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Digital technology


14.1 and 14.2
What are binary digits?
Computers use binary numbers, and
therefore use binary digits in place of
decimal digits.
The word bit is a shortening of the
words "Binary digit."
Whereas decimal digits have 10
possible values ranging from 0 to
9, bits have only two possible values: 0
and 1.
Decimal and binary numbers.
You can see that in binary numbers, each bit holds the value of
   increasing powers of 2.
That makes counting in binary pretty easy E.g 1011 means
(1 * 23) + (0 * 22) + (1 * 21) + (1 * 20) = 8 + 0 + 2 + 1 = 11
Some more examples
   10 = 1010
   12 = 1100
   13 = 1101
   16 = 10000
Conversions
 Change into   • Change into decimal
  binary        100
14              11010
31              10011
46              101010
59
Bits and bytes.
   Bits are rarely seen alone in computers. They are
    almost always bundled together into 8-bit
    collections, and these collections are called bytes.
   With 8 bits in a byte, you can represent 256
    values ranging from 0 to 255, as shown here:
                       0 = 00000000
                         1 = 00000001
                         2 = 00000010
                               ...
                       254 = 11111110
                       255 = 11111111
Bits and bytes continued
 CD uses 2 bytes, or 16 bits, per sample. That
  gives each sample a range from 0 to
  65,535, like this:
 0 = 0000000000000000
  1 = 0000000000000001
  2 = 0000000000000010
  ...
  65534 = 1111111111111110
  65535 = 1111111111111111
Analog at a glance
As a technology, analog is the process of
taking an audio or video signal (in most
cases, the human voice) and translating it
into electronic pulses.

Digital on the other hand is breaking the
signal into a binary format where the audio
or video data is represented by a series of
"1"s and "0"s.
A to D
   Digital technology breaks your voice (or
    television) signal into binary code—a
    series of 1s and 0s—transfers it to the
    other end where another device
    (phone, modem or TV) takes all the
    numbers and reassembles them into the
    original signal. The beauty of digital is
    that it knows what it should be when it
    reaches the end of the transmission.
Is the duplication perfect?
   But like any transferred
    technology, digital has a few
    shortcomings. Since devices are
    constantly translating, coding, and
    reassembling your voice, you won't get
    the same rich sound quality as you do
    with analog.
Can we use the digital phone
       using an analog line?
 There are digital-to-analog adapters that not
  only let you use analog equipment in a digital
  environment, but also safeguard against
  frying the internal circuitry of your
  phone, fax, modem, or laptop.
 Some adapters manufactured come designed
  to work with one specific piece of office
  equipment: phone, modem, laptop, or
  teleconferencer. Simply connect the adapter
  in between your digital line and your analog
  device.
Ancient way of recording the
           analog way
In the Beginning: Etching Tin
Thomas Edison is credited with creating the
   first device for recording and playing back
   sounds in 1877. His approach used a very
   simple mechanism to store an analog wave
   mechanically. In Edison's original
   phonograph, a diaphragm directly controlled
   a needle, and the needle scratched an analog
   signal onto a tinfoil cylinder .
http://communication.howstuffworks.com/analog-
   digital1.htm
An analog wave



                                              Image from
                                              www.howstuffworks.com




Analog Wave
What is it that the needle in Edison's phonograph is
scratching onto the tin cylinder? It is an analog wave
representing the vibrations created by your voice.
For example, here is a graph showing the analog
wave created by saying the word "hello":
Analog recording              contd….
The waveform was recorded electronically
  rather than on tinfoil, but the principle is
  the same.
What this graph is showing is the position of
  the microphone's diaphragm (Y axis) over
  time (X axis). The vibrations are very quick
  -- the diaphragm is vibrating on the order
  of 1,000 oscillations per second.
Notice that the waveform for the word
  "hello" is fairly complex.
Getting in to the digital world
In a CD (and any other digital recording technology), the
      goal is to create a recording with :

1.    very high fidelity (very high similarity between the
      original signal and the reproduced signal)

2.    perfect reproduction (the recording sounds the
      same every single time you play it no matter how
      many times you play it).
To accomplish these two goals, digital
  recording converts the analog wave into a
  stream of numbers and records the
  numbers instead of the wave.

The conversion is done by a device called
  an analog-to-digital converter (ADC). To
  play back the music, the stream of
  numbers is converted back to an analog
  wave by a digital-to-analog converter
  (DAC).

