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Chapter 9Chapter 9
Solids and FluidsSolids and Fluids
• Elasticity
• Archimedes Principle
• Bernoulli’s Equation
States of MatterStates of Matter
• Solid
• Liquid
• Gas
• Plasmas
Solids: Stress and StrainSolids: Stress and Strain
Stress = Measure of force felt by material
• SI units are Pascals, 1 Pa = 1 N/m2
(same as pressure)
Stress =
Force
Area
Solids: Stress and StrainSolids: Stress and Strain
Strain = Measure of deformation
• dimensionless
F
A
∆L
L
Strain =
∆L
L
Y =
F
A( )
∆L
L( )
Young’s Modulus (Tension)Young’s Modulus (Tension)
F
A
∆L
L
• Measure of stiffness
• Tensile refers to tension
tensile stress
tensile strain
Example 9.1Example 9.1
King Kong (a 8.0x104
-kg monkey) swings from a 320-
m cable from the Empire State building. If the 3.0-
cm diameter cable is made of steel (Y=1.8x1011
Pa),
by how much will the cable stretch?
1.97 m
S =
F
A( )
∆x
h( )
Shear ModulusShear Modulus
Sheer Stress
Sheer Strain
B = −
∆F
A
∆V
V
= −
∆P
∆V
V( )
Bulk ModulusBulk Modulus
Change in Pressure
Volume Strain
B = Y
3
Pascals as units for PressurePascals as units for Pressure
1 Pa = 1 N/m2
P =
F
A
Example 9.2Example 9.2
A large solid steel (Y=1.8x1011
Pa) block (L 5 m, W=4 m,
H=3 m) is submerged in the Mariana Trench where the
pressure is 7.5x107
Pa.
a) By what percentage does the length change?
b) What are the changes in the length, width and height?
c) By what percentage does the volume change?
-2.08 mm, -1.67 mm, -1.25 mm
-0.041 %
-0.125%
Solids and LiquidsSolids and Liquids
• Solids have Young’s, Bulk, and Shear moduli
• Liquids have only bulk moduli
Ultimate StrengthUltimate Strength
• Maximum F/A before fracture or crumbling
• Different for compression and tension
DensitiesDensities
ρ =
M
V
Density and Specific GravityDensity and Specific Gravity
• Densities depend on temperature, pressure...
• Specific gravity = ratio of density to density of
H2O at 4 °C.
Example 9.3Example 9.3
The specific gravity of gold is 19.3. What is the mass
(in kg) and weight (in lbs.) of 1 cubic meter of gold?
19,300 kg
42549 lbs
Pressure & Pascal’s PrinciplePressure & Pascal’s Principle
“Pressure applied to any part of
an enclosed fluid is transmitted
undimished to every point of the
fluid and to the walls of the
container”
Each face feels same force
P =
F
A
Transmitting forceTransmitting force
An applied force F1 can
be “amplified”:
Hydraulic press
Examples: hydraulic brakes,
forklifts, car lifts, etc.
P =
F1
A1
=
F2
A2
F2 = F1
A2
A1
Pressure and DepthPressure and Depth
w is weight
Sum forces to zero,
Factor A
w = Mg = ρVg = ρAhg
PA − P0A − w = 0
P = P0 + ρgh
Example 9.5 (skip)Example 9.5 (skip)
Find the pressure at 10,000 m of water.
DATA: Atmospheric pressure = 1.015x105
Pa.
9.82x107
Pa
Example 9.6Example 9.6
Assume the ultimate strength of legos is 4.0x104
Pa. If the density of legos is 150 kg/m3
, what is
the maximum possible height for a lego tower?
27.2 m
Example 9.7Example 9.7
Estimate the mass of the Earth’s atmosphere given
that atmospheric pressure is 1.015x105
Pa.
Data: Rearth=6.36x106
m
5.26x1018
kg
Archimedes PrincipleArchimedes Principle
Any object completely or partially submerged in a fluid
is buoyed up by a force whose magnitude is equal to
the weight of the fluid displaced by the object.
Example 9.8Example 9.8
A helicopter lowers a probe into Lake Michigan which
is suspended on a cable. The probe has a mass of 500
kg and its average density is 1400 kg/m3
. What is the
tension in the cable?
1401 N
Example 9.9aExample 9.9a
A wooden ball of mass M and volume V floats on a
swimming pool. The density of the wood is ρwood <ρH20.
