As a JavaScript developer you must have used the typeof and the instanceof operator sometime in your code to detect the the type of a variable in your program logic. And most often or not you might have been confused with the different results that show up while expecting a desired result. In this post I am gonna show you an easy technique to determine the type and instance of a variable. Let’s see some examples first. For the full post download this file or visit the actual blog post link: http://jbkflex.wordpress.com/2013/05/09/javascript-typeof-and-instanceof-the-concept-and-differences/

1. JavaScript typeof and instanceof –
the concept and differences
For the actual blog post link visit : http://jbkflex.wordpress.com/2013/05/09/javascript-typeof-and-
instanceof-the-concept-and-differences/
As a JavaScript developer you must have used the typeof and the instanceof operator sometime in your code to
detect the the type of a variable in your program logic. And most often or not you might have been confused with
the different results that show up while expecting a desired result. In this post I am gonna show you an easy
technique to determine the type and instance of a variable. Let’s see some examples first.
The typeof operator
var str1 = "Hello, how are you?";
typeof str1;
Output: "string"
So, we have a string literal str1, and when we find the typeof str1, it gives “string”. Remember string is a primitive
data type in JavaScript. Let’s see another example,
var str2 = new String("I am doing good. Thank you!");
typeof str2;
Output: "object"
Now, we have a String Object and we have created an instance of that Object using the new operator, which is str2.
Now if we do a typeof, it gives object. Remember that in JavaScript, other than the primitive data types (and null,
undefined, function), everything else is an Object. So as expected you get the type as object.
Now, let’s work with Array’s and try the same thing,
var arr1 = [2,3,4]; //defining an array literal
typeof arr1;
Output: "object"

2. var arr2 = new Array(4,5,6); //creating an Array Object instance
typeof arr2;
Output: "object"
Firstly, we have an Array literal – arr1 and if we do a typeof it gives “object”. Why? Since Array’s are Objects and
they are not part of the primitive data set.
The next example is more obvious, we create an Array Object instance – arr2, and then do a typeof. As expected we
get a “object”. So we have seen, if the typeof does not return a primitive data type (which are number, boolean,
string), it will return an object. There are some special cases though, look at the bottom of this page to find out.
The instanceof operator
Now let’s take up some examples of the instanceof operator.
var str1 = "Hello, how are you?"; //defining a string literal, same as above
str1 instanceof String;
Output: false
If you see above, we have a string literal and when we do a instanceof to check if the variable is an instance of the
String Object, it returns false. Since a string literal belongs to the string primitive data type. Now, consider the
example below,
var str2 = new String("I am doing good. Thank you!"); //defining a String
object instance
str2 instanceof String;
Output: true
Here, str2 is actually an instance, so the test returns true.
But What’s up with the Array’s though? Let’s see,
var arr1 = [2,3,4]; //defining an array literal
arr1 instanceof Array;
Output: true

3. var arr2 = new Array(4,5,6); //creating an Array Object instance
arr2 instanceof Array;
Output: true
Both returns true as both arr1 and arr2 are Array objects and they are not part of the primitve data set.
In fact the following test also returns true
arr1 instanceof Object;
Output: true
arr2 instanceof Object;
Output: true
This is because the Array object inherits from the more generic Object object. (Yes, you heard it right Object
object!).
Still confused about finding types and instances? Here is the rule to do it easily.
Rule for the test
So, how do you guess if a variable is an instance of its Object or Type. Here is the rule,
1) First check the type of the variable using typeof.
2) Now do the instanceof test.
3) a) If the typeof test returns a primitive type – number, boolean, string. Then instanceof test will return false.
Because these are just primitive type data. They are not instances of any Object.
b) But if typeof returns an object, then instanceof test will return true. So you know that you are dealing with
objects and instances.
For eg.
var regexp = /d{3}/; //define a regular expression object
typeof regexp; -> "object", not a primitive type

4. regexp instanceof RegExp; -> true
regexp instanceof Object; -> true
Take another,
var str = "Hello, me again!";
typeof str; -> "string" , a primitive type
str instanceof String; -> false
Now, you can think of some examples and put the rule to a test.
Special cases
1) typeof null = “object” , since null is a special value in JavaScript which represents emptyness and it does not
have any type.
2) typeof undefined = “undefined”, as expected
3) typeof NaN = number, since NaN is actually a special number, although it says Not a Number. Confusing? Just
keep in mind.
4) typeof Function = “function”
5) typeof xmlObj = “xml”
References
1) typeof operator : https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Operators/typeof
2) instanceof operator: https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Operators/instanceof