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April 8, 2013

                  Today:

  Khan Academy Topics for the Week:
 Solving Quadratics by Taking the Square Root
   **Graphing Parabolas in Standard Form
             Warm-Up (7)
Using Square Roots to Solve Quadratics
Warm-Up/Review:
1. Find the axis of symmetry, vertex, and graph the function
Warm-Up/Review:
2. Find the zeros of the function
Warm-Up/Review:
Write a Quadratic Equation Given Roots
Write a Quadratic Equation Given Roots
If all you had were the roots of a quadratic equation.
Could you write the equation that produced the roots?
The roots of a quadratic equation are -2 and 6. Write a
quadratic model with leading coefficient of 1.
 Work backwards: start with your answer
 x = -2      or x = 6      solutions/roots
    x + 2 = 0 or x – 6 = 0   equation for roots
 (x + 2)(x - 6) = 0        quadratic equation
 x² - 6x + 2x – 12 = 0     distribute using FOIL
  x² - 4x – 12 = 0         combine like terms
                This is the quadratic equation with roots {-2, 6}
Write a Quadratic Equation Given Roots

The roots of a quadratic equation are 7 and - 1. Write a
quadratic model with leading coefficient of 1.
 x=7       or     x=-1        solutions/roots
  x - 7 = 0 or x + 1 = 0     equation for roots

x² - 6x – 7 = 0            combine like terms
Write a Quadratic Equation Given Roots

  A parabola crosses the y axis at -3 and 1.
a. Write a quadratic function with a leading
   coefficient of 1. b. Graph the resulting parabola.
 y2 + 2y - 3
 Vertex is: -4,-1
Axis of Symmetry is: -4,-1
Plot for y = 2, then graph                •    •
                                     •
                                          •    •
Take the square root of
both sides

2. Graph the function.

Change the equation to:
y=
The solution is usually
                    further simplified by
                    "rationalizing the
                    denominator." This is
                    done by removing the
                    square root from the
                    denominator. How can we
                    make thedenominator 5?
Always factor out
perfect squares
Determining the Number of Solutions
April 9, 2013

                 Today:

         Reminder: Khan Academy
               Warm-Up

Using Square Roots to Solve Quadratics:
    Roots & Radicals by the Rules
Practice Questions for Tests/Finals
(4)
Class Work

   10-2: Simplifying Radical Expressions

Ladies: Do even numbered Problems
Gentlemen: Odd numbered Problems

             Show All Work!!
Warm-Up/Review:

A batter smashed a fastball high into the gap between
left and center fields. The path of the ball is shown
by the equation y = -.2x2 + .5x. This allowed the center
fielder enough time to run and make the catch. How
high was the ball hit?

     -1/.02 = 50; x = 50

   Substitute 50 for x; y =
     y=
Warm-Up/Review:

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April 8

  • 1. April 8, 2013 Today: Khan Academy Topics for the Week: Solving Quadratics by Taking the Square Root **Graphing Parabolas in Standard Form Warm-Up (7) Using Square Roots to Solve Quadratics
  • 2. Warm-Up/Review: 1. Find the axis of symmetry, vertex, and graph the function
  • 3. Warm-Up/Review: 2. Find the zeros of the function
  • 5. Write a Quadratic Equation Given Roots
  • 6. Write a Quadratic Equation Given Roots If all you had were the roots of a quadratic equation. Could you write the equation that produced the roots? The roots of a quadratic equation are -2 and 6. Write a quadratic model with leading coefficient of 1. Work backwards: start with your answer x = -2 or x = 6 solutions/roots x + 2 = 0 or x – 6 = 0 equation for roots (x + 2)(x - 6) = 0 quadratic equation x² - 6x + 2x – 12 = 0 distribute using FOIL x² - 4x – 12 = 0 combine like terms This is the quadratic equation with roots {-2, 6}
  • 7. Write a Quadratic Equation Given Roots The roots of a quadratic equation are 7 and - 1. Write a quadratic model with leading coefficient of 1. x=7 or x=-1 solutions/roots x - 7 = 0 or x + 1 = 0 equation for roots x² - 6x – 7 = 0 combine like terms
  • 8. Write a Quadratic Equation Given Roots A parabola crosses the y axis at -3 and 1. a. Write a quadratic function with a leading coefficient of 1. b. Graph the resulting parabola. y2 + 2y - 3 Vertex is: -4,-1 Axis of Symmetry is: -4,-1 Plot for y = 2, then graph • • • • •
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  • 11. Take the square root of both sides 2. Graph the function. Change the equation to: y=
  • 12. The solution is usually further simplified by "rationalizing the denominator." This is done by removing the square root from the denominator. How can we make thedenominator 5? Always factor out perfect squares
  • 13. Determining the Number of Solutions
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  • 15. April 9, 2013 Today: Reminder: Khan Academy Warm-Up Using Square Roots to Solve Quadratics: Roots & Radicals by the Rules
  • 16. Practice Questions for Tests/Finals
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  • 27. Class Work 10-2: Simplifying Radical Expressions Ladies: Do even numbered Problems Gentlemen: Odd numbered Problems Show All Work!!
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  • 29. Warm-Up/Review: A batter smashed a fastball high into the gap between left and center fields. The path of the ball is shown by the equation y = -.2x2 + .5x. This allowed the center fielder enough time to run and make the catch. How high was the ball hit? -1/.02 = 50; x = 50 Substitute 50 for x; y = y=