1. Determine los valores de las intensidades de corriente que
circulan por cada lazo, para cada uno de los siguientes
circuitos:

2.  Solución:

 V= I*R
 10v = I1 * 5 ohm + I1 * 3 ohm – I2 * 5 ohm
 6v = I2 * 3 ohm + I2 * 5 ohm – I2 * 6 ohm - I1 * 3 ohm

 10v = I1 * (5 ohm + 3 ohm) – I2 * 3 ohm
 6v = I2 * (5 ohm + 3 ohm + 6ohm) – I1 3 ohm


 10v = I1 8 ohm – I2 3 ohm (3) 10v = I1 8 – I2 3
 6v = I2 14ohm – I1 3 ohm (8) 6v = I1 3 – I2 14


30v = I1 24 – I2 9
 48v = I1 24 – I2 112


78v = I2 103ohm

 78 = I2 I2= 0.75 A
 103 I2= 750 mA

 10v = I1 8 ohm – I2 0,75 ohm(3)
 6v = I1 8ohm – 2.25v
 12.25 = I1 8ohm

 12.25 = I1 I1 = 0.28
 8 I1= 280 mA

3.  V= I*R
 12v = -I1 * 6 ohm + I1 * 2 ohm – I1 * 3 ohm + 10v + I1 * 5 ohm – I2 - 3 ohm
 10v = -I2 * 3 ohm +6v + I2 * 6 ohm + I2 * 5 ohm – I1 - 3 ohm

 12v = -I1(6 ohm + 2 ohm + 3 ohm + 5 ohm) + 10 v - I2 - 3 ohm
 10v = -I2(3 ohm + 6 ohm + 5 ohm )+ 6v – I1 - 3 ohm

 12v = -I1( 16 ohm) + 10 v - I2 - 3 ohm
 10v = -I2(14ohm)+ 6v – I1 - 3 ohm

 12v-10v = -I1 ( 16 ohm) - I2 - 3 ohm (3)2v= I1( 16 ohm) - I2
– (3 ohm )
 10v -6v = -I2 (14ohm) – I1 - 3 ohm (16)4v= - I1( 3 ohm) +I2
– (14 ohm)

 6v= I1( 48ohm) - I2 – (9
ohm )
 64v= -I1( 48ohm) + I2 –
(124 ohm )

 70v= -I2(115ohm)

 70v = -I2 = 0.60 A
 115v

 2v= I1( 16 ohm) -0.60 – (3 ohm )
 2v= I1( 16ohm) - 1.8 ohm
 2v + 1.8v= I1 (16 ohm)
 3.8V= I1 (16 ohm)
 3.8v = I1 = 0.23 A
 16ohm