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Chapter 20 t - Test for Two Matched Samples
Vodka & Whiskey The researcher randomly selected 10 Cranberry vodka drinkers and 7 Boilermaker drinkers. The  vodka group had a mean drunkenness of 52  and the  whiskey group had a mean drunkenness of 39 . Previous Experiment Previous Decision The drunkenness of vodka drinkers and whiskey drinkers is different Question : Who typically drinks Cranberry Vodkas and who drinks Boilermakers? 2nd Question Who typically weighs more? 3rd Question : Was the difference in the previous experiment due to different alcohol or different weights? Women Men Lighter Heavier
Two Independent Sample  t -Test ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Two Independent Sample  t -Test ,[object Object],[object Object],[object Object],[object Object],[object Object],Always going to affect the error Can we minimize this factor by forcing the selected samples to be similar?
Matched Samples  t -Test Reducing a Two-Sample test into a Single Sample Comparison  (Single Sample  t -Test)
Matched Samples  t -Test FAQ ,[object Object],[object Object]
Matched Samples  t -Test FAQ ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Matched Samples  t -Test FAQ ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Matched Samples  t -Test FAQ ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Matched Samples  t -Test FAQ ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Matched Samples  t -Test FAQ ,[object Object],[object Object]
Hypothesis Test 11 Vodka & Whiskey  Matched Samples t-Test
Vodka/Whiskey: Matched  t -Test Are all types of alcohol the same, even if the proofs are the same? This question was raised by a researcher who had observed vodka drinkers and noticed that they seemed to get drunk faster than whiskey drinkers.  To test whether whiskey is the same or different than vodka, the researcher decided to compare people who drank 3 Cranberry Vodka’s to people to drank 3 Boilermakers. Since weight is known to affect drunkenness, the researcher has matched the samples to make sure that weight is evenly distributed between the group (on next slide).What will the researcher conclude at a .01 level of significance.
Vodka/Whiskey: Matched  t -Test Step 0) Convert to Difference Scores 19 25 210 20 24 190 31 30 170 36 34 150 42 47 130 63 52 110 Whiskey Vodka Weight +6 +4 -1 -2 + 5 - 11 D
Vodka/Whiskey: Matched  t -Test Step 0) Convert to Difference Scores =   D  /   n dif =    /   6 =  .16 +6 +4 -1 -2 + 5 - 11 D D   (D 2  s D   =  D) 2 n dif n dif   - 1
Vodka/Whiskey: Matched  t -Test Step 0) Convert to Difference Scores =   D  /   n dif =    /   6 =  .16 =  6.37 +6 +4 -1 -2 + 5 - 11 D D   (D 2  s D   =  D) 2 n dif n dif   - 1   s D   =  ) 2 6 6   - 1 36 16 1 4 25 121 D 2
Vodka/Whiskey: Matched  t -Test ,[object Object],[object Object],[object Object],[object Object],[object Object]
Vodka/Whiskey: Matched  t -Test Is the mean of the vodka pop. the same as the whiskey pop? Hypothesis H 0 :   D =0  H 1 :   D    0 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],A)   =.16 s D =6.37 n dif  = 6  df dif  = 5     = .01 C) Reject H 0   Fail to reject H 0   Reject H 0 B) .005 .005 t( 5 ) crit =  -4.032 t( 5 ) crit = +4.032 ,[object Object],[object Object],[object Object],E) D
Vodka/Whiskey: Matched  t -Test Is the mean of the vodka pop. the same as the whiskey pop? Hypothesis H 0 :   D =0  H 1 :   D    0  D  =   hyp =  0 =  2.6   =.16 s D =6.37 n dif  = 6  df dif  = 5     = .01 ,[object Object],[object Object],[object Object],E) D  = 6   = 2.45 s D s D = n dif 
Vodka/Whiskey: Matched  t -Test Is the mean of the vodka pop. the same as the whiskey pop? Hypothesis H 0 :   D =0  H 1 :   D    0 Based upon a sampling distribution with    &  =  2.6 Step 4) Calculate Test Statistic  D  =   = .06   =.16 s D =6.37 n dif  = 6  df dif  = 5     = .01 ,[object Object],[object Object],[object Object],E) D s D t obt  =  D s D D - t obt  = .16 - 0 2.6
Vodka/Whiskey: Matched  t -Test Step 6) Interpret Decision Step 5) Make Decision ,[object Object],Is the mean of the vodka pop. the same as the whiskey pop? Hypothesis H 0 :   D =0  H 1 :   D    0 Based upon a sampling distribution with    &  =  2.6  D  =   t obt  = .06 ,[object Object],  =.16 s D =6.37 n dif  = 6  df dif  = 5     = .01 ,[object Object],[object Object],[object Object],E) D s D
Why Matching Works! Why can we assume the standard error is reduced ( if the matching variable is correlated with the dependent measure )
Why Matching Works
When Matching Doesn’t Work
Matched Sample  t -Test ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Repeated Measures The Ultimate Matching
Repeated Measures ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
To match, or not to match… That is the question……
Matched vs Independent Tests Which test is more sensitive? Smaller Larger Standard Error Less More Degrees of Freedom Matched Independent
Matched vs Independent Tests Which test is more sensitive? Brings in Critical Values Spreads out Critical Values Standard Error Spreads out Critical Values Brings in Critical Values Degrees of Freedom Matched Independent …  has a much greater effect on critical scores?
