SlideShare uma empresa Scribd logo
1 de 19
Baixar para ler offline
:




2008                                                                                                                                                                       :
                                                          .                                     q = 12°C                                     ( H 2O2 )
                                                                                                                                    2 H 2O2( aq) = 2 H 2O( l ) + O2( g ) :
                                                ( VM = 24 L.mol -1                                                                                                                           )
                               . [ H 2O2 ]0 = 8, 0 ´10 -2 mol.L-1                                                                    VS = 500mL                       t =0
                                       :                                                                                          (V )
                                                                                                                                   O2


         t ( min )            0             4                 8            12                 16             20              24           28               32           36             40

        VO2 ( mL )            0            60            114               162                204           234              253         276               288         294             300

    [ H 2O2 ] mol.L-1
                                                                                                                              .                                                        .1
                                       . VO2       VM         VS       [ H 2O2 ]0     :             t                                   [ H 2O2 ]                                      .2
                                                                                                                                                       .                           - .3
                                                                                          .                                   [ H 2O2 ] = f ( t )                              -
                                                                                                                         .                                                         -
                     .                                                     . t2 = 24 min                 t1 = 16 min                                                               -
                                                                                                                                    .        t1 2                                  -
.                .                                                [ H 2O2 ]                                           q ' = 35°C                                                       .4

    .                                                                                                                                                                          :
                                             2 H 2O2 (aq ) ® O2 ( g ) + 2 H 2O(l )                                                                 .                                   .1
                                                                                                                                               :
                                           ( mol )
                                                                                                                                    . n = [ H 2O2 ]0 .VS = 8, 0 ´10-2 ´ 0,5
                                  0               n                    0                  0
                                                                                                                                                                    . n = 4 ´ 10-2 mol
                              x (t )        n - 2x (t )              x (t )         2x ( t )
                                                                                                                                     [ H 2O2 ]                                         .2
                                xf            n - 2x f                xf             2x f
                                                                                                               . VO2         VM     VS [ H 2O2 ]0           :          t
                            ni ( H 2O2 ) - 2 x ( t )                             x (t )
              [ H 2O2 ] =                              = [ H 2O2 ]0 - 2.                                n( H 2O2 ) ( t ) = ni ( H 2O2 ) - 2 x ( t ) :           t
                                      VS                                          VS
                                                                                                                     2                                      VO2
                                                                        . [ H 2O2 ] = [ H 2O2 ]0 -                      .VO :                n ( O2 ) =              =x :
                                                                                                                  VS .VM 2                                  VM
                                                                                                                                                            .                      - .3
                                                                                            1                                                                            2
                                                                  . [ H 2O2 ] = 8,0 ´ 10-2 - .VO2 :                           [ H 2O2 ] = 8, 0 ´10-2 -                        .VO :
                                                                                            6                                                                        0, 5 ´ 24 2


                                                                                     1
t ( min )                   0             4            8            12            16           20             24         28               32          36            40

   [ H 2O2 ] ´10-2 mol.L-1               8,0            7,0      6,1              5,3           4,6          4,1            3,8        3,4              3,2        3,1            3,0

                                                                                           .                                   [ H 2O2 ] = f ( t )                                -


                                                                                                                        .                                                             -
                                                                                                                                     1 dx
                                                                                                                            vvol =     .   :
                                                                                                                                     VS dt
                                                                                                    d [ H 2O2 ]         1 d                 2 dx
                                                                                                .                  =         ( n - 2x) = -       :
                                                                                                        dt             VS dt               VS dt
                                                                                                                                                          1 d [ H 2O2 ]
                                                                                                                                                  vvol = - .             :
                                                                                                                                                          2      dt
                                                                                                                                                            d [ H 2O2 ]
                                                                                  .t                 [ H 2O2 ] = f ( t )                                                :
                                                                                                                                                                dt
                                                                              . t2 = 24 min               t1 = 16 min                                                                 -
                                                                                                          1 ( 7, 0 - 4, 6 ) ´ 10
                                                                                                                                           -3

                                                                                           vvol ( t1 ) = - .                                     = 7, 5 ´10 -4 mol.L-1 .min -1
                                                                                                          2        16 - 0
                                                                                                           1 ( 7, 0 - 5,5 ) ´ 10
                                                                                                                                            -3

                                                                                            vvol ( t2 ) = - .                                    = 3,1´ 10-5 mol.L-1.min -1
                                                                                                           2        24 - 0
                                                                                                                 .
                                                                                                                                       .         t1 2                                 -
                                                                                                                                  [ H 2O2 ]0                                  xmax
                                                (                                                   ) . [ H 2O2 ] ( t1/2 ) =                     :            x ( t1/ 2 ) =        :
                                                                                                                                      2                                        2
                                                                                                                                                 0, 08
                                                                .(                     ) t1/ 2 » 20 min :              [ H 2O2 ] ( t1/2 ) =            = 40mmol .L-1 :
                                                                                                                                                   2
                          . (                   ) q ' = 35°C                                                                           [ H 2O2 ]                                   .4
                                  ,
2008                                                                                                                                                                     :
                                 .(                                           )
                                                         30mL                                                                               m = 36mg                   Mg ( S )
                                                                                                                                       .
                                                    .                                                                                                                              .1

                   (H (
                      +
                          aq )           )
                                 / H 2( g ) :                                                                                                                                      .2

                                                                                                                                                 (
                                                                                                                                             . Mg 2 + ( aq ) / Mg( s )        )
                                                                                                             :                                                                     .3
       t ( min )          0              2                  4             6                 8                10              12             14                16               18

  VH 2 ( mL )             0            12,0              19,2            25,2              28,8           32,4              34,8           36,0               37,2            37,2

       x ( mol )

                                                                                       2
.                                 x                                                              -
                                                                                                      .              x = f (t )                                 -
                                                                                                                      . t =0                                      -
                                         .                                                                        pH = 1                                          .4
                 . VM = 24, 0 L.mol -1                                              M ( Mg ) = 24 g .mol -1                                          :

.                                                                                                                                                        :
                                                 .                                                                                                                .1


                                                                                .
                                                              .(                                     )
                                                                        .                                                                                         .2
                                                                                                          . Mg( S ) ® Mg 2+ ( aq ) + 2e- :
                                                                                                          . 2 H + ( aq) + 2e - ® H 2( g ) :
                                                             Mg( S ) + 2 H + ( aq ) ® Mg 2+ ( aq ) + H 2( g ) :

                                                 Mg( S ) + 2 H + ( aq ) ® Mg 2+ ( aq ) + H 2( g )                                 .                          - .3
                                                                                                                                      :
                                                 ( mol )
                                                                                                                              m 36 ´10-3
                             0                  n1                 n0               0                0               . n1 =     =        1,5 ´10-3 mol
                                                                                                                              M    24
                           x (t )        n1 - x ( t )        n0 - 2 x ( t )     x (t )           x (t )
                            xf               n1 - x f         n0 - 2 x f         xf                  xf                                             x

     t ( min )   0     2         4     6             8        10        12      14              16         18
                                                                                                                         . x = n ( H2 ) =
                                                                                                                                              VH 2
                                                                                                                                                         :
                                                                                                                                               VM
    x ( mmol )   0 0,50 0,80 1,05 1,20 1,35 1,45 1,50 1,55 1,55
                                                                                                                                          .                   -
                                                                                                                              . x = f (t )                          -


                                                                                                                     . t =0                                     -
                                                                                                                                                         dx
                                                                                            :            t =0                                  v=           :
                                                                                                                                                         dt
                                                                                                             17 ´10-4 - 0
                                                                                                     .v =                 = 2,83 ´10-4 mol .min -1
                                                                                                                 6-0
                                                                                        .                                                       .4
                                                                                                                   . x f = 1,55 ´ 10 -3 mol
                     . n f ( H + ) = 3 ´ 10-3 mol :            n f ( H + ) = é H + ù f .V = 10 - pH .V = 10 -1 ´ 30 ´10 -3 :
                                                                             ë û                                                               H+

