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ELECTRICAL 
TRANSMISSION 
Line 
---By Dhananjay Jha, Engineer (E), SJVN
 Electrical transmission system is the 
means of transmitting power from 
generating station to different load 
centres. 
---By Dhananjay Jha, Engineer (E), SJVN
 gridmappowergrid_map.pdf 
---By Dhananjay Jha, Engineer (E), SJVN
 Transmission Network 
 Conductor 
 Earthwire 
 Inuslator 
 Tower 
---By Dhananjay Jha, Engineer (E), SJVN
 Network 
 Transmission line model 
 Characteristics 
 Conductors 
 Insulators 
 Earthwire 
---By Dhananjay Jha, Engineer (E), SJVN
 Generating Station 
 Transmission Line 
 Sub-Stations 
---By Dhananjay Jha, Engineer (E), SJVN
 Associated system 
 Voltage magnitudes & angle 
 Active and reactive power 
---By Dhananjay Jha, Engineer (E), SJVN
---By Dhananjay Jha, Engineer (E), SJVN
A transmission line can be represented by a 2-port network – a 
network that can be isolated from the outside world by two 
connections (ports) as shown: 
---By Dhananjay Jha, Engineer (E), SJVN
If the network is linear, an elementary circuits theorem (analogous to 
Thevenin’s theorem) establishes the relationship between the sending and 
receiving end voltages and currents as 
V AV BI 
I CV DI 
  
  
S R R 
S R R 
Here constants A and D are dimensionless, a constant B has units of , 
and a constant C is measured in siemens. These constants are sometimes 
referred to as generalized circuit constants, or ABCD constants.
•Upto 80 Km 
•Shunt capacitance is neglected and resistance & inductance are lumped 
together. 
•Therefore, IS = IR = I 
Hence the ABCD constants for the short transmission line model, are 
A 
 
1 
B  
Z 
C 
 
0 
D 
 
1
Considering medium-length lines (80 to 250 Km-long). 
•The shunt admittance is also included for 
calculations. However, the total admittance is 
usually modeled ( model) as two capacitors of 
equal values (each corresponding to a half of total 
admittance) placed at the sending and receiving 
ends.
The current through the receiving end capacitor can be found as : 
Y 
I V 
2 2 C R 
And the current through the series impedance elements is : 
Y 
I V  I 
2 ser R R 
---By Dhananjay Jha, Engineer (E), SJVN
From the Kirchhoff’s voltage law, the sending end voltage is 
YZ 
  
  2 1 
S ser R C R R 2 R R ZI V Z I I V 
V V ZI 
     
  
     
The source current will be 
Y Y 
    
I I  I  I  I  I  V 
  I Y V I 
ZY 
V 
ZY 
        
1 1 2 1 1 
2 2 4 2 S C ser C C R S R R R R 
   
 
 
Therefore, the ABCD constants of a medium-length transmission line are 
1 
ZY 
2 
1 
4 
1 
2 
A 
B Z 
ZY 
C Y 
ZY 
D 
  
 
  
    
  
  
If the shunt capacitance of the line is 
ignored, the ABCD constants are the 
constants for a short transmission line.
• For long lines, it is not accurate enough to approximate the shunt 
admittance by two constant capacitors at either end of the line. 
Instead, both the shunt capacitance and the series impedance must be 
treated as distributed quantities. 
• The voltages and currents on the line is found by solving differential 
equations of the line.
d 
 
 
  
sinh 
' 
tanh 2 
' 
2 
Z Z 
d 
d 
Y Y 
 
d 
 
 
 
Here, Z is the series impedance of the line, 
Y is the shunt admittance of the line, 
d is the length of the line, 
 is the propagation constant of the line. 
  yz 
where y is the shunt admittance per kilometer and z is the 
series impedance per km.
The ABCD constants for a long transmission line are 
Z Y 
' ' 
1 
2 
' 
' ' 
' 1 
4 
' ' 
1 
2 
A 
B Z 
Z Y 
C Y 
Z Y 
D 
  
 
  
    
  