The analog wave produced by the DAC is
  amplified and fed to the speakers to
  produce the sound.
CDs and DVDs.
 http://electronics.howstuffworks.com/cd.ht
  m
 Exploring Sound: Digital Sound
    – Laser discs such as CDs and DVDs carry
     digital information, which is represented by
     the binary code -- combinations of 1s and
     0s. Any number can be represented in
     binary code.
COMPACT DISCS (CD’S)
 A CD is a fairly simple piece of plastic
  about 1.2 mm thick.
 The CD consists of a moulded piece of
  plastic that is impressed with
  microscopic bumps arranged as a
  single, continuous spiral track of data.
 A thin, reflective aluminium layer is
  placed onto the top of the disc, to cover
  the bumps.
 A thin acrylic layer is sprayed over the
  aluminum to protect it.
 The label is then printed onto the acrylic.
 A CD has a single spiral track of
  data circling from the inside of
  the disc to the outside.
 The data track is incredibly small.
  It is about 0.5 microns wide, with
  1.6 microns separating one track
  from the next.
 Due to the extreme thinness, the total
  length of the track squeezed onto this
  small disc is about 8 km.
 The information on the disc is read by
  shining a laser beam from the underside
  of the compact disc.
 Thus the laser is seeing the
  ―bumps‖, not the ―pits‖.
   The diagram below gives you some idea of
    how small a CD ―bump‖ is compared to a
    human hair.
   The sequence of bumps, the length of the
    bumps and the length of the spaces between
    the bumps provides the information that the
    CD player decodes.
 The laser that is used is an infrared laser
  emitting light at a wavelength of 780 nm.
 The laser passes through the plastic and is
  reflected off the aluminum coating on the
  bumps and the land between them.
   A very important point is that the height of the
    ―bumps‖ is approximately one quarter the
    wavelength of the laser light.

   When the laser light is passing over the
    ―land‖, all of the light is reflected off and it
    travels back to photoelectric cell.

   The photoelectric cell then produces an
    electric current.
 This electric current then goes on to
  generate sound in a loudspeaker (see
  loudspeaker application).
 Now lets look at what happens when
  the laser light approaches a ―bump‖.
 When the light reaches a bump, half of
  the light is reflected off the ―bump‖ and
  half of the light is reflected off the ―land‖.
 Because the bump is ¼ of a wavelength in
  height, the light being reflected off the land
  travels one half a wavelength further.
 The light reaching the photoelectric cell
  coming from the ―land‖ and the ―bump‖ is out
  of phase. This leads to partial cancellation
  and a decrease in intensity.
 This leads to decreased current being
  produced.
 As the laser moves along the track the
  intensity of the light falling on the
  photoelectric cell changes every time it
  comes into approaches or leaves a
  bump.
 It is this change in intensity which
  causes the fluctuation in electric
  current, which causes the movement of
  the loudspeaker and ultimately the
  fluctuation in sound.
USING INTERFERENCE TO KEEP A
            LASER ON TRACK

 The musical data on the CD is read
  from the inside out.
 The CD spins above the laser.
 After one revolution, the laser must
  move to the outside exactly 1.6 microns
  to remain on track.
 This requires a very precise tracking
  mechanism and an accurate correction
  mechanism to move the laser back on
  track if it should stray off the line.
 The tracking correction is achieved by
  first passing the laser beam through a
  diffraction grating, before it reaches the
  CD.
   When the monochromatic light passes
    through the diffraction grating a central
    beam and a first order diffracted beam
    will land on the CD.
 The central beam is focused on the
  track of the CD and passes over the
  bumps while the two first order
  diffracted beams are focused on the
  land on either side of the bumps.
 One diffracted beam is slightly ahead of
  the other.
   The laser beam is tracking correctly
    when the central beam is varying in
    intensity from 35% to 100% and the two
    diffracted beams have a constant
    intensity of 100%.
 If the laser beam should stray to one side of
  its correct position, then the variation in
  intensity of the main beam is now reduced.
 The leading tracking beam will also have a
  variation in the intensity because some of it is
  passing over the bumps.
 The tracking mechanism ―senses‖ that it
  must adjust the position of the laser down in
  order to put it back on track.
 If the laser beam were to stray to the other
  side of its correct position, then the variation
  in intensity of the main beam is again
  reduced.
 The TRAILING beam will now have a
  reduction in intensity.
 The tracking mechanism ―senses‖ that it must
  adjust its position up in order to get back on
  track.
CD’s and DVD’s
Data is stored digitally
   – A series of ones and zeros read by laser light
     reflected from the disk
Strong reflections correspond to constructive
  interference
   – These reflections are chosen to represent zeros
Weak reflections correspond to destructive
 interference
   – These reflections are chosen to represent ones
A CD’s pits and bumps
islands