Matched vs Independent Tests Which test is more sensitive? Brings in a lot Spreads out a lot Standard Error Spreads out a little Brings in a little Degrees of Freedom Matched Independent …  has a much greater effect on critical scores? More Sensitive
Two Sample Tests Final Notes
Two Sample Tests ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

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香港六合彩

  • 1. Chapter 20 t - Test for Two Matched Samples
  • 2. Vodka & Whiskey The researcher randomly selected 10 Cranberry vodka drinkers and 7 Boilermaker drinkers. The vodka group had a mean drunkenness of 52 and the whiskey group had a mean drunkenness of 39 . Previous Experiment Previous Decision The drunkenness of vodka drinkers and whiskey drinkers is different Question : Who typically drinks Cranberry Vodkas and who drinks Boilermakers? 2nd Question Who typically weighs more? 3rd Question : Was the difference in the previous experiment due to different alcohol or different weights? Women Men Lighter Heavier
  • 3.
  • 4.
  • 5. Matched Samples t -Test Reducing a Two-Sample test into a Single Sample Comparison (Single Sample t -Test)
  • 6.
  • 7.
  • 8.
  • 9.
  • 10.
  • 11.
  • 12. Hypothesis Test 11 Vodka & Whiskey  Matched Samples t-Test
  • 13. Vodka/Whiskey: Matched t -Test Are all types of alcohol the same, even if the proofs are the same? This question was raised by a researcher who had observed vodka drinkers and noticed that they seemed to get drunk faster than whiskey drinkers. To test whether whiskey is the same or different than vodka, the researcher decided to compare people who drank 3 Cranberry Vodka’s to people to drank 3 Boilermakers. Since weight is known to affect drunkenness, the researcher has matched the samples to make sure that weight is evenly distributed between the group (on next slide).What will the researcher conclude at a .01 level of significance.
  • 14. Vodka/Whiskey: Matched t -Test Step 0) Convert to Difference Scores 19 25 210 20 24 190 31 30 170 36 34 150 42 47 130 63 52 110 Whiskey Vodka Weight +6 +4 -1 -2 + 5 - 11 D
  • 15. Vodka/Whiskey: Matched t -Test Step 0) Convert to Difference Scores =  D / n dif =  / 6 = .16 +6 +4 -1 -2 + 5 - 11 D D   (D 2  s D =  D) 2 n dif n dif - 1
  • 16. Vodka/Whiskey: Matched t -Test Step 0) Convert to Difference Scores =  D / n dif =  / 6 = .16 = 6.37 +6 +4 -1 -2 + 5 - 11 D D   (D 2  s D =  D) 2 n dif n dif - 1   s D =  ) 2 6 6 - 1 36 16 1 4 25 121 D 2
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  • 22. Why Matching Works! Why can we assume the standard error is reduced ( if the matching variable is correlated with the dependent measure )
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  • 26. Repeated Measures The Ultimate Matching
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  • 28. To match, or not to match… That is the question……
  • 29. Matched vs Independent Tests Which test is more sensitive? Smaller Larger Standard Error Less More Degrees of Freedom Matched Independent
  • 30. Matched vs Independent Tests Which test is more sensitive? Brings in Critical Values Spreads out Critical Values Standard Error Spreads out Critical Values Brings in Critical Values Degrees of Freedom Matched Independent … has a much greater effect on critical scores?
  • 31. Matched vs Independent Tests Which test is more sensitive? Brings in a lot Spreads out a lot Standard Error Spreads out a little Brings in a little Degrees of Freedom Matched Independent … has a much greater effect on critical scores? More Sensitive
  • 32. Two Sample Tests Final Notes
  • 33.