 
AC voltages are usually expressed as phasors. 
Load with lagging power factor. 
Load with unity power factor. 
Load with leading power factor. 
For a given source voltage VS and 
magnitude of the line current, the 
received voltage is lower for 
lagging loads and higher for 
leading loads.
In overhead transmission lines, the line reactance XL is normally much larger than 
the line resistance R; therefore, the line resistance is often neglected. We consider 
next some important transmission line characteristics… 
1. The effect of load changes 
Assuming that a single generator 
supplies a single load through a 
transmission line. 
Assuming that the generator is ideal, an increase of load will increase a 
real and (or) reactive power drawn from the generator and, therefore, 
the line current. 
1) If more load is added with the same lagging power factor, the 
magnitude of the line current increases but the current remains at the 
same angle  with respect to VR as before.
The voltage drop across the reactance increases but stays at the same 
angle. 
Assuming zero line resistance and source voltage to 
be of constant magnitude: 
Vs = VR + jXLI 
voltage drop across reactance jXLI will stretch 
between VR and VS. 
Therefore, when a lagging load increases, the received voltage 
decreases. 
2) An increase in a unity PF load, 
on the other hand, will slightly 
decrease the received voltage at 
the end of the transmission line.
3) Finally, an increase in a load with 
leading PF increases the received 
(terminal) voltage of the transmission line.
 In a summary: 
1. If lagging (inductive) loads are added at the end of a line, the 
voltage at the end of the transmission line decreases . 
2. If leading (capacitive) loads are added at the end of a line, the 
voltage at the end of the transmission line increases. 
---By Dhananjay Jha, Engineer (E), SJVN
The voltage regulation of a transmission 
line is 
 VReg = (Vnl - Vfl )/ Vfl 
where Vnl and Vfl are the no-load and full 
load voltages at the line output. 
---By Dhananjay Jha, Engineer (E), SJVN
2. Power flow in a transmission line 
The real power input to a 3-phase transmission line can be computed as 
, 3 cos Pin  VS IS S  3VLL S IS cosS 
where VS is the magnitude of the source (input) line-to-neutral voltage and VLL,S is 
the magnitude of the source (input) line-to-line voltage. 
Similarly, the real output power from the transmission line is 
, 3 cos 3 cos out R R R LL R R R P  V I   V I  
The reactive power input to a 3-phase transmission line can be computed as 
, 3 sin 3 sin in S S S LL S S S Q  V I   V I 
And the reactive output power is 
, 3 sin Qout  VRIR R  3VLL RIR sinR 
The apparent power input to a 3-phase transmission line can be 
computed as 
, 3 3 in S S LL S S S  V I  V I 
And the apparent output power is 
, 3 3 out R R LL R R S  V I  V I
A simplified phasor diagram of a transmission line indicating that IS = IR = I. 
Further it can be observed that the vertical segment bc can be expressed as 
either VS sin or XLIcos. Therefore: 
sin 
cos S 
L 
V 
I 
X 
 
 
Then the output power of the transmission line equals to its input 
power: 
V V 
3 sin S R 
L 
P 
X 
 
 
Therefore, the power supplied by a transmission line depends on the angle between 
the phasors representing the input and output voltages. 
The maximum power supplied by the transmission line occurs when  = 900: 
max 
V V 
3 S R 
L 
P 
X 
 
This maximum power is called the steady-state stability limit of the transmission 
line. The real transmission lines have non-zero resistance and, therefore, overheat 
long before this point. Full-load angles of 250 are more typical for real 
transmission lines.
 Few interesting observations can be made from the power 
expressions: 
 The maximum power handling capability of a transmission 
line is a function of the square of its voltage. For instance, if 
all other parameters are equal, a 220 kV line will have 4 times 
the power handling capability of a 110 kV transmission line. 
 Therefore, it is beneficial to increase the voltage. However, 
very high voltages is limit by other factors. 
---By Dhananjay Jha, Engineer (E), SJVN
 The maximum power handling capability of a transmission line is 
inversely proportional to its series reactance, which may be a 
serious problem for long transmission lines. Some very long lines 
include series capacitors to reduce the total series reactance and 
thus increase the total power handling capability of the line. 
 In a normal operation of a power system, the magnitudes of 
voltages VS and VR do not change much, therefore, the angle  
basically controls the power flowing through the line. It is 
possible to control power flow by placing a phase-shifting 
transformer at one end of the line and varying voltage phase.
3. Transmission line efficiency 
The efficiency of the transmission line is 
P 
P 
100% out 
in 
  