                                                         n0 ( H + ) = n f ( H + ) + 2 x f :               n f ( H + ) = n0 ( H + ) - 2 x f :
                                     6,1´10-3
                            ë û 0 30 ´10-3 » 0, 2mol.L : n0 ( H ) = 3 ´ 10 + 2 ´ 1,55 ´ 10 = 6,1´ 10 mol :
                            éH + ù =                  -1       +          -3              -3        -3




                                                                            3
2008                                                                                                                                                                             :
                                                  :                                                                                    Mg
                                                  Mg( s ) + 2 H 3O + ( aq ) = 2 H 2O( l ) + Mg 2+ ( aq) + H 2( g )
                 C = 5, 0mol.L-1                      V = 60mL                                                                                   m = 1,0 g
                                                                                             .
                                                        .
             t ( min )            0            1                  2                   3                   4                 5                6                    7                  8

           VH 2 ( mL )            0          336                 625                 810             910               970                  985                 985              985

             x ( mol )
                                                                                                                                                      .                                   .1
                                                                                                                       .                          x                                       .2
                                                                                                                              .                  x = f (t )                               .3
                                                                                                              .                                                  xf                       .4
                                                                          . ( t = 3min )             ( t = 0 min )                                                                        .5
                                                                                                                                                  . t1 2                                  .6

                                                                                                                                     (H O )
                                                                                                                                       3
                                                                                                                                            +
                                                                                                                                                                                          .7

                                                      . VM = 24 L.mol -1                                                              M ( Mg ) = 24,3 g.mol -1 :
.                                                                                                                                                                                    :
                                                                                                                                                      .                                   .1
                                                                   +                                                   2+
                                          Mg( s ) + 2 H 3O             ( aq )   = 2 H 2O( l ) + H 2( g ) + Mg               ( aq )                        :                                :
                                                      ( mol )                                                                                                                   . n1 =
                                                                                                                                                                                         m
                                                                                                                                                                                           =
                                                                                                                                                                                             1
                             0                                                                            0             0                                                                M 24
                                             n1                     n0
                                                                                                                                                                         n1 » 4,1´ 10-2 mol
                             x            n1 - x                n0 - 2 x                                  x            x
                                                                                                                                                          :
                             xf           n1 - x f              n0 - 2 x f                                xf           xf
                                                                                                                                           . n0 = C.V = 5 ´ 60 ´ 10-3 = 0,3mol
     t ( min )     0     1            2       3             4              5          6          7                8
                                                                                                                                                                         .                .2
    x ( mmol )     0 14,0 26,0 33,7 37,9 40,4 41,0 41,0 41,0                                                                                                                     x
                                                                                                                                                                         VH 2
                                                                                                                                            . x = n ( H2 ) =                     :
                                                                                                                                                                         VM
                                                                                                                                             . x = f (t )                                 .3


                                                                                                      .                                                         xf                        .4

                                                                                                     n0 ( Mg )                                                n1 ( H 3O + )
                                                                                                               = 4,1´10 -2 mol                                                  = 0, 3mol :
                                                                                                          2                                                          1
                                                                                                                                                               n0 ( Mg ) n1 ( H 3O )
                                                                                                                                                                                  +
                                                                                                                  -2
                                                      . Mg                                x f = 4,1´10 mol :                                                            <
                                                                                                                                                                   2           1

                                                                                       4
.                                                         :
                                                                             ( t = 3min ) ( t = 0 min )                                                                                                          .5
                     dnH 2       dx 33, 7 - 17                                dnH 2 dx 35 - 0
       vH 2 ( 3) =           =      =          » 5, 6mmol.min -1 vH 2 ( 0 ) =      =    =      = 17,5mmol.min -1
                      dt         dt   3-0                                      dt    dt   2-0
                                                                                            . t1 2               .6

                                                                                                                                          x ( t1 2 ) =
                                                                                                                                                             xf
                                                                                                    . t1 2 = 1,5 min                                              » 20, 05mmol :
                                                                                                                                                              2
                                                                                                                                          (H O )    3
                                                                                                                                                        +
                                                                                                                                                                                                                 .7
                                  n0 - 2 x f                           xf                           4,1´10 -2
               é H 3O + ù =
               ë        ûf                               =C -2               = 5, 0 - 2                       :                   x f = 4,1´10-2 mol :
                                        V                              V                            60 ´10-3
                                                                                                                                                   . é H 3O + ù ; 3, 6mol.L-1 :
                                                                                                                                                     ë        ûf
2008                                                                                                                                                                                                :
           ( S2 )                   ( 2K (    +
                                                  aq )
                                                         + S2 O82 - ( aq )   )                                            ( S1 )
                                                                                                                                           .                                 (K (  +
                                                                                                                                                                                       aq )
                                                                                                                                                                                              + I -( aq )    )
            V2 = 50mL                    C1 = 2, 0 ´ 10-1 mol.L-1                                           ( S1 )                    V1 = 50mL                             t =0
                                                                                                          S 2O82 -                                          . C2 = 1, 0mol.L-1                                      ( S2 )
                                                                                                                                                                                                            . -3-
                                                                                                                                               :
                                                                                                                                            . 2 I -( aq ) + S2O82-( aq) = I 2( aq ) + 2SO4 -( aq)
                                                                                                                                                                                         2



                                                                                                                                  .                                        ox / red                              .1
                                                                                                                                                                   .                                             .2
                                                                                                                                                        .                                                        .3
                                                                                                                              .                                   t1                                             .4
                                                                                                                                                                       2

                                                                                                                                                                                                                 .5
                                                                                                                                                                       . t1
                                                                                                                                                                              2

                                                                                                                                                                                                                 .6
                                                                                                                                                                                   . t = 10 min
.                                                                                                                                                                                                       :
                                                                                                                             .                                         ox / red                                  .1
                                                                                 .   (S O   2
                                                                                                -2
                                                                                                8     / SO4 2 ) :
                                                                                                          -
                                                                                                                                            S 2O 8-2(aq ) + 2e - = 2SO 4-2( aq ) :

                                    -2                    -                      -2
                                                                                                                (I   2   / I-):                              2I - (aq ) = I 2(aq ) + 2e - :
                             S 2O   8 (aq )   + 2I            (aq )   = 2SO      4 ( aq )   + I 2( aq )
                                                                                                                                                                              .                                  .2
                                    mmol
                                                                                                                                               :
                0            n1 = 10              n2 = 50                    0                      0
                                                                                                                                               n1 = C1.V1 = 0, 2 ´ 50 ´ 10-3 = 10-2 mol
               x             n1 - x               n2 - 2 x                  2x                      x
                                                                                                                                                                                  . n1 = 10mmol :
               xf            n1 - x f             n2 - 2 x f                2x f                    xf

                                                                                                5
. n2 = 50mmol :                              n2 = C2 .V2 = 1, 0 ´ 50 ´10-3 = 5 ´10-2 mol :                                         I-
                                                                                                                                   .                                                         .3
                                                                       . xmax = n1 = 10mmol                                            n2 - 2 xmax = 0               n1 - xmax = 0 :
                                                                                                                . S 2O 8-2                                           :
                                                                                                                       .                       t1                                            .4
                                                                                                                                                    2

                               n1 10                                                          xf
                   nS O -2 =     =   = 5mmol :                                x ( t1/ 2 ) =            :
                     2 8
                               2   2                                                          2
                                                                                                                      . t1/2 = 17,5 min :                nS O-2 = 5mmol
                                                                                                                                                              2 8

                                                                       . t1                                                                                                                  .5
                                                                              2

                                                  t1
                                                       2

            2n + n                              x1/ 2                                  2 x1/ 2                                     n - 2x1/2                             n -x
    éK + ù = 1 2
    ë û V +V                        [I2 ] =                                é SO4-2 ù =                                     éI - ù = 2
                                                                                                                           ë û V +V                          é S2O8-2 ù = 1 1/2
                                                                                                                                                             ë        û V +V
                                              V1 + V2                      ë       û V +V
             1   2                                                                            1            2                          1  2                                 1  2

               20 + 50                            5                                  10                                               50 - 10                            10 - 5
             =                                =                                      =                                             =                                     =
                  100                            100                                 100                                                100                               100
       é K ù = 0, 7 mol.L-1
       ë û
          +
                                    [ I 2 ] = 0, 05mol.L-1                  é SO4 ù = 0,1mol.L-1
                                                                            ë
                                                                                -2
                                                                                   û                                       é I - ù = 0, 4mol.L-1
                                                                                                                           ë û                                é S2O8-2 ù = 0,05mol.L-1
                                                                                                                                                              ë        û
                                                                                                   . t = 10 min                                                                              .6

