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IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 46
FINITE-VOLUME SOLUTION OF DIFFUSION EQUATION AND
APPLICATION TO MODEL PROBLEMS
Asish Mitra
Reviewer: Heat and Mass Transfer, WSEAS, Associate Professor& HOD of BSH Dept.
College of Engineering & Management, Kolaghat, East Midnapur, West Bengal
mitra_asish@yahoo.com.
Abstract
In the present numerical study, the two dimensional diffusion equations are converted to a system of linear equations using finite-
volume method. The system of equations is solved by a direct method. For the entire process a computer code is developed in Matlab.
In the second part of the present study, the computer codes developed for solving diffusion equation is then applied to a series of
model problems. These problems contain features found in more complicated engineering situations. The problems are distinguished
by their different boundary conditions, and by the variation of the source term and diffusivity in the domain.
Keywords: Diffusion Equation, Finite Volume Method, Numerical Study, Model Problems.
---------------------------------------------------------------------***---------------------------------------------------------------------
1. INTRODUCTION
List of Symbols
Cv specific heat capacity at constant volume
i internal (thermal) energy
p pressure
R universal gas constant
S source term
SMx x-component momentum source
SMy yy-component momentum source
SMz z-component momentum source
T temperature
t time
u velocity vector
u x-component velocity
v y-component velocity
w z-component velocity
Dimensionless parameters
Greek Symbols
ρ density
μ viscosity
 general variable
Ф dissipation function
Г diffusion coefficient
The conservative or divergence form of the system of
equations which governs the time-dependent three
dimensional fluid flow and heat transfer of a compressible
Newtonian fluid is written in table 1
Table 1: Governing equations of the flow of a compressible Newtonian fluid
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 47
It is clear from Table 1 that there are significant
commonalities between the various equations. If we introduce
a general variable , the conservative form of all fluid flow
equations, including equations for scalar quantities such as
temperature and pollutant concentration etc., can be usefully
written in the following form
Where Г = diffusion coefficient, S = source term
The above equation is the so-called transport equation for
property . The dependent variable can stand for a variety
of different quantities, such as the mass fraction of a chemical
species, the temperature, a velocity component etc.
Accordingly, for each of the variables, an appropriate meaning
will have to given to the diffusion coefficient, Г
Table 2 (φ, Г and s) in General Transport Equation to stand
for different equations
Equations  Г S
Continuity 1 1 0
x-momentum u μ