4. Transmission line ratings 
One of the main limiting factors in transmission line operation is its resistive 
heating. Since this heating is a function of the square of the current flowing through 
the line and does not depend on its phase angle, transmission lines are typically 
rated at a nominal voltage and apparent power. 
5. Transmission line limits 
Several practical constrains limit the maximum real and reactive power that a 
transmission line can supply. The most important constrains are: 
1. The maximum steady-state current must be limited to prevent the overheating in 
the transmission line. The power lost in a line is approximated as 
Ploss  3IL2R 
The greater the current flow, the greater the resistive heating losses.
2. The voltage drop in a practical line should be limited to approximately 5%. In 
other words, the ratio of the magnitude of the receiving end voltage to the 
magnitude of the sending end voltage should be greater than 95%. 
This limit prevents excessive voltage variations in a power system. 
3. The angle  in a transmission line should typically be  300 ensuring that the 
power flow in the transmission line is well below the static stability limit and, 
therefore, the power system can handle transients.
 Any of these limits can be more or less important in different 
circumstances. 
 In short lines, where series reactance X is relatively small, the 
resistive heating usually limits the power that the line can supply. 
 In longer lines operating at lagging power factors, the voltage 
drop across the line is usually the limiting factor. 
 In longer lines operating at leading power factors, the maximum 
angle  can be the limiting f actor. 
---By Dhananjay Jha, Engineer (E), SJVN
 Standard Voltage - 66,110,132, 220, 400 KV 
or above 
 Selection Criterion of Economic Voltage – 
 Quantum of power to be evacuated 
 Length of line 
 Voltage regulation 
 Power loss in Transmission 
 Surge impedance level 
---By Dhananjay Jha, Engineer (E), SJVN
Economic Voltage of Transmission of Power 
L KVA 
Nc 
Empirical Formula 
V 
 5.5  
1.6 150 * 
V = Transmission voltage (KV) (L-L). 
L = Distance of transmission line in KM 
KVA=Power to be transferred 
Nc= Number of circuits 
---By Dhananjay Jha, Engineer (E), SJVN
---By Dhananjay Jha, Engineer (E), SJVN
 Aluminium Conductor Steel Reinforced consists of a 
solid or stranded steel core surrounded by one or more 
layers of strands of 1350 aluminium. The high-strength 
ACSR 8/1, 12/7 and 16/19 standings', are used mostly 
for overhead ground wires, extra long spans, river 
crossings, etc. The inner core wires of ACSR is of zinc 
coated (galvanized) steel. 
---By Dhananjay Jha, Engineer (E), SJVN
 Nomenclature :- Al/Steel/dia. 
 Panther :- 30/7/3.0 mm 
 Zebra :- 54/7/3.18mm 
 Snowbird :- 42/3.98 + 7/2.21mm 
 Moose :- 54/7/3.53mm 
---By Dhananjay Jha, Engineer (E), SJVN
 AAC (All Aluminium Conductor) 
 AAAC (All Aluminium Alloy Conductor) 
 AL-59 
 ACCC (Aluminium conductor composite core) 
---By Dhananjay Jha, Engineer (E), SJVN
ACSR Moose AAAC Moose Al-59 
Dia. (mm) 31.77 31.05 31.50 
Cross sectional area 
(sq-mm) 
597 570 586.59 
Ambient 
Temperature 
(deg.C) 
40 40 40 
Current carrying 
capacity(A) at 75 C 
728 699 759 
At 95 C NA 952 976 
SAG (m) at 85 C 13.26 14.15 14.52 
---By Dhananjay Jha, Engineer (E), SJVN
 Mechanical Requirement 
 Electrical Requirement 
Mechanical Requirement 
 Tensile Strength(For Tension) 
 Strain Strength(For Vibration) 
---By Dhananjay Jha, Engineer (E), SJVN
o Continuous current rating. 
o Short time current carrying rating. 
o Voltage drop 
o Power loss 
o Minimum dia to avoid corona 
o Length of line 
---By Dhananjay Jha, Engineer (E), SJVN
According to short time rating conductor size is given 
by- 
A 7.58* IF * t 
Where A=area of conductor(mm2) 
IF= fault current(KA) 
t= fault duration(1 sec.) 
---By Dhananjay Jha, Engineer (E), SJVN
Visual corona voltage in fair weather condition is 
given by- 
 (1  0.3) 
 
 V0= corona starting voltage, KV(rms) 
 r= radius of conductor in cm 
 
D 
 D= GMD equivalent spacing between conductors in cm 
 m= roughness factor 
= 1.0 for clean smooth conductor 
=0.85 for stranded conductor 
  
 
  
 
  
r 
n 
r 
r 
V 0 21.1 
m log 
 
---By Dhananjay Jha, Engineer (E), SJVN
Voltage gradient at the surface of conductor at operating voltage- 
 
 
 
g 3 
 
 
 
 
D 
r 
V 
Log 
n 
0 
Corona discharge form at the surface of conductor if g0≥ corona 
starting gradient i.e. 
g m r (1 0.3) 
r 
21.1 
0 
 
