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1
Chapter 3
Project Management
2
Definition of Project Management
Work Breakdown Structure
Project Control Charts
Structuring Projects
Critical Path Scheduling
OBJECTIVES
3
Project is a series of related jobs usually
directed toward some major output and
requiring a significant period of time to perform
Project Management are the management
activities of planning, directing, and controlling
resources (people, equipment, material) to meet
the technical, cost, and time constraints of a
project
Project Management
Defined
4
Gantt Chart
Activity 1
Activity 2
Activity 3
Activity 4
Activity 5
Activity 6
Time
Vertical Axis:
Always Activities
or Jobs
Vertical Axis:
Always Activities
or Jobs
Horizontal Axis: Always TimeHorizontal Axis: Always Time
Horizontal bars used to denote length
of time for each activity or job.
Horizontal bars used to denote length
of time for each activity or job.
5
Structuring Projects: Pure Project Advantages
The project manager has full authority over the
project
Team members report to one boss
Shortened communication lines
Team pride, motivation, and commitment are
high
Pure Project
A pure project is where a self-contained team
works full-time on the project
6
Structuring Projects: Pure Project
Disadvantages
Duplication of resources
Organizational goals and policies are ignored
Lack of technology transfer
Team members have no functional area "home"
7
Functional Project
President
Research and
Development
Engineering Manufacturing
Project
A
Project
B
Project
C
Project
D
Project
E
Project
F
Project
G
Project
H
Project
I
A functional project is housed within
a functional division
Example, Project “B” is in the functional
area of Research and Development.
Example, Project “B” is in the functional
area of Research and Development.
8
Structuring Projects
Functional Project: Advantages
A team member can work on several projects
Technical expertise is maintained within the
functional area
The functional area is a “home” after the project is
completed
Critical mass of specialized knowledge
9
Structuring Projects
Functional Project:
Disadvantages
Aspects of the project that are not directly related
to the functional area get short-changed
Motivation of team members is often weak
Needs of the client are secondary and are
responded to slowly
10
Matrix Project Organization Structure
President
Research and
Development
Engineering Manufacturing Marketing
Manager
Project A
Manager
Project B
Manager
Project C
11
Structuring Projects
Matrix: Advantages
Enhanced communications between functional areas
Pinpointed responsibility
Duplication of resources is minimized
Functional “home” for team members
Policies of the parent organization are followed
12
Structuring Projects
Matrix: Disadvantages
Too many bosses
Depends on project manager’s negotiating skills
Potential for sub-optimization
13
Work Breakdown Structure
Program
Project 1 Project 2
Task 1.1
Subtask 1.1.1
Work Package 1.1.1.1
Level
1
2
3
4
Task 1.2
Subtask 1.1.2
Work Package 1.1.1.2
A work breakdown structure defines the
hierarchy of project tasks, subtasks, and
work packages
14
Network-Planning Models
A project is made up of a sequence of activities that
form a network representing a project
The path taking longest time through this network of
activities is called the “critical path”
The critical path provides a wide range of scheduling
information useful in managing a project
Critical Path Method (CPM) helps to identify the
critical path(s) in the project networks
15
Prerequisites for Critical Path
Methodology
A project must have:
 well-defined jobs or tasks whose completion
marks the end of the project;
 independent jobs or tasks;
 and tasks that follow a given sequence.
16
Types of Critical Path Methods
 CPM with a Single Time Estimate
 Used when activity times are known with certainty
 Used to determine timing estimates for the project, each activity in
the project, and slack time for activities
 CPM with Three Activity Time Estimates
 Used when activity times are uncertain
 Used to obtain the same information as the Single Time Estimate
model and probability information
 Time-Cost Models
 Used when cost trade-off information is a major consideration in
planning
 Used to determine the least cost in reducing total project time
17
Steps in the CPM with Single Time
Estimate
1. Activity Identification
2. Activity Sequencing and Network Construction
3. Determine the critical path
From the critical path all of the project and activity
timing information can be obtained
18
CPM with Single Time Estimate
Consider the following consulting project:
Activity Designation Immed. Pred. Time (Weeks)
Assess customer's needs A None 2
Write and submit proposal B A 1
Obtain approval C B 1
Develop service vision and goals D C 2
Train employees E C 5
Quality improvement pilot groups F D, E 5
Write assessment report G F 1
Develop a critical path diagram and determine
the duration of the critical path and slack times
for all activities.