The buoyant force acting on the ball is:
a) Mg upward
b) ρH20gV upward
c) (ρH20-ρwood)gV upward
Example 9.9bExample 9.9b
A steel ball of mass M and volume V rests on the
bottom of a swimming pool. The density of the steel
is ρsteel >ρH20. The buoyant force acting on the ball is:
a) Mg upward
b) ρH20gV upward
c) (ρsteel-ρH20)gV upward
Example 9.10Example 9.10
A small swimming pool has an area of 10 square
meters. A wooden 4000-kg statue of density 500
kg/m3
is then floated on top of the pool. How far
does the water rise?
Data: Density of water = 1000 kg/m3
40 cm
Floating Coke Demo (SKIP)Floating Coke Demo (SKIP)
The can will
a) Float
b) Sink
Paint Thinner Demo (SKIP)Paint Thinner Demo (SKIP)
When I pour in the paint thinner, the cylinder will:
a) Rise
b) Fall
Equation of ContinuityEquation of Continuity
What goes in must come out!
Mass that passes a point
in pipe during time ∆t
mass density
∆M = ρA∆x = ρAv∆t
Eq. of Continuity
ρ1A1v1 = ρ2A2v2
Example 9.11Example 9.11
Water flows through a 4.0 cm diameter pipe at 5
cm/s. The pipe then narrows downstream and has a
diameter of of 2.0 cm. What is the velocity of the
water through the smaller pipe?
20 cm/s
Laminar or Streamline FlowLaminar or Streamline Flow
• Fluid elements move
along smooth paths
• Friction in laminar flow
is called viscosity
TurbulenceTurbulence
• Fluid elements move along irregular paths
• Sets in for high velocity gradients (small pipes)
Ideal FluidsIdeal Fluids
• Laminar Flow -> No turbulence
• Non-viscous -> No friction between fluid layers
• Incompressible -> Density is same everywhere
Bernoulli’s EquationBernoulli’s Equation
Sum of P, KE/V and PE/V is constant
How can we derive this?
P +
1
2
ρv2
+ ρgy = const ant
Bernoulli’s Equation: derivationBernoulli’s Equation: derivation
Consider a volume ∆V of mass ∆M of incompressible fluid,
∆KE =
1
2
Mv2
2
−
1
2
Mv1
2
=
1
2
ρ∆Vv2
2
−
1
2
ρ∆Vv1
2
∆PE = Mgy2 − Mgy1
= ρ∆Vgy2 − ρ∆Vgy1
W = F1∆x1 − F2∆x2
= P1A1∆x1 − P2A2∆x2
= P1∆V − P2∆V
P1 + ρgh1 +
1
2
ρv1
2
= P2 + ρgh2 +
1
2
ρv2
2
Example 9.12Example 9.12
A very large pipe carries
water with a very slow
velocity and empties into a
small pipe with a high
velocity. If P2 is 7000 Pa
lower than P1, what is the
velocity of the water in
the small pipe?
3.74 m/s
Venturi Meter
Applications of Bernoulli’s EquationApplications of Bernoulli’s Equation
•Venturi meter
•Curve balls
•Airplanes
Beach Ball & Straws DemosBeach Ball & Straws Demos
Example 9.13aExample 9.13a
Consider an ideal incompressible fluid,
choose >, < or =
ρ1 ____ ρ2
a) =
b) <
c) >
Example 9.13bExample 9.13b
Consider an ideal incompressible fluid,
choose >, < or =
Mass that passes “1” in one second
_____ mass that passes “2” in one second
a) =
b) <
c) >
Example 9.13cExample 9.13c
Consider an ideal incompressible fluid,
choose >, < or =
v1 ____ v2
a) =
b) <
c) >
Example 9.13dExample 9.13d
Consider an ideal incompressible fluid,
choose >, < or =
P1 ____ P2
a) =
b) <
c) >
Example 9.14Example 9.14
Water drains out of the bottom of a
cooler at 3 m/s, what is the depth of
the water above the valve?
a
b
45.9 cm
Three Vocabulary WordsThree Vocabulary Words
•Viscosity
•Diffusion
•Osmosis
ViscosityViscosity
•Friction between the layers
•Pressure drop required to
force water through pipes
(Poiselle’s Law)
•At high enough v/d,
turbulence sets in
F = ηA
v
d
DiffusionDiffusion
• Molecules move from region of high concentration
to region of low concentration
• Fick’s Law:
• D = diffusion
coefficient
Diffusion rate =
Mass
time
= DA
C2 − C1
L




OsmosisOsmosis
Movement of water through a boundary while
denying passage to specific molecules, e.g.