    
(rms kv/cm) 
---By Dhananjay Jha, Engineer (E), SJVN
 River crossing 
 Weight/ Dia. - Less Weight/Dia ratio conductor swing more. 
---By Dhananjay Jha, Engineer (E), SJVN
In overhead transmission lines, the conductors are suspended 
from a pole or a tower via insulators.
Insulator are required to support the line conductor and 
provide clearance from ground and structure. 
 Insulator material- 
 High grade Electrical Porcelain 
 Toughened Glass 
 Fiber Glass 
---By Dhananjay Jha, Engineer (E), SJVN
 System over voltage factors shall be 
evaluated. 
 Due to switching 
 Power frequency 
 Lightning 
---By Dhananjay Jha, Engineer (E), SJVN
 Switching over-voltage : 
 Switching off of long lines on no load 
 Energizing lines of no load 
---By Dhananjay Jha, Engineer (E), SJVN
 Power frequency over voltage 
 Loaded line interrupted at one end 
 Occurrence of fault 
 Open line suddenly connected to load 
---By Dhananjay Jha, Engineer (E), SJVN
---By Dhananjay Jha, Engineer (E), SJVN
Type of Insulator- 
 Pin type insulator 
 Suspension insulator 
 Strain insulator 
---By Dhananjay Jha, Engineer (E), SJVN
 Pin Type Insulator : Used for transmission and 
distribution of electric power at voltages up 
to 33 kV 
---By Dhananjay Jha, Engineer (E), SJVN
 Suspension : For voltages greater than 33 kV, 
it is a usual practice to use suspension type 
insulators 
---By Dhananjay Jha, Engineer (E), SJVN
 Strain : A dead end or anchor pole or tower is used 
where a straight section of line ends, or angles off 
in another direction. 
---By Dhananjay Jha, Engineer (E), SJVN
 Disc insulator are joint by their ball pins and 
socket in their caps to form string. 
 No of insulator disc is decided by system 
voltage, switching and lighting over voltage 
amplitude and pollution level. 
 Insulator string can be used either suspension 
or tension. 
 Swing of suspension string due to wind has to 
be taken into consider. 
Fig. single string 
Fig. Double string 
---By Dhananjay Jha, Engineer (E), SJVN
Earth wire provided above the phase conductor across the line 
and grounded at every tower. 
 It shield the line conductor from direct strokes 
 Reduces voltage stress across the insulating strings during lightning 
strokes 
Design criterion: 
 Shield angle 
 25°-30° up to 220 KV 
 20° for 400 KV and above 
 Earth wire should be adequate to carry very short duration lightning 
surge current of 100 KA without excessive over heating 
---By Dhananjay Jha, Engineer (E), SJVN
EARTH WIRE 
A  5 I  t 
A= Area(in mm2) of conductor 
I =current in KA 
t = Time in second 
Area of Steel Wire = 3*A(mm2) 
 For EHV line it is suggested as 70 mm2 (7/3.66 mm). 
 ACSR is used as earth wire (12/3.0 mm AL+7/3.0 mm steel) 
 OPGW 
---By Dhananjay Jha, Engineer (E), SJVN
 Optical Ground Wire 
 Advantages : 
 Serves the dual purpose of ground wire and 
communication. 
 High speed data transmission. 
 
---By Dhananjay Jha, Engineer (E), SJVN
OPGW 
---By Dhananjay Jha, Engineer (E), SJVN
---By Dhananjay Jha, Engineer (E), SJVN
---By Dhananjay Jha, Engineer (E), SJVN
 A Smart Grid is an electricity network that can 
intelligently integrate the actions of all users connected 
to it – generators, consumers and those that do both – 
in order to efficiently deliver sustainable, economic 
and secure electricity supplies. European Smart Grid 
Technology Platform 
 SG3 defines Smart Grids as the concept of 
modernizing the electric grid. The Smart Grid is 
integrating the electrical and information technologies 
in between any point of generation and any point of 
consumption. Smart Grid Working Group 3 
---By Dhananjay Jha, Engineer (E), SJVN
 The aim of smart grid is to provide real-time 
monitoring and control, and thus improve the 
overall efficiency of the entire system apart from 
inclusion of renewable energy resources into the 
system. 
---By Dhananjay Jha, Engineer (E), SJVN
 Presently, the Indian electricity system faces 
a number of challenges: 
 Shortage of power 
 Power Theft 
 Poor access to electricity in rural areas 
 Huge losses in the grid 
 Inefficient power consumption 
 Poor reliability 
---By Dhananjay Jha, Engineer (E), SJVN
 The Smart Grid is a transition of the present 
energy system into a new era of reliability, 
availability and efficiency. 
 The smart grid vision involves a uniformly 
integrated communication system with the present 
power system. 
---By Dhananjay Jha, Engineer (E), SJVN
 The India Smart Grid Task Force (ISGTF) is an 
inter-ministerial group set up under the 
chairmanship of Shri Sam Pitroda in September 
2010 to serve as Government's focal point for 
activities related to Smart Grid and to evolve a 
road map for Smart Grids in India. 
---By Dhananjay Jha, Engineer (E), SJVN
 Indian Smart Grid Forum (ISGF) was set up in 
2010 to provide a mechanism through which 
academia, industry, utilities and other stakeholders 
could participate in the development of Indian 
smart grid systems and provide relevant inputs to 
the government’s decision-making. 
---By Dhananjay Jha, Engineer (E), SJVN
 UHBVN,Haryana 
 CESC, Mysore 
 TSECL, Tripura 
 KSEB, Kerala 
 Electricity department-Govt. of Puducherry 
 UGVCL, Gujrat 
 AP CPDCL, Andhra Pradesh 
 APDCL, Assam 
 MSEDCL, Maharashtra 
 CSPDCL, Chattisgarh 
 HPSEB, Himachal Pradesh 
 PSPCL, Punjab 
 WBSEDCL, West Bengal 
 JVVNL, Rajasthan 
---By Dhananjay Jha, Engineer (E), SJVN
 HPSEB, Himachal Pradesh 
 Project Area- Kala Amb 
 No. of Consumers-650 
 Total Cost- 17.85 Cr. 
 MoP Share-Rs. 8.92 Cr. 
---By Dhananjay Jha, Engineer (E), SJVN
 Benefits Envisaged 
 Shifting peak load 
 Reduction in penalties 
 Reduction in outages 
 Status- RFP (Request for Proposal) issued on 
25.08.2014. 
---By Dhananjay Jha, Engineer (E), SJVN
---By Dhananjay Jha, Engineer (E), SJVN