p
dx
y-momentum v μ

p
dy
z-momentum w μ

p
dz
Energy T k i
In this paper, we develop the finite volume method by
considering the simplest transport process of all: pure
diffusion in the steady state. The governing equation of steady
state diffusion can easily be derived from the general transport
equation for property  by deleting the transient and
convective term. This gives
(1)
The two dimensional diffusion equation in Cartesian coordinates is
(2)
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 48
We seek the solution φ(x,y) to the eqn (2) in a rectangular
region subject to appropriate boundary conditions.
2. FINITE VOLUME MESH
Figure 1 depicts a rectangular domain. The domain is divided
into non-overlapping control volumes by the dashed lines that
define the boundaries of the individual control volumes. The
pattern created by the lines is called the computational grid or
mesh. In Figure 1 the control volumes are square, but this is
not required. At the center of each control volume is a node. A
general nodal point is identified by P, its neighbors, the nodes
to the west and east, are identified by W and E whereas the
nodes to the north and south are by N and S. The west and east
side faces of the control volume are referred as w and e
whereas north and south as n and s. Two sets of grid lines can
be identified: the grid lines (dashed) that define the control
volume faces, and the grid lines (solid) that define the
locations of the nodes.
Fig1: A part of two-dimensional grid
Regardless of the grid spacing P is always located in the
geometric center of its control volume.
(3)
In these expressions it is crucial to distinguish between upper
and lower case letters used as sub-scripts. Lower case
subscripts refer to the locations of the control volume faces.
Upper case sub-scripts refer to the locations of the nodes.
3. UNIFORM AND BLOCK-UNIFORM MESHES
For many problems either a uniform or block-uniform mesh
are suitable. We define a uniform mesh to have uniform
control volume widths in any one coordinate direction. The
widths of the control volumes in different directions need not
be uniform. This situation is depicted in the left hand side of
Figure 2 where Δx ≠ Δy, but Δx is same for all control
volumes. For a uniform mesh, the x, xu, y, and yv vectors are
computed in fvUniformMesh.
A block-uniform mesh is shown in the right hand side of
Figure 2. In a block-uniform mesh, the calculation domain is
divided into a number of panels in the x and y direction. The
intersections of these panels define rectangular blocks. The
width Δx of control volumes is uniform within an within an x-
direction panel, and adjacent panels can have different Δx.
Similarly, Δy is uniform within a y-direction panel, but may
vary from panel to panel. The fvUniBlockMesh function is
used to define block-uniform meshes.
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 49
Fig2: Uniform and block-uniform meshes.
4. DISCRETISATION
Concept: Transferring continuous models and equations into
discreet counterparts.
The key step of the finite volume method is the integration of
the governing equation over a control volume to yield a
discretized equation at its nodal point P. When eqn (2) is
formally integrated over the control volume we obtain
(4)
So, noting that Ae = Aw =Δy and An = As = Δx, we get
(5)
This equation represents the balance of the generation of
 in
a control volume and the fluxes through its cell faces. Now we
assume linear approximation to calculate gradients (hence
fluxes) at the control volume aces:
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 50
By substituting the above expressions into eqn (4) we obtain
(6)
When the source term is represented in linearized
form , this equation can be re-arranged
as
(7)
Equation (6) is now cast in the general discretised equation form for interior nodes
(8)
Where
4.1 Solution of equations
Discretized equations of the form (7) must be set up at each
nodal point in order to solve a problem. For control volumes
that are adjacent to the domain boundaries the general
discretized equation (7) is modified to incorporate boundary
conditions. The resulting system of linear algebraic equations
is then solved to obtain the distribution property φ at nodal
points.
4.2 Matlab Codes
This section describes a set of Matlab routines for the solution
of eqn (1). The generic Matlab functions are listed in Table 3.
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 51
Table 3: A set of Matlab routines used to solve Equation (1).
Main Task Matlab code Description
Define mesh and
boundary conditions
uniformmesh.m Compute the location of cell centers and cell interfaces for a
group of cells with uniform size.
blockuniformmesh.m Compute the location of cell centers and cell interfaces for a mesh
consisting of blocks that contain uniform meshes.
Compute FV
coefficients for
interior cells
coef.m Compute the neighboring finite volume coefficients (aE, aW, aN,
and aS) for all interior control volumes.
Adjust coefficients
for boundary
conditions.
bc.m Modify finite volume coefficients and source terms to include the
effect of boundary conditions. The final value of aP is also
computed.
Assemble and solve
the system of
equations
amatrix.m Store the finite volume coefficients aE, aW, aN, aS, and aP for all
nodal points.
Compute boundary
values and/or fluxes
Plots
postprocess.m The dependent variable is stored in a matrix suitable for use with
Matlab contour and surface plotting routines.
4.3 Model Problems
The computer codes developed for solving diffusion equation
is then applied to a series of model problems. These problems
contain features found in more complicated engineering
situations. The problems are distinguished by their different
boundary conditions, and by the variation of the source term
and diffusivity in the domain.
The model problems require solution of Equation (1) on a
rectangular domain
4.3.1 Model Problem 1: A Membrane Deflection
Problem (Г=1)
We consider the transverse deflection of a uniformly tensioned
membrane which is subjected to uniform pressure. The
transverse deflection u for a membrane which has zero
deflection on a boundary L satisfies the differential equation
(9)
Where γ is a physical constant This equation is comparable
with eqn(1) where
   u S, , 1 . Properties of
harmonic functions [4] imply that the differential equation is
satisfied by a series of the form
(10)
Where z = x + ıy and constants cj are chosen to make the
boundary defection as small as possible, in the least squares
sense. As a specific example, we analyze a membrane
consisting of a rectangular part. The plot in Figure 3 is
produced by the function membrane.m (with γ =2) which
agrees well with equation (10) using a twenty-term series.
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 52
0
1
2
3
0
1
2
3
4
5
0
0.5
1
1.5
2
y
x
Fig3: Solution to model problem 1on a 25 × 25 mesh
Note that the gradient of the surface is zero at the centre and
largest near the boundary. Consequently, the tangential stress
will be smaller in the middle and larger at the edges.
4.3.2 Model Problem 2: Plate Deflection (Г=1)
Civil engineers are sometimes asked to determine the
deflection of mechanical structures under various loads. As an
illustration, we consider the problem of computing the
deflection of a rectangular plate that is subject to a distributed
area load f. Suppose the plate is simply supported along the
edges, which means that both the deflection and slope of the
plate are zero along the edges. If u(x, y) denotes the deflection
of the plate at coordinates (x, y), the plate can be described by
the following fourth-order partial differential equation [5]