500nm


           CD                           1.6 m

500nm

                           ©ikes080 7
              830nm

           islands


   320nm


           DVD                     740nm

  320nm

                      ©ikes0 807
              400nm
Reading a CD
As the disk rotates, the laser
  reflects off the sequence of
  bumps and lower areas into
  a photodector
   – The photodector converts the
     fluctuating reflected light
     intensity into an electrical string
     of zeros and ones


The pit depth is made equal to
  one-quarter of the
  wavelength of the light
Question
   If a laser emits light of wavelength
    760nm calculate how deep the pits
    would have to be for data to be stored
    appropriately?
Solution
 The depth of the pit is d
 From the bottom of pit the light travels
  an extra distance of 2d
 For interference to occur the difference
  in path travelled needs to be λ/2
           d = λ/4
           d = 760/4 nm
DVD’s
DVD’s use shorter wavelength lasers
  – The track separation, pit depth and
    minimum pit length are all smaller
  – Therefore, the DVD can store about 30
    times more information than a CD

  If the pit depth on a DVD is 0.4micrometre
     what laser wavelength is used?
In the case of CD sound, fidelity (the similarity
  between the original wave and the DAC's
  output ) is an important goal, so the sampling
  rate is 44,100 samples per second and the
  number of gradations is 65,536. At this
  level, the output of the DAC so closely
  matches the original waveform that the sound
  is essentially "perfect" to most human ears .
Why is a CD’s capacity approximately
                750 mb?
One thing about the CD's sampling rate and precision is
  that it produces a lot of data.
On a CD, the digital numbers produced by the ADC are
  stored as bytes, and it takes 2 bytes to represent
  65,536 gradations.
There are two sound streams being recorded (one for
  each of the speakers on a stereo system). A CD can
  store up to 74 minutes of music, so the total amount
  of digital data that must be stored on a CD is:
      44,100 samples/(channel*second) * 2
  bytes/sample * 2 channels * 74 minutes * 60
  seconds/minute = 783,216,000 bytes (Convert to
  kbs and then Mbs.)
Why store digitally?
There are five main reasons we prefer
  storing data in a digital format rather
  than analogue
 Quality
 Reproducibility
 Portability
 Manipulation
 Retrieval speed
Quality

Digital is less likely to be corrupted with
  time.
  – Consider a magnetic tape recording, the
    field strength will drop with time thus data
    can be lost. If it was digitally sorted as
    magnetic field and zero then the
    boundaries will still be readable even if
    strength diminishes.
Reproducibility
With digital data it is possible to assign
 locations

With analogue data it is usual to store
 alphabetically
Portability
 Analogue storage is sequential and is
  often large
 Digital storage allows for large amounts
  to be stored in pocket sized devices

What are the implications on society of
 the ever increasing storage capacity?
Manipulation
 Digital data is less prone to error in
  calculations
 Digital is easier to manipulate and
  process
Capacitance
Capacitance is the quantity of charge that
  can be stored per unit electric potential
           C = Q/V
The unit of capacitance is the Farad, F
A Farad is one coulomb per unit potential
  difference.
The capacitance of the Earth is 0.1F so
  we usually deal with pF
Charge couple device (CCD)
   Structure
   An individual pixel element consists of three
    sections as shown in the diagram below.

                       Channel stops




          Electrodes
                                           Photo-electron collector
                                            (potential energy well)

                                 ©IKES07




   The white bars represent electron-collecting
    zones of low electric potential, on the surface
    of very thin semiconducting silicon (5 - 8µm).
    These electron collecting zones are called the
    potential energy wells and are where
    photoelectrons are collected.
   The coloured bars are zones of higher electric
    potential that act as barriers to keep the electrons in
    the potential energy wells. The heights of these
    potentials can be changed by means of three sets of
    electrodes shown as green lines which run across the
    surface of the chip and work together to move the
    electrons in the potential well along the channels.

   The pixels are laid out in closely spaced columns or
    channels, which shows a section of three columns
    each with three pixels, giving 9 pixels in total.




                                         One pixel



                               ©IKES07
CCD
A CCD is basically just like any other silicon
  microchip except it has an array of pixels
  which are exposed and are sensitive to light.
  The size of such an array can vary from about
  256 x 256 to 2048 x 2048.

   Each pixel in this array counts the number of
    photons which fall upon it. The number of
    photons counted is stored as electric charge
    in a capacitor by each pixel. Each time a
    photon hits a pixel, a small amount of electric
    charge is added to the capacitor.
CCD
This process continues until the stored number
  counts in all of the capacitors are read. This
  process, called 'readout', happens very
  quickly in such a way that the data is read line
  by line until the last line has been read.