                                                                                                                       dx    dnS O-2
                                                                                                                 .        =-    2 8
                                                                                                                                     :                       nS O-2 = n1 - x :
                                                                                                                       dt      dt                              2 8



                                                                                                                                                    1 dx    1 dnS2O8-2
                                                                                                                                        vvol =           =-            :
                                                                                                                                                    V dt    V dt
                                                                                                                                                              dnS O-2
                                                                                                               . t = 10 min                                                       2 8

                                                                                                                                                                              dt
                                                                                                                                 1 6,6 - 9,3
                                                                                                                     vvol = -                = 2,7mmol.L-1.min -1 :
                                                                                                                                0,1 10 - 0
2009                                                                                                                                                                      :
                      :                                              (I )
                                                                       -
                                                                                              (S O )
                                                                                                   2
                                                                                                           2-
                                                                                                           8

                                                             S 2O82- ( aq) + 2 I -( aq ) = 2SO42- ( aq ) + I 2( aq)
                      V1 = 100mL                           (t = 0)                                             (q = 35°C )                                                                        .I
                                    V2 = 100mL                         C1 = 4, 0 ´ 10-2 mol.L-1                                    ( 2K   +
                                                                                                                                              + S 2O82 - )

                                              . VT = 200mL                                                      C2 = 8, 0 ´ 10-2 mol.L-1                                 (K   +
                                                                                                                                                                                  + I-)
                                                                                                                                                .                                                     -
  ( I2 )                        [ I2 ]    V2 V1                C1                                                                             é S2O82- ù
                                                                                                                                              ë        û                                          -
                                                                                                                                                                                        .

           (I )
             -
                      (S O )
                           2
                               2-
                               8                                               (t = 0)                                                                         é S 2O82- ù
                                                                                                                                                               ë         û0                       -

        V0 = 10mL                                            . ti ........ t2 t1                                                                                                            .II
                                    ( 2Na     +
                                                  + S2 O32 - )                                                  ti

                                                                                    6
:                                                                                                                  V'                              C ' = 1,5 ´ 10-2 mol.L-1
             t ( min )                  0                5                        10                   15              20                30                    45                  60
            V ' ( ml )                  0                4,0                      6,7                  8,7             10,4             13,1                  15,3             16,7
        [ I 2 ] ( mmol / l )
                                                                                                                                                                                                   -
                                                                                   . I 2( aq) / I -( aq)         S 4O62-( aq) / S 2O32-( aq ) :                                                -
                                                                                                   .                                                                                       ·
                                      1 C '´ V '
                         [ I2 ] =       ´        :                                                                                                                                              -
                                      2   V0
                                                                                                                                                               .                                -
                                                                                                                                . [ I2 ] = f (t )                                               -
                                                                                                             . ( t = 20 min )                                                                  -
.                                                                                                                                                                                  :
                                                                                                                                                   .                         -             .I
                                                  2-                 -                       2-
                                            S 2O  8 ( aq )   + 2I        ( aq )   = 2SO      4 ( aq )   + I 2( aq)           S 2O  2-
                                                                                                                                   8

                                              ( mmol )                                                                                  . n1 = C1.V1 = 4, 0 ´10-2 ´10-1 :
                                                                                                                                                    n1 = 4, 0 ´ 10 -3 mol = 4mmol
                               0              4                      8                         0                0
                                                                                                                                               :         I-
                             x (t )      4 - x (t )          8 - 2x (t )                   2x ( t )           x (t )
                                                                                                                                         . n2 = C2 .V2 = 8, 0 ´10-2 ´10-1
                               xf           4-xf               8 - 2x f                     2x f               xf
                                                                                                                                                    n2 = 8, 0 ´ 10-3 mol = 8mmol
                                                                         .                                                                     é S2O82- ù
                                                                                                                                               ë        û                                          -
                                                                                                 n - x C1.V1         x
                                                                                  é S 2O82- ù = 1
                                                                                  ë         û           =        -          :       (                                          )
                                                                                                   VT     V1 + V2 V1 + V2
                                                                                                     C .V
                                                                                      é S 2O82- ù = 1 1 - [ I 2 ] :
                                                                                                                                    x
                                                                                      ë         û V +V                . [ I2 ] =         :                                     nI 2 = x :
                                                                                                      1   2                      V1 + V2
                                                                                                                                                              . é S 2O82- ù
                                                                                                                                                                ë         û0                       -
                                                                          4 ´10-2 ´10-1                                                                                     C .V
                                                     .       é S2O82- ù =
                                                             ë        û0      -1    -1
                                                                                        = 2 ´10-2 mol.L-1 :                                                   é S 2O82- ù = 1 1 :
                                                                                                                                                              ë         û0 V + V
                                                                           10 + 10                                                                                          1    2

                         .                                                               ( I2 )                                                                                        - .II
                                                                                                                        .                                                                          -
                                                                                                                            2-                     2-               -
                                                                                                                 . 2 S 2O   3 ( aq )   ® S4 O      6 ( aq )   + 2e :
                                                                                                                            . I 2(aq ) + 2e - ® 2 I - (aq ) :
                                                               2S 2O32-( aq ) + I 2( aq) ® S4O6 - ( aq ) + 2 I - ( aq ) :
                                                                                              2


                                                                                                                        .                                                                          -
                                        2S 2O32-( aq ) + I 2( aq) ® S4O6 - ( aq ) + 2 I - ( aq )
                                                                       2

                                                                                                                                                                         .
                                             ( mol )                                                                          n '- 2 xE = 0              n0 - x E = 0 :
                             0               n'                 n0                      0                 0                                                                             n'
                                                                                                                                                                    xE = n0 =              :
                             xE          n '- 2 xE           n0 - x E                   xE               2x E                                                                           2


                                                                                          7
t ( min )                                                                                                                  1 C '.V '                                  n0
                        0     5        10      15    20           30      45       60                                   . [ I2 ] = .        :                  [ I2 ] =         :
                                                                                                                                  2 V0
[ I 2 ] ( mmol.L-1 )
                                                                                                                                                                             V0
                        0 3,0 5,0 6,5 7,8 9,8 11,5 12,5
                                                                                                                                                                   .                  -
                                                                                             1,5 ´10-2                                                         1 C '.V '
                 ( mmol.L-1         [ I2 ]      mL        V'                ) . [ I2 ] =                V ' = 0, 75 ´ V ' :                         [ I2 ] =    .        :
                                                                                            2 ´10 ´10-3                                                        2 V0
                                                                                                                                     . [ I2 ] = f (t )                         -


                                                                                                                                                               .

                                                                                            . ( t = 20 min )                                                                   -
                                                                                                              d æ x ö d [I2 ]                                           1 dx
                                                                                             . vvol =            ç ÷=         :                         vvol =               :
                                                                                                              dt è VT ø dt                                             VT dt
                                                                                                                                                                           d [ I2 ]
                                                                                  . t = 20 min                                                              vvol =
                                                                                                                                                                             dt
                                                                                                                       7,8 - 3, 2
                                                                                                           . v vol =              = 0, 23mmol .min -1 .L-1 :
                                                                                                                        20 - 0
2009                                                                                                                                                        :
                              2,0g                        .                             (H    +
                                                                                                  + Cl - )
                                                                       . C = 1,0 ´10-1 mol.L-1                                                      100mL                    CaCO3
                                                                                                                                                                       :
       t (s)           20                60              100
                                                                               (1L )
 P(CO2 ) ( Pa )        2280            5560              7170
                                                                                        :                                                T = 25°C
 n( CO2 ) ( mol )                                                                                      :
   x ( mol )                                                                                      . CaCO3( s ) + 2 H + ( aq ) = CO2( g ) + H 2O( l ) + Ca 2+ ( aq )
                                                                                                                                                                               .1
                                                                                   .                       ( x)                              (n )
                                                                                                                                                CO2                            .2
                                                              .                         ( P.V = n.R.T )                                                                        .3
                                                                           . 1L = 10-3 m3                   R = 8,32SI               . x = f (t )                              .4
                                                                                                                                                                       :
                                                     :                                                                               (H )+


         t (s)               20               60              100                                  .                                                (n H + )
                                                                                                                                                      ( )
                                                                                                                                                                              .1