 

 
4
4
4
2 2
4
4
2
u
x
u
x y
u
y
f
  
(11)
Here the parameter α, called the flexural rigidity of the plate,
depends on such things as the plate thickness and the modulus
of elasticity of the material.
The plate deflection equation is roughly similar to Poisson’s
equation, but it differs in that it is of higher order and it
includes a mixed partial derivative term. One way to approach
its solution would be to develop finite difference formulas
suitable for this class of equation. However, because of the
special perfect-square structure of, an alternative approach is
available. In particular, the above equation can be
reformulated as a sequence of two Poisson problem. Let v (x,
y) denotes a new intermediate variable defined as
v
u
x
u
y
 




2
2
2
2
(12)
applying the Laplacian operator to both sides in eqn (12), we
find that the that (11) can be recast in terms of v as



 
2
2
2
2
v
x
v
y
f
 
(13)
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 53
We find v (x, y) by solving (13) subject to the appropriate
boundary conditions. Then, using (12), the deflection u(x, y)
can be found by solving




2
2
2
2
u
x
u
y
v 
In this way, the original fourth-order problem in (11) is
transformed into a sequence of two second-order Poisson
problems. To make the problem specific, suppose the plate is a
= 3 m by b = 3 m, the area load on the plate is f = 2000 N/m2
and the flexural rigidity is α = 1.5 × 104
m/N. The boundary
conditions for the plate that is simply supported along the
edges are u(x, y) = v(x, y) = 0 along the boundary. The code
plate.m gives the plot in Fig 4.
0
1
2
3
00.511.5
22.53
0
0.01
0.02
0.03
0.04
0.05
y
sol u
x
Fig 4 Plate deflection on a 15 × 15 mesh
4.3.3 Model Problem 3: Electrostatic Potential Due to
a Dipole (Г=1)
The electrostatic potential surrounding the dipole can be
modeled by the Poisson equation






2
2
2
2
u
x
u
y p
  
(14)
Here u(x,y) is the electrostatic potential, in volts, at
coordinates (x,y). The parameters εP is the permittivity of the
material, and ρ (x,y) is the charge density. This equation is
comparable with eqn(1) where



