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Daniel Bernoulli, in 1738, was the first to understand air
pressure from a molecular point of view. He drew a picture of a vertical cylinder, closed at the
bottom, with a piston at the top, the piston having a weight on it, both piston and weight being
supported by the air pressure inside the cylinder. He described what went on inside the cylinder
as follows: “let the cavity contain very minute corpuscles, which are driven hither and thither
with a very rapid motion; so that these corpuscles, when they strike against the piston and sustain
it by their repeated impacts, form an elastic fluid which will expand of itself if the weight is
removed or diminished…”

Movement of atom according


The Link between Molecular Energy and Pressure
It is not difficult to extend Bernoulli’s picture to a quantitative description, relating the gas
pressure to the molecular velocities. As a warm up exercise, let us consider a single perfectly
elastic particle, of mass m, bouncing rapidly back and forth at speed v inside a narrow cylinder of
length L with a piston at one end, so all motion is along the same line.

Click here: Demonstration

What is the force on the piston?

Obviously, the piston doesn’t feel a smooth continuous force, but a series of equally spaced
impacts. However, if the piston is much heavier than the particle, this will have the same effect
as a smooth force over times long compared with the interval between impacts. So what is the
value of the equivalent smooth force?
Using Newton’s law in the form force = rate of change of momentum, we see that the particle’s
momentum changes by 2mv each time it hits the piston. The time between hits is 2L/v, so the
frequency of hits is v/2L per second. This means that if there were no balancing force, by
conservation of momentum the particle would cause the momentum of the piston to change by
2mv  v/2L units in each second. This is the rate of change of momentum, and so must be equal to
the balancing force, which is therefore F = mv2/L.

We now generalize to the case of many particles bouncing around inside a rectangular box, of
length L in the x-direction (which is along an edge of the box). The total force on the side of
area A perpendicular to the x-direction is just a sum of single particle terms, the relevant velocity
being the component of the velocity in the x-direction. The pressure is just the force per unit
area, P = F/A. Of course, we don’t know what the velocities of the particles are in an actual gas,
but it turns out that we don’t need the details. If we sum N contributions, one from each particle
in the box, each contribution proportional to vx2 for that particle, the sum just gives us N times
the average value of vx2. That is to say,




where there are N particles in a box of volume V. Next we note that the particles are equally
likely to be moving in any direction, so the average value of vx2 must be the same as that
of vy2 or vz2, and since v2 = vx2 + vy2 + vz2, it follows that
This is a surprisingly simple result! The macroscopic pressure of a gas relates directly to the
average kinetic energy per molecule. Of course, in the above we have not thought about possible
complications caused by interactions between particles, but in fact for gases like air at room
temperature these interactions are very small. Furthermore, it is well established experimentally
that most gases satisfy the Gas Law over a wide temperature range:

                                            PV = nRT

for n moles of gas, that is, n = N/NA, with NA Avogadro’s number and R the gas constant.

Introducing Boltzmann’s constant k = R/NA, it is easy to check from our result for the pressure
and the ideal gas law thatthe average molecular kinetic energy is proportional to the absolute
temperature,




Boltzmann’s constant k = 1.38.10-23 joules/K.




Newton's Laws and Collisions

Applying Newton's Laws to an ideal gas under the assumptions of kinetic theoryallows the
determination of the average force on container walls. This treatment assumes that the collisions
with the walls are perfectly elastic.
In this development, an overbar indicates an average quantity. In the expression for the average
force from N molecules, it is important to note that it is the average of the square of the velocity
which is used, and that this is distinctly different from the square of the average velocity.



Gas Pressure from Kinetic Theory

Under the assumptions of kinetic theory, the average force on container walls has been
determined to be




                                                         and assuming random speeds in all
                                                         directions


The average force and pressure on a given wall
depends only upon the components of
                                                         Then the pressure in a container can be
velocity toward that wall. But it can be expressed in
                                                         expressed as
terms of the average of the entire translational kinetic
energy using the assumption that the molecular
motion is random.


Expressed in terms of average molecular kinetic energy:


                    This leads to a concept of kinetic temperature and to theideal gas law.




                                       Kinetic Temperature

The expression for gas pressure developed from kinetic theory relates pressure and volume to the
average molecular kinetic energy. Comparison with the ideal gas law leads to an expression
for temperature sometimes referred to as the kinetic temperature.
This leads to the expression




The more familiar form expresses the average molecular kinetic energy:




It is important to note that the average kinetic energy used here is limited to the translational
kinetic energy of the molecules. That is, they are treated as point masses and no account is made
of internal degrees of freedom such as molecular rotation and vibration. This distinction becomes
quite important when you deal with subjects like the specific heats of gases. When you try to
assess specific heat, you must account for all the energy possessed by the molecules, and the
temperature as ordinarily measured does not account for molecular rotation and vibration. The
kinetic temperature is the variable needed for subjects like heat transfer, because it is the
translational kinetic energy which leads to energy transfer from a hot area (larger kinetic
temperature, higher molecular speeds) to a cold area (lower molecular speeds) in direct
collisional transfer.