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Electrical transmission line

  • 1. ELECTRICAL TRANSMISSION Line ---By Dhananjay Jha, Engineer (E), SJVN
  • 2.  Electrical transmission system is the means of transmitting power from generating station to different load centres. ---By Dhananjay Jha, Engineer (E), SJVN
  • 3.  gridmappowergrid_map.pdf ---By Dhananjay Jha, Engineer (E), SJVN
  • 4.  Transmission Network  Conductor  Earthwire  Inuslator  Tower ---By Dhananjay Jha, Engineer (E), SJVN
  • 5.  Network  Transmission line model  Characteristics  Conductors  Insulators  Earthwire ---By Dhananjay Jha, Engineer (E), SJVN
  • 6.  Generating Station  Transmission Line  Sub-Stations ---By Dhananjay Jha, Engineer (E), SJVN
  • 7.  Associated system  Voltage magnitudes & angle  Active and reactive power ---By Dhananjay Jha, Engineer (E), SJVN
  • 8. ---By Dhananjay Jha, Engineer (E), SJVN
  • 9. A transmission line can be represented by a 2-port network – a network that can be isolated from the outside world by two connections (ports) as shown: ---By Dhananjay Jha, Engineer (E), SJVN
  • 10. If the network is linear, an elementary circuits theorem (analogous to Thevenin’s theorem) establishes the relationship between the sending and receiving end voltages and currents as V AV BI I CV DI     S R R S R R Here constants A and D are dimensionless, a constant B has units of , and a constant C is measured in siemens. These constants are sometimes referred to as generalized circuit constants, or ABCD constants.
  • 11. •Upto 80 Km •Shunt capacitance is neglected and resistance & inductance are lumped together. •Therefore, IS = IR = I Hence the ABCD constants for the short transmission line model, are A  1 B  Z C  0 D  1
  • 12. Considering medium-length lines (80 to 250 Km-long). •The shunt admittance is also included for calculations. However, the total admittance is usually modeled ( model) as two capacitors of equal values (each corresponding to a half of total admittance) placed at the sending and receiving ends.
  • 13. The current through the receiving end capacitor can be found as : Y I V 2 2 C R And the current through the series impedance elements is : Y I V  I 2 ser R R ---By Dhananjay Jha, Engineer (E), SJVN
  • 14. From the Kirchhoff’s voltage law, the sending end voltage is YZ     2 1 S ser R C R R 2 R R ZI V Z I I V V V ZI             The source current will be Y Y     I I  I  I  I  I  V   I Y V I ZY V ZY         1 1 2 1 1 2 2 4 2 S C ser C C R S R R R R      Therefore, the ABCD constants of a medium-length transmission line are 1 ZY 2 1 4 1 2 A B Z ZY C Y ZY D              If the shunt capacitance of the line is ignored, the ABCD constants are the constants for a short transmission line.
  • 15. • For long lines, it is not accurate enough to approximate the shunt admittance by two constant capacitors at either end of the line. Instead, both the shunt capacitance and the series impedance must be treated as distributed quantities. • The voltages and currents on the line is found by solving differential equations of the line.
  • 16. d     sinh ' tanh 2 ' 2 Z Z d d Y Y  d    Here, Z is the series impedance of the line, Y is the shunt admittance of the line, d is the length of the line,  is the propagation constant of the line.   yz where y is the shunt admittance per kilometer and z is the series impedance per km.
  • 17. The ABCD constants for a long transmission line are Z Y ' ' 1 2 ' ' ' ' 1 4 ' ' 1 2 A B Z Z Y C Y Z Y D             
  • 18. AC voltages are usually expressed as phasors. Load with lagging power factor. Load with unity power factor. Load with leading power factor. For a given source voltage VS and magnitude of the line current, the received voltage is lower for lagging loads and higher for leading loads.
  • 19. In overhead transmission lines, the line reactance XL is normally much larger than the line resistance R; therefore, the line resistance is often neglected. We consider next some important transmission line characteristics… 1. The effect of load changes Assuming that a single generator supplies a single load through a transmission line. Assuming that the generator is ideal, an increase of load will increase a real and (or) reactive power drawn from the generator and, therefore, the line current. 1) If more load is added with the same lagging power factor, the magnitude of the line current increases but the current remains at the same angle  with respect to VR as before.