  u S
p
, , 1
.
Suppose the electrostatic potential is to be determined over a
rectangular region of width a = 2 cm and length b= 2 cm. Let
the charge density be zero everywhere except near the point
(0.8, 0.8), where there is a positive charge, and the point (1.2,
1.2), where there is an equal negative charge.
ρ (0.8, 0.8) = - ρ (1.2, 1.2) = 10-8
C/m2
Suppose the voltage along the boundary of the rectangular
region is zero and the medium is air for which . ε0 = 8.9 × 10-
12
C2
/N-m2
. The code dipole m produces the plot in Fig 5
.
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 54
0
1
2
0
0.5
1
1.5
2
-6
-4
-2
0
2
4
6
y
x
Fig 5 Electrostatic Potential Due to a Dipole on a 20 × 20 mesh
4.3.4 Model Problem 4: Fully-Developed Flow in a Rectangular Duct (Г=μ)
Fig6: Two possible calculation domains (shaded regions) for fully-developed flow in a rectangular duct.
Figure 6 shows two representations of the cross section of a
rectangular duct. For simple fully-developed flow the
governing equation for the axial velocity w is
(15)
The code for solving Equation (1) can be used to solve the
above equation by making the following definitions
For the full duct simulation depicted on the left hand side of
Figure 6, the boundary conditions are no slip conditions on all
four walls.
For the quarter duct simulation depicted on the right hand side
of Figure 6, the boundary conditions are no slip conditions on
the solid walls (x = Lx and y = Ly)
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 55
And symmetry conditions on the other two planes
The code ductflow.m produces the plot in Fig 7.
0
0.1
0.2
0.3
0.4
0.5
0
0.2
0.4
0.6
0.8
0
0.5
1
1.5
2
2.5
Fig7: Solution to model problem 4 on a 10 × 10 mesh.
CONCLUSIONS
The basic conservation equations can be written in the form of
a differential equation for a general variable
 . The concept of
discretization can be used as a tool to solving these differential
equations over a domain of interest. Finite Volume Method
can be used to find the discrete solution of diffusion problems.
Concept of Finite Volume Method
 Subdivide the problem domain into non overlapping
control volumes
 Integrate the governing equation over each of these
control volumes.
 Representative value of variable = value of the
variable at the geometric centre of CV
 Piecewise profiles expressing the variation of φ
between the grid points are used to evaluate the
integrals.
 Discretized equation obtained in this manner,
represents the conservation principle for the finite
control volume.
REFERENCES
[1] Jack J. Dongarra, Iain S. Du_, Danny C. Sorensen, and
Henk A. van der Vorst. Solving Linear Systems on Vector and
Shared Memory Computers. SIAM, Philadelphia, 1991.
[2] Gene Golub and James M. Ortega Scienti_c Computing:
An Introduction with Parallel Computing. Academic Press,
Inc., Boston, 1993
[3] S.V. Patankar. Numerical Heat Transfer and Fluid Flow
Hemisphere, Washington D.C., 1980
[4] R. V. Churchhill, J. W. Brown, and R. F. Verhey. Complex
Variables and Applications McGraw-Hill, 1974
[5] Carnahan B, Luther A, and Wilkes J O, Applied Numerical
Methods, New York, 1969.

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Finite volume solution of diffusion equation and application to model problems