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Pressure and kinetic energy of particles

  • 1. Daniel Bernoulli, in 1738, was the first to understand air pressure from a molecular point of view. He drew a picture of a vertical cylinder, closed at the bottom, with a piston at the top, the piston having a weight on it, both piston and weight being supported by the air pressure inside the cylinder. He described what went on inside the cylinder as follows: “let the cavity contain very minute corpuscles, which are driven hither and thither with a very rapid motion; so that these corpuscles, when they strike against the piston and sustain it by their repeated impacts, form an elastic fluid which will expand of itself if the weight is removed or diminished…” Movement of atom according The Link between Molecular Energy and Pressure It is not difficult to extend Bernoulli’s picture to a quantitative description, relating the gas pressure to the molecular velocities. As a warm up exercise, let us consider a single perfectly elastic particle, of mass m, bouncing rapidly back and forth at speed v inside a narrow cylinder of length L with a piston at one end, so all motion is along the same line. Click here: Demonstration What is the force on the piston? Obviously, the piston doesn’t feel a smooth continuous force, but a series of equally spaced impacts. However, if the piston is much heavier than the particle, this will have the same effect as a smooth force over times long compared with the interval between impacts. So what is the value of the equivalent smooth force?
  • 2. Using Newton’s law in the form force = rate of change of momentum, we see that the particle’s momentum changes by 2mv each time it hits the piston. The time between hits is 2L/v, so the frequency of hits is v/2L per second. This means that if there were no balancing force, by conservation of momentum the particle would cause the momentum of the piston to change by 2mv v/2L units in each second. This is the rate of change of momentum, and so must be equal to the balancing force, which is therefore F = mv2/L. We now generalize to the case of many particles bouncing around inside a rectangular box, of length L in the x-direction (which is along an edge of the box). The total force on the side of area A perpendicular to the x-direction is just a sum of single particle terms, the relevant velocity being the component of the velocity in the x-direction. The pressure is just the force per unit area, P = F/A. Of course, we don’t know what the velocities of the particles are in an actual gas, but it turns out that we don’t need the details. If we sum N contributions, one from each particle in the box, each contribution proportional to vx2 for that particle, the sum just gives us N times the average value of vx2. That is to say, where there are N particles in a box of volume V. Next we note that the particles are equally likely to be moving in any direction, so the average value of vx2 must be the same as that of vy2 or vz2, and since v2 = vx2 + vy2 + vz2, it follows that
  • 3. This is a surprisingly simple result! The macroscopic pressure of a gas relates directly to the average kinetic energy per molecule. Of course, in the above we have not thought about possible complications caused by interactions between particles, but in fact for gases like air at room temperature these interactions are very small. Furthermore, it is well established experimentally that most gases satisfy the Gas Law over a wide temperature range: PV = nRT for n moles of gas, that is, n = N/NA, with NA Avogadro’s number and R the gas constant. Introducing Boltzmann’s constant k = R/NA, it is easy to check from our result for the pressure and the ideal gas law thatthe average molecular kinetic energy is proportional to the absolute temperature, Boltzmann’s constant k = 1.38.10-23 joules/K. Newton's Laws and Collisions Applying Newton's Laws to an ideal gas under the assumptions of kinetic theoryallows the determination of the average force on container walls. This treatment assumes that the collisions with the walls are perfectly elastic.
  • 4. In this development, an overbar indicates an average quantity. In the expression for the average force from N molecules, it is important to note that it is the average of the square of the velocity which is used, and that this is distinctly different from the square of the average velocity. Gas Pressure from Kinetic Theory Under the assumptions of kinetic theory, the average force on container walls has been determined to be and assuming random speeds in all directions The average force and pressure on a given wall depends only upon the components of Then the pressure in a container can be velocity toward that wall. But it can be expressed in expressed as terms of the average of the entire translational kinetic energy using the assumption that the molecular motion is random. Expressed in terms of average molecular kinetic energy: This leads to a concept of kinetic temperature and to theideal gas law. Kinetic Temperature The expression for gas pressure developed from kinetic theory relates pressure and volume to the average molecular kinetic energy. Comparison with the ideal gas law leads to an expression for temperature sometimes referred to as the kinetic temperature.
  • 5. This leads to the expression The more familiar form expresses the average molecular kinetic energy: It is important to note that the average kinetic energy used here is limited to the translational kinetic energy of the molecules. That is, they are treated as point masses and no account is made of internal degrees of freedom such as molecular rotation and vibration. This distinction becomes quite important when you deal with subjects like the specific heats of gases. When you try to assess specific heat, you must account for all the energy possessed by the molecules, and the temperature as ordinarily measured does not account for molecular rotation and vibration. The kinetic temperature is the variable needed for subjects like heat transfer, because it is the translational kinetic energy which leads to energy transfer from a hot area (larger kinetic temperature, higher molecular speeds) to a cold area (lower molecular speeds) in direct collisional transfer.