 é H + ù ( mol.L-1 )
 ë û
                            0,080            0,056            0,040               (n H + )                                                                                    .2
                                                                                       ( )
   n H + ( mol )                                                                  .                                     ( n0 )                           ( x)
       ( )
       x ( mol )
                                                                                                                         .               ( x)                                 .3
                                                                                                                                         x = f (t )                           .4
                                                                                                                                                .                             .5
                                                                                                                                 .                       t1/ 2                .6
                                                                                                       . t = 50s                                                              .7
                               . M ( Ca ) = 40 g .mol -1               M ( C ) = 12 g .mol -1                M ( O ) = 16 g .mol -1



                                                                            8
.                                                                                                                                                               :
                                                                                                                                                                   :
                                             CaCO3( s ) +          2 H + ( aq ) = CO2( g ) + Ca 2+ ( aq ) + H 2O(l )
                                                                                                                                                        .                   .1
                                                            ( mol )                                                                             :
                              0              n = 2 ´10-2          n0 = 10-2             0               0                                       n0 = C .V = 0,1´ 0,1

                              x              n- x                 n0 - 2 x               x              x                                           . n0 = 10-2 mol :
                             xmax            n - xmax             n0 - 2 xmax          xmax            xmax                                 :
                                                                                                                                                                    m   2
                                                                                                                                                              n=      =
                                                                                                                                                                    M 100
                                                                                                                                     . n = 2 ´ 10-2 mol :
         t (s)               20              60         100
                                                                                                                           . nCO2 = x :                                     .2
         n( CO2 ) ( mmol )   0,92        2,24           2,89
                                                                                                                                                    .                       .3
         x ( mmol )          0,92        2,24           2,89                                            VCO2
                                                                                             nCO2 =               PCO2 :           PCO2 .VCO2 = nCO2 .R.T :
                                                                                                         R.T
                                                                                                                                     1´10-3
                                                                      nCO2 = 4, 03 ´10-7.PCO2 :                        nCO2 =                        .PCO2 :
                                                                                                                                8,32 ´ . ( 25 + 273)
                                                                                                              .                  . x = f (t )                               .4
                                                                                                                                                                   :
                                                                                              .                                                 (n H + )               .1
                                                                                                                                                        ( )
                                                                                                                  . n H + = é H + ù .V = 0,1´ é H + ù :
          t (s)                20             60         100                                                         ( ) ë û                  ë û

          n H + ( mmol )                                                                                .     ( n0 ) ( x )       (n H + )
                                                                                                                                   ( )
                                                                                                                                                                       .2
            ( )               8,0             5,6        4,0
                                                                                                                       . n H + = n0 - 2 x :
          x ( mmol )          1,0             2,2        3,0                                                               ( )
                                                                                                                   .             ( x)                                  .3
                                                           1 æ -2            ö                         1æ               ö
                                                    . x=     ç 10 - n( H + ) ÷ :                  x=    ç n0 - n( H + ) ÷ :         n H + = n0 - 2 x :
                                                           2è                ø                         2è               ø             ( )
    .(                              ).                           :                                      .                   . x = f (t )           .4
                                                                                                                                        .                              .5

xmax = 5mmol :                      (H ) +                                            n0 n
                                                                                        < :
                                                                                      2 1
                                                                                                                  n
                                                                                                                  1
                                                                                                                    = 2 ´10-2 mol
                                                                                                                                   n0
                                                                                                                                   2
                                                                                                                                      = 5 ´ 10-3 mol :

                                                                                                                        .             t1/ 2       .6
             x ( mmol )
                                                                                                                        ( )    x    5
                                                                                                                     x t 1 = max = = 2,5mmol :
                                                                                                                          2      2  2
                                                                                                       . t 1 » 70s :
                                                                                                              2
                                                                                                                                  ( ) = 2,5mmol
                                                                                                                                 x t1
                                                                                                                                        2

                                                                                              . t = 50s                                                             .7
                                                                                                                  dx                                             1 dx
                                                                             . t = 50s                                       vvol                              =       :
                                                                                                                  dt                                             V dt
                                                                                             dx (1,95 - 0, 45 ) ´ 10
                                                                                                                     -3

                                                                                                 =                      = 3 ´ 10-5 mol.s -1 :
                                                                                             dt            50 - 0
                                                                                                                           1
                                                         t ( s)              . vvol   = 3 ´10-4 mol.L-1.s -1 :     vvol =     ´ 3 ´10-5 :
                                                                                                                          0,1

                                                                         9
2009                                                                                                                                        :
                                                          .                                      ( H 2O2( aq)                           )
                                                                                  10L                                     (1L )             (10V )
                                                                                                                                  . Vm = 22, 4 L.mol -1
                                 . 2 H 2O2( aq) = 2 H 2O( l ) + O2( g ) :                                                                                    .1
                                                                           . C = 0,893mol.L-1 :                                                                  -
                                                                 . 100mL                                                   V1                                -
                                                                                                                                                     ·
                                                                    . C1 = 0,1mol.L-1                                       V1                       ·

       (K (
         +
              aq )
                     + MnO4-( aq )    )                                                       20mL           (10V )                                          .2

                                                              . VE = 38mL                                       C0 = 0, 02mol.L-1

                (O ( ) / H O ( ) ) :
                      2 g        2   2 aq                                                                                                                        -

                                                                                                                      (
                                                                                                                   . MnO4 ( aq ) / Mn 2 + ( aq )
                                                                                                                        -
                                                                                                                                                         )
                                                                                          .                                                                  -
.                                                                                                                                                :
                                                                   . C = 0,893mol.L-1 :                                                              - .1
                                             VO2         10
                             .       nO2 =          =         » 0, 4464mol :                             (1L )
                                             Vm         22, 4
                                                                        ni ( H 2O2 ) = 2n f ( O2 ) = 2 ´ 0, 4464 » 0,893mol :
                                                                                                        ni ( H 2O2 ) 0,893
                                                                                               .C=                  =      = 0,893mol.L-1 :
                                                                                                           VH 2O2      1
                                                                                  .                                                                  -
                                                                                                                          . V1                       -
                                                           0,1                                        C1
                                                 . V1 =         .100 = 11, 2mL :              V1 =       .V :         CV1 = C1V :
                                                          0,893                                       C
                                                                                      .                                                              - .2

                                                                    (                                                              )
                                                              . 2 ´ MnO4 ( aq ) + 8H + ( aq ) + 5e - ® Mn 2 + ( aq ) + 4 H 2O( l ) :
                                                                       -



                                                                              . 5 ´ ( H 2O2( aq ) ® O2( g ) + 2 H + ( aq ) + 2e - ) :
             . 2MnO4 ( aq ) + 5H 2O2( aq ) + 6 H +( aq) ® 2Mn 2+( aq) + 5O2( g ) + 8H 2O( l ) :
                   -



                                                                                  .                                                              -
                            n ( MnO4- )          n ( H 2 O2 )
         . xmax =                            =                :            n ( H 2O2 ) - 5 xmax = 0     n ( MnO4- ) - 2 xmax = 0 :
                                 2                    5
                            5                                                                                                                   5
       . n ( H 2 O2 )( t ) = C0 .VE :                              V0 = 20mL                  n ( H 2 O2 )                   n ( H 2 O2 ) =       n ( MnO4- )
                            2                                                                                                                   2
                                                   5 C .V  5 0, 02 ´ 38
                                 C ' = [ H 2 O2 ] = . 0 E = .           = 0, 095mol.L-1 :
                                                   2 V0    2     20
                                                                            10
C '.V 0, 095 ´ 100
                                                                   C '' =         =             = 0,848mol.L-1 :
                                                                              V1       11, 2
                                                                                                                                                                       C '' ¹ C
2009                                                                                                                                                                       :
    20m3                  SO2                                        .                                                                      SO2
                             ( S0 )        V = 50mL                      .(                     SO2                      ) ( S0 )                                              1L
                                                                      . C1 = 2, 0 ´ 10-4 mol.L-1                                  (K ( +
                                                                                                                                           aq )
                                                                                                                                                  + MnO4-( aq )        )
            (
           . MnO4 ( aq ) / Mn 2 + ( aq )
                -
                                           ) ( SO  2-
                                                   4 ( aq )              )
                                                              / SO2( g ) :                                                                                                          .1
                                                                                                                                                                                    .2
.                 (C )                       VE = 9,5mL                                (K ( +
                                                                                                aq )
                                                                                                       + MnO4-( aq )     )                                                          .3
                                                                                                        .                                   SO2                                     .4
                            .                                     250m g.m -3               SO2                                                                                     .5
                                                                                                       . M ( O ) = 16 g .mol -1                       M ( S ) = 32 g .mol -1 :
.                                                                                                                                                                              :
                                                                                                                              :                                                     .1