  • 1. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 46 FINITE-VOLUME SOLUTION OF DIFFUSION EQUATION AND APPLICATION TO MODEL PROBLEMS Asish Mitra Reviewer: Heat and Mass Transfer, WSEAS, Associate Professor& HOD of BSH Dept. College of Engineering & Management, Kolaghat, East Midnapur, West Bengal mitra_asish@yahoo.com. Abstract In the present numerical study, the two dimensional diffusion equations are converted to a system of linear equations using finite- volume method. The system of equations is solved by a direct method. For the entire process a computer code is developed in Matlab. In the second part of the present study, the computer codes developed for solving diffusion equation is then applied to a series of model problems. These problems contain features found in more complicated engineering situations. The problems are distinguished by their different boundary conditions, and by the variation of the source term and diffusivity in the domain. Keywords: Diffusion Equation, Finite Volume Method, Numerical Study, Model Problems. ---------------------------------------------------------------------***--------------------------------------------------------------------- 1. INTRODUCTION List of Symbols Cv specific heat capacity at constant volume i internal (thermal) energy p pressure R universal gas constant S source term SMx x-component momentum source SMy yy-component momentum source SMz z-component momentum source T temperature t time u velocity vector u x-component velocity v y-component velocity w z-component velocity Dimensionless parameters Greek Symbols ρ density μ viscosity  general variable Ф dissipation function Г diffusion coefficient The conservative or divergence form of the system of equations which governs the time-dependent three dimensional fluid flow and heat transfer of a compressible Newtonian fluid is written in table 1 Table 1: Governing equations of the flow of a compressible Newtonian fluid
  • 2. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 47 It is clear from Table 1 that there are significant commonalities between the various equations. If we introduce a general variable , the conservative form of all fluid flow equations, including equations for scalar quantities such as temperature and pollutant concentration etc., can be usefully written in the following form Where Г = diffusion coefficient, S = source term The above equation is the so-called transport equation for property . The dependent variable can stand for a variety of different quantities, such as the mass fraction of a chemical species, the temperature, a velocity component etc. Accordingly, for each of the variables, an appropriate meaning will have to given to the diffusion coefficient, Г Table 2 (φ, Г and s) in General Transport Equation to stand for different equations Equations  Г S Continuity 1 1 0 x-momentum u μ  p dx y-momentum v μ  p dy z-momentum w μ  p dz Energy T k i In this paper, we develop the finite volume method by considering the simplest transport process of all: pure diffusion in the steady state. The governing equation of steady state diffusion can easily be derived from the general transport equation for property  by deleting the transient and convective term. This gives (1) The two dimensional diffusion equation in Cartesian coordinates is (2)
  • 3. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 48 We seek the solution φ(x,y) to the eqn (2) in a rectangular region subject to appropriate boundary conditions. 2. FINITE VOLUME MESH Figure 1 depicts a rectangular domain. The domain is divided into non-overlapping control volumes by the dashed lines that define the boundaries of the individual control volumes. The pattern created by the lines is called the computational grid or mesh. In Figure 1 the control volumes are square, but this is not required. At the center of each control volume is a node. A general nodal point is identified by P, its neighbors, the nodes to the west and east, are identified by W and E whereas the nodes to the north and south are by N and S. The west and east side faces of the control volume are referred as w and e whereas north and south as n and s. Two sets of grid lines can be identified: the grid lines (dashed) that define the control volume faces, and the grid lines (solid) that define the locations of the nodes. Fig1: A part of two-dimensional grid Regardless of the grid spacing P is always located in the geometric center of its control volume. (3) In these expressions it is crucial to distinguish between upper and lower case letters used as sub-scripts. Lower case subscripts refer to the locations of the control volume faces. Upper case sub-scripts refer to the locations of the nodes. 3. UNIFORM AND BLOCK-UNIFORM MESHES For many problems either a uniform or block-uniform mesh are suitable. We define a uniform mesh to have uniform control volume widths in any one coordinate direction. The widths of the control volumes in different directions need not be uniform. This situation is depicted in the left hand side of Figure 2 where Δx ≠ Δy, but Δx is same for all control volumes. For a uniform mesh, the x, xu, y, and yv vectors are computed in fvUniformMesh. A block-uniform mesh is shown in the right hand side of Figure 2. In a block-uniform mesh, the calculation domain is divided into a number of panels in the x and y direction. The intersections of these panels define rectangular blocks. The width Δx of control volumes is uniform within an within an x- direction panel, and adjacent panels can have different Δx. Similarly, Δy is uniform within a y-direction panel, but may vary from panel to panel. The fvUniBlockMesh function is used to define block-uniform meshes.