19
First draw the network
A(2) B(1) C(1)
D(2)
E(5)
F(5) G(1)
A None 2
B A 1
C B 1
D C 2
E C 5
F D,E 5
G F 1
Act. Imed. Pred. Time
20
Determine early starts and early finish
times
ES=9
EF=14
ES=14
EF=15
ES=0
EF=2
ES=2
EF=3
ES=3
EF=4
ES=4
EF=9
ES=4
EF=6
A(2) B(1) C(1)
D(2)
E(5)
F(5) G(1)
Hint: Start with ES=0
and go forward in the
network from A to G.
Hint: Start with ES=0
and go forward in the
network from A to G.
21
Determine late
starts and late
finish times
ES=9
EF=14
ES=14
EF=15
ES=0
EF=2
ES=2
EF=3
ES=3
EF=4
ES=4
EF=9
ES=4
EF=6
A(2) B(1) C(1)
D(2)
E(5)
F(5) G(1)
LS=14
LF=15
LS=9
LF=14
LS=4
LF=9
LS=7
LF=9
LS=3
LF=4
LS=2
LF=3
LS=0
LF=2
Hint: Start with LF=15
or the total time of the
project and go
backward in the
network from G to A.
Hint: Start with LF=15
or the total time of the
project and go
backward in the
network from G to A.
22
Critical Path & Slack
ES=9
EF=14
ES=14
EF=15
ES=0
EF=2
ES=2
EF=3
ES=3
EF=4
ES=4
EF=9
ES=4
EF=6
A(2) B(1) C(1)
D(2)
E(5)
F(5) G(1)
LS=14
LF=15
LS=9
LF=14
LS=4
LF=9
LS=7
LF=9
LS=3
LF=4
LS=2
LF=3
LS=0
LF=2
Duration=15 weeks
Slack=(7-4)=(9-6)= 3 Wks
23
Example 2. CPM with Three Activity
Time Estimates
Task
Immediate
Predecesors Optimistic Most Likely Pessimistic
A None 3 6 15
B None 2 4 14
C A 6 12 30
D A 2 5 8
E C 5 11 17
F D 3 6 15
G B 3 9 27
H E,F 1 4 7
I G,H 4 19 28
24
Example 2. Expected Time
Calculations ET(A)= 3+4(6)+15
6
ET(A)= 3+4(6)+15
6
ET(A)=42/6=7ET(A)=42/6=7
Task
Immediate
Predecesors
Expected
Time
A None 7
B None 5.333
C A 14
D A 5
E C 11
F D 7
G B 11
H E,F 4
I G,H 18
Task
Immediate
Predecesors Optimistic Most Likely Pessimistic
A None 3 6 15
B None 2 4 14
C A 6 12 30
D A 2 5 8
E C 5 11 17
F D 3 6 15
G B 3 9 27
H E,F 1 4 7
I G,H 4 19 28
Expected Time =
Opt. Time + 4(Most Likely Time) + Pess. Time
6
25
Ex. 2. Expected Time Calculations
Task
Immediate
Predecesors
Expected
Time
A None 7
B None 5.333
C A 14
D A 5
E C 11
F D 7
G B 11
H E,F 4
I G,H 18
ET(B)=32/6=5.333ET(B)=32/6=5.333
ET(B)= 2+4(4)+14
6
ET(B)= 2+4(4)+14
6
Task
Immediate
Predecesors Optimistic Most Likely Pessimistic
A None 3 6 15
B None 2 4 14
C A 6 12 30
D A 2 5 8
E C 5 11 17
F D 3 6 15
G B 3 9 27
H E,F 1 4 7
I G,H 4 19 28
Expected Time =
Opt. Time + 4(Most Likely Time) + Pess. Time
6
26
Ex 2. Expected Time Calculations
Task
Immediate
Predecesors
Expected
Time
A None 7
B None 5.333
C A 14
D A 5
E C 11
F D 7
G B 11
H E,F 4
I G,H 18
ET(C)= 6+4(12)+30
6
ET(C)= 6+4(12)+30
6
ET(C)=84/6=14ET(C)=84/6=14
Task
Immediate
Predecesors Optimistic Most Likely Pessimistic
A None 3 6 15
B None 2 4 14
C A 6 12 30
D A 2 5 8
E C 5 11 17
F D 3 6 15
G B 3 9 27
H E,F 1 4 7
I G,H 4 19 28
Expected Time =
Opt. Time + 4(Most Likely Time) + Pess. Time
6
27
Example 2. Network
A(7)
B
(5.333)
C(14)
D(5)
E(11)
F(7)
H(4)
G(11)
I(18)
Duration = 54 Days
28
Example 2. Probability
Exercise
What is the probability of finishing this project in
less than 53 days?