The CCD is then 'flushed' which means that the
  charges in all of the capacitors are reset to
  zero. The charge storage process then
  repeats.
Light and pixels
Photons have energy that is proportional to the wave
 frequency:
                    E=hf,
where h is Planck's constant and f is the wave
 frequency.

In a CCD being exposed, photons enter the chip from
   the rear. When a photon strikes the silicon, it is very
   likely to interact with an electron in the thin layer of
   silicon (approximately 8µm) and give sufficient
   energy to the electron to displace it from the silicon
   lattice. This creates an electron-hole pair.
 The displaced electron, or photoelectron, is
  collected in the nearest potential well while
  the hole created by the loss of the electron is
  eventually filled by an electron from the
  silicon substrate.
 The more photons which strike the silicon, the
  more electron-holes produced and so the
  more electrons stored within each potential
  well.
                 electrons captured

             -                        -    -
                 -   liberated electrons
                                           -   silicon substrate


                                               incident photon

                      incident photon
Photoelectric effect
 How does the photoelectric effect apply
  to CCDs?
 How much charge would a pixel hold if
  its capacitance was 30pF and the
  potential changes by 0.2mV?
 How many photons hit the pixel if the
  time for the potential change is 10ms?
What is a digital image?
Essentially, a digital image is just a long string of 1s
  and 0s that represent all the tiny colored dots -- or
  pixels -- that collectively make up the image. If you
  want to get a picture into this form, you have
  two options:

You can take a photograph
You can directly sample … you can use a digital
 camera
What is a digital image?
The first line shows the initial state with the coloured
  bucket three from the left hand side.
The second line shows position of the coloured
  bucket after the first swap. The free bucket at the
  right hand side contains the charge which is then
  digitised. The potential formed by the charge is
  amplified and converted into a digital signal by an
  Analogue to Digital Converter (ADC).
After each swap, the buckets move one place further
  to the right.
   Consider a CCD where the maximum output voltage
    from a pixel, after amplification, is 0.8V. If this is to
    be converted into a 3-bit binary number, then there
    will be 8 different quantisation levels




   e.g. The voltage at the output is 0.42 V. This falls in
    the quantisation level represented by 4 and will give a
    digital signal of 100.
Capturing image
The image sensor employed by
  most digital cameras is a charge
  coupled device (CCD). Some
                                        A CMOS sensor
  cameras use complementary
  metal oxide semiconductor
  (CMOS) technology instead. Both
  CCD and CMOS image sensors
  convert light into electrons.

A simplified way to think about these
  sensors is to think of a 2-D array
  of thousands or millions of tiny
  solar cells.
Digitisation of the light
 http://www.olympusmicro.com/primer/digitalimaging
  /concepts/concepts.html
 Electrode measures the potential difference
  developed across the pixel and this is then
  converted into a digital signal
 Pixel position is also stored
Capturing Color
   Unfortunately, each photosite is
    colorblind. It only keeps track of the
    total intensity of the light that strikes its
    surface. In order to get a full color
    image, most sensors use filtering to
    look at the light in its three primary
    colors. Once the camera records all
    three colors, it combines them to create
    the full spectrum
For illustrations and explanations visit:
http://electronics.howstuffworks.com/digital-camera3.htm
Definitions
You need to know
 Quantum efficiency
 Magnification
 Resolution
Quantum Efficiency
 This is the ratio of the number of
  photoelectrons emitted to the number of
  photons incident on the pixel
 This will never be 100% due to
  scattering or non-interaction with
  substrate

                     Number of photoelect rons
Quantum efficiency                               100%
                       Number of photons
 Quantum efficiency is a measure of the
  sensitivity of a light detector. Many
  photoelectric materials typically emit an
  electron for every 5 to 10 incident
  photons and so therefore have a
  quantum efficiency of between 10 and
  20%.
 Typical values are 70-80%
Magnification
The ratio of the length of the image on the
 CCD to the length of the real object

                                           lens       CCD


 O
                                                            I


                                          ©IKES07

                                                      Image
     Object


                                      image height    I
              linear magnificat ion
                                      object height   O
Magnification
         Resolution
         Two points on an object will be resolved if
          the images of the two points are at least
          two pixels apart
                                  charge
charge




                      charge




                                                    pixels
                       pixels




                                           pixels
Digital Camera Resolution



                                   The more pixels a
                                    camera has, the more
                                    detail it can capture and
  Photo courtesy Morguefile         the larger pictures can
The size of an image taken at
    different resolutions
                                    be without becoming
                                    blurry or "grainy."
Image quality
 Larger magnification = more pixels
  activated = more detailed
 Greater resolution = more pixels /unit
  length = more detailed
Use of CCDs
 Digital cameras
 Video cameras
 Telescopes
 Medical imaging
 Photocopiers
 Barcode readers
Advantages over emulsion
Reusable - once an image has been captured, the CCD can then
  be reset ready for the next image to be captured.
  Photographic emulsion is a 'one off' process and cannot be
  reused.

