: >Bubble: similar >Particle mixing: similar
  • 52. 3. More Realistic Surface Characterization Measurement of Stress-Deforemation Characteristics for a Polypropylene Particle of Fluidized Bed Polymerization for DEM Simulation M. Horio, N. Furukawa*, H. Kamiya and Y. Kaneko *) Idemitsu Petrochemicals Co.
  • 53. Computation conditions Particles Number of particles nt 14000 Particle diameter dp 1.0×10-3 m Restitution coefficient e 0.9 Friction coefficient μ 0.3 Spring constant k 800 N/m Bed Bed size 0.153×0.383 m Types of distributor perforated plate Gas velocity 0.156 m/s (=3Umf) Initial temperature 343 K Pressure 3.0 MPa Numerical parameters Number of fluid cells 41×105 Time step 1.30×10-5 s
  • 54. 0 7 15 ΔT [K] Snapshots of temperature distribution in PP bed (without van der Waals force)
  • 55. Ha = 5×10-20 J Ha = 5×10-19 J 0 7 15 ΔT [K] Snapshots of temperature distribution in PP bed (with van der Waals force)
  • 56. 3. Surface Characterization Experimental determination of repulsion force
  • 57. 3. Surface Characterization Catalyst TiCl3 0.35 Pressure 0.98 MPa 0.3 Diameter[mm] Temperature 343 K 0.25 Reactor stage φ14 mm 0.2 0.15 0.1 0.05 0 0 10 20 30 40 50 60 Time [min] PP growth with time The micro reactor 0 min 1 min 2 min 5 min 10 min 15 min 20 min 30 min 60 min Optical microscope images Polymerization in a Micro Reactor
  • 58. 3. Surface Characterization 1: material testing machine’s 10 stage 2: electric balance 9 3: table 7 8 4: polypropylene particle 5: aluminum rod 6 5 6: capacitance change 1 4 3 7: micro meter 2 8: nano-stage 9: x-y stage 1 10: cross-head of material testing machine Force-displacement meter
  • 59. k ~100 N/m Fdp0.5x1.5 (Hertzean spring) 10 -3 10-3 10-3 dp = 597μm dp = 597μm dp = 597μm 3rd 10-4 10-4 10-4 Force [N] Force [N] Force [N] 2nd 3rd 10-5 10-5 10-5 2nd 2nd 2nd 1st 1st 1st 10-6 10-6 10-6 10 -8 10-7 10 -6 10 -5 10 -8 10-7 10 -6 10 -5 10 -8 10 -7 10-6 10-5 Displacement [m] Displacement [m] Displacement [m] x dp=597mm FE-SEM images: whole grain and its surface Repeated force-displacement characteristics of a polypropylene particle
  • 60. Fdp0.5x1.5 (Hertzean spring) 10 -3 10-3 10-3 dp = 487μm dp = 487μm dp = 487μm 10 -4 10-4 10-4 3rd Force [N] Force [N] Force [N] 3rd 2nd 10 -5 1st 10-5 10-5 2nd 1st 1st 2nd 2nd 1st 1st 1st 10 -6 10-6 10-6 10-8 10 -7 10 -6 10 -5 10 -8 10-7 -6 10 10 -5 10-8 10-7 10-6 10 -5 Displacement [m] Displacement [m] Displacement [m] x dp=487mm FE-SEM images: whole grain and its surface Repeated force-displacement characteristics of a polypropylene particle (maximum load from first cycle)
  • 61. 3. Surface Characterization FE-SEM image of the top particle after three times pressing
  • 62. 3. Surface Characterization Particle surface morphology changes by collisions Plastic deformation in the case of PP Hertz model stands OK Experimental Determination of Cohesion Force: Now on going
  • 63. 4. Lubrication Force Lubrication Force and effective Restitution Coefficient W. Zhang, R. Noda and M. Horio Submitted to Powder Technology
  • 64. 4. Lubrication Force Restitution Spring constant coefficient ? ? Heat transfer, agglomeration Realistic collision process Fluidization behavior ‘Near Contact’ force: Interparticle forces Lubrication force Field force: Contact force: Electrostatic Van der Waals force force Liquid and solid bridge force Impact force
  • 65. 4. Lubrication Force Classical lubrication theory For Liquid-Solid Systems; Tribology, filtration etc. Why not in Gas-solid systems?  Lubrication force negligible ?  Introduction of “Stokes Paradox” ? Two solid surfaces can never make contact in a finite time in any viscous fluid due to the infinite lubrication force when surface distance approaches zero Can we avoid the paradox practically or essentially?