                                                                             (
                                                                    . 5 ´ SO2( g ) + 2 H 2O( l ) ® SO4 -( aq ) + 4 H + ( aq ) + 2e - :
                                                                                                     2
                                                                                                                                                               )
                                                                     (
                                                              . 2 ´ MnO4 ( aq ) + 8H +( aq ) + 5e - ® Mn 2 + ( aq ) + 4 H 2 O( l )
                                                                       -
                                                                                                                                                           )       :

                     5SO2( g ) + 2 MnO4-( aq ) + 2 H 2O( l ) ® 5SO4 -( aq ) + 2Mn 2+ ( aq ) + 4 H + ( aq ) :
                                                                  2



                                      . MnO 4-                                        (                         )                                                                   .2
                                                                                                                     .                        (C )                                  .3

                                                      n0 ( SO2 ) n0 ( MnO4 )
                                                                                       -
                             C.V C1 .VE
                                =       :                       =            :                              (                                     )
                              5    2                       5           2
                                                                                                                                           5 C1.VE 5 2 ´10-4
                                                                . C = 10-2 mol.L-1                                                C=              =             :
                                                                                                                                           2 V      2 50 ´10 -3
                                                                                                  .                                        SO2                    .4
                                                                                                                              Cm = M .C = 64 ´ 10-2 = 0, 64 g .L-1
                                                                                                                                   .                                                .5
                         SO2                       m = 0, 64 g                        SO2                           1L                                     Cm = 0, 64 g .L-1 :
                                                                                                                               m 0, 64
                                                 3, 2 ´ 104 m g .m -3 > 250 m g .m -3 :                                  t=            = 3, 2 ´ 10-2 g.m -3 :
                                                                                                                              Vair 20
                                                                                                                     .
2010                                                                                                                                                                       :
                                :
                                                              Zn( s ) + 2 H + ( aq) = Zn 2+ (aq ) + H 2( g )
                                                                                 V = 40mL                                              m = 1, 0 g                  t =0
       . VM = 25 L.mol -1 :                                                                                                                             . C = 5, 0 ´ 10-1 mol.L-1

                                                                                 11
:                                                                                            VH 2

       t (s)          0             50              100            150             200              250              300                 400                 500         750
    VH 2 ( mL )       0             36              64             86              104              120              132                 154                 170         200
     x ( mol )
                                                          . VH 2                                            x                                                                    .1
                                                                                                                                                         .                       .2
                                          . 1cm ® 1, 0 ´ 10-3 mol                         1cm ® 100s :                                              x = f (t )                   .3
                            .                                            . t2 = 400s           t1 = 100 s :                                                                      .4
                                                                                                                                .                                                .5
                                                                                                      .                             xmax                                     -
                           M ( Zn ) = 65 g .mol -1 :                                                             .                  t1/ 2                                -
.                                                                                                                                                                        :
                                                                                                                                                     :                           .1
                                  Zn( s ) + 2 H +( aq) = Zn 2+ ( aq) + H 2( g )                                                                              :
                                                                                                                                                   1
                                    ( mmol )                                                                                        . n1 =
                                                                                                                                               m
                                                                                                                                                 =   = 1,54 ´ 10-2 mol
                                                                                                                                               M 65
                      0            15,4                20                0               0                                           :
                      x         15, 4 - x           20 - 2x              x               x                           n0 = C.V = 0, 5 ´ 40 ´ 10-3 = 2 ´ 10 -2 mol
                      xf        15, 4 - x f         20 - 2 x f           xf              xf                            . VH 2                  x                                 ·
                                                                                       1                                 VH 2
                                                                          . x=            ´ VH 2 :           nH 2 =             :              nH 2 = x :
                                                                                       25                                VM

       t (s)      0        50     100         150      200         250        300        400        500      750                                                 .               .2
                                                                                                                                             : x = f (t )                        .3
    x ( mmol )    0 1,44 2,56 3,44 4,16 4,80 5,28 6,16 6,80 8,00
                                                                                                                                                                     .
                                                                                               . t2       t1 :                                                                   .4
                                                                                                                                         dx              1 dx
                                                                                         t2    t1                                                  vvol = .    :
                                                                                                                                         dt              V dt
                                                                                                                                           t1 = 100 s        :

                                                                                                                vvol =
                                                                                                                             1     ( 2,56 - 0, 7 ) ´10-3 :
                                                                                                                         40 ´ 10-3       100 - 0
                                                                                                                           . vvol = 4, 6 ´10 -4 mol.L-1 .s -1
                                                                                                                                            t1 = 400 s

                                                                                                                 vvol =
                                                                                                                               1     ( 6,16 - 3, 0 ) ´10-3
                                                                                                                           40 ´ 10-3       400 - 0
                                                                                                                           . vvol = 2, 0 ´10 -4 mol.L-1 .s -1
                                                                              .



                                                                                  12
Unit01 bac
Unit01 bac
Unit01 bac
Unit01 bac
Unit01 bac
Unit01 bac
Unit01 bac

Mais conteúdo relacionado

Semelhante a Unit01 bac

Rotation3
Rotation3Rotation3
Rotation3hprmup
 
2011 4 opstinsko
2011 4 opstinsko2011 4 opstinsko
2011 4 opstinskoduskolatas
 
11.[95 103]solution of telegraph equation by modified of double sumudu transf...
11.[95 103]solution of telegraph equation by modified of double sumudu transf...11.[95 103]solution of telegraph equation by modified of double sumudu transf...
11.[95 103]solution of telegraph equation by modified of double sumudu transf...Alexander Decker
 
11 complex formation-titrations
11 complex formation-titrations11 complex formation-titrations
11 complex formation-titrationsmohamed_elkayal
 
Inorganic chemistry revision package solutions
Inorganic chemistry revision package solutionsInorganic chemistry revision package solutions
Inorganic chemistry revision package solutionsPham Quang
 

Semelhante a Unit01 bac (11)

Rotation3
Rotation3Rotation3
Rotation3
 
2011 4 opstinsko
2011 4 opstinsko2011 4 opstinsko
2011 4 opstinsko
 
Ism et chapter_2
Ism et chapter_2Ism et chapter_2
Ism et chapter_2
 
Ism et chapter_2
Ism et chapter_2Ism et chapter_2
Ism et chapter_2
 
Ism et chapter_2
Ism et chapter_2Ism et chapter_2
Ism et chapter_2
 
11.[95 103]solution of telegraph equation by modified of double sumudu transf...
11.[95 103]solution of telegraph equation by modified of double sumudu transf...11.[95 103]solution of telegraph equation by modified of double sumudu transf...
11.[95 103]solution of telegraph equation by modified of double sumudu transf...
 