   Greater sensitivity - modern CCDs are over 1000 million times
    more sensitive than the human eye

   Greater colour response - modern CCDs will respond to
    electromagnetic radiation over a wider range of wavelengths
    than either the human eye or photographic emulsion

   Linear response - the output voltage from a CCD is
    proportional to the charge collected by each pixel, which in turn
    is proportional to the number of photons incident on the CCD.
Image retrieval
 Light focussed on CCD
 Photoelectric effect
 Number of electrons released from each
  pixel will vary
 Potential change occurs
 Pixel location sorted along with pd
  change as a digital signal
 Digital signal converted to image

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Digital technology

  • 2. What are binary digits? Computers use binary numbers, and therefore use binary digits in place of decimal digits. The word bit is a shortening of the words "Binary digit." Whereas decimal digits have 10 possible values ranging from 0 to 9, bits have only two possible values: 0 and 1.
  • 3. Decimal and binary numbers. You can see that in binary numbers, each bit holds the value of increasing powers of 2. That makes counting in binary pretty easy E.g 1011 means (1 * 23) + (0 * 22) + (1 * 21) + (1 * 20) = 8 + 0 + 2 + 1 = 11 Some more examples 10 = 1010 12 = 1100 13 = 1101 16 = 10000
  • 4. Conversions  Change into • Change into decimal binary 100 14 11010 31 10011 46 101010 59
  • 5. Bits and bytes.  Bits are rarely seen alone in computers. They are almost always bundled together into 8-bit collections, and these collections are called bytes.  With 8 bits in a byte, you can represent 256 values ranging from 0 to 255, as shown here:  0 = 00000000 1 = 00000001 2 = 00000010 ... 254 = 11111110 255 = 11111111
  • 6. Bits and bytes continued  CD uses 2 bytes, or 16 bits, per sample. That gives each sample a range from 0 to 65,535, like this:  0 = 0000000000000000 1 = 0000000000000001 2 = 0000000000000010 ... 65534 = 1111111111111110 65535 = 1111111111111111
  • 7. Analog at a glance As a technology, analog is the process of taking an audio or video signal (in most cases, the human voice) and translating it into electronic pulses. Digital on the other hand is breaking the signal into a binary format where the audio or video data is represented by a series of "1"s and "0"s.
  • 8. A to D  Digital technology breaks your voice (or television) signal into binary code—a series of 1s and 0s—transfers it to the other end where another device (phone, modem or TV) takes all the numbers and reassembles them into the original signal. The beauty of digital is that it knows what it should be when it reaches the end of the transmission.
  • 9. Is the duplication perfect?  But like any transferred technology, digital has a few shortcomings. Since devices are constantly translating, coding, and reassembling your voice, you won't get the same rich sound quality as you do with analog.
  • 10. Can we use the digital phone using an analog line?  There are digital-to-analog adapters that not only let you use analog equipment in a digital environment, but also safeguard against frying the internal circuitry of your phone, fax, modem, or laptop.  Some adapters manufactured come designed to work with one specific piece of office equipment: phone, modem, laptop, or teleconferencer. Simply connect the adapter in between your digital line and your analog device.
  • 11. Ancient way of recording the analog way In the Beginning: Etching Tin Thomas Edison is credited with creating the first device for recording and playing back sounds in 1877. His approach used a very simple mechanism to store an analog wave mechanically. In Edison's original phonograph, a diaphragm directly controlled a needle, and the needle scratched an analog signal onto a tinfoil cylinder . http://communication.howstuffworks.com/analog- digital1.htm
  • 12. An analog wave Image from www.howstuffworks.com Analog Wave What is it that the needle in Edison's phonograph is scratching onto the tin cylinder? It is an analog wave representing the vibrations created by your voice. For example, here is a graph showing the analog wave created by saying the word "hello":
  • 13. Analog recording contd…. The waveform was recorded electronically rather than on tinfoil, but the principle is the same. What this graph is showing is the position of the microphone's diaphragm (Y axis) over time (X axis). The vibrations are very quick -- the diaphragm is vibrating on the order of 1,000 oscillations per second. Notice that the waveform for the word "hello" is fairly complex.
  • 14. Getting in to the digital world In a CD (and any other digital recording technology), the goal is to create a recording with : 1. very high fidelity (very high similarity between the original signal and the reproduced signal) 2. perfect reproduction (the recording sounds the same every single time you play it no matter how many times you play it).
  • 15. To accomplish these two goals, digital recording converts the analog wave into a stream of numbers and records the numbers instead of the wave. The conversion is done by a device called an analog-to-digital converter (ADC). To play back the music, the stream of numbers is converted back to an analog wave by a digital-to-analog converter (DAC). The analog wave produced by the DAC is amplified and fed to the speakers to produce the sound.