  • 66. Davies’ development of lubrication theory to gas-solid systems dh = -v(t ) = -(v1 + v2 ) v1 dt dv m = -F (t ) = - FL dt r H(r,t) h(0,t) p(r,t) • identical and elastic • head-on collision v2 • rigid during approaching Assumptions in classical lubrication theory  Initial gap size h0 is assumed to be much smaller than particle radius  Upper limit of integration of pressure for lubrication force is extended to infinity  Paraboloid approximation of undeformed surface  Fluid is treated as a continuum 3mRv  3 H (r , t ) = h(0, t ) + r / R 2 p(r , t ) = FL , =  2prp(r , t )dr = pmR 2v / h 2(h + r 2 / R) 2 0 2
  • 67. Examination of the assumptions in gas-solid systems R: particle Ratio of lubrication force FL,R/FL,¡Þ 10 radius Ratio of FL,0 to other forces 1.0 8 0.9 FL,0/Fd 6 0.8 h0: initial 4 0.7 separation 0.6 2 FL,0/G 0.5 0 0.4 0.01 0.1 1 0.0 0.2 0.4 0.6 0.8 1.0 h0/R Relative initial distance Order-of-magnitude estimation  FL, =  2prp(r , t )dr 0 • FCC particles: 50mm, v0=ut, at 20C R FL, R =  2prp(r , t )dr accurate 0 • Comparison of initial lubrication force to other forces more reasonable with large • Particle radius as “near contact lubrication effect area area” or “lubrication effect area”
  • 68. Numerical solutions for pressure distribution Pressure h0=0.01R h0=0. 1R h0=R Relative radial distance r/R numerical analytical with paraboloid approximation • Pressure decays to zero much more slowly than that with paraboloid approximation • Contribution of pressure in the outer region to the lubrication force may play an important role • Numerical calculations for lubrication force are needed
  • 69. Avoidance of “Stokes Paradox” • Assume that minimum surface distance equals to surface roughness • Whether the fluid remains as a continuum is determined by the relative magnitude of surface distance to mean free path of fluid molecules Case 1: hmin>l0 FL ,num h h K1 (h) = = 1.041 - 0.281lg - 0.035 lg 2 FL ,ana R R 25 Ratio of lubrication force to 1 1  initial value FL,0 at h0 R 3 20 contact FL ,ana (h) =  2prpdr = pmR 2v -  0 2 h h+R 15 10 approaching  Surface roughness of FCC is observed 5 to be one tenth of particle radius detaching 0 0.0 0.2 0.4 0.6 0.8 1.0  Maximum lubrication force is reached hmin/h0 Ratio of surface distance h/h when roughness make contact 0 • FCC particle: 50mm, v0=ut/5  To realistic particles, stokes paradox is avoided • Fluid: Continuum
  • 70. Avoidance of “Stokes Paradox” Case 2: hmin<l0 • Particles in this case have relatively smaller roughness • Non-continuum fluid effect should be considered in the last stage of approaching • Maxwell slip theory (Hocking 1973) was adopted v0=ut/2 FL ,num, slip h h 1E-6 K 2 ( h) = = 1.309 - 0.082 lg - 0.009 lg 2 Lubrication force FL (N) Non-continuum fluid FL ,ana,slip R R v0=ut/5 1E-7 Continuum fluid pmR 2v   h + 6l0   h + R + 6l0  1E-8 FL ,ana, slip = (h + 6l0 ) ln  h  - (h + R + 6l0 ) ln  h + R      2 12l 0  1E-9 l0>>h 1E-10 pmR 2v  6l0  FL ,ana, slip = ln   2l0  h  1E-11 1E-8 1E-7 1E-6 1E-5 1E-4 Surface distance h (m)  Increase of lubrication force is slowed down in close approaching distance • GB particle: 50mm, v0=ut/5  Treatment of fluid as a non-continuum • Fluid: Non-continuum helps us avoid the infinite lubrication force
  • 71. Avoidance of “Stokes Paradox” Case 3: hmin is comparable to Z0 • When the surface distance can be approached to the dominant range of van der Waals force, ----- -7 FL m dv = - F (t ) = -( FL - Fvw ) 2.0x10 0.0 dt -7 F total AR -2.0x10 F Fvw = - Forces F(N) A: Hamaker constant Forces F (N) -7 -4.0x10 vw 12h 2 -7 -6.0x10 -8.0x10 -7  Magnitude of van der Waals force -6 -1.0x10 increases more rapidly when h -> 0 -6 -1.2x10 hvw -1.4x10 -6  A characteristic distance hvw is 1E-10 1E-9 1E-8 1E-7 1E-6 1E-5 1E-4 defined to indicate the adhesive force Surface distance h (m) dominant region (~10-9m) • GB particle: 50mm, v0=ut/10  Consideration of adhesive force in the last approaching stage saves us • Fluid: Non-continuum again from Stokes Paradox