  • 20. The voltage drop across the reactance increases but stays at the same angle. Assuming zero line resistance and source voltage to be of constant magnitude: Vs = VR + jXLI voltage drop across reactance jXLI will stretch between VR and VS. Therefore, when a lagging load increases, the received voltage decreases. 2) An increase in a unity PF load, on the other hand, will slightly decrease the received voltage at the end of the transmission line.
  • 21. 3) Finally, an increase in a load with leading PF increases the received (terminal) voltage of the transmission line.
  • 22.  In a summary: 1. If lagging (inductive) loads are added at the end of a line, the voltage at the end of the transmission line decreases . 2. If leading (capacitive) loads are added at the end of a line, the voltage at the end of the transmission line increases. ---By Dhananjay Jha, Engineer (E), SJVN
  • 23. The voltage regulation of a transmission line is  VReg = (Vnl - Vfl )/ Vfl where Vnl and Vfl are the no-load and full load voltages at the line output. ---By Dhananjay Jha, Engineer (E), SJVN
  • 24. 2. Power flow in a transmission line The real power input to a 3-phase transmission line can be computed as , 3 cos Pin  VS IS S  3VLL S IS cosS where VS is the magnitude of the source (input) line-to-neutral voltage and VLL,S is the magnitude of the source (input) line-to-line voltage. Similarly, the real output power from the transmission line is , 3 cos 3 cos out R R R LL R R R P  V I   V I  The reactive power input to a 3-phase transmission line can be computed as , 3 sin 3 sin in S S S LL S S S Q  V I   V I 
  • 25. And the reactive output power is , 3 sin Qout  VRIR R  3VLL RIR sinR The apparent power input to a 3-phase transmission line can be computed as , 3 3 in S S LL S S S  V I  V I And the apparent output power is , 3 3 out R R LL R R S  V I  V I
  • 26. A simplified phasor diagram of a transmission line indicating that IS = IR = I. Further it can be observed that the vertical segment bc can be expressed as either VS sin or XLIcos. Therefore: sin cos S L V I X   
  • 27. Then the output power of the transmission line equals to its input power: V V 3 sin S R L P X   Therefore, the power supplied by a transmission line depends on the angle between the phasors representing the input and output voltages. The maximum power supplied by the transmission line occurs when  = 900: max V V 3 S R L P X  This maximum power is called the steady-state stability limit of the transmission line. The real transmission lines have non-zero resistance and, therefore, overheat long before this point. Full-load angles of 250 are more typical for real transmission lines.
  • 28.  Few interesting observations can be made from the power expressions:  The maximum power handling capability of a transmission line is a function of the square of its voltage. For instance, if all other parameters are equal, a 220 kV line will have 4 times the power handling capability of a 110 kV transmission line.  Therefore, it is beneficial to increase the voltage. However, very high voltages is limit by other factors. ---By Dhananjay Jha, Engineer (E), SJVN
  • 29.  The maximum power handling capability of a transmission line is inversely proportional to its series reactance, which may be a serious problem for long transmission lines. Some very long lines include series capacitors to reduce the total series reactance and thus increase the total power handling capability of the line.  In a normal operation of a power system, the magnitudes of voltages VS and VR do not change much, therefore, the angle  basically controls the power flowing through the line. It is possible to control power flow by placing a phase-shifting transformer at one end of the line and varying voltage phase.
  • 30. 3. Transmission line efficiency The efficiency of the transmission line is P P 100% out in   
  • 31. 4. Transmission line ratings One of the main limiting factors in transmission line operation is its resistive heating. Since this heating is a function of the square of the current flowing through the line and does not depend on its phase angle, transmission lines are typically rated at a nominal voltage and apparent power. 5. Transmission line limits Several practical constrains limit the maximum real and reactive power that a transmission line can supply. The most important constrains are: 1. The maximum steady-state current must be limited to prevent the overheating in the transmission line. The power lost in a line is approximated as Ploss  3IL2R The greater the current flow, the greater the resistive heating losses.
  • 32. 2. The voltage drop in a practical line should be limited to approximately 5%. In other words, the ratio of the magnitude of the receiving end voltage to the magnitude of the sending end voltage should be greater than 95%. This limit prevents excessive voltage variations in a power system. 3. The angle  in a transmission line should typically be  300 ensuring that the power flow in the transmission line is well below the static stability limit and, therefore, the power system can handle transients.