salts

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041616 week6 archimedes

  • 1. Chapter 9Chapter 9 Solids and FluidsSolids and Fluids • Elasticity • Archimedes Principle • Bernoulli’s Equation
  • 2. States of MatterStates of Matter • Solid • Liquid • Gas • Plasmas
  • 3. Solids: Stress and StrainSolids: Stress and Strain Stress = Measure of force felt by material • SI units are Pascals, 1 Pa = 1 N/m2 (same as pressure) Stress = Force Area
  • 4. Solids: Stress and StrainSolids: Stress and Strain Strain = Measure of deformation • dimensionless F A ∆L L Strain = ∆L L
  • 5. Y = F A( ) ∆L L( ) Young’s Modulus (Tension)Young’s Modulus (Tension) F A ∆L L • Measure of stiffness • Tensile refers to tension tensile stress tensile strain
  • 6. Example 9.1Example 9.1 King Kong (a 8.0x104 -kg monkey) swings from a 320- m cable from the Empire State building. If the 3.0- cm diameter cable is made of steel (Y=1.8x1011 Pa), by how much will the cable stretch? 1.97 m
  • 7. S = F A( ) ∆x h( ) Shear ModulusShear Modulus Sheer Stress Sheer Strain
  • 8. B = − ∆F A ∆V V = − ∆P ∆V V( ) Bulk ModulusBulk Modulus Change in Pressure Volume Strain B = Y 3
  • 9. Pascals as units for PressurePascals as units for Pressure 1 Pa = 1 N/m2 P = F A
  • 10. Example 9.2Example 9.2 A large solid steel (Y=1.8x1011 Pa) block (L 5 m, W=4 m, H=3 m) is submerged in the Mariana Trench where the pressure is 7.5x107 Pa. a) By what percentage does the length change? b) What are the changes in the length, width and height? c) By what percentage does the volume change? -2.08 mm, -1.67 mm, -1.25 mm -0.041 % -0.125%
  • 11. Solids and LiquidsSolids and Liquids • Solids have Young’s, Bulk, and Shear moduli • Liquids have only bulk moduli
  • 12. Ultimate StrengthUltimate Strength • Maximum F/A before fracture or crumbling • Different for compression and tension
  • 14. Density and Specific GravityDensity and Specific Gravity • Densities depend on temperature, pressure... • Specific gravity = ratio of density to density of H2O at 4 °C.
  • 15. Example 9.3Example 9.3 The specific gravity of gold is 19.3. What is the mass (in kg) and weight (in lbs.) of 1 cubic meter of gold? 19,300 kg 42549 lbs
  • 16. Pressure & Pascal’s PrinciplePressure & Pascal’s Principle “Pressure applied to any part of an enclosed fluid is transmitted undimished to every point of the fluid and to the walls of the container” Each face feels same force P = F A
  • 17. Transmitting forceTransmitting force An applied force F1 can be “amplified”: Hydraulic press Examples: hydraulic brakes, forklifts, car lifts, etc. P = F1 A1 = F2 A2 F2 = F1 A2 A1
  • 18. Pressure and DepthPressure and Depth w is weight Sum forces to zero, Factor A w = Mg = ρVg = ρAhg PA − P0A − w = 0 P = P0 + ρgh
  • 19. Example 9.5 (skip)Example 9.5 (skip) Find the pressure at 10,000 m of water. DATA: Atmospheric pressure = 1.015x105 Pa. 9.82x107 Pa
  • 20. Example 9.6Example 9.6 Assume the ultimate strength of legos is 4.0x104 Pa. If the density of legos is 150 kg/m3 , what is the maximum possible height for a lego tower? 27.2 m
  • 21. Example 9.7Example 9.7 Estimate the mass of the Earth’s atmosphere given that atmospheric pressure is 1.015x105 Pa. Data: Rearth=6.36x106 m 5.26x1018 kg
  • 22. Archimedes PrincipleArchimedes Principle Any object completely or partially submerged in a fluid is buoyed up by a force whose magnitude is equal to the weight of the fluid displaced by the object.