  • 16. CDs and DVDs.  http://electronics.howstuffworks.com/cd.ht m  Exploring Sound: Digital Sound – Laser discs such as CDs and DVDs carry digital information, which is represented by the binary code -- combinations of 1s and 0s. Any number can be represented in binary code.
  • 17. COMPACT DISCS (CD’S)  A CD is a fairly simple piece of plastic about 1.2 mm thick.  The CD consists of a moulded piece of plastic that is impressed with microscopic bumps arranged as a single, continuous spiral track of data.  A thin, reflective aluminium layer is placed onto the top of the disc, to cover the bumps.
  • 18.  A thin acrylic layer is sprayed over the aluminum to protect it.  The label is then printed onto the acrylic.
  • 19.  A CD has a single spiral track of data circling from the inside of the disc to the outside.  The data track is incredibly small. It is about 0.5 microns wide, with 1.6 microns separating one track from the next.
  • 20.  Due to the extreme thinness, the total length of the track squeezed onto this small disc is about 8 km.  The information on the disc is read by shining a laser beam from the underside of the compact disc.  Thus the laser is seeing the ―bumps‖, not the ―pits‖.
  • 21. The diagram below gives you some idea of how small a CD ―bump‖ is compared to a human hair.
  • 22. The sequence of bumps, the length of the bumps and the length of the spaces between the bumps provides the information that the CD player decodes.
  • 23.  The laser that is used is an infrared laser emitting light at a wavelength of 780 nm.  The laser passes through the plastic and is reflected off the aluminum coating on the bumps and the land between them.
  • 24. A very important point is that the height of the ―bumps‖ is approximately one quarter the wavelength of the laser light.  When the laser light is passing over the ―land‖, all of the light is reflected off and it travels back to photoelectric cell.  The photoelectric cell then produces an electric current.
  • 25.  This electric current then goes on to generate sound in a loudspeaker (see loudspeaker application).  Now lets look at what happens when the laser light approaches a ―bump‖.  When the light reaches a bump, half of the light is reflected off the ―bump‖ and half of the light is reflected off the ―land‖.
  • 26.
  • 27.  Because the bump is ¼ of a wavelength in height, the light being reflected off the land travels one half a wavelength further.  The light reaching the photoelectric cell coming from the ―land‖ and the ―bump‖ is out of phase. This leads to partial cancellation and a decrease in intensity.  This leads to decreased current being produced.
  • 28.  As the laser moves along the track the intensity of the light falling on the photoelectric cell changes every time it comes into approaches or leaves a bump.  It is this change in intensity which causes the fluctuation in electric current, which causes the movement of the loudspeaker and ultimately the fluctuation in sound.
  • 29. USING INTERFERENCE TO KEEP A LASER ON TRACK  The musical data on the CD is read from the inside out.  The CD spins above the laser.  After one revolution, the laser must move to the outside exactly 1.6 microns to remain on track.
  • 30.  This requires a very precise tracking mechanism and an accurate correction mechanism to move the laser back on track if it should stray off the line.  The tracking correction is achieved by first passing the laser beam through a diffraction grating, before it reaches the CD.
  • 31. When the monochromatic light passes through the diffraction grating a central beam and a first order diffracted beam will land on the CD.
  • 32.  The central beam is focused on the track of the CD and passes over the bumps while the two first order diffracted beams are focused on the land on either side of the bumps.  One diffracted beam is slightly ahead of the other.
  • 33. The laser beam is tracking correctly when the central beam is varying in intensity from 35% to 100% and the two diffracted beams have a constant intensity of 100%.
  • 34.  If the laser beam should stray to one side of its correct position, then the variation in intensity of the main beam is now reduced.  The leading tracking beam will also have a variation in the intensity because some of it is passing over the bumps.  The tracking mechanism ―senses‖ that it must adjust the position of the laser down in order to put it back on track.
  • 35.  If the laser beam were to stray to the other side of its correct position, then the variation in intensity of the main beam is again reduced.  The TRAILING beam will now have a reduction in intensity.  The tracking mechanism ―senses‖ that it must adjust its position up in order to get back on track.
  • 36. CD’s and DVD’s Data is stored digitally – A series of ones and zeros read by laser light reflected from the disk Strong reflections correspond to constructive interference – These reflections are chosen to represent zeros Weak reflections correspond to destructive interference – These reflections are chosen to represent ones
  • 37. A CD’s pits and bumps
  • 38. islands 500nm CD 1.6 m 500nm ©ikes080 7 830nm islands 320nm DVD 740nm 320nm ©ikes0 807 400nm