  • 33.  Any of these limits can be more or less important in different circumstances.  In short lines, where series reactance X is relatively small, the resistive heating usually limits the power that the line can supply.  In longer lines operating at lagging power factors, the voltage drop across the line is usually the limiting factor.  In longer lines operating at leading power factors, the maximum angle  can be the limiting f actor. ---By Dhananjay Jha, Engineer (E), SJVN
  • 34.  Standard Voltage - 66,110,132, 220, 400 KV or above  Selection Criterion of Economic Voltage –  Quantum of power to be evacuated  Length of line  Voltage regulation  Power loss in Transmission  Surge impedance level ---By Dhananjay Jha, Engineer (E), SJVN
  • 35. Economic Voltage of Transmission of Power L KVA Nc Empirical Formula V  5.5  1.6 150 * V = Transmission voltage (KV) (L-L). L = Distance of transmission line in KM KVA=Power to be transferred Nc= Number of circuits ---By Dhananjay Jha, Engineer (E), SJVN
  • 36. ---By Dhananjay Jha, Engineer (E), SJVN
  • 37.  Aluminium Conductor Steel Reinforced consists of a solid or stranded steel core surrounded by one or more layers of strands of 1350 aluminium. The high-strength ACSR 8/1, 12/7 and 16/19 standings', are used mostly for overhead ground wires, extra long spans, river crossings, etc. The inner core wires of ACSR is of zinc coated (galvanized) steel. ---By Dhananjay Jha, Engineer (E), SJVN
  • 38.  Nomenclature :- Al/Steel/dia.  Panther :- 30/7/3.0 mm  Zebra :- 54/7/3.18mm  Snowbird :- 42/3.98 + 7/2.21mm  Moose :- 54/7/3.53mm ---By Dhananjay Jha, Engineer (E), SJVN
  • 39.  AAC (All Aluminium Conductor)  AAAC (All Aluminium Alloy Conductor)  AL-59  ACCC (Aluminium conductor composite core) ---By Dhananjay Jha, Engineer (E), SJVN
  • 40. ACSR Moose AAAC Moose Al-59 Dia. (mm) 31.77 31.05 31.50 Cross sectional area (sq-mm) 597 570 586.59 Ambient Temperature (deg.C) 40 40 40 Current carrying capacity(A) at 75 C 728 699 759 At 95 C NA 952 976 SAG (m) at 85 C 13.26 14.15 14.52 ---By Dhananjay Jha, Engineer (E), SJVN
  • 41.  Mechanical Requirement  Electrical Requirement Mechanical Requirement  Tensile Strength(For Tension)  Strain Strength(For Vibration) ---By Dhananjay Jha, Engineer (E), SJVN
  • 42. o Continuous current rating. o Short time current carrying rating. o Voltage drop o Power loss o Minimum dia to avoid corona o Length of line ---By Dhananjay Jha, Engineer (E), SJVN
  • 43. According to short time rating conductor size is given by- A 7.58* IF * t Where A=area of conductor(mm2) IF= fault current(KA) t= fault duration(1 sec.) ---By Dhananjay Jha, Engineer (E), SJVN
  • 44. Visual corona voltage in fair weather condition is given by-  (1  0.3)   V0= corona starting voltage, KV(rms)  r= radius of conductor in cm  D  D= GMD equivalent spacing between conductors in cm  m= roughness factor = 1.0 for clean smooth conductor =0.85 for stranded conductor         r n r r V 0 21.1 m log  ---By Dhananjay Jha, Engineer (E), SJVN
  • 45. Voltage gradient at the surface of conductor at operating voltage-    g 3     D r V Log n 0 Corona discharge form at the surface of conductor if g0≥ corona starting gradient i.e. g m r (1 0.3) r 21.1 0      (rms kv/cm) ---By Dhananjay Jha, Engineer (E), SJVN
  • 46.  River crossing  Weight/ Dia. - Less Weight/Dia ratio conductor swing more. ---By Dhananjay Jha, Engineer (E), SJVN
  • 47. In overhead transmission lines, the conductors are suspended from a pole or a tower via insulators.
  • 48. Insulator are required to support the line conductor and provide clearance from ground and structure.  Insulator material-  High grade Electrical Porcelain  Toughened Glass  Fiber Glass ---By Dhananjay Jha, Engineer (E), SJVN
  • 49.  System over voltage factors shall be evaluated.  Due to switching  Power frequency  Lightning ---By Dhananjay Jha, Engineer (E), SJVN
  • 50.  Switching over-voltage :  Switching off of long lines on no load  Energizing lines of no load ---By Dhananjay Jha, Engineer (E), SJVN
  • 51.  Power frequency over voltage  Loaded line interrupted at one end  Occurrence of fault  Open line suddenly connected to load ---By Dhananjay Jha, Engineer (E), SJVN
  • 52. ---By Dhananjay Jha, Engineer (E), SJVN
  • 53. Type of Insulator-  Pin type insulator  Suspension insulator  Strain insulator ---By Dhananjay Jha, Engineer (E), SJVN
  • 54.  Pin Type Insulator : Used for transmission and distribution of electric power at voltages up to 33 kV ---By Dhananjay Jha, Engineer (E), SJVN
