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Alg1 lesson 9-2
1.
DistributiveProperty 4(x +
3) = 4x + 12 Factoring 4x + 12 = 4(x + 3) GCF of 4x and 12
2.
Factor GCF of
10y and 25 10y = 2 · 5 · y 25 = 5 · 5 GCF = 5 Factor 10y – 25 = 5(2y – 5) GCF: Example 2-1a
3.
3x2y = 3·x·x·y 12xy2 = 2·2·3·x·y·y Factor = 3xy (x + 4y) GCF: 3xy
4.
Factor GCF: Example
2-1a
5.
( 7 )(
0 ) = 0 ( 51 )( 0 )= 0 ( 0 )( 31 ) = 0 ( 79 )( 0 ) = 0 ( 42 )( 0 ) = 0 ( 0 )( 0 ) = 0
6.
Solve: (x
+ 1)(x – 2) = 0 x + 1 = 0 or x – 2 = 0 - 1 - 1 + 2 +2 x = -1 or x = 2 Check 2: (x + 1)(x – 2) = 0 (2 + 1)(2 – 2) = 0 (3)(0) = 0 Check -1: (x + 1)(x – 2) = 0 (-1 + 1)(-1 – 2) = 0 (0)(-3) = 0
7.
Solve: (x
+ 3)(x – 5) = 0 x + 3 = 0 or x – 5 = 0 - 3 - 3 + 5 +5 x = -3 or x = 5
8.
Solve or +2
+2 +1 +1 4 4 Example 2-4a
9.
Solve: x2 –
4x = 12 x2 – 4x – 12 = 0 -12 -12 Solve: (x + 2)(x – 6) = 0 x + 2 = 0 or x – 6 = 0 - 2 - 2 + 6 +6 x = -2 or x = 6
10.
Solve -12y2
-12y2 or 4 4 -1 -1 -3y = -1 -3 -3