  • 23. Example 9.8Example 9.8 A helicopter lowers a probe into Lake Michigan which is suspended on a cable. The probe has a mass of 500 kg and its average density is 1400 kg/m3 . What is the tension in the cable? 1401 N
  • 24. Example 9.9aExample 9.9a A wooden ball of mass M and volume V floats on a swimming pool. The density of the wood is ρwood <ρH20. The buoyant force acting on the ball is: a) Mg upward b) ρH20gV upward c) (ρH20-ρwood)gV upward
  • 25. Example 9.9bExample 9.9b A steel ball of mass M and volume V rests on the bottom of a swimming pool. The density of the steel is ρsteel >ρH20. The buoyant force acting on the ball is: a) Mg upward b) ρH20gV upward c) (ρsteel-ρH20)gV upward
  • 26. Example 9.10Example 9.10 A small swimming pool has an area of 10 square meters. A wooden 4000-kg statue of density 500 kg/m3 is then floated on top of the pool. How far does the water rise? Data: Density of water = 1000 kg/m3 40 cm
  • 27. Floating Coke Demo (SKIP)Floating Coke Demo (SKIP) The can will a) Float b) Sink
  • 28. Paint Thinner Demo (SKIP)Paint Thinner Demo (SKIP) When I pour in the paint thinner, the cylinder will: a) Rise b) Fall
  • 29. Equation of ContinuityEquation of Continuity What goes in must come out! Mass that passes a point in pipe during time ∆t mass density ∆M = ρA∆x = ρAv∆t Eq. of Continuity ρ1A1v1 = ρ2A2v2
  • 30. Example 9.11Example 9.11 Water flows through a 4.0 cm diameter pipe at 5 cm/s. The pipe then narrows downstream and has a diameter of of 2.0 cm. What is the velocity of the water through the smaller pipe? 20 cm/s
  • 31. Laminar or Streamline FlowLaminar or Streamline Flow • Fluid elements move along smooth paths • Friction in laminar flow is called viscosity
  • 32. TurbulenceTurbulence • Fluid elements move along irregular paths • Sets in for high velocity gradients (small pipes)
  • 33. Ideal FluidsIdeal Fluids • Laminar Flow -> No turbulence • Non-viscous -> No friction between fluid layers • Incompressible -> Density is same everywhere
  • 34. Bernoulli’s EquationBernoulli’s Equation Sum of P, KE/V and PE/V is constant How can we derive this? P + 1 2 ρv2 + ρgy = const ant
  • 35. Bernoulli’s Equation: derivationBernoulli’s Equation: derivation Consider a volume ∆V of mass ∆M of incompressible fluid, ∆KE = 1 2 Mv2 2 − 1 2 Mv1 2 = 1 2 ρ∆Vv2 2 − 1 2 ρ∆Vv1 2 ∆PE = Mgy2 − Mgy1 = ρ∆Vgy2 − ρ∆Vgy1 W = F1∆x1 − F2∆x2 = P1A1∆x1 − P2A2∆x2 = P1∆V − P2∆V P1 + ρgh1 + 1 2 ρv1 2 = P2 + ρgh2 + 1 2 ρv2 2
  • 36. Example 9.12Example 9.12 A very large pipe carries water with a very slow velocity and empties into a small pipe with a high velocity. If P2 is 7000 Pa lower than P1, what is the velocity of the water in the small pipe? 3.74 m/s Venturi Meter
  • 37. Applications of Bernoulli’s EquationApplications of Bernoulli’s Equation •Venturi meter •Curve balls •Airplanes Beach Ball & Straws DemosBeach Ball & Straws Demos
  • 38. Example 9.13aExample 9.13a Consider an ideal incompressible fluid, choose >, < or = ρ1 ____ ρ2 a) = b) < c) >
  • 39. Example 9.13bExample 9.13b Consider an ideal incompressible fluid, choose >, < or = Mass that passes “1” in one second _____ mass that passes “2” in one second a) = b) < c) >
  • 40. Example 9.13cExample 9.13c Consider an ideal incompressible fluid, choose >, < or = v1 ____ v2 a) = b) < c) >
  • 41. Example 9.13dExample 9.13d Consider an ideal incompressible fluid, choose >, < or = P1 ____ P2 a) = b) < c) >
  • 42. Example 9.14Example 9.14 Water drains out of the bottom of a cooler at 3 m/s, what is the depth of the water above the valve? a b 45.9 cm
  • 43. Three Vocabulary WordsThree Vocabulary Words •Viscosity •Diffusion •Osmosis
  • 44. ViscosityViscosity •Friction between the layers •Pressure drop required to force water through pipes (Poiselle’s Law) •At high enough v/d, turbulence sets in F = ηA v d
  • 45. DiffusionDiffusion • Molecules move from region of high concentration to region of low concentration • Fick’s Law: • D = diffusion coefficient Diffusion rate = Mass time = DA C2 − C1 L    
  • 46. OsmosisOsmosis Movement of water through a boundary while denying passage to specific molecules, e.g. salts