  • 39. Reading a CD As the disk rotates, the laser reflects off the sequence of bumps and lower areas into a photodector – The photodector converts the fluctuating reflected light intensity into an electrical string of zeros and ones The pit depth is made equal to one-quarter of the wavelength of the light
  • 40. Question  If a laser emits light of wavelength 760nm calculate how deep the pits would have to be for data to be stored appropriately?
  • 41. Solution  The depth of the pit is d  From the bottom of pit the light travels an extra distance of 2d  For interference to occur the difference in path travelled needs to be λ/2 d = λ/4 d = 760/4 nm
  • 42. DVD’s DVD’s use shorter wavelength lasers – The track separation, pit depth and minimum pit length are all smaller – Therefore, the DVD can store about 30 times more information than a CD If the pit depth on a DVD is 0.4micrometre what laser wavelength is used?
  • 43. In the case of CD sound, fidelity (the similarity between the original wave and the DAC's output ) is an important goal, so the sampling rate is 44,100 samples per second and the number of gradations is 65,536. At this level, the output of the DAC so closely matches the original waveform that the sound is essentially "perfect" to most human ears .
  • 44. Why is a CD’s capacity approximately 750 mb? One thing about the CD's sampling rate and precision is that it produces a lot of data. On a CD, the digital numbers produced by the ADC are stored as bytes, and it takes 2 bytes to represent 65,536 gradations. There are two sound streams being recorded (one for each of the speakers on a stereo system). A CD can store up to 74 minutes of music, so the total amount of digital data that must be stored on a CD is: 44,100 samples/(channel*second) * 2 bytes/sample * 2 channels * 74 minutes * 60 seconds/minute = 783,216,000 bytes (Convert to kbs and then Mbs.)
  • 45. Why store digitally? There are five main reasons we prefer storing data in a digital format rather than analogue  Quality  Reproducibility  Portability  Manipulation  Retrieval speed
  • 46. Quality Digital is less likely to be corrupted with time. – Consider a magnetic tape recording, the field strength will drop with time thus data can be lost. If it was digitally sorted as magnetic field and zero then the boundaries will still be readable even if strength diminishes.
  • 47. Reproducibility With digital data it is possible to assign locations With analogue data it is usual to store alphabetically
  • 48. Portability  Analogue storage is sequential and is often large  Digital storage allows for large amounts to be stored in pocket sized devices What are the implications on society of the ever increasing storage capacity?
  • 49. Manipulation  Digital data is less prone to error in calculations  Digital is easier to manipulate and process
  • 50. Capacitance Capacitance is the quantity of charge that can be stored per unit electric potential C = Q/V The unit of capacitance is the Farad, F A Farad is one coulomb per unit potential difference. The capacitance of the Earth is 0.1F so we usually deal with pF
  • 51. Charge couple device (CCD)  Structure
  • 52. An individual pixel element consists of three sections as shown in the diagram below. Channel stops Electrodes Photo-electron collector (potential energy well) ©IKES07  The white bars represent electron-collecting zones of low electric potential, on the surface of very thin semiconducting silicon (5 - 8µm). These electron collecting zones are called the potential energy wells and are where photoelectrons are collected.
  • 53. The coloured bars are zones of higher electric potential that act as barriers to keep the electrons in the potential energy wells. The heights of these potentials can be changed by means of three sets of electrodes shown as green lines which run across the surface of the chip and work together to move the electrons in the potential well along the channels.  The pixels are laid out in closely spaced columns or channels, which shows a section of three columns each with three pixels, giving 9 pixels in total. One pixel ©IKES07
  • 54. CCD A CCD is basically just like any other silicon microchip except it has an array of pixels which are exposed and are sensitive to light. The size of such an array can vary from about 256 x 256 to 2048 x 2048.  Each pixel in this array counts the number of photons which fall upon it. The number of photons counted is stored as electric charge in a capacitor by each pixel. Each time a photon hits a pixel, a small amount of electric charge is added to the capacitor.
  • 55. CCD This process continues until the stored number counts in all of the capacitors are read. This process, called 'readout', happens very quickly in such a way that the data is read line by line until the last line has been read. The CCD is then 'flushed' which means that the charges in all of the capacitors are reset to zero. The charge storage process then repeats.
  • 56. Light and pixels Photons have energy that is proportional to the wave frequency: E=hf, where h is Planck's constant and f is the wave frequency. In a CCD being exposed, photons enter the chip from the rear. When a photon strikes the silicon, it is very likely to interact with an electron in the thin layer of silicon (approximately 8µm) and give sufficient energy to the electron to displace it from the silicon lattice. This creates an electron-hole pair.
