1. Ejemplo 1
R= 280
E= 6.20
PI = 0+580
E= r(sec (α/2) -1)
6.2/280=sec(d/2)-1
0.02217+1 = sec(α/2)
1.02214=(1/cos(α/2)
α/2= arcos(0 .98)
α=23.89=23°53°38.29°
Lc= 2πrα/360
Lc=( π*280*23.89)/180
Lc= 116.749
Subtang E = Rtang (α/2)
Subtang E =280tang(11.95)
Subtang E =59.21m
M= R(1-cos(α/2))
M=280(1-cos11.95))
M=6.07m
Pc=0+580.63-59.21 =0+521.42
Pt=0+521.42+116.75= 638.17

2. Ϫ О L parc L Acumula α Parc α Acumula
Pc 0+521.42
540 18.58 18.58 1°54°4.63° 1°54°4.63°
560 20 38.58 2°2°47.73° 3°56°52.36°
580 20 58.58 2°2°47.73° 5°59°40.09°
600 20 78.58 2°2°47.73° 8°2°27.82°
620 20 98.58 2°2°47.73° 10°5°15.55°
638.17 18.17 116.75 1°51°33.59° 11°10°49.14°
Ejemplo 2
E=7.2m
M=6.8m
Pi= 6+310.08
M= R(1-cos(α/2))
E= r(sec (α/2) -1)
M/(1-cos(α/2))= E/(sec (α/2) -1)
M/E= Cos(α/2)
6.8/7.2= cos (α/2)
α=2*19.88
α=38°22°34.58°
Subtang E = Rtang (α/2)
Subtang E =122.4 *tg19.188
Subtang E =42.60m
Lc= 2πrα/360= 38°22°34.58°*122.4*π= 81.98
Cp=22rsen(α/2)
Cp=2*122.4sen(38°22°34.58°/2)
Cp=80.46m

3. Ϫ О L parc L Acumula α Parc α Acumula
Pc 6+267.48
6+280 12.52 12.52 2°55°49.5° 2°55°49.5°
6+300 20 32.52 4°40°52.23° 7°36°41.73
6+320 20 52.52 4°40°52.23° 12°17°33.96
6+340 20 72.52 4°40°52.23° 16°58°26.19
6+349.46 9.46 81.98 2°12°51.1° 19°11°17.29