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Table showing equivalence points obtained from the graphs above for both the weak and strong acid
                 pH Graph (day 1)    pH Graph (day 2)   1st derivative   2nd derivative      Gran Plot
Strong acid           16.04               18.68               18.53           19.105             19.33
Weak acid             36.11               39.83               22.38            22.45             15.72

                             Sample calculation of Concentration of Acid
       ∗   Concentration of Strong Acid – HCl
2nd derivative
1dm3 NaOH = 0.0971M NaOH
19.105ml NaOH = 19.105ml/1000ml * 0.0971mole
                 = 1.8551 x 10-3 mole NaOH
       1:1 mole ratio
25ml (pipetted) HCl = 1.8551 x 10-3 mole
1000ml HCl = (1000ml * 1.8551 x 10-3 mole)/25ml
              = 0.074M HCl


       ∗   Concentration of Weak Acid – CH3COOH
2nd derivative
1dm3 NaOH = 0.0971M NaOH
22.45ml NaOH = 22.45ml/1000ml * 0.0971mole
                 = 2.1799 x 10-3 mole NaOH
       1:1 mole ratio
25ml (pipetted) CH3COOH = 2.1799 x 10-3 mole
1000ml HCl = (1000ml * 2.1799 x 10-3 mole)/25ml
              = 0.087M CH3COOH


Table Showing the Calculated Concentration of the Hydrochloric Acid and Acetic Acid Obtained
From the Average Concentration and Equivalence Volume of the Sodium Hydroxide
                  Ph Graph          Ph Graph      1st Derivative     2nd Derivative       Gran Plot
                  (Day 1)           (Day 2)
[HCl]             0.062             0.073         0.072              0.074                0.075
[Acetic Acid]     0.140             0.155         0.087              0.087                0.061




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  • 1. Table showing equivalence points obtained from the graphs above for both the weak and strong acid pH Graph (day 1) pH Graph (day 2) 1st derivative 2nd derivative Gran Plot Strong acid 16.04 18.68 18.53 19.105 19.33 Weak acid 36.11 39.83 22.38 22.45 15.72 Sample calculation of Concentration of Acid ∗ Concentration of Strong Acid – HCl 2nd derivative 1dm3 NaOH = 0.0971M NaOH 19.105ml NaOH = 19.105ml/1000ml * 0.0971mole = 1.8551 x 10-3 mole NaOH 1:1 mole ratio 25ml (pipetted) HCl = 1.8551 x 10-3 mole 1000ml HCl = (1000ml * 1.8551 x 10-3 mole)/25ml = 0.074M HCl ∗ Concentration of Weak Acid – CH3COOH 2nd derivative 1dm3 NaOH = 0.0971M NaOH 22.45ml NaOH = 22.45ml/1000ml * 0.0971mole = 2.1799 x 10-3 mole NaOH 1:1 mole ratio 25ml (pipetted) CH3COOH = 2.1799 x 10-3 mole 1000ml HCl = (1000ml * 2.1799 x 10-3 mole)/25ml = 0.087M CH3COOH Table Showing the Calculated Concentration of the Hydrochloric Acid and Acetic Acid Obtained From the Average Concentration and Equivalence Volume of the Sodium Hydroxide Ph Graph Ph Graph 1st Derivative 2nd Derivative Gran Plot (Day 1) (Day 2) [HCl] 0.062 0.073 0.072 0.074 0.075 [Acetic Acid] 0.140 0.155 0.087 0.087 0.061 5