  • 72. Effective Restitution Coefficient • Lubrication effect is actually a kind of damping effect, causing kinetic energy dissipation during both approaching and separating stage • Restitution coefficient can be regarded as a criterion for evaluating the lubrication effect on collision process * Ste mv0 e = 1- where St = Ratio of particle inertia to viscous force St 6pmR 2 * * mvc mve Critical Stokes Number St = * Ste = * = 2Stc * c 6pmR 2 6pmR 2 • vc* is called “critical contact velocity” under which particles cannot make contact due to the repulsive lubrication force in the approaching stage • ve* is called “critical escape velocity” under which particles cannot escape from the lubrication effect area and will cease during the separation stage  h  2 h  3 h  f1 (h) = 0.962 ln   - 0.079 ln   - 0.004 ln   Case 1 St = f (h0 ) - f (hmin ) * e h+R h+R h+R 2 2 1  h   6l  1  h+R   ln 1 + 0  - ln 1 +  - 6l R R f(h): characteristic function f 2 (h) =  6 +  ln 1 + 0  -  6 +       h+R   Case 2,3 36  l0  h  36  l0    h  6l0
  • 73. Examples and discussion 1.0 1.0 Restitution coefficient e Restitution coefficient e ut hmin/h0=1/5 0.8 0.8 ut/5 0.6 0.6 ut/2 ut/20 hmin/h0=1/10 ut/10 0.4 0.4 ut/50 0.2 umf 0.2 hmin/h0=1/20 0.0 0.0 20 30 40 50 60 70 80 90 100 110 0.1 1 10 100 1000 Diameter of FCC particles dp (mm) Stokes Number St Case 1: FCC, hmin/h0=1/10 Case 1: FCC, different roughness  Under same approaching velocity, effect of the lubrication force on larger particles is less significant than on smaller particles  The independent effects of particle size and approaching velocity on the coefficient of restitution can be included in the consideration of Stokes numbers  Collisions with Stokes numbers less than Ste* result in a restitution coefficient to be zero, consequently causing cluster and agglomeration to occur
  • 74. Examples and discussion Restitution coefficient e Restitution coefficient e 1.0 1.0 0.8 0.8 0.6 0.6 0.4 ut 0.4 ut 0.2 ut /2 0.2 ut /5 ut /10 0.0 0.0 ut /20 ut /50 20 30 40 50 60 70 80 90 100 110 20 30 40 50 60 70 80 90 100 110 Diameter of GB d (mm) Diameter of smooth GB dp (mm) Case 2: GB, solid line: with slip, dotted Case 3: GB, solid line: with slip and van der line: without slip Waals force, dotted line: without slip  Consideration of non-continuum fluid weakens the lubrication effect and thus increases the values of the restitution coefficient  The lubrication effect is more significant in case 3 since particles can approach much more closely so that the effect of non-continuum fluid may be more significant
  • 75. 4. Lubrication Force Remarks  By numerically extending classical lubrication theory into gas-solid systems, semi-empirical expressions for lubrication force are proposed.  Evaluation of lubrication effect on collision process are made according to restitution coefficient.  Stokes Paradox is avoided by considering surface roughness, non-continuum fluid and van der Waals force.  Further research should be aiming at incorporating lubrication force and an effective restitution coefficient into DEM simulation in the near contact area.
  • 76. Industrial Development and Fundamental Knowledge Development need each other Wishing much frequent Exchange and Collaboration between Physical/Mechanical Scientists and Chemical Engineers
  • 77. In Japanese very old folk song Ryojin-Hisho: Asobi-wo sen-to-ya Umare-kem. (Were’nt we born for doing fun?)