  • 55.  Suspension : For voltages greater than 33 kV, it is a usual practice to use suspension type insulators ---By Dhananjay Jha, Engineer (E), SJVN
  • 56.  Strain : A dead end or anchor pole or tower is used where a straight section of line ends, or angles off in another direction. ---By Dhananjay Jha, Engineer (E), SJVN
  • 57.  Disc insulator are joint by their ball pins and socket in their caps to form string.  No of insulator disc is decided by system voltage, switching and lighting over voltage amplitude and pollution level.  Insulator string can be used either suspension or tension.  Swing of suspension string due to wind has to be taken into consider. Fig. single string Fig. Double string ---By Dhananjay Jha, Engineer (E), SJVN
  • 58. Earth wire provided above the phase conductor across the line and grounded at every tower.  It shield the line conductor from direct strokes  Reduces voltage stress across the insulating strings during lightning strokes Design criterion:  Shield angle  25°-30° up to 220 KV  20° for 400 KV and above  Earth wire should be adequate to carry very short duration lightning surge current of 100 KA without excessive over heating ---By Dhananjay Jha, Engineer (E), SJVN
  • 59. EARTH WIRE A  5 I  t A= Area(in mm2) of conductor I =current in KA t = Time in second Area of Steel Wire = 3*A(mm2)  For EHV line it is suggested as 70 mm2 (7/3.66 mm).  ACSR is used as earth wire (12/3.0 mm AL+7/3.0 mm steel)  OPGW ---By Dhananjay Jha, Engineer (E), SJVN
  • 60.  Optical Ground Wire  Advantages :  Serves the dual purpose of ground wire and communication.  High speed data transmission.  ---By Dhananjay Jha, Engineer (E), SJVN
  • 61. OPGW ---By Dhananjay Jha, Engineer (E), SJVN
  • 62. ---By Dhananjay Jha, Engineer (E), SJVN
  • 63. ---By Dhananjay Jha, Engineer (E), SJVN
  • 64.  A Smart Grid is an electricity network that can intelligently integrate the actions of all users connected to it – generators, consumers and those that do both – in order to efficiently deliver sustainable, economic and secure electricity supplies. European Smart Grid Technology Platform  SG3 defines Smart Grids as the concept of modernizing the electric grid. The Smart Grid is integrating the electrical and information technologies in between any point of generation and any point of consumption. Smart Grid Working Group 3 ---By Dhananjay Jha, Engineer (E), SJVN
  • 65.  The aim of smart grid is to provide real-time monitoring and control, and thus improve the overall efficiency of the entire system apart from inclusion of renewable energy resources into the system. ---By Dhananjay Jha, Engineer (E), SJVN
  • 66.  Presently, the Indian electricity system faces a number of challenges:  Shortage of power  Power Theft  Poor access to electricity in rural areas  Huge losses in the grid  Inefficient power consumption  Poor reliability ---By Dhananjay Jha, Engineer (E), SJVN
  • 67.  The Smart Grid is a transition of the present energy system into a new era of reliability, availability and efficiency.  The smart grid vision involves a uniformly integrated communication system with the present power system. ---By Dhananjay Jha, Engineer (E), SJVN
  • 68.  The India Smart Grid Task Force (ISGTF) is an inter-ministerial group set up under the chairmanship of Shri Sam Pitroda in September 2010 to serve as Government's focal point for activities related to Smart Grid and to evolve a road map for Smart Grids in India. ---By Dhananjay Jha, Engineer (E), SJVN
  • 69.  Indian Smart Grid Forum (ISGF) was set up in 2010 to provide a mechanism through which academia, industry, utilities and other stakeholders could participate in the development of Indian smart grid systems and provide relevant inputs to the government’s decision-making. ---By Dhananjay Jha, Engineer (E), SJVN
  • 70.  UHBVN,Haryana  CESC, Mysore  TSECL, Tripura  KSEB, Kerala  Electricity department-Govt. of Puducherry  UGVCL, Gujrat  AP CPDCL, Andhra Pradesh  APDCL, Assam  MSEDCL, Maharashtra  CSPDCL, Chattisgarh  HPSEB, Himachal Pradesh  PSPCL, Punjab  WBSEDCL, West Bengal  JVVNL, Rajasthan ---By Dhananjay Jha, Engineer (E), SJVN
  • 71.  HPSEB, Himachal Pradesh  Project Area- Kala Amb  No. of Consumers-650  Total Cost- 17.85 Cr.  MoP Share-Rs. 8.92 Cr. ---By Dhananjay Jha, Engineer (E), SJVN
  • 72.  Benefits Envisaged  Shifting peak load  Reduction in penalties  Reduction in outages  Status- RFP (Request for Proposal) issued on 25.08.2014. ---By Dhananjay Jha, Engineer (E), SJVN
  • 73. ---By Dhananjay Jha, Engineer (E), SJVN

Notas do Editor

  1. (rms kv/cm)
  2. Fig. single string
  3. Area of steel wire will be