  • 4. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 49 Fig2: Uniform and block-uniform meshes. 4. DISCRETISATION Concept: Transferring continuous models and equations into discreet counterparts. The key step of the finite volume method is the integration of the governing equation over a control volume to yield a discretized equation at its nodal point P. When eqn (2) is formally integrated over the control volume we obtain (4) So, noting that Ae = Aw =Δy and An = As = Δx, we get (5) This equation represents the balance of the generation of  in a control volume and the fluxes through its cell faces. Now we assume linear approximation to calculate gradients (hence fluxes) at the control volume aces:
  • 5. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 50 By substituting the above expressions into eqn (4) we obtain (6) When the source term is represented in linearized form , this equation can be re-arranged as (7) Equation (6) is now cast in the general discretised equation form for interior nodes (8) Where 4.1 Solution of equations Discretized equations of the form (7) must be set up at each nodal point in order to solve a problem. For control volumes that are adjacent to the domain boundaries the general discretized equation (7) is modified to incorporate boundary conditions. The resulting system of linear algebraic equations is then solved to obtain the distribution property φ at nodal points. 4.2 Matlab Codes This section describes a set of Matlab routines for the solution of eqn (1). The generic Matlab functions are listed in Table 3.
  • 6. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 51 Table 3: A set of Matlab routines used to solve Equation (1). Main Task Matlab code Description Define mesh and boundary conditions uniformmesh.m Compute the location of cell centers and cell interfaces for a group of cells with uniform size. blockuniformmesh.m Compute the location of cell centers and cell interfaces for a mesh consisting of blocks that contain uniform meshes. Compute FV coefficients for interior cells coef.m Compute the neighboring finite volume coefficients (aE, aW, aN, and aS) for all interior control volumes. Adjust coefficients for boundary conditions. bc.m Modify finite volume coefficients and source terms to include the effect of boundary conditions. The final value of aP is also computed. Assemble and solve the system of equations amatrix.m Store the finite volume coefficients aE, aW, aN, aS, and aP for all nodal points. Compute boundary values and/or fluxes Plots postprocess.m The dependent variable is stored in a matrix suitable for use with Matlab contour and surface plotting routines. 4.3 Model Problems The computer codes developed for solving diffusion equation is then applied to a series of model problems. These problems contain features found in more complicated engineering situations. The problems are distinguished by their different boundary conditions, and by the variation of the source term and diffusivity in the domain. The model problems require solution of Equation (1) on a rectangular domain 4.3.1 Model Problem 1: A Membrane Deflection Problem (Г=1) We consider the transverse deflection of a uniformly tensioned membrane which is subjected to uniform pressure. The transverse deflection u for a membrane which has zero deflection on a boundary L satisfies the differential equation (9) Where γ is a physical constant This equation is comparable with eqn(1) where    u S, , 1 . Properties of harmonic functions [4] imply that the differential equation is satisfied by a series of the form (10) Where z = x + ıy and constants cj are chosen to make the boundary defection as small as possible, in the least squares sense. As a specific example, we analyze a membrane consisting of a rectangular part. The plot in Figure 3 is produced by the function membrane.m (with γ =2) which agrees well with equation (10) using a twenty-term series.
  • 7. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 52 0 1 2 3 0 1 2 3 4 5 0 0.5 1 1.5 2 y x Fig3: Solution to model problem 1on a 25 × 25 mesh Note that the gradient of the surface is zero at the centre and largest near the boundary. Consequently, the tangential stress will be smaller in the middle and larger at the edges. 