11 complex formation-titrations
11 complex formation-titrations11 complex formation-titrations
11 complex formation-titrations
 
Inorganic chemistry revision package solutions
Inorganic chemistry revision package solutionsInorganic chemistry revision package solutions
Inorganic chemistry revision package solutions
 
GC Chemical Equilibrium
GC  Chemical EquilibriumGC  Chemical Equilibrium
GC Chemical Equilibrium
 
GC Chemical Equilibrium
GC  Chemical EquilibriumGC  Chemical Equilibrium
GC Chemical Equilibrium
 
Gc chemical equilibrium
Gc  chemical equilibriumGc  chemical equilibrium
Gc chemical equilibrium
 

Unit01 bac

  • 1. : 2008 : . q = 12°C ( H 2O2 ) 2 H 2O2( aq) = 2 H 2O( l ) + O2( g ) : ( VM = 24 L.mol -1 ) . [ H 2O2 ]0 = 8, 0 ´10 -2 mol.L-1 VS = 500mL t =0 : (V ) O2 t ( min ) 0 4 8 12 16 20 24 28 32 36 40 VO2 ( mL ) 0 60 114 162 204 234 253 276 288 294 300 [ H 2O2 ] mol.L-1 . .1 . VO2 VM VS [ H 2O2 ]0 : t [ H 2O2 ] .2 . - .3 . [ H 2O2 ] = f ( t ) - . - . . t2 = 24 min t1 = 16 min - . t1 2 - . . [ H 2O2 ] q ' = 35°C .4 . : 2 H 2O2 (aq ) ® O2 ( g ) + 2 H 2O(l ) . .1 : ( mol ) . n = [ H 2O2 ]0 .VS = 8, 0 ´10-2 ´ 0,5 0 n 0 0 . n = 4 ´ 10-2 mol x (t ) n - 2x (t ) x (t ) 2x ( t ) [ H 2O2 ] .2 xf n - 2x f xf 2x f . VO2 VM VS [ H 2O2 ]0 : t ni ( H 2O2 ) - 2 x ( t ) x (t ) [ H 2O2 ] = = [ H 2O2 ]0 - 2. n( H 2O2 ) ( t ) = ni ( H 2O2 ) - 2 x ( t ) : t VS VS 2 VO2 . [ H 2O2 ] = [ H 2O2 ]0 - .VO : n ( O2 ) = =x : VS .VM 2 VM . - .3 1 2 . [ H 2O2 ] = 8,0 ´ 10-2 - .VO2 : [ H 2O2 ] = 8, 0 ´10-2 - .VO : 6 0, 5 ´ 24 2 1
  • 2. t ( min ) 0 4 8 12 16 20 24 28 32 36 40 [ H 2O2 ] ´10-2 mol.L-1 8,0 7,0 6,1 5,3 4,6 4,1 3,8 3,4 3,2 3,1 3,0 . [ H 2O2 ] = f ( t ) - . - 1 dx vvol = . : VS dt d [ H 2O2 ] 1 d 2 dx . = ( n - 2x) = - : dt VS dt VS dt 1 d [ H 2O2 ] vvol = - . : 2 dt d [ H 2O2 ] .t [ H 2O2 ] = f ( t ) : dt . t2 = 24 min t1 = 16 min - 1 ( 7, 0 - 4, 6 ) ´ 10 -3 vvol ( t1 ) = - . = 7, 5 ´10 -4 mol.L-1 .min -1 2 16 - 0 1 ( 7, 0 - 5,5 ) ´ 10 -3 vvol ( t2 ) = - . = 3,1´ 10-5 mol.L-1.min -1 2 24 - 0 . . t1 2 - [ H 2O2 ]0 xmax ( ) . [ H 2O2 ] ( t1/2 ) = : x ( t1/ 2 ) = : 2 2 0, 08 .( ) t1/ 2 » 20 min : [ H 2O2 ] ( t1/2 ) = = 40mmol .L-1 : 2 . ( ) q ' = 35°C [ H 2O2 ] .4 , 2008 : .( ) 30mL m = 36mg Mg ( S ) . . .1 (H ( + aq ) ) / H 2( g ) : .2 ( . Mg 2 + ( aq ) / Mg( s ) ) : .3 t ( min ) 0 2 4 6 8 10 12 14 16 18 VH 2 ( mL ) 0 12,0 19,2 25,2 28,8 32,4 34,8 36,0 37,2 37,2 x ( mol ) 2
  • 3. . x - . x = f (t ) - . t =0 - . pH = 1 .4 . VM = 24, 0 L.mol -1 M ( Mg ) = 24 g .mol -1 : . : . .1 . .( ) . .2 . Mg( S ) ® Mg 2+ ( aq ) + 2e- : . 2 H + ( aq) + 2e - ® H 2( g ) : Mg( S ) + 2 H + ( aq ) ® Mg 2+ ( aq ) + H 2( g ) : Mg( S ) + 2 H + ( aq ) ® Mg 2+ ( aq ) + H 2( g ) . - .3 : ( mol ) m 36 ´10-3 0 n1 n0 0 0 . n1 = = 1,5 ´10-3 mol M 24 x (t ) n1 - x ( t ) n0 - 2 x ( t ) x (t ) x (t ) xf n1 - x f n0 - 2 x f xf xf x t ( min ) 0 2 4 6 8 10 12 14 16 18 . x = n ( H2 ) = VH 2 : VM x ( mmol ) 0 0,50 0,80 1,05 1,20 1,35 1,45 1,50 1,55 1,55 . - . x = f (t ) - . t =0 - dx : t =0 v= : dt 17 ´10-4 - 0 .v = = 2,83 ´10-4 mol .min -1 6-0 . .4 . x f = 1,55 ´ 10 -3 mol . n f ( H + ) = 3 ´ 10-3 mol : n f ( H + ) = é H + ù f .V = 10 - pH .V = 10 -1 ´ 30 ´10 -3 : ë û H+ n0 ( H + ) = n f ( H + ) + 2 x f : n f ( H + ) = n0 ( H + ) - 2 x f : 6,1´10-3 ë û 0 30 ´10-3 » 0, 2mol.L : n0 ( H ) = 3 ´ 10 + 2 ´ 1,55 ´ 10 = 6,1´ 10 mol : éH + ù = -1 + -3 -3 -3 3
  • 4. 2008 : : Mg Mg( s ) + 2 H 3O + ( aq ) = 2 H 2O( l ) + Mg 2+ ( aq) + H 2( g ) C = 5, 0mol.L-1 V = 60mL m = 1,0 g . . t ( min ) 0 1 2 3 4 5 6 7 8 VH 2 ( mL ) 0 336 625 810 910 970 985 985 985 x ( mol ) . .1 . x .2 . x = f (t ) .3 . xf .4 . ( t = 3min ) ( t = 0 min ) .5 . t1 2 .6 (H O ) 3 + .7 . VM = 24 L.mol -1 M ( Mg ) = 24,3 g.mol -1 : . : . .1 + 2+ Mg( s ) + 2 H 3O ( aq ) = 2 H 2O( l ) + H 2( g ) + Mg ( aq ) : : ( mol ) . n1 = m = 1 0 0 0 M 24 n1 n0 n1 » 4,1´ 10-2 mol x n1 - x n0 - 2 x x x : xf n1 - x f n0 - 2 x f xf xf . n0 = C.V = 5 ´ 60 ´ 10-3 = 0,3mol t ( min ) 0 1 2 3 4 5 6 7 8 . .2 x ( mmol ) 0 14,0 26,0 33,7 37,9 40,4 41,0 41,0 41,0 x VH 2 . x = n ( H2 ) = : VM . x = f (t ) .3 . xf .4 n0 ( Mg ) n1 ( H 3O + ) = 4,1´10 -2 mol = 0, 3mol : 2 1 n0 ( Mg ) n1 ( H 3O ) + -2 . Mg x f = 4,1´10 mol : < 2 1 4