  • 57.  The displaced electron, or photoelectron, is collected in the nearest potential well while the hole created by the loss of the electron is eventually filled by an electron from the silicon substrate.  The more photons which strike the silicon, the more electron-holes produced and so the more electrons stored within each potential well. electrons captured - - - - liberated electrons - silicon substrate incident photon incident photon
  • 58. Photoelectric effect  How does the photoelectric effect apply to CCDs?  How much charge would a pixel hold if its capacitance was 30pF and the potential changes by 0.2mV?  How many photons hit the pixel if the time for the potential change is 10ms?
  • 59. What is a digital image? Essentially, a digital image is just a long string of 1s and 0s that represent all the tiny colored dots -- or pixels -- that collectively make up the image. If you want to get a picture into this form, you have two options: You can take a photograph You can directly sample … you can use a digital camera
  • 60. What is a digital image? The first line shows the initial state with the coloured bucket three from the left hand side. The second line shows position of the coloured bucket after the first swap. The free bucket at the right hand side contains the charge which is then digitised. The potential formed by the charge is amplified and converted into a digital signal by an Analogue to Digital Converter (ADC). After each swap, the buckets move one place further to the right.
  • 61. Consider a CCD where the maximum output voltage from a pixel, after amplification, is 0.8V. If this is to be converted into a 3-bit binary number, then there will be 8 different quantisation levels  e.g. The voltage at the output is 0.42 V. This falls in the quantisation level represented by 4 and will give a digital signal of 100.
  • 62. Capturing image The image sensor employed by most digital cameras is a charge coupled device (CCD). Some A CMOS sensor cameras use complementary metal oxide semiconductor (CMOS) technology instead. Both CCD and CMOS image sensors convert light into electrons. A simplified way to think about these sensors is to think of a 2-D array of thousands or millions of tiny solar cells.
  • 63. Digitisation of the light  http://www.olympusmicro.com/primer/digitalimaging /concepts/concepts.html  Electrode measures the potential difference developed across the pixel and this is then converted into a digital signal  Pixel position is also stored
  • 64. Capturing Color  Unfortunately, each photosite is colorblind. It only keeps track of the total intensity of the light that strikes its surface. In order to get a full color image, most sensors use filtering to look at the light in its three primary colors. Once the camera records all three colors, it combines them to create the full spectrum For illustrations and explanations visit: http://electronics.howstuffworks.com/digital-camera3.htm
  • 65. Definitions You need to know  Quantum efficiency  Magnification  Resolution
  • 66. Quantum Efficiency  This is the ratio of the number of photoelectrons emitted to the number of photons incident on the pixel  This will never be 100% due to scattering or non-interaction with substrate Number of photoelect rons Quantum efficiency 100% Number of photons
  • 67.  Quantum efficiency is a measure of the sensitivity of a light detector. Many photoelectric materials typically emit an electron for every 5 to 10 incident photons and so therefore have a quantum efficiency of between 10 and 20%.  Typical values are 70-80%
  • 68. Magnification The ratio of the length of the image on the CCD to the length of the real object lens CCD O I ©IKES07 Image Object image height I linear magnificat ion object height O
  • 69. Magnification Resolution Two points on an object will be resolved if the images of the two points are at least two pixels apart charge charge charge pixels pixels pixels
  • 70. Digital Camera Resolution  The more pixels a camera has, the more detail it can capture and Photo courtesy Morguefile the larger pictures can The size of an image taken at different resolutions be without becoming blurry or "grainy."
  • 71. Image quality  Larger magnification = more pixels activated = more detailed  Greater resolution = more pixels /unit length = more detailed
  • 72. Use of CCDs  Digital cameras  Video cameras  Telescopes  Medical imaging  Photocopiers  Barcode readers
  • 73. Advantages over emulsion Reusable - once an image has been captured, the CCD can then be reset ready for the next image to be captured. Photographic emulsion is a 'one off' process and cannot be reused.  Greater sensitivity - modern CCDs are over 1000 million times more sensitive than the human eye  Greater colour response - modern CCDs will respond to electromagnetic radiation over a wider range of wavelengths than either the human eye or photographic emulsion   Linear response - the output voltage from a CCD is proportional to the charge collected by each pixel, which in turn is proportional to the number of photons incident on the CCD.
  • 74. Image retrieval  Light focussed on CCD  Photoelectric effect  Number of electrons released from each pixel will vary  Potential change occurs  Pixel location sorted along with pd change as a digital signal  Digital signal converted to image