What is the probability of finishing this project in
less than 53 days?
p(t < D)
TE = 54
Z =
D - TE
cp
2
σ∑
t
D=53
29
Activity variance, = (
Pessim. - Optim.
6
)2 2
σ
Task Optimistic Most Likely Pessimistic Variance
A 3 6 15 4
B 2 4 14
C 6 12 30 16
D 2 5 8
E 5 11 17 4
F 3 6 15
G 3 9 27
H 1 4 7 1
I 4 19 28 16
(Sum the variance along the critical
path.) σ 2
∑ = 41
30
There is a 43.8% probability that this project will be
completed in less than 53 weeks.
There is a 43.8% probability that this project will be
completed in less than 53 weeks.
p(Z < -.156) = .438, or 43.8 % (NORMSDIST(-.156))p(Z < -.156) = .438, or 43.8 % (NORMSDIST(-.156))
Z =
D - T
=
53- 54
41
= -.156E
cp
2
σ∑
TE = 54
p(t < D)
t
D=53
31
Ex 2. Additional Probability Exercise
What is the probability that the project duration
will exceed 56 weeks?
What is the probability that the project duration
will exceed 56 weeks?
32
Example 2. Additional Exercise Solution
t
TE = 54
p(t < D)
D=56
Z =
D - T
=
56- 54
41
= .312E
cp
2
σ∑
p(Z > .312) = .378, or 37.8 % (1-NORMSDIST(.312))p(Z > .312) = .378, or 37.8 % (1-NORMSDIST(.312))
33
Time-Cost Models
Basic Assumption: Relationship between activity
completion time and project cost
Time Cost Models: Determine the optimum point in
time-cost tradeoffs
Activity direct costs
Project indirect costs
Activity completion times
34
CPM Assumptions/Limitations
Project activities can be identified as entities (There
is a clear beginning and ending point for each
activity.)
 Project activity sequence relationships can be
specified and networked
Project control should focus on the critical path
The activity times follow the beta distribution, with
the variance of the project assumed to equal the sum
of the variances along the critical path
Project control should focus on the critical path

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Project management

  • 2. 2 Definition of Project Management Work Breakdown Structure Project Control Charts Structuring Projects Critical Path Scheduling OBJECTIVES
  • 3. 3 Project is a series of related jobs usually directed toward some major output and requiring a significant period of time to perform Project Management are the management activities of planning, directing, and controlling resources (people, equipment, material) to meet the technical, cost, and time constraints of a project Project Management Defined
  • 4. 4 Gantt Chart Activity 1 Activity 2 Activity 3 Activity 4 Activity 5 Activity 6 Time Vertical Axis: Always Activities or Jobs Vertical Axis: Always Activities or Jobs Horizontal Axis: Always TimeHorizontal Axis: Always Time Horizontal bars used to denote length of time for each activity or job. Horizontal bars used to denote length of time for each activity or job.
  • 5. 5 Structuring Projects: Pure Project Advantages The project manager has full authority over the project Team members report to one boss Shortened communication lines Team pride, motivation, and commitment are high Pure Project A pure project is where a self-contained team works full-time on the project
  • 6. 6 Structuring Projects: Pure Project Disadvantages Duplication of resources Organizational goals and policies are ignored Lack of technology transfer Team members have no functional area "home"
  • 7. 7 Functional Project President Research and Development Engineering Manufacturing Project A Project B Project C Project D Project E Project F Project G Project H Project I A functional project is housed within a functional division Example, Project “B” is in the functional area of Research and Development. Example, Project “B” is in the functional area of Research and Development.