  • 5. . : ( t = 3min ) ( t = 0 min ) .5 dnH 2 dx 33, 7 - 17 dnH 2 dx 35 - 0 vH 2 ( 3) = = = » 5, 6mmol.min -1 vH 2 ( 0 ) = = = = 17,5mmol.min -1 dt dt 3-0 dt dt 2-0 . t1 2 .6 x ( t1 2 ) = xf . t1 2 = 1,5 min » 20, 05mmol : 2 (H O ) 3 + .7 n0 - 2 x f xf 4,1´10 -2 é H 3O + ù = ë ûf =C -2 = 5, 0 - 2 : x f = 4,1´10-2 mol : V V 60 ´10-3 . é H 3O + ù ; 3, 6mol.L-1 : ë ûf 2008 : ( S2 ) ( 2K ( + aq ) + S2 O82 - ( aq ) ) ( S1 ) . (K ( + aq ) + I -( aq ) ) V2 = 50mL C1 = 2, 0 ´ 10-1 mol.L-1 ( S1 ) V1 = 50mL t =0 S 2O82 - . C2 = 1, 0mol.L-1 ( S2 ) . -3- : . 2 I -( aq ) + S2O82-( aq) = I 2( aq ) + 2SO4 -( aq) 2 . ox / red .1 . .2 . .3 . t1 .4 2 .5 . t1 2 .6 . t = 10 min . : . ox / red .1 . (S O 2 -2 8 / SO4 2 ) : - S 2O 8-2(aq ) + 2e - = 2SO 4-2( aq ) : -2 - -2 (I 2 / I-): 2I - (aq ) = I 2(aq ) + 2e - : S 2O 8 (aq ) + 2I (aq ) = 2SO 4 ( aq ) + I 2( aq ) . .2 mmol : 0 n1 = 10 n2 = 50 0 0 n1 = C1.V1 = 0, 2 ´ 50 ´ 10-3 = 10-2 mol x n1 - x n2 - 2 x 2x x . n1 = 10mmol : xf n1 - x f n2 - 2 x f 2x f xf 5
  • 6. . n2 = 50mmol : n2 = C2 .V2 = 1, 0 ´ 50 ´10-3 = 5 ´10-2 mol : I- . .3 . xmax = n1 = 10mmol n2 - 2 xmax = 0 n1 - xmax = 0 : . S 2O 8-2 : . t1 .4 2 n1 10 xf nS O -2 = = = 5mmol : x ( t1/ 2 ) = : 2 8 2 2 2 . t1/2 = 17,5 min : nS O-2 = 5mmol 2 8 . t1 .5 2 t1 2 2n + n x1/ 2 2 x1/ 2 n - 2x1/2 n -x éK + ù = 1 2 ë û V +V [I2 ] = é SO4-2 ù = éI - ù = 2 ë û V +V é S2O8-2 ù = 1 1/2 ë û V +V V1 + V2 ë û V +V 1 2 1 2 1 2 1 2 20 + 50 5 10 50 - 10 10 - 5 = = = = = 100 100 100 100 100 é K ù = 0, 7 mol.L-1 ë û + [ I 2 ] = 0, 05mol.L-1 é SO4 ù = 0,1mol.L-1 ë -2 û é I - ù = 0, 4mol.L-1 ë û é S2O8-2 ù = 0,05mol.L-1 ë û . t = 10 min .6 dx dnS O-2 . =- 2 8 : nS O-2 = n1 - x : dt dt 2 8 1 dx 1 dnS2O8-2 vvol = =- : V dt V dt dnS O-2 . t = 10 min 2 8 dt 1 6,6 - 9,3 vvol = - = 2,7mmol.L-1.min -1 : 0,1 10 - 0 2009 : : (I ) - (S O ) 2 2- 8 S 2O82- ( aq) + 2 I -( aq ) = 2SO42- ( aq ) + I 2( aq) V1 = 100mL (t = 0) (q = 35°C ) .I V2 = 100mL C1 = 4, 0 ´ 10-2 mol.L-1 ( 2K + + S 2O82 - ) . VT = 200mL C2 = 8, 0 ´ 10-2 mol.L-1 (K + + I-) . - ( I2 ) [ I2 ] V2 V1 C1 é S2O82- ù ë û - . (I ) - (S O ) 2 2- 8 (t = 0) é S 2O82- ù ë û0 - V0 = 10mL . ti ........ t2 t1 .II ( 2Na + + S2 O32 - ) ti 6
  • 7. : V' C ' = 1,5 ´ 10-2 mol.L-1 t ( min ) 0 5 10 15 20 30 45 60 V ' ( ml ) 0 4,0 6,7 8,7 10,4 13,1 15,3 16,7 [ I 2 ] ( mmol / l ) - . I 2( aq) / I -( aq) S 4O62-( aq) / S 2O32-( aq ) : - . · 1 C '´ V ' [ I2 ] = ´ : - 2 V0 . - . [ I2 ] = f (t ) - . ( t = 20 min ) - . : . - .I 2- - 2- S 2O 8 ( aq ) + 2I ( aq ) = 2SO 4 ( aq ) + I 2( aq) S 2O 2- 8 ( mmol ) . n1 = C1.V1 = 4, 0 ´10-2 ´10-1 : n1 = 4, 0 ´ 10 -3 mol = 4mmol 0 4 8 0 0 : I- x (t ) 4 - x (t ) 8 - 2x (t ) 2x ( t ) x (t ) . n2 = C2 .V2 = 8, 0 ´10-2 ´10-1 xf 4-xf 8 - 2x f 2x f xf n2 = 8, 0 ´ 10-3 mol = 8mmol . é S2O82- ù ë û - n - x C1.V1 x é S 2O82- ù = 1 ë û = - : ( ) VT V1 + V2 V1 + V2 C .V é S 2O82- ù = 1 1 - [ I 2 ] : x ë û V +V . [ I2 ] = : nI 2 = x : 1 2 V1 + V2 . é S 2O82- ù ë û0 - 4 ´10-2 ´10-1 C .V . é S2O82- ù = ë û0 -1 -1 = 2 ´10-2 mol.L-1 : é S 2O82- ù = 1 1 : ë û0 V + V 10 + 10 1 2 . ( I2 ) - .II . - 2- 2- - . 2 S 2O 3 ( aq ) ® S4 O 6 ( aq ) + 2e : . I 2(aq ) + 2e - ® 2 I - (aq ) : 2S 2O32-( aq ) + I 2( aq) ® S4O6 - ( aq ) + 2 I - ( aq ) : 2 . - 2S 2O32-( aq ) + I 2( aq) ® S4O6 - ( aq ) + 2 I - ( aq ) 2 . ( mol ) n '- 2 xE = 0 n0 - x E = 0 : 0 n' n0 0 0 n' xE = n0 = : xE n '- 2 xE n0 - x E xE 2x E 2 7
  • 8. t ( min ) 1 C '.V ' n0 0 5 10 15 20 30 45 60 . [ I2 ] = . : [ I2 ] = : 2 V0 [ I 2 ] ( mmol.L-1 ) V0 0 3,0 5,0 6,5 7,8 9,8 11,5 12,5 . - 1,5 ´10-2 1 C '.V ' ( mmol.L-1 [ I2 ] mL V' ) . [ I2 ] = V ' = 0, 75 ´ V ' : [ I2 ] = . : 2 ´10 ´10-3 2 V0 . [ I2 ] = f (t ) - . . ( t = 20 min ) - d æ x ö d [I2 ] 1 dx . vvol = ç ÷= : vvol = : dt è VT ø dt VT dt d [ I2 ] . t = 20 min vvol = dt 7,8 - 3, 2 . v vol = = 0, 23mmol .min -1 .L-1 : 20 - 0 2009 : 2,0g . (H + + Cl - ) . C = 1,0 ´10-1 mol.L-1 100mL CaCO3 : t (s) 20 60 100 (1L ) P(CO2 ) ( Pa ) 2280 5560 7170 : T = 25°C n( CO2 ) ( mol ) : x ( mol ) . CaCO3( s ) + 2 H + ( aq ) = CO2( g ) + H 2O( l ) + Ca 2+ ( aq ) .1 . ( x) (n ) CO2 .2 . ( P.V = n.R.T ) .3 . 1L = 10-3 m3 R = 8,32SI . x = f (t ) .4 : : (H )+ t (s) 20 60 100 . (n H + ) ( ) .1 é H + ù ( mol.L-1 ) ë û 0,080 0,056 0,040 (n H + ) .2 ( ) n H + ( mol ) . ( n0 ) ( x) ( ) x ( mol ) . ( x) .3 x = f (t ) .4 . .5 . t1/ 2 .6 . t = 50s .7 . M ( Ca ) = 40 g .mol -1 M ( C ) = 12 g .mol -1 M ( O ) = 16 g .mol -1 8