4.3.2 Model Problem 2: Plate Deflection (Г=1) Civil engineers are sometimes asked to determine the deflection of mechanical structures under various loads. As an illustration, we consider the problem of computing the deflection of a rectangular plate that is subject to a distributed area load f. Suppose the plate is simply supported along the edges, which means that both the deflection and slope of the plate are zero along the edges. If u(x, y) denotes the deflection of the plate at coordinates (x, y), the plate can be described by the following fourth-order partial differential equation [5]         4 4 4 2 2 4 4 2 u x u x y u y f    (11) Here the parameter α, called the flexural rigidity of the plate, depends on such things as the plate thickness and the modulus of elasticity of the material. The plate deflection equation is roughly similar to Poisson’s equation, but it differs in that it is of higher order and it includes a mixed partial derivative term. One way to approach its solution would be to develop finite difference formulas suitable for this class of equation. However, because of the special perfect-square structure of, an alternative approach is available. In particular, the above equation can be reformulated as a sequence of two Poisson problem. Let v (x, y) denotes a new intermediate variable defined as v u x u y       2 2 2 2 (12) applying the Laplacian operator to both sides in eqn (12), we find that the that (11) can be recast in terms of v as      2 2 2 2 v x v y f   (13)
  • 8. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 53 We find v (x, y) by solving (13) subject to the appropriate boundary conditions. Then, using (12), the deflection u(x, y) can be found by solving     2 2 2 2 u x u y v  In this way, the original fourth-order problem in (11) is transformed into a sequence of two second-order Poisson problems. To make the problem specific, suppose the plate is a = 3 m by b = 3 m, the area load on the plate is f = 2000 N/m2 and the flexural rigidity is α = 1.5 × 104 m/N. The boundary conditions for the plate that is simply supported along the edges are u(x, y) = v(x, y) = 0 along the boundary. The code plate.m gives the plot in Fig 4. 0 1 2 3 00.511.5 22.53 0 0.01 0.02 0.03 0.04 0.05 y sol u x Fig 4 Plate deflection on a 15 × 15 mesh 4.3.3 Model Problem 3: Electrostatic Potential Due to a Dipole (Г=1) The electrostatic potential surrounding the dipole can be modeled by the Poisson equation       2 2 2 2 u x u y p    (14) Here u(x,y) is the electrostatic potential, in volts, at coordinates (x,y). The parameters εP is the permittivity of the material, and ρ (x,y) is the charge density. This equation is comparable with eqn(1) where      u S p , , 1 . Suppose the electrostatic potential is to be determined over a rectangular region of width a = 2 cm and length b= 2 cm. Let the charge density be zero everywhere except near the point (0.8, 0.8), where there is a positive charge, and the point (1.2, 1.2), where there is an equal negative charge. ρ (0.8, 0.8) = - ρ (1.2, 1.2) = 10-8 C/m2 Suppose the voltage along the boundary of the rectangular region is zero and the medium is air for which . ε0 = 8.9 × 10- 12 C2 /N-m2 . The code dipole m produces the plot in Fig 5 .
  • 9. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 54 0 1 2 0 0.5 1 1.5 2 -6 -4 -2 0 2 4 6 y x Fig 5 Electrostatic Potential Due to a Dipole on a 20 × 20 mesh 4.3.4 Model Problem 4: Fully-Developed Flow in a Rectangular Duct (Г=μ) Fig6: Two possible calculation domains (shaded regions) for fully-developed flow in a rectangular duct. Figure 6 shows two representations of the cross section of a rectangular duct. For simple fully-developed flow the governing equation for the axial velocity w is (15) The code for solving Equation (1) can be used to solve the above equation by making the following definitions For the full duct simulation depicted on the left hand side of Figure 6, the boundary conditions are no slip conditions on all four walls. For the quarter duct simulation depicted on the right hand side of Figure 6, the boundary conditions are no slip conditions on the solid walls (x = Lx and y = Ly)
  • 10. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 11 | Nov-2013, Available @ http://www.ijret.org 55 And symmetry conditions on the other two planes The code ductflow.m produces the plot in Fig 7. 0 0.1 0.2 0.3 0.4 0.5 0 0.2 0.4 0.6 0.8 0 0.5 1 1.5 2 2.5 Fig7: Solution to model problem 4 on a 10 × 10 mesh. CONCLUSIONS The basic conservation equations can be written in the form of a differential equation for a general variable  . The concept of discretization can be used as a tool to solving these differential equations over a domain of interest. Finite Volume Method can be used to find the discrete solution of diffusion problems. Concept of Finite Volume Method  Subdivide the problem domain into non overlapping control volumes  Integrate the governing equation over each of these control volumes.  Representative value of variable = value of the variable at the geometric centre of CV  Piecewise profiles expressing the variation of φ between the grid points are used to evaluate the integrals.  Discretized equation obtained in this manner, represents the conservation principle for the finite control volume. REFERENCES [1] Jack J. Dongarra, Iain S. Du_, Danny C. Sorensen, and Henk A. van der Vorst. Solving Linear Systems on Vector and Shared Memory Computers. SIAM, Philadelphia, 1991. [2] Gene Golub and James M. Ortega Scienti_c Computing: An Introduction with Parallel Computing. Academic Press, Inc., Boston, 1993 [3] S.V. Patankar. Numerical Heat Transfer and Fluid Flow Hemisphere, Washington D.C., 1980 [4] R. V. Churchhill, J. W. Brown, and R. F. Verhey. Complex Variables and Applications McGraw-Hill, 1974 [5] Carnahan B, Luther A, and Wilkes J O, Applied Numerical Methods, New York, 1969.