  • 8. 8 Structuring Projects Functional Project: Advantages A team member can work on several projects Technical expertise is maintained within the functional area The functional area is a “home” after the project is completed Critical mass of specialized knowledge
  • 9. 9 Structuring Projects Functional Project: Disadvantages Aspects of the project that are not directly related to the functional area get short-changed Motivation of team members is often weak Needs of the client are secondary and are responded to slowly
  • 10. 10 Matrix Project Organization Structure President Research and Development Engineering Manufacturing Marketing Manager Project A Manager Project B Manager Project C
  • 11. 11 Structuring Projects Matrix: Advantages Enhanced communications between functional areas Pinpointed responsibility Duplication of resources is minimized Functional “home” for team members Policies of the parent organization are followed
  • 12. 12 Structuring Projects Matrix: Disadvantages Too many bosses Depends on project manager’s negotiating skills Potential for sub-optimization
  • 13. 13 Work Breakdown Structure Program Project 1 Project 2 Task 1.1 Subtask 1.1.1 Work Package 1.1.1.1 Level 1 2 3 4 Task 1.2 Subtask 1.1.2 Work Package 1.1.1.2 A work breakdown structure defines the hierarchy of project tasks, subtasks, and work packages
  • 14. 14 Network-Planning Models A project is made up of a sequence of activities that form a network representing a project The path taking longest time through this network of activities is called the “critical path” The critical path provides a wide range of scheduling information useful in managing a project Critical Path Method (CPM) helps to identify the critical path(s) in the project networks
  • 15. 15 Prerequisites for Critical Path Methodology A project must have:  well-defined jobs or tasks whose completion marks the end of the project;  independent jobs or tasks;  and tasks that follow a given sequence.
  • 16. 16 Types of Critical Path Methods  CPM with a Single Time Estimate  Used when activity times are known with certainty  Used to determine timing estimates for the project, each activity in the project, and slack time for activities  CPM with Three Activity Time Estimates  Used when activity times are uncertain  Used to obtain the same information as the Single Time Estimate model and probability information  Time-Cost Models  Used when cost trade-off information is a major consideration in planning  Used to determine the least cost in reducing total project time
  • 17. 17 Steps in the CPM with Single Time Estimate 1. Activity Identification 2. Activity Sequencing and Network Construction 3. Determine the critical path From the critical path all of the project and activity timing information can be obtained
  • 18. 18 CPM with Single Time Estimate Consider the following consulting project: Activity Designation Immed. Pred. Time (Weeks) Assess customer's needs A None 2 Write and submit proposal B A 1 Obtain approval C B 1 Develop service vision and goals D C 2 Train employees E C 5 Quality improvement pilot groups F D, E 5 Write assessment report G F 1 Develop a critical path diagram and determine the duration of the critical path and slack times for all activities.
  • 19. 19 First draw the network A(2) B(1) C(1) D(2) E(5) F(5) G(1) A None 2 B A 1 C B 1 D C 2 E C 5 F D,E 5 G F 1 Act. Imed. Pred. Time
  • 20. 20 Determine early starts and early finish times ES=9 EF=14 ES=14 EF=15 ES=0 EF=2 ES=2 EF=3 ES=3 EF=4 ES=4 EF=9 ES=4 EF=6 A(2) B(1) C(1) D(2) E(5) F(5) G(1) Hint: Start with ES=0 and go forward in the network from A to G. Hint: Start with ES=0 and go forward in the network from A to G.
  • 21. 21 Determine late starts and late finish times ES=9 EF=14 ES=14 EF=15 ES=0 EF=2 ES=2 EF=3 ES=3 EF=4 ES=4 EF=9 ES=4 EF=6 A(2) B(1) C(1) D(2) E(5) F(5) G(1) LS=14 LF=15 LS=9 LF=14 LS=4 LF=9 LS=7 LF=9 LS=3 LF=4 LS=2 LF=3 LS=0 LF=2 Hint: Start with LF=15 or the total time of the project and go backward in the network from G to A. Hint: Start with LF=15 or the total time of the project and go backward in the network from G to A.