  • 9. . : : CaCO3( s ) + 2 H + ( aq ) = CO2( g ) + Ca 2+ ( aq ) + H 2O(l ) . .1 ( mol ) : 0 n = 2 ´10-2 n0 = 10-2 0 0 n0 = C .V = 0,1´ 0,1 x n- x n0 - 2 x x x . n0 = 10-2 mol : xmax n - xmax n0 - 2 xmax xmax xmax : m 2 n= = M 100 . n = 2 ´ 10-2 mol : t (s) 20 60 100 . nCO2 = x : .2 n( CO2 ) ( mmol ) 0,92 2,24 2,89 . .3 x ( mmol ) 0,92 2,24 2,89 VCO2 nCO2 = PCO2 : PCO2 .VCO2 = nCO2 .R.T : R.T 1´10-3 nCO2 = 4, 03 ´10-7.PCO2 : nCO2 = .PCO2 : 8,32 ´ . ( 25 + 273) . . x = f (t ) .4 : . (n H + ) .1 ( ) . n H + = é H + ù .V = 0,1´ é H + ù : t (s) 20 60 100 ( ) ë û ë û n H + ( mmol ) . ( n0 ) ( x ) (n H + ) ( ) .2 ( ) 8,0 5,6 4,0 . n H + = n0 - 2 x : x ( mmol ) 1,0 2,2 3,0 ( ) . ( x) .3 1 æ -2 ö 1æ ö . x= ç 10 - n( H + ) ÷ : x= ç n0 - n( H + ) ÷ : n H + = n0 - 2 x : 2è ø 2è ø ( ) .( ). : . . x = f (t ) .4 . .5 xmax = 5mmol : (H ) + n0 n < : 2 1 n 1 = 2 ´10-2 mol n0 2 = 5 ´ 10-3 mol : . t1/ 2 .6 x ( mmol ) ( ) x 5 x t 1 = max = = 2,5mmol : 2 2 2 . t 1 » 70s : 2 ( ) = 2,5mmol x t1 2 . t = 50s .7 dx 1 dx . t = 50s vvol = : dt V dt dx (1,95 - 0, 45 ) ´ 10 -3 = = 3 ´ 10-5 mol.s -1 : dt 50 - 0 1 t ( s) . vvol = 3 ´10-4 mol.L-1.s -1 : vvol = ´ 3 ´10-5 : 0,1 9
  • 10. 2009 : . ( H 2O2( aq) ) 10L (1L ) (10V ) . Vm = 22, 4 L.mol -1 . 2 H 2O2( aq) = 2 H 2O( l ) + O2( g ) : .1 . C = 0,893mol.L-1 : - . 100mL V1 - · . C1 = 0,1mol.L-1 V1 · (K ( + aq ) + MnO4-( aq ) ) 20mL (10V ) .2 . VE = 38mL C0 = 0, 02mol.L-1 (O ( ) / H O ( ) ) : 2 g 2 2 aq - ( . MnO4 ( aq ) / Mn 2 + ( aq ) - ) . - . : . C = 0,893mol.L-1 : - .1 VO2 10 . nO2 = = » 0, 4464mol : (1L ) Vm 22, 4 ni ( H 2O2 ) = 2n f ( O2 ) = 2 ´ 0, 4464 » 0,893mol : ni ( H 2O2 ) 0,893 .C= = = 0,893mol.L-1 : VH 2O2 1 . - . V1 - 0,1 C1 . V1 = .100 = 11, 2mL : V1 = .V : CV1 = C1V : 0,893 C . - .2 ( ) . 2 ´ MnO4 ( aq ) + 8H + ( aq ) + 5e - ® Mn 2 + ( aq ) + 4 H 2O( l ) : - . 5 ´ ( H 2O2( aq ) ® O2( g ) + 2 H + ( aq ) + 2e - ) : . 2MnO4 ( aq ) + 5H 2O2( aq ) + 6 H +( aq) ® 2Mn 2+( aq) + 5O2( g ) + 8H 2O( l ) : - . - n ( MnO4- ) n ( H 2 O2 ) . xmax = = : n ( H 2O2 ) - 5 xmax = 0 n ( MnO4- ) - 2 xmax = 0 : 2 5 5 5 . n ( H 2 O2 )( t ) = C0 .VE : V0 = 20mL n ( H 2 O2 ) n ( H 2 O2 ) = n ( MnO4- ) 2 2 5 C .V 5 0, 02 ´ 38 C ' = [ H 2 O2 ] = . 0 E = . = 0, 095mol.L-1 : 2 V0 2 20 10
  • 11. C '.V 0, 095 ´ 100 C '' = = = 0,848mol.L-1 : V1 11, 2 C '' ¹ C 2009 : 20m3 SO2 . SO2 ( S0 ) V = 50mL .( SO2 ) ( S0 ) 1L . C1 = 2, 0 ´ 10-4 mol.L-1 (K ( + aq ) + MnO4-( aq ) ) ( . MnO4 ( aq ) / Mn 2 + ( aq ) - ) ( SO 2- 4 ( aq ) ) / SO2( g ) : .1 .2 . (C ) VE = 9,5mL (K ( + aq ) + MnO4-( aq ) ) .3 . SO2 .4 . 250m g.m -3 SO2 .5 . M ( O ) = 16 g .mol -1 M ( S ) = 32 g .mol -1 : . : : .1 ( . 5 ´ SO2( g ) + 2 H 2O( l ) ® SO4 -( aq ) + 4 H + ( aq ) + 2e - : 2 ) ( . 2 ´ MnO4 ( aq ) + 8H +( aq ) + 5e - ® Mn 2 + ( aq ) + 4 H 2 O( l ) - ) : 5SO2( g ) + 2 MnO4-( aq ) + 2 H 2O( l ) ® 5SO4 -( aq ) + 2Mn 2+ ( aq ) + 4 H + ( aq ) : 2 . MnO 4- ( ) .2 . (C ) .3 n0 ( SO2 ) n0 ( MnO4 ) - C.V C1 .VE = : = : ( ) 5 2 5 2 5 C1.VE 5 2 ´10-4 . C = 10-2 mol.L-1 C= = : 2 V 2 50 ´10 -3 . SO2 .4 Cm = M .C = 64 ´ 10-2 = 0, 64 g .L-1 . .5 SO2 m = 0, 64 g SO2 1L Cm = 0, 64 g .L-1 : m 0, 64 3, 2 ´ 104 m g .m -3 > 250 m g .m -3 : t= = 3, 2 ´ 10-2 g.m -3 : Vair 20 . 2010 : : Zn( s ) + 2 H + ( aq) = Zn 2+ (aq ) + H 2( g ) V = 40mL m = 1, 0 g t =0 . VM = 25 L.mol -1 : . C = 5, 0 ´ 10-1 mol.L-1 11
  • 12. : VH 2 t (s) 0 50 100 150 200 250 300 400 500 750 VH 2 ( mL ) 0 36 64 86 104 120 132 154 170 200 x ( mol ) . VH 2 x .1 . .2 . 1cm ® 1, 0 ´ 10-3 mol 1cm ® 100s : x = f (t ) .3 . . t2 = 400s t1 = 100 s : .4 . .5 . xmax - M ( Zn ) = 65 g .mol -1 : . t1/ 2 - . : : .1 Zn( s ) + 2 H +( aq) = Zn 2+ ( aq) + H 2( g ) : 1 ( mmol ) . n1 = m = = 1,54 ´ 10-2 mol M 65 0 15,4 20 0 0 : x 15, 4 - x 20 - 2x x x n0 = C.V = 0, 5 ´ 40 ´ 10-3 = 2 ´ 10 -2 mol xf 15, 4 - x f 20 - 2 x f xf xf . VH 2 x · 1 VH 2 . x= ´ VH 2 : nH 2 = : nH 2 = x : 25 VM t (s) 0 50 100 150 200 250 300 400 500 750 . .2 : x = f (t ) .3 x ( mmol ) 0 1,44 2,56 3,44 4,16 4,80 5,28 6,16 6,80 8,00 . . t2 t1 : .4 dx 1 dx t2 t1 vvol = . : dt V dt t1 = 100 s : vvol = 1 ( 2,56 - 0, 7 ) ´10-3 : 40 ´ 10-3 100 - 0 . vvol = 4, 6 ´10 -4 mol.L-1 .s -1 t1 = 400 s vvol = 1 ( 6,16 - 3, 0 ) ´10-3 40 ´ 10-3 400 - 0 . vvol = 2, 0 ´10 -4 mol.L-1 .s -1 . 12