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Test for maximum, minimum and points of inflexion
1. Find stationary point a  :  f ' (a) = 0
2. Study the sign of f ' to the right and left of a
+
+
+
maximum
­
f ' (a)=0
horizontal
point of inflexion
­
­ f ' (a)=0f ' (a)=0
+­
minimum
f ' (a)=0
Find the coordinates of the stationary points on the 
curve y= x4 
­ 4 x3
  and determine their nature.
Example 5:
Find the stationary points for the curve
                       and determine their nature.
Sketch the function.
Example 6:
Find turning points for                                    .
 Sketch the curve.
Example 7:
 For the curve  y = x3
 + x2
 find the stationary 
points and sketch the curve.
Example 8:
 y = x3
 + x2
By the end of the lesson you will be able to:
• Use the second derivative to test the nature of a 
stationary point and/or point of inflexion.
 
•  
•  
A
B
f is concave upwards
gradient is increasing
f '  is increasing
f ''  > 0
If a function is 
increasing then its 
derivative is positive
Concavity
 
f is concave downwards
gradient is decreasing
f '  is decreasing
f ''  < 0
If a function is 
decreasing then its 
derivative is negative
•   
•   A
B
f is concave upwards  f ''  > 0
f is concave downwards  f ''  < 0
The second derivative and turning points
•  
•  
B
A
at A:
          f ' (a)= 0
f is concave up. f ''(a) > 0
f '(a) = 0
A is a minimum point
          f ' (b)= 0
f is concave down.
f '(b) = 0
f ''(b) < 0
B is a maximum point
at B:
P is a minimum point
at P :
f '(x) = 0  
f ''(x) > 0
P is a maximum point
at P :
f '(x) = 0  
f ''(x)< 0
P
•  
A point of inflexion is when the curve changes 
from concave down to concave up or vice versa.
P is a point of inflexion
•  
P
at P:
f ''(x) = 0
 f '' changes sign  
If f ' is also zero then P is a horizontal point 
of inflexion.
Find the  points of inflection of  
                     f (x) = x4
­ 4 x3  
+ 5
Find the stationary points for the curve
 y= 4 + 3x ­ x3
 and determine their nature. Draw a 
sketch of the function.
y= 4 + 3x ­ x3
Find the point of inflexion on the curve 
y = 2 x 3
 + 3 x 2
 + 6 x ­ 7  and sketch its graph
y = 2 x 3
 + 3 x 2
 + 6 x ­ 7
 For the curve  y = x3
 + x2
 find the stationary points 
and point of inflexion.
 y = x3
 + x2
Find turning points for    y =x3 
­ 3x2 
­ 9x +2. Sketch 
the curve.
y =x3 
­ 3x2 
­ 9x +2
Test for maximum, minimum and points of inflexion
Method 1: First derivative Sign test
1. Find a  :  f ' (a) = 0
2. Study the sign of f ' to the right 
and left of a
++ ­ ­
maximum minimum
+
+
­
­
f ' (a)=0
horizontal
point of inflexion
Method 2 : Second derivative test
1. Find a  :  f ' (a) = 0
2. Study the sign of  f ''(a)
  
  f '' (a) <0   
f '' (a) = 0
     and
f '' changes 
sign at a
f ' (a)=0
f ' (a)=0
f ' (a)=0
f '' (a) >0    minimum
maximum
point of inflexion
http://www.mindomo.com/view.htm?m=7af63ca6ad1b462fa05b7762859f45d3
Derivative puzzle 1
Big derivative puzzle

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