  • 22. 22 Critical Path & Slack ES=9 EF=14 ES=14 EF=15 ES=0 EF=2 ES=2 EF=3 ES=3 EF=4 ES=4 EF=9 ES=4 EF=6 A(2) B(1) C(1) D(2) E(5) F(5) G(1) LS=14 LF=15 LS=9 LF=14 LS=4 LF=9 LS=7 LF=9 LS=3 LF=4 LS=2 LF=3 LS=0 LF=2 Duration=15 weeks Slack=(7-4)=(9-6)= 3 Wks
  • 23. 23 Example 2. CPM with Three Activity Time Estimates Task Immediate Predecesors Optimistic Most Likely Pessimistic A None 3 6 15 B None 2 4 14 C A 6 12 30 D A 2 5 8 E C 5 11 17 F D 3 6 15 G B 3 9 27 H E,F 1 4 7 I G,H 4 19 28
  • 24. 24 Example 2. Expected Time Calculations ET(A)= 3+4(6)+15 6 ET(A)= 3+4(6)+15 6 ET(A)=42/6=7ET(A)=42/6=7 Task Immediate Predecesors Expected Time A None 7 B None 5.333 C A 14 D A 5 E C 11 F D 7 G B 11 H E,F 4 I G,H 18 Task Immediate Predecesors Optimistic Most Likely Pessimistic A None 3 6 15 B None 2 4 14 C A 6 12 30 D A 2 5 8 E C 5 11 17 F D 3 6 15 G B 3 9 27 H E,F 1 4 7 I G,H 4 19 28 Expected Time = Opt. Time + 4(Most Likely Time) + Pess. Time 6
  • 25. 25 Ex. 2. Expected Time Calculations Task Immediate Predecesors Expected Time A None 7 B None 5.333 C A 14 D A 5 E C 11 F D 7 G B 11 H E,F 4 I G,H 18 ET(B)=32/6=5.333ET(B)=32/6=5.333 ET(B)= 2+4(4)+14 6 ET(B)= 2+4(4)+14 6 Task Immediate Predecesors Optimistic Most Likely Pessimistic A None 3 6 15 B None 2 4 14 C A 6 12 30 D A 2 5 8 E C 5 11 17 F D 3 6 15 G B 3 9 27 H E,F 1 4 7 I G,H 4 19 28 Expected Time = Opt. Time + 4(Most Likely Time) + Pess. Time 6
  • 26. 26 Ex 2. Expected Time Calculations Task Immediate Predecesors Expected Time A None 7 B None 5.333 C A 14 D A 5 E C 11 F D 7 G B 11 H E,F 4 I G,H 18 ET(C)= 6+4(12)+30 6 ET(C)= 6+4(12)+30 6 ET(C)=84/6=14ET(C)=84/6=14 Task Immediate Predecesors Optimistic Most Likely Pessimistic A None 3 6 15 B None 2 4 14 C A 6 12 30 D A 2 5 8 E C 5 11 17 F D 3 6 15 G B 3 9 27 H E,F 1 4 7 I G,H 4 19 28 Expected Time = Opt. Time + 4(Most Likely Time) + Pess. Time 6
  • 28. 28 Example 2. Probability Exercise What is the probability of finishing this project in less than 53 days? What is the probability of finishing this project in less than 53 days? p(t < D) TE = 54 Z = D - TE cp 2 σ∑ t D=53
  • 29. 29 Activity variance, = ( Pessim. - Optim. 6 )2 2 σ Task Optimistic Most Likely Pessimistic Variance A 3 6 15 4 B 2 4 14 C 6 12 30 16 D 2 5 8 E 5 11 17 4 F 3 6 15 G 3 9 27 H 1 4 7 1 I 4 19 28 16 (Sum the variance along the critical path.) σ 2 ∑ = 41
  • 30. 30 There is a 43.8% probability that this project will be completed in less than 53 weeks. There is a 43.8% probability that this project will be completed in less than 53 weeks. p(Z < -.156) = .438, or 43.8 % (NORMSDIST(-.156))p(Z < -.156) = .438, or 43.8 % (NORMSDIST(-.156)) Z = D - T = 53- 54 41 = -.156E cp 2 σ∑ TE = 54 p(t < D) t D=53
  • 31. 31 Ex 2. Additional Probability Exercise What is the probability that the project duration will exceed 56 weeks? What is the probability that the project duration will exceed 56 weeks?
  • 32. 32 Example 2. Additional Exercise Solution t TE = 54 p(t < D) D=56 Z = D - T = 56- 54 41 = .312E cp 2 σ∑ p(Z > .312) = .378, or 37.8 % (1-NORMSDIST(.312))p(Z > .312) = .378, or 37.8 % (1-NORMSDIST(.312))
  • 33. 33 Time-Cost Models Basic Assumption: Relationship between activity completion time and project cost Time Cost Models: Determine the optimum point in time-cost tradeoffs Activity direct costs Project indirect costs Activity completion times
  • 34. 34 CPM Assumptions/Limitations Project activities can be identified as entities (There is a clear beginning and ending point for each activity.)  Project activity sequence relationships can be specified and networked Project control should focus on the critical path The activity times follow the beta distribution, with the variance of the project assumed to equal the sum of the variances along the critical path